david raju 1.1 lines. at the end of this lesson you will be able to: write equations for...

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David Raju 1.1 Lines

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  • Slide 1
  • David Raju 1.1 Lines
  • Slide 2
  • At the end of this lesson you will be able to: Write equations for non-vertical lines. Write equations for horizontal lines. Write equations for vertical lines. Use various forms of linear equations. Calculate the slope of a line passing through two points. David Raju Y X
  • Slide 3
  • Lets review some vocabulary. David Raju Y X Slope (m) = Y) Vertical change ( Y) Y-intercept (b): The y-coordinate of the point where the graph of a line crosses the y-axis. Slope (m): The measure of the steepness of a line; it is the ratio of vertical change ( Y) to horizontal change ( X). X) Horizontal change ( X) X-intercept (a): The x-coordinate of the point where the graph of a line crosses the x-axis.
  • Slide 4
  • Equations of Non-vertical Lines. Lets look at a line with a y-intercept of b, a slope m and let (x,y) be any point on the line. David Raju Y X Y-axis X-axis (0,b) (x,y)
  • Slide 5
  • Slope Intercept Form The equation for the non-vertical line is: David Raju Y X Y-axis X-axis (0,b) (x,y) YYYY XXXX y = mx + b y = mx + b ( Slope Intercept Form ) Where m is: m = YY XX = (y b) (x 0)
  • Slide 6
  • More Equations of Non-vertical Lines. Lets look at a line passing through Point 1 (x 1,y 1 ) and Point 2 (x 2,y 2 ). David Raju Y X Y-axis X-axis (x 1,y 1 ) (x 2,y 2 )
  • Slide 7
  • Point Slope Form The equation for the non-vertical line is: David Raju Y X Y-axis X-axis YYYY XXXX y y 1 = m(x x 1 ) y y 1 = m(x x 1 ) ( Point Slope Form ) Where m is: m =m = YY XX = (y 2 y 1 ) (x 2 x 1 ) (x 1,y 1 ) (x 2,y 2 )
  • Slide 8
  • Equations of Horizontal Lines. Lets look at a line with a y-intercept of b, a slope m = 0, and let (x,b) be any point on the Horizontal line. David Raju Y X Y-axis X-axis (0,b) (x,b)
  • Slide 9
  • Horizontal Line The equation for the horizontal line is still David Raju Y X Y-axis X-axis y = mx + b y = mx + b ( Slope Intercept Form ). Where m is: m =m = YY XX = (b b) (x 0) Y = 0 XXXX (0,b) (x,b) = 0
  • Slide 10
  • Horizontal Line Because the value of m is 0, David Raju Y X y = mx + b becomes y = b (A Constant Function) Y-axis X-axis (0,b) (x,b)
  • Slide 11
  • Equations of Vertical Lines. Lets look at a line with no y-intercept b, an x- intercept a, an undefined slope m, and let (a,y) be any point on the vertical line. David Raju Y X Y-axis X-axis (a,0) (a,y)
  • Slide 12
  • Vertical Line The equation for the vertical line is David Raju Y X Y-axis X-axis x = a x = a ( a is the X-Intercept of the line). Because m is: m =m = YY XX = (y 0) (a a) = Undefined (a,0) (a,y)
  • Slide 13
  • Vertical Line Because the value of m is undefined, caused by the division by zero, there is no slope m. David Raju Y X x = a becomes the equation x = a (The equation of a vertical line) Y-axis X-axis (a,0) (a,y)
  • Slide 14
  • Example 1: Slope Intercept Form Find the equation for the line with m = 2/3 and b = 3 David Raju Y X Y-axis X-axis Because b = 3 Y = 2 X = 3 (0,3) X = 3 The line will pass through (0,3) Because m = 2/3 The Equation for the line is: y = 2/3 x + 3 Y = 2
  • Slide 15
  • Slope Intercept Form Practice Write the equation for the lines using Slope Intercept form. David Raju Y X 1.) m = 3 & b = 3 2.) m = 1 & b = -4 3.) m = -4 & b = 7 4.) m = 2 & b = 0 5.) m = 1/4 & b = -2
  • Slide 16
  • Example 2: Point Slope Form Lets find the equation for the line passing through the points (3,-2) and (6,10) David Raju Y X Y-axis X-axis YYYY XXXX First, Calculate m : m =m = YY XX = (10 -2) (6 3) (3,-2) (6,10) 3 12= =4
  • Slide 17
  • Example 2: Point Slope Form To find the equation for the line passing through the points (3,-2) and (6,10) David Raju Y X Y-axis X-axis YYYY XXXX y y 1 = m(x x 1 ) Next plug it into Point Slope From : (3,-2) (6,10) y -2 = 4(x 3) Select one point as P 1 : Lets use (3,-2) The Equation becomes:
  • Slide 18
