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Coverage Analysis of HetNets with
Base Station Cooperation and Interference Cancellation
Martin Haenggi
Dept. of Electrical Engineering
University of Notre Dame
Notre Dame, IN, USA
2014 HetNet Workshop
June 16, 2014
Work supported by:U.S. NSF (CNS 1014932 and CCF 1216407)
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 1 / 46
Coverage Analysis of HetNets withBase Station Cooperation and Interference Cancellation:
Why the Waist-to-Hip Ratio is Essential
Martin Haenggi
Dept. of Electrical Engineering
University of Notre Dame
Notre Dame, IN, USA
2014 HetNet Workshop
June 16, 2014
Work supported by:U.S. NSF (CNS 1014932 and CCF 1216407)
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 2 / 46
Content
Contents
Coverage
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 3 / 46
Content
Small cells
A small cell.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 4 / 46
Content
Cell-ular user
A cell phone.
No noise
This is a completely noise-less talk.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 5 / 46
Overview
Menu
Overview
Bird’s view of cellular networks
The HIP model and its properties
Comparing SIR distributions: The crucial role of the meaninterference-to-signal ratio (MISR)
MISR gain due to BS silencing and cooperation
DUI: Diversity under interference
General BS cooperation
Back to modeling: Inter- and intra-tier dependence
Conclusions
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 6 / 46
Introduction The big picture
Big picture
Frequency reuse 1: A single friend, many foes
−4 −3 −2 −1 0 1 2 3 4−4
−3
−2
−1
0
1
2
3
4
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 7 / 46
Introduction The big picture
A walk through a single-tier cellular network
−4 −3 −2 −1 0 1 2 3 4−4
−3
−2
−1
0
1
2
3
4
−3 −2 −1 0 1 2 3−6
−4
−2
0
2
4
6
8
10
12SIR (no fading)
x
SIR
(dB
)
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 8 / 46
Introduction The big picture
Coverage at 0 dB
−4 −3 −2 −1 0 1 2 3 4−4
−3
−2
−1
0
1
2
3
4
−3 −2 −1 0 1 2 3−6
−4
−2
0
2
4
6
8
10
12SIR (no fading)
x
SIR
(dB
)
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 9 / 46
Introduction The big picture
SIR distribution
−3 −2 −1 0 1 2 3−25
−20
−15
−10
−5
0
5
10
15SIR (with fading)
x
SIR
(dB
)
For ergodic models, the fraction of the curve that is above the threshold θis the ccdf of the SIR at θ:
ps(θ) , F̄SIR(θ) , P(SIR > θ)
It is the fraction of the users with SIR > θ if users are uniformly distributed.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 10 / 46
HIP model Definition
The HIP baseline model for HetNets
The HIP (homogeneous independent Poisson) model
−2 −1.5 −1 −0.5 0 0.5 1 1.5 2−2
−1.5
−1
−0.5
0
0.5
1
1.5
2
Start with a homogeneous Poisson point process (PPP). Here λ = 6.Then randomly color them to assign them to the different tiers.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 11 / 46
HIP model Definition
The HIP (homogeneous independent Poisson) model
−2 −1.5 −1 −0.5 0 0.5 1 1.5 2−2
−1.5
−1
−0.5
0
0.5
1
1.5
2
−2 −1.5 −1 −0.5 0 0.5 1 1.5 2−2
−1.5
−1
−0.5
0
0.5
1
1.5
2
Randomly assign BS to each tier according to the relative densities. Hereλi = 1, 2, 3. Assign power levels Pi to each tier.This model is doubly independent and thus highly tractable.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 12 / 46
HIP model Basic result
Basic result for downlink
Assumptions:
A user connects to the BS that is strongest on average, while allothers interfere.
Homogeneous path loss law ℓ(r) = r−α and Rayleigh fading.
Result for α = 4:
ps(θ) = P(SIR > θ) = F̄SIR(θ) =1
1 +√θ arctan
√θ.
Remarkably, this is independent of the number of tiers, their densities, andtheir power levels.So as far as the SIR is concerned, we can replace the multi-tier HIP modelby an equivalent single-tier model.(For bounded path loss laws, this does not hold.)
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 13 / 46
HIP model Basic result
Properties of the HIP model
For the unbounded path loss law:
E(S) = ∞ and E(SIR) = ∞ due to the proximity of the strongest BS.
E(I ) = ∞ for α ≥ 4 due to the proximity of the strongest interferer.
The first two properties are not restricted to the Poisson model.
