copyright © 2011 pearson education, inc. polynomials chapter 5.1exponents and scientific notation...
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Slide 5- 3 Copyright © 2011 Pearson Education, Inc. Objective 1 Evaluate exponential forms with integer exponents.TRANSCRIPT
Copyright © 2011 Pearson Education, Inc.
PolynomialsCHAPTER
5.1 Exponents and Scientific Notation5.2 Introduction to Polynomials5.3 Adding and Subtracting Polynomials5.4 Exponent Rules and Multiplying
Monomials5.5 Multiplying Polynomials; Special
Products5.6 Exponent Rules and Dividing
Polynomials
55
Copyright © 2011 Pearson Education, Inc.
Exponents and Scientific Notation5.15.11. Evaluate exponential forms with integer exponents.2. Write scientific notation in standard form.3. Write standard form numbers in scientific notation.
Slide 5- 3Copyright © 2011 Pearson Education, Inc.
Objective 1Evaluate exponential forms with integer exponents.
Slide 5- 4Copyright © 2011 Pearson Education, Inc.
Evaluating Exponential Forms with Negative BasesIf the base of an exponential form is a negative number and the exponent is even, then the product is positive.If the base is a negative number and the exponent is odd, then the product is negative.
Raising a Quotient to a PowerIf a and b are real numbers, where b 0 and n is a natural number, then
.
n n
n
a ab b
Slide 5- 5Copyright © 2011 Pearson Education, Inc.
Example 1Evaluate each exponential form.a. b. c.
Solution a.
b.
c.
56 43
56 6 6 6 6 6 7776
43 3 3 3 3 81
337
337
3
3
37
27343
Slide 5- 6Copyright © 2011 Pearson Education, Inc.
Zero as an ExponentIf a is a real number and then
If a is a real number, where a 0 and n is a natural number, then
0,a 0 1.a
1 . nna
a
Slide 5- 7Copyright © 2011 Pearson Education, Inc.
Example 2Rewrite with a positive exponent; then if the expression is numeric, evaluate it.a. b. c.
Solution a.
b.
c.
410 34
410 4
110
110,000
Rewrite using then simplify.1 , nna
a
3
14
34
14 4 4
1 164 64
22
22 2
12
12 2
14
Slide 5- 8Copyright © 2011 Pearson Education, Inc.
continuedd. e. f.
Solution
d.
e.
f.
4x 35
3
15
35
24y
4x4
1x
24y 2
14y
2
4y
1125
Slide 5- 9Copyright © 2011 Pearson Education, Inc.
If a is a real number, where a 0 and n is a natural number, then 1 . n
n aa
If a and b are real numbers, where a 0 and b 0
and n is a natural number, then
.
n na bb a
Slide 5- 10Copyright © 2011 Pearson Education, Inc.
Example 3Rewrite with a positive exponent; then if the expression is numeric, evaluate it. a. b.
Solution a.
b.
3
13 3
1x
3
13
33 3 3 3 27
3
1x
3x
Slide 5- 11Copyright © 2011 Pearson Education, Inc.
Example 4Rewrite with a positive exponent, then if the expression is numeric, evaluate it.a. b.
Solution
a.
b.
323
323
332
3
3
32
278
6mn
6mn
6nm
6
6
nm
Slide 5- 12Copyright © 2011 Pearson Education, Inc.
Objective 2Write scientific notation in standard form.
Slide 5- 13Copyright © 2011 Pearson Education, Inc.
Scientific notation: A number expressed in the form where a is a decimal number with and n is an integer.
Scientific notation gives us a shorthand way to write very large or very small numbers.
10 ,na1 10 a
Changing Scientific Notation (Positive Exponent) to Standard FormTo change from scientific notation with a positive integer exponent to standard form, move the decimal point to the right the number of places indicated by the exponent.
Slide 5- 14Copyright © 2011 Pearson Education, Inc.
Example 5Write in standard form.
SolutionMultiplying 4.26 by 105 means that the decimal point will move five places to the right.
54.26 10
54.26 10 426,000
Slide 5- 15Copyright © 2011 Pearson Education, Inc.
Changing Scientific Notation (Negative Exponent) to Standard FormTo change from scientific notation with a negative exponent in standard form, move the decimal point to the left the same number of places as the absolute value of the exponent.
Slide 5- 16Copyright © 2011 Pearson Education, Inc.
Example 6Write in standard form.
SolutionMultiplying 3.87 by 10–4 is equivalent to dividing by 104, which causes the decimal point to move four places to the left.