  • Example 2: Point Slope Form Simplify the equation / put it into Slope Intercept Form David Raju Y X Y-axis X-axis YYYY XXXX y + 2 = 4x 12 Distribute on the right side and the equation becomes: (3,-2) (6,10) Subtract 2 from both sides gives. y + 2 = 4x 12 -2 = - 2 y = 4x 14
  • Slide 19
  • Point Slope Form Practice Find the equation for the lines passing through the following points using Point Slope form. David Raju Y X 1.) (3,2) & ( 8,-2) 2.) (-5,4) & ( 10,-12) 3.) (1,-5) & ( 7,7) 4.) (4,2) & ( -8,-4) 5.) (5,3) & ( 7,9)
  • Slide 20
  • Example 3: Horizontal Line Lets find the equation for the line passing through the points (0,2) and (5,2) David Raju Y X Y-axis X-axis y = mx + b y = mx + b ( Slope Intercept Form ). Where m is: m =m = YY XX = (2 2) (5 0) Y = 0 XXXX (0,2) (5,2) = 0
  • Slide 21
  • Example 3: Horizontal Line Because the value of m is 0, David Raju Y X y = 0x + 2 becomes y = 2 (A Constant Function) Y-axis X-axis (0,2) (5,2)
  • Slide 22
  • Horizontal Line Practice Find the equation for the lines passing through the following points. David Raju Y X 1.) (3,2) & ( 8,2) 2.) (-5,4) & ( 10,4) 3.) (1,-2) & ( 7,-2) 4.) (4,3) & ( -2,3)
  • Slide 23
  • Example 4: Vertical Line Lets look at a line with no y- intercept b, an x-intercept a, passing through (3,0) and (3,7). David Raju Y X Y-axis X-axis (3,0) (3,7)
  • Slide 24
  • Example 4: Vertical Line The equation for the vertical line is: David Raju Y X Y-axis X-axis x = 3 x = 3 ( 3 is the X-Intercept of the line). Because m is: m =m = YY XX = (7 0) (3 3) = Undefined (3,0) (3,7) = 7 0
  • Slide 25
  • Vertical Line Practice Find the equation for the lines passing through the following points. David Raju Y X 1.) (3,5) & ( 3,-2) 2.) (-5,1) & ( -5,-1) 3.) (1,-6) & ( 1,8) 4.) (4,3) & ( 4,-4)
  • Slide 26
  • Graphing Calculator Activity Using a TI-84 calculator, graph the following equations. David Raju y 1 = 4x + 5 y 2 = ( 1/2 )x + 3 Y 3 = -2x + 2 y 4 = -(1/4)x + 1 y 5 = 4x + 0
  • Slide 27
  • Graphing Calculator Activity Describe the graphs of each of the lines. Include any similarities or differences you see in the graphs. Be sure to Zoom Standard and Zoom Square before you answer these questions. David Raju y 1 = 4x + 5 y 2 = ( 1/2 )x + 3 Y 3 = -2x + 2 y 4 = -(1/4)x + 1 y 5 = 4x + 0 Y-axis X-axis Press the space bar to compare your graphs with mine. The equation and its graph are color coded.
  • Slide 28
  • Graphing Calculator Activity Using a TI-84 calculator, graph the following equations. David Raju y 1 = 2x + 3 y 2 = ? Y 3 = -3x + -1 y 4 = ? y 5 = 7 y 6 = ? Now, graph each line given and a line that is Parallel to it on the calculator. Record the equations you use on your sheet.
  • Slide 29
  • Graphing Calculator Activity Compare the graphs of each set of lines. Be sure to Zoom Standard and Zoom Square before you compare graphs. David Raju Y-axis X-axis Press the space bar to compare your graphs with mine. The equations and their graphs are color coded. y 1 = 2x + 3 y 2 = ? Y 3 = -3x + -1 y 4 = ? y 5 = 7 y 6 = ?
  • Slide 30
  • Graphing Calculator Activity Using a TI-84 calculator, graph the following equations. David Raju y 1 = 2x + 3 y 2 = ? Y 3 = -3x + -1 y 4 = ? y 5 = 7 y 6 = ? Now, graph each line given and a line that is Perpendicular to it on the calculator. Record the equations you use on your sheet.
  • Slide 31
  • Graphing Calculator Activity Compare the graphs of each set of lines. Be sure to Zoom Standard and Zoom Square before you compare graphs. David Raju Y-axis X-axis Press the space bar to compare your graphs with mine. The equations and their graphs are color coded. y 1 = 2x + 3 y 2 = ? Y 3 = -3x + -1 y 4 = ? y 5 = 7 y 6 = ?
  • Slide 32
  • Graphing Equations Conclusions What are the similarities you see in the equations for Parallel lines? What are the similarities you see in the equations for Perpendicular lines? Record your observations on your sheet. David Raju
  • Slide 33
  • Equation Summary David Raju Slope (m) = Y) Vertical change ( Y) X) Horizontal change ( X) Slope-Intercept Form: y = mx + b Point-Slope Form: y y 1 = m(x x 1 )