Remarks
Per-user capacity improves with smaller cells, but coverage does not.(Unless the interference benefit from inactive BSs kicks in.)
Question: How to boost coverage?⇒ Non-Poisson deployment⇒ BS silencing⇒ BS cooperation
How to quantify the improvement in the SIR distribution?
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 14 / 46
Comparing SIR Distributions
Comparing SIR distributions
Two distributions
−15 −10 −5 0 5 10 15 20 250
0.2
0.4
0.6
0.8
1SIR CCDF
θ (dB)
P(S
IR>
θ)
baseline schemeimproved scheme
How to quantify the improvement?
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 15 / 46
Comparing SIR Distributions Vertical comparison
The standard comparison: vertical
−15 −10 −5 0 5 10 15 20 250
0.2
0.4
0.6
0.8
1SIR CCDF
θ (dB)
P(S
IR>
θ)
baseline schemeimproved scheme
At -10 dB, the gap is 0.058. Or 6.4%.
At 0 dB, the gap is 0.22. Or 39%.
At 10 dB, the gap is 0.15. Or 73%.
At 20 dB, the gap is 0.05. Or 78%.
Or use the gain in P(SIR ≤ θ)?
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 16 / 46
Comparing SIR Distributions Horizontal comparison
A better choice: horizontal
−15 −10 −5 0 5 10 15 20 250
0.2
0.4
0.6
0.8
1SIR CCDF
θ (dB)
P(S
IR>
θ)
G
G
G
Gbaseline schemeimproved scheme
Use the horizontal gap instead.
This SIR gain is nearly constantover θ in many cases.
If the improvement is due to betterBS deployment, it is the deploymentgain.
ps = P(SIR > θ) ⇒ ps = P(SIR > θ/G ).
Can we quantify this gain?
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 17 / 46
Comparing SIR Distributions The horizontal gap
Horizontal gap at probability p
The horizontal gap between two SIR ccdfs is
G (p) ,F̄−1
SIR2(p)
F̄−1SIR1
(p), p ∈ (0, 1),
where F̄−1SIR is the inverse of the ccdf of the SIR, and p is the target success
probability.We also define the asymptotic gain (whenever the limit exists) as
G , G (1) = limp→1
G (p).
Relevance
We will show that
G is relatively easy to determine.
G (p) ≈ G for all practical p.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 18 / 46
Comparing SIR Distributions ISR
The ISR
Definition (ISR)
The interference-to-average-signal ratio is
ISR ,I
Eh(S),
where Eh(S) is the desired signal power averaged over the fading.
Comments
The ISR is a random variable due to the random positions of BSs andusers. Its mean MISR is a function of the network geometry only.
If the desired signal comes from a single BS at distance R , ISR = IRα.
If the interferers are located at distances Rk ,
MISR , E(ISR) = E
(
Rα∑
hkR−αk
)
=∑
E
(
R
Rk
)α
.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 19 / 46
Comparing SIR Distributions ISR
Relevance of the ISR
−30 −25 −20 −15 −10 −5 0
10−3
10−2
10−1
100
SIR CDF (outage probability)
θ (dB)
P(S
IR<
θ)
Gasym
baseline schemeimproved scheme
pout = P(hR−α < θI ) = P(h < θ ISR)
For exponential h and θ → 0,
P(h < θ ISR | ISR) ∼ θ ISR,
thus P(h < θ ISR) ∼ θE(ISR).
So the asymptotic gain is
G , E(ISR1)/E(ISR2) .
So the gain is the ratio of the two MISRs.
How accurate is the asymptotic gain for non-vanishing θ?
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 20 / 46
Comparing SIR Distributions ISR
The ISR for the HIP model
For the (single-tier) HIP model, we need to calculate the MISR
E(ISR) = E
(
Rα1
∞∑
k=2
R−αk
)
=
∞∑
k=2
E
(
R1
Rk
)α
,
where Rk is the distance to the k-th nearest BS.The distribution of νk = R1/Rk is
Fνk (x) = 1 − (1 − x2)k−1, x ∈ [0, 1].
Summing up the α-th moments E(ναk ), we obtain (remarkably)
E(ISR) =2
α− 2.