43.87 10
43.87 10 4
3.8710
0.000387
Slide 5- 17Copyright © 2011 Pearson Education, Inc.
Objective 3Write standard form numbers in scientific notation.
Slide 5- 18Copyright © 2011 Pearson Education, Inc.
Changing Standard Form to Scientific NotationTo write a number greater than 1 in scientific notation:1. Move the decimal point so that the number is greater
than or equal to 1 but less than 10. (Tip: Place the decimal point to the right of the first nonzero digit.)
2. Write the decimal number multiplied by 10n, where n is the number of places between the new decimal position and the original decimal position.
3. Delete zeros to the right of the last nonzero digit.
Slide 5- 19Copyright © 2011 Pearson Education, Inc.
Example 7Write 875,000 in scientific notation.Solution Place the decimal to the right of the first
nonzero digit, 8. Next, we count the places to the right of this decimal position, which is five places. We write the 5 as the exponent of 10. Finally, we delete all the 0s to the right of the last nonzero digit, which is 5 in this case.
875,000 58.75 10Move the decimal point here to express a number whose absolute value is greater than or equal to 1 but less than 10.
There are five places to the right of the new decimal point.
Slide 5- 20Copyright © 2011 Pearson Education, Inc.
Changing Standard Form to Scientific NotationTo write a positive decimal number that is less than 1 in
scientific notation:1. Move the decimal point so that the number is greater
than or equal to 1 but less than 10. (Tip: Place the decimal point to the right of the first nonzero digit.)
2. Write the decimal number multiplied by 10n , where n is a negative integer whose absolute value is the number of places between the new decimal position and the original decimal position.
3. Delete zeros to the left of the first nonzero digit.
Slide 5- 21Copyright © 2011 Pearson Education, Inc.
Example 8Write 0.0000000472 in scientific notation.Solution Place the decimal point between the 4 and 7
digits, so that we have 4.72, which is a decimal number greater than 1 but less than 10. Since there are eight decimal places between the original decimal position and the new position, the exponent is –8.
0.0000000472 Move the decimal point here to express a number whose absolute value is greater than or equal to 1 but less than 10.
8.4 72 10
There are eight decimal places in between the original position and the new position, so the exponent is –8.
Slide 5- 22Copyright © 2011 Pearson Education, Inc.
Evaluate –2–6 .
a)
b)
c)
d) 64
12
164
164
5.1
Slide 5- 23Copyright © 2011 Pearson Education, Inc.
Evaluate –2–6 .
a)
b)
c)
d) 64
12
164
164
5.1
Slide 5- 24Copyright © 2011 Pearson Education, Inc.
Write 13,030,000 in scientific notation.
a)
b)
c)
d)
41303 10
613.03 10
71.303 10
90.1303 10
5.1
Slide 5- 25Copyright © 2011 Pearson Education, Inc.
Write 13,030,000 in scientific notation.
a)
b)
c)
d)
41303 10
613.03 10
71.303 10
90.1303 10
5.1
Slide 5- 26Copyright © 2011 Pearson Education, Inc.
Write in standard notation.
a) 4,690,000
b) 4,690,000,000
c) 0.000000469
d) 0.00000469
64.69 10
5.1
Slide 5- 27Copyright © 2011 Pearson Education, Inc.
Write in standard notation.
a) 4,690,000
b) 4,690,000,000
c) 0.000000469
d) 0.00000469
64.69 10
5.1
Copyright © 2011 Pearson Education, Inc.
Introduction to Polynomials5.25.21. Identify monomials.2. Identify the coefficient and degree of a monomial.3. Classify polynomials.4. Identify the degree of a polynomial.5. Evaluate polynomials.6. Write polynomials in descending order of degree.7. Combine like terms.
Slide 5- 29Copyright © 2011 Pearson Education, Inc.
Objective 1Identify monomials.
Slide 5- 30Copyright © 2011 Pearson Education, Inc.
Monomial: An expression that is a constant, a variable, or a product of a constant and variable(s) that are raised to whole number powers.
Slide 5- 31Copyright © 2011 Pearson Education, Inc.
Example 1Is the given expression a monomial? Explain.a. 18 b. –0.4a2b c. 5a2 + 4b –
1Answera. 18 is a monomial because it is a constant.b. –0.4a2b is a monomial because it is a product of a
constant, –0.4, and variables, a2 and b, which have whole-number exponents.
c. 5a2 + 4b – 1 is not a monomial because it is not a product of a constant and variables. Instead, addition and subtraction are involved.
Slide 5- 32Copyright © 2011 Pearson Education, Inc.
