Tools of GeometryDAY3: 1-3 Measuring Segments

distanceba

145 99 or

514 99

310 77

DISTANCE IS ALWAYS POSITIVE

AB andCD

Segments of the same length

AB

CD

midpoint segment

bisectortic marks

betweenA

B+BC=

AC

Part

+Part

=WHOLE

A P EAP +PE =AE

Part

+Part

=WHOLE

A P EAP + PE = AE

3x x+5AE=25

x=AP=PE=

(3x) +

(x+5) = 254x+5 =

25x=5

51525

AP=3(5)

PE=(5)+5

Part Part =

8x+11

= 12x – 1

12 = 4x3 = x8(3)+11=

12(3) – 135 = 35

35

357

2TU UV=

120

Part +Part =WHOLEJK +KL = JL(4x+6)

+(7x+15)

=12011x +21 = 120 x =

9

JK=4(9)+6

KL=7(9)+15

JK=42

KL=78

P RQ

PQ = QR6x – 7 = 5x

+ 1x = 8

6(8) – 7 = 5(8) + 141 =

41

41

41

PR = 82

NA B

59

3x+4

2x

AN + NB = AB(3x+4) + (2x) = 595x= 55x= 11

AN = 37NB = 22

Write your name in the top left of your notecard.

Pick any of the following three letters: A, B, or C.

Write that letter in the top right corner of your notecard.

You will complete the problem associated with your letter. Find what x equals and what each segment equals.

Point A is between points C and T.

CA= 2x – 2AT= 9xCT= 20

Point O is the midpoint of DG.DO= 12x – 6 OG= 10x

Point N is between points A and D.

AN= 5ND= 4x – 8AD= 3x+4

C A T

A N D

D O G

A

B

C