This is the baseline E(ISR) relative to which we measure the gain.For α = 4, it is 1. Hence pout(θ) = FSIR(θ) ∼ θ, θ → 0.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 21 / 46
Gains due to Deployment and Cooperation Deployment gain
Deployment gain
−20 −15 −10 −5 0 5 100.3
0.4
0.5
0.6
0.7
0.8
0.9
1PPP and square lattice, α= 3.0
θ (dB)
P(S
IR>
θ)
PPPsquare latticeISR−based gain
−20 −15 −10 −5 0 5 100.3
0.4
0.5
0.6
0.7
0.8
0.9
1PPP and square lattice, α= 4.0
θ (dB)P
(SIR
>θ)
PPPsquare latticeISR−based gain
For the square lattice, the gap (deployment gain) is quite exactly 3dB—irrespective of α! For α = 4, psq
s = (1 +√
θ/2 arctan√
θ/2)−1.
For the triangular lattice, it is 3.4 dB. This is the maximum achievable.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 22 / 46
Gains due to Deployment and Cooperation BS silencing
BS silencing: neutralize nearby foes
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M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 23 / 46
Gains due to Deployment and Cooperation BS silencing
Gain due to BS silencing (or interference cancellation) for HIP model
Let ISR(!n)
be the ISR obtained when the n strongest (on average)interferers are silenced.For HIP,
E(ISR(!n)
) =2Γ(1 + α/2)
α− 2
Γ(n + 2)
Γ(n + 1 + α/2).
For α = 4, in particular,
E(ISR(!n)
) =2
n + 2.
So the gain from silencing n BSs is simply
Gsilence = 1 +n
2.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 24 / 46
Gains due to Deployment and Cooperation Interference cancellation
Remarks on interference cancellation
The gain from successive canceling interferers is highest if transmittersare clustered.
For a non-homogeneous Poisson model with intensity functionλ(x) = a‖x‖b , b ∈ (−2, α− 2), the closer b to −2, the better.
If small-cell BSs are clustered due to high user density or ifclosed-access femtocells exist, SIC is promising.
Probability of decoding k-th strongest transmitter if k − 1 havealready been decoded, for arbitrary fading:
For θ ≥ 1 : Pk =1
θkβΓ(1 + kβ)(Γ(1 − β))k,
where β = (2 + b)/α ∈ (0, 1).
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 25 / 46
Gains due to Deployment and Cooperation BS cooperation
BS cooperation: turn nearby foes into friends
−4 −3 −2 −1 0 1 2 3 4−4
−3
−2
−1
0
1
2
3
4
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 26 / 46
Gains due to Deployment and Cooperation BS cooperation
Cooperation for worst-case users
SIR at Voronoi vertices with cooperation
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−1
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At these locations (×), the user isfar away from any BS, and thereare two interfering BS at thesame distance.
In the Poisson model,
F̄×
SIR(θ) =F̄ 2
SIR(θ)
(1 + θ)2.
With BS cooperation from the 3equidistant BSs, for α = 4,
F̄×,coop
SIR (θ) = F̄ 2SIR(θ/3) =
(
1 +√
θ/3 arctan(√
θ/3))
−2
.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 27 / 46
Gains due to Deployment and Cooperation BS cooperation
SIR at Voronoi vertices with cooperation
−20 −15 −10 −5 0 5 100
0.2
0.4
0.6
0.8
1SIR CCDF for PPP, α=4
θ (dB)
P(S
IR>
θ)
general userworst−case, no coop.worst−case, 3−BS coop.
Without cooperation,E(ISR) = 4 (for α = 4).
With 3-BS cooperation, theSIR performance is slightlybetter for the worst-case usersthan the general users, andE(ISR) = 2/3.
So the gain from 3-BScooperation is 6, or 7.8 dB.
Can we approximate the SIR distribution using the ratio of the two MISRs?
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 28 / 46
Gains due to Deployment and Cooperation BS cooperation
Using the ISR approximation
−20 −15 −10 −5 0 5 100
0.2
0.4
0.6
0.8
1SIR CCDF for PPP, α=4
θ (dB)
P(S
IR>
θ)
general userworst−case, no coop.worst−case, 3−BS coop.shifted by E(ISR) ratio
For worst-case users withn ∈ {1, 2, 3} BSs cooperating,
E(ISR) =4 + (3 − n)(α− 2)
n(α− 2).
So for n = 3, the ratio of the twoMISRs is
Gcoop =MISR
MISRcoop
= 3 +3
2(α− 2).
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 29 / 46
Diversity Definition
DUI: Diversity under interference
Decreasing the variability in the SIR
The shift along the θ axis preserves the variability in the SIR.The variability can be decreased by increasing the diversity.
Definition (DUI)
The diversity under interference is defined as
d , limθ→0
log pout(θ)
log θ.