Objective 2Identify the coefficient and degree of a monomial.
Slide 5- 33Copyright © 2011 Pearson Education, Inc.
Coefficient of a monomial: The numerical factor in a monomial.
Degree of a monomial: The sum of the exponents of all variables in a monomial.
Slide 5- 34Copyright © 2011 Pearson Education, Inc.
Example 2Identify the coefficient and degree of each monomial.a. b. 9
Answer a. We can express as . In this form, we can see
that our coefficient is –2 and the exponents for the variables are 1 and 3. Since the degree is the sum of the variables’ exponents, the degree is 4.
b. Since 9 = 9x0 , where x is any real number except 0, we can see that 9 is the coefficient and 0 is the degree.
32 xy
32 xy 1 32 x y
Slide 5- 35Copyright © 2011 Pearson Education, Inc.
Objective 3Classify polynomials.
Slide 5- 36Copyright © 2011 Pearson Education, Inc.
Polynomial: A monomial or an expression that can be written as a sum of monomials.
Examples: 4x, 4x + 8, 2x2 + 5xy + 8y
Polynomial in one variable: A polynomial in which every variable term has the same variable.
Example: x2 – 5x + 2 is a polynomial in one variable
Binomial: A polynomial containing two terms.Trinomial: A polynomial containing three terms.
Degree of a polynomial: The greatest degree of any of the terms in the polynomial.
Slide 5- 37Copyright © 2011 Pearson Education, Inc.
Example 3Determine whether the expression is a monomial, binomial, trinomial, or none of these. a. 4ab2 b. –9x2 + z c. 4n3+ 2n – 1Answer
a. 4ab2 is a monomial because it has a single term.
b. –9x2 + z is a binomial because it contains two terms.
c. 4n3+ 2n – 1 is a trinomial because it contains three terms.
Slide 5- 38Copyright © 2011 Pearson Education, Inc.
continuedDetermine whether the expression is a monomial, binomial, trinomial, or none of these. d. x3 + 9x2 – x + 4 e. Answer
d. Although x3 + 9x2 – x + 4 is a polynomial, it has no special name because it has more than three terms.
e. is not a polynomial because is not a
monomial.
68yx
68yx
6x
Slide 5- 39Copyright © 2011 Pearson Education, Inc.
Objective 4Identify the degree of a polynomial.
Slide 5- 40Copyright © 2011 Pearson Education, Inc.
Example 4aIdentify the degree of the polynomial.
5 2 6 35 6 8x x x x x
Answer The degree is 6 because it is the greatest degree of all the terms.
Slide 5- 41Copyright © 2011 Pearson Education, Inc.
Example 4bIdentify the degree of the polynomial.
4 5 2 28 2 9 1 a a b ab b
Answer To determine the degree of the monomial –2a5b2, add the exponents of its variables: 5 + 2 = 7Add the exponents of the variables in ab2: 1 + 2 = 3 Compare the degrees of all the terms: 4, 7, 3, 1 7 is the greatest degree. Therefore, 7 is the degree of the polynomial.
Slide 5- 42Copyright © 2011 Pearson Education, Inc.
Objective 5Evaluate polynomials.
Slide 5- 43Copyright © 2011 Pearson Education, Inc.
Example 5Evaluate when c = –6.2 4 7 c c
Solution 2 4 7 c c
2 + 46 6 7
36 24 7
19
Replace c with –6.
Simplify.
Slide 5- 44Copyright © 2011 Pearson Education, Inc.
Example 6If we neglect air resistance, the polynomial −16t2 + h0 describes the height of a falling object from an initial height h0 for t seconds. If a rock is dropped from a building that is 120 feet tall, what is the height of the rock after it falls for 2 seconds?
Answer Evaluate −16t2 + h0 when t = 2 and h0 = 120.
−16(2)2 + 120 = 56= −64 + 120
After 2 seconds, the height of the rock is 56 feet.
Slide 5- 45Copyright © 2011 Pearson Education, Inc.
Objective 6Write polynomials in descending order of degree.
Slide 5- 46Copyright © 2011 Pearson Education, Inc.
Writing a Polynomial in Descending Order of DegreeTo write a polynomial in descending order of degree, place the highest degree term first, then the next highest degree, and so on.
Slide 5- 47Copyright © 2011 Pearson Education, Inc.
Example 7Write the polynomial in descending order.
2 3 42 5 7 4 x x x x
Solution Rearrange the terms so that the highest degree term is first, then the next highest degree, and so on.
