Đáp án đề thi tuyển sinh vào lớp 10 môn toán 2015 - tp.hồ chí minh
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Đáp án đề thi tuyển sinh vào lớp 10 Môn Toán 2015 - Tp.Hồ Chí MinhTRANSCRIPT
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THI T
UY
N S
INH
V
O L
P
10
M
N T
O
N
Tp. H
C
h M
inh
- 201
5
Cu
1.
(2
im
) Gi
i cc
ph
ng
trnh
v h
ph
ng
trnh
sau:
2
.
8
150
ax
x
2
.2
2
20
b
x
x
4
2
.
5
60
cx
x
2
5
3
. 3
4x
y
dxy
Cu
2.
(1,5
i
m) T
rong
mt
ph
ng t
a
cho
para
bol
2
:P
yx
v
ng
ng
thn
g :
2.
D
yx
.a V
P v
D tr
n c
ng m
t h
tr
c ta
.
.b T
m t
a
giao
i
m c
a P v
D b
ng
php
tnh
.
Cu
3.
(1,5
i
m) T
hu g
n c
c bi
u th
c sa
u:
1
10
0,
4
4
2
2
134
37
43
820
243
243
x
x
x
A
x
x
x
x
x
B
Cu
4.
(1,5
i
m) C
ho p
hn
g tr
nh
2
20
1,
xmxm
x
l n
s.
.a C
hng
min
h ph
ng
trn
h 1
lun
c 2
ngh
im
ph
n bi
t v
i m
i
.m
.b
nh m
h
ai n
ghi
m 1
2,xx
tha
mn
:
2
2
1
2
1
22
24.
1
1
x
x
x
x
Cu
5.
(3,5
i
m) C
ho ta
m g
ic
ABCAB
AC
c b
a gc
nh
n.
ng
trn
tm
O
ng
kn
h BC
ct
cc c
nh
,AB
AC l
n l
t t
i ,
.EF
Gi
H l
gia
o i
m c
a BE
v
;CF
D l
gia
o i
m c
a AH
v
.BC
.a C
hng
min
h AD
BC
v
.
..
AHAD
AEAC
.b C
hng
min
h EFDO
l t
gi
c ni
tip
.
.c T
rn
tia
i c
a tia
DE
ly
im
L sa
o ch
o
.
DLDF
Tn
h s
o
gc
.
BLC
.d G
i
,RS
ln
lt
l h
nh
chi
u c
a ,BC
ln
.EF
Ch
ng m
inh
.
DEDF
RS
-
P
N
TH
I TU
YN
SIN
H V
O
L
P 10
M
N
TO
N
Tp. H
C
h M
inh
- 201
5
Cu
1. G
ii c
c p
hn
g tr
nh v
h p
hn
g tr
nh.
.a
2
5
8
150
.3x
x
x
x
Vy
ph
ng
trnh
c h
ai n
ghi
m l
3x
v
5.
x
.b
2
2
2
20
x
x
2
2
1
2
4
2
42
2
18
32
23
22
2
4
23
2
2 .
2
4
2
b
ac
b
x
a
b
x
a
Vy
ph
ng
trnh
c h
ai n
ghi
m l
2
x
v
2 .
2
x
.c
4
2
5
60
x
x
t
2 ,0.
txt
K
hi
2
6
56
0
1
(nha
n)
(lo
ai)
t
t
t
t
Vi
2
6
6
6
.6
x
t
x
x
Vy
ph
ng
trnh
c h
ai n
ghi
m l
6
x
v
6.
x
.d
2
5
3
2
5
3
2
5
3
1 .
3
4
15
5
20
17
17
1
x
y
x
y
x
y
x
xy
x
y
x
y
Vy
ngh
im
ca h
ph
ng
trnh
l
1;
1.
-
C
u 2
. Ta c
2
:
,
:
2.
Pyx
D
yx
.a V
th c
a
P v
D tr
n c
ng h
tr
c ta
.
.b P
hn
g tr
nh h
onh
giao
i
m c
a P v
:
D
2
2
1
1
2
20
2
4.
x
y
x
x
x
x
x
y
Vy
P v
D g
iao
nhau
ti h
ai
im
1;1,
2;4
.
A
B
Cu
3.
Rt g
n c
c bi
u th
c
1
10
4
2
2
2
1
2
10
4
4
2
2
102
8
4
4
4
2.
x
x
x
A
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
134
37
43
820
243
243
134
37
43
820
24
33
134
37
43
83
31
35
B
-
Cu
4. P
hn
g tr
nh
2
20
1
x
mxm
.a
Ta c
2
2
2
4
2
4
8
2
40,
.
m
m
m
m
m
m
Vy
ph
ng
trnh
1 lu
n c
hai
ngh
im
ph
n bi
t.
.b
Theo
n
h l
Vi-
t ta c
1
2
12
2
xx
m
xx
m
Ta c
2
2
2
2
2
2
12
1
2
1
2
1
2
12
1
22
22
12
1
2
12
12
1
2
2
2
2
2
4
2
2
1
1
1
2
2
4
1
2
2
2
2
4
2
1
.
xx
x
x
x
x
x
x
xx
xx
xx
xx
xx
xx
xx
m
m
m
m
m
m
Suy
ra
2
2
2
2
1
2
1
2
2
2
24
4
8
2
1
1
m
x
x
m
m
m
x
x
-
Cu
5.
.a
V BEC
v BFC
l c
c gc
ni
tip
chn
na
ng tr
n
ng
kn
h BC
nn
90o
BE
AC
BEC
BFC
H
BF
AB
l tr
c t
m c
a tam
gi
c
.
ABC
AD
BC
Hai
tam
vu
ng ADC
v AEH
c g
c DAC
chun
g n
n
.
..
AD
AE
ADC
AEH
ADAH
ACAE
AC
AH
.b
Ta c
1
EOB
BE
Mt
kh
c ta d
dn
g ch
ng
min
h
c t
gi
c BDHF
ni
tip
nn
1
2
2
HFD
HBD
EC
-
Ta c
ng c
1
3
2
EFC
EC
T 2 v
3 su
y ra
4
HFD
DFE
EFC
EC
T 1 v
4 su
y ra
180o
EOBDFEBE
ECBC
Suy
ra t
gi
c EFDO
ni
tip
.
.c
V
5
FDH
FBH
ECH
EDH
FDB
EDC
BDL
Hai
tam
gi
c BED
v BLD
c
ED ch
ung.
FBD
LBD
(d
o 5)
FD
DL
(gi
thi
t)
BED
BLD
(c-g
-c)
;
90.
: chu
ng
o
FBC
LBCBF
BL
BLC
BFC
BLC
BFC
BC
.d
V t
heo
cu c
ta
c
0
90
BLC
nn
.
L
O
Gi
,
,
.
M
CS
ON
BM
LEM
C
Khi
ta d
dn
g th
y NBE
cn
ti
,N
NLM
cn
ti
.N
.
NENB
ELBM
NM
NL
M
.
RSBM
MNNM
LNNE
ELED
DLED
EF
TRU
NG
T
M C
N
G H
C
TO
N