Hencepout(θ) = FSIR(θ) = Θ(θd).
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 30 / 46
Diversity Diversity for HIP model
Diversity for HIP model
−40 −30 −20 −10 0
10−4
10−3
10−2
10−1
100
Outage for PPP with Nakagami fading, m=[1 2 5 ∞ ]
θ (dB)
P(S
IR<
θ)
m=1m=2m=5no fading
−20 −15 −10 −5 0 5 100.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1PPP with Nakagami fading, m=[1 2 5 ∞ ]
θ (dB)P
(SIR
>θ)
m=1m=2m=5no fading
For a PPP with Nagakami-m fading, d = m.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 31 / 46
Diversity SIR gain
SIR gain with diversity
If the fading distribution satisfies Fh(x) ∼ axm, x → 0, (Nakagami fading)
pout(θ) ∼ aθmE(ISRm).
The diversity order is m—if the m-th moment of the ISR is finite.
The asymptotic gain is
G (m) =
(
E(ISRm
1 )
E(ISRm
2 )
)1/m
≈ G (1).
For the PPP, all moments of the ISRm
are finite.
For a large class of mixing motion-invariant point process models, themoments E(ISR
m) exist, and all outage curves have the same slope. The
exact necessary conditions have not been established.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 32 / 46
Diversity SIR gain
Deployment gain for Nakagami fading
−15 −10 −5 0 5 100.3
0.4
0.5
0.6
0.7
0.8
0.9
1SIR CCDF, α=4, Nakagami fading, m= 2
θ (dB)
P(S
IR>
θ)
PPPsquare latticeISR−based approx
−15 −10 −5 0 5 100.3
0.4
0.5
0.6
0.7
0.8
0.9
1SIR CCDF, α=4, Nakagami fading, m= 5
θ (dB)
P(S
IR>
θ)
PPPsquare latticeISR−based approx
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 33 / 46
General BS sharing
General BS sharing
Fluid sharing of BS resources
Take a non-increasing function f : R+ 7→ R+.
Let (r1, r2, r3) be the triplet of distances to the 3 nearest BSs.
s = f (r1) + f (r2) + f (r3)
Allocate resources according to f (ri )/s from BS i .
Example:• f (r) = r−α. For α → ∞, this is the non-sharing (hard) scheme.• f (r) ≡ 1: BS sharing with equal powers.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 34 / 46
Amorphous networks
Towards amorphous networks
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No BS sharing
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BS sharing with α = 4
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 35 / 46
Amorphous networks
"SIR walk"
−4 −3 −2 −1 0 1 2 3 4−4
−3
−2
−1
0
1
2
3
4
BS sharing with α = 4
−3 −2 −1 0 1 2 3−10
−5
0
5
10
15
20
25
xS
IR (
dB)
SIR (no fading)
without BS sharingwith BS sharing
SIR improvement atequal total power consumption
This BS sharing framework can be reversed for the uplink in a natural way.There is hope that such a fluid BS sharing model is tractable.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 36 / 46
Cellular network modeling
Back to modeling
Introducing dependencies
BS of one tier are not placed completely independently (intra-tierdependence).
BS of different tiers are not placed independently, either (inter-tierdependence).
Intra-tier dependence
The HIP model is conservative since it places BSs arbitrarily close to eachother.In actual deployments, it is unlikely to have two BSs very close, so the BSsform a soft-core or hard-core process. In other words, the BSs process isrepulsive.Repulsion can be quantified using the pair correlation function g(r). Forthe PPP, g(r) ≡ 1. For a repulsive process, g(r) < 1.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 37 / 46
Cellular network modeling
Adjusting to population density
−6 −4 −2 0 2 4 6−6
−4
−2
0
2
4
6
A single tier with density adjusted according to the population density tokeep the average number of (active) users per cell constant.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 38 / 46
Cellular network modeling
Two-tier models
−6 −4 −2 0 2 4 6−6
−4
−2
0
2
4
6
Small cells for urban regions−6 −4 −2 0 2 4 6
−6
−4
−2
0
2
4
6
Overlay with small cells
Either way, there is intra- and inter-tier dependence.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 39 / 46
Cellular network modeling The Ginibre point process
The Ginibre model
Realizations of PPP and the Ginibre point process (GPP) on b(o, 8)
−5 0 5
−5
0
5
PPP with n=65
−5 0 5−8
−6
−4
−2
0
2
4
6
81−GPP with n=64
The GPP exhibits repulsion—just as BSs in a cellular network.Its pair correlation function is g(r) = 1 − e−r2 .
