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1. (d)2. (a)3. (a)4. (a)5. (a)6. (b)7. (b)8. (c)9. (b)10. (d)11. (d)12. (b)13. (d)14. (c)15. (d)16. (b)17. (a)18. (c)19. (c)20. (c)21. (c) E = E1 + E2

21

hchchc 21

111 2

1680

1355

1 2 = 742.76 nm.22. (b) x P = 4h

x [mv] = 4hv = 100005.0600 = 0.03So x [9.1 1031 0.03] =

14.34106.6 34

x = 3134 1003.01.914.34 106.6 = 1.92 103M.

IIT ASHRAMA VENTURE OF JEE MAINS/ JEE ADVANCED/ AIPMT/ AIIMS/ KVPY/ OLYMIPIAD EXPERTS

COMMON PRACTI CE TEST-14ANANDALAYA

11th (Medical) Chemistry Solution Dt. 02-11-2014

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23. (c) The electron have n + l higher value have hegher energy.n + l = 3 + 0 = 3n + l = 3 + 1 = 4n + l = 3 + 2 = 5(highest energy)n + l = 4 + 0 = 4

24. (a) 28Ni [Ar]3d8 4s2 4p3d 4sNumber of unpaired electrons (n) = 2 = 84.28)22(2)2n(n

25. (d) Angular momentum of the electron, mvr = 2nh where n = 5 (given) Angular momentum = h5.22h5

26. (c)27. (d)

28. (b) Molarity = ltV

soluteofMoles = 1000/100

1002.6/1102.6 2320 = 0.01 M

29. (b) MnO4 ; x + 4(2) = 1 or x = + 7 ;CrO2Cl2 ; x + 2(2) + 2(1) = 0 or x = +6.

30. (a) 2(+1) + 1(x) + 5(1) + 1 (+1) = 0. x = + 2.31. (b) Eq. mass = Mnof.NooxidationinChange

weightMolecular = 24

wt.Mol. = 2

wt.Mol.

(O.N. of Mn in MnSO4 = +2; O.N. of Mn in MnO2 = +4).

32. (b) PV = P1001P V2V2 =

P100101PV V2 = 101100 V

% decrease % deh = VV

101100

= 101100

%

33. (c) V T (at constant n and P).34. (d) PV = nRT

P dM

= nRT dMVd = RT

PM

35. (a) Equal masses of CO and N2 contain equal moles alsoOn applying charles law :

V P (At const T and n) 2NP = PCO

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36. (a) P.PCH4 = 1616

4444

2856

1616

720 (where P.P = Partial pressure)= 4

1 720 = 180 mm.

37. (b) 2

2

H

O)dt/dn()dt/dn(

=

2

2

OH

MM

Here, ;gk x = wt. of H2 (H2 dk Hkkj gS

dt2/x

dt32/4

= 322

x32

8 = 4

1

x = 1 g.

38. (a) 2

1

dtdndtdn

= 32Mx

(Here dn is same)

45dn18dn

= 32Mx

2

1845 = 32Mx

Mx = 2

1845 32.

39. (a) 2

2

OSOr

r =

2

2

SOO

MM

2

2

OSOr

r = 64

32 2

2

OSOr

r = 2

1 = 1 : 2

40. (b) 2

1

gasgas

r

r =

1

2

gasgas

dd

2

1

gasgas

r

r = 16

2

1

gasgas

r

r = 4