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 40 / 46
Cellular network modeling The Ginibre point process
The Ginibre point process
The GPP is a motion-invariant determinantal point process.
Remarkable property: If Φ = {x1, x2, . . .} ⊂ R2 is a GPP, then
{‖x1‖2, ‖x2‖2, . . .} d= {y1, y2, . . .}
where (yk) are independent gamma distributed random variables with pdf
fyk (x) =xk−1e−x
Γ(k); E(yk) = k .
Removing y1 from the process yields the Palm measure.
The intensity is 1/π but can be adjusted by scaling.
The GPP can be made less repulsive by independently deleting pointswith probability 1 − β and re-scaling. This β-GPP approaches thePPP in the limit as β → 0.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 41 / 46
Cellular network modeling The Ginibre point process
The Ginibre point process in action
We would like to model these two deployments:
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360000 380000 400000 420000
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0012
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0016
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Rural Region (75000m x 65000m)
E−W
N−
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528000 529000 53000018
0500
1815
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Urban Region (2500m x 1800m)
E−W
N−
S
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 42 / 46
Cellular network modeling The Ginibre point process
The Ginibre point process in action
SIR distributions for different path loss exponents:
−10 −5 0 5 10 15 200
0.2
0.4
0.6
0.8
1
SIR Threshold (dB)
Cov
erag
e P
roba
bilit
y
Rural Region
Experimental Data w. α=4Experimental Data w. α=3.5Experimental Data w. α=3Experimental Data w. α=2.5The fitted β−GPP
−10 −5 0 5 10 15 200
0.2
0.4
0.6
0.8
1
SIR Threshold (dB)C
over
age
Pro
babi
lity
Urban Region
Experimental Data w. α=4Experimental Data w. α=3.5Experimental Data w. α=3Experimental Data w. α=2.5The fitted β−GPP
For the rural region, β = 0.2. For the urban region, β = 0.9.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 43 / 46
Conclusions
Conclusions
The gain of a deployment/architecture/scheme is best measured asthe horizontal gap relatively to a baseline (e.g., the HIP) model.
The MISR E(ISR) is easy to obtain by simulation, since it does notdepend on the fading. The ISR-based approximation is very accuratefor ps > 3/4, and the gains are quite insensitive to the path lossexponent and the fading statistics.
The DUI "compresses" the SIR distribution. Care is needed due to thecorrelation in the interference across time and space. The existence ofa diversity gain is coupled with the moments of the ISR.
General BS sharing is a promising framework to analyze amorphousnetworks.
Future work should also include models with intra- and inter-tierdependence. The Ginibre point process is promising as a repulsivemodel due to its tractability.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 44 / 46
Conclusions
Key Take-away: What matters is the
WAIST-HIP Ratio
MISRHIP
MISRWAIST
WAIST: Wireless Advanced InterferenceSuppression Technique
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 45 / 46
References
ReferencesM. Haenggi, "The Mean Interference-to-Signal Ratio and its Key Role in Cellular and
Amorphous Networks", arXiv, June 2014.
N. Deng, W. Zhou, and M. Haenggi, "A Heterogeneous Cellular Network Model with
Inter-tier Dependence", GLOBECOM 2014. Submitted.
A. Guo and M. Haenggi, "Asymptotic Deployment Gain: A Simple Approach to
Characterize the SINR Distribution in General Cellular Networks", IEEE Trans. Comm.,
submitted.
G. Nigam, P. Minero, and M. Haenggi, "Coordinated Multipoint Joint Transmission in
Heterogeneous Networks", IEEE Trans. Comm., submitted.
X. Zhang and M. Haenggi., "A Stochastic Geometry Analysis of Inter-cell Interference
Coordination and Intra-cell Diversity", IEEE Trans. Wireless, submitted.
N. Deng, W. Zhou, and M. Haenggi, "The Ginibre Point Process as a Model for Wireless
Networks with Repulsion", IEEE Trans. Wireless, accepted.
X. Zhang and M. Haenggi, "The Performance of Successive Interference Cancellation in
Random Wireless Networks", IEEE Trans. Info. Theory, submitted.
A. Guo and M. Haenggi, "Spatial Stochastic Models and Metrics for the Structure of
Base Stations in Cellular Networks", IEEE Trans. Wireless, Nov. 2013.
See http://www.nd.edu/~mhaenggi/pubs for our publications.
M. Haenggi (Univ. of Notre Dame) Coverage of HetNets 06/16/2014 46 / 46