4 3 24 7 2 +5 x x x x
Degree 4 Degree 3 Degree 2 Degree 1 Degree 0
Answer 4 3 24 7 2 5 x x x x
Slide 5- 48Copyright © 2011 Pearson Education, Inc.
Objective 7Combine like terms.
Slide 5- 49Copyright © 2011 Pearson Education, Inc.
Example 8 Combine like terms and write the resulting polynomial in descending order of degree.
Solution
3 2 3 34 6 3 7 4 3 6x x x x x x
38 x 26x 2x 4
3 28 6 2 4x x x
3 2 3 34 6 3 7 4 3 6x x x x x x 3 3 3 24 3 6 4 6 7 3x x x x x x
Slide 5- 50Copyright © 2011 Pearson Education, Inc.
Example 9 Combine like terms.
Solution
5 2 5 26 2 3 1 3 3 a a b b a b a b
5 2 5 26 2 3 1 3 3 a a b b a b a b5 5 2 23 2 3 3 6 1 a a a b a b b b
52 a 23 a b 0 5
5 22 +3 5a a b
Slide 5- 51Copyright © 2011 Pearson Education, Inc.
continued Alternative Solution Instead of first collecting like terms, we strike through like terms in the given polynomial as they are combined.
5 2 5 26 2 3 1 3 3 a a b b a b a b
52 a 23 a b 0 5
5 22 +3 5a a b
Slide 5- 52Copyright © 2011 Pearson Education, Inc.
Classify the expression
a) Monomial
b) Binomial
c) Trinomial
d) None of these
2 33 5.x y
5.2
Slide 5- 53Copyright © 2011 Pearson Education, Inc.
Classify the expression
a) Monomial
b) Binomial
c) Trinomial
d) None of these
2 33 5.x y
5.2
Slide 5- 54Copyright © 2011 Pearson Education, Inc.
Evaluate when x = –3.
a) –118
b) –10
c) 10
d) 134
3 23 5 8 x x
5.2
Slide 5- 55Copyright © 2011 Pearson Education, Inc.
Evaluate when x = –3.
a) –118
b) –10
c) 10
d) 134
3 23 5 8 x x
5.2
Slide 5- 56Copyright © 2011 Pearson Education, Inc.
Identify the degree of the polynomial.
a) 3
b) 5
c) 6
d) 7
3 2 4 6 56 5 8 4 x x y x y y
5.2
Slide 5- 57Copyright © 2011 Pearson Education, Inc.
Identify the degree of the polynomial.
a) 3
b) 5
c) 6
d) 7
3 2 4 6 56 5 8 4 x x y x y y
5.2
Copyright © 2011 Pearson Education, Inc.
Adding and Subtracting Polynomials5.35.31. Add polynomials.2. Subtract polynomials.
Slide 5- 59Copyright © 2011 Pearson Education, Inc.
Objective 1Add polynomials.
Slide 5- 60Copyright © 2011 Pearson Education, Inc.
We can add and subtract polynomials in the same way that we add and subtract numbers. In fact, polynomials are like whole numbers that are in an expanded form. In our base-ten number system, each place value is a power of 10. We can think of polynomials as a variable-base number system, where x2 is like the hundreds place (102) and x is like the tens place (101). To add whole numbers, we add the digits in like place values; in polynomials, we add like terms.
Adding PolynomialsTo add polynomials, combine like terms.
Slide 5- 61Copyright © 2011 Pearson Education, Inc.
Example 1Add and write the resulting polynomial in descending
order of degree.
Solution
3 2 3 24 6 8 2 4 3 a a a a a a
3 2 3 24 6 8 2 4 3 a a a a a a
36 a3 26 +2 5 a a
22 a 0 5
Slide 5- 62Copyright © 2011 Pearson Education, Inc.
Example 2Add and write the resulting polynomial in descending
order of degree.
Solution
4 2 4 22 57 2.5 3 3 4 73 6
a ab ab a ab ab
34 a
3 2 14 1.5 46
a ab ab
21.5ab16
ab 4
4 2 4 22 57 2.5 3 3 4 73 6
a ab ab a ab ab
Slide 5- 63Copyright © 2011 Pearson Education, Inc.
Example 3Write an expression in simplest form for the perimeter of the rectangle shown.
5b + 2
9b – 10
Understand Perimeter means the total distance around the shape. Therefore, we need to
add the lengths of all the sides.Plan The lengths of the sides are represented by polynomials. Therefore, we add the polynomials to represent the perimeter.
Slide 5- 64Copyright © 2011 Pearson Education, Inc.
continuedExecute Perimeter = Length + Width + Length + Width
9 10 b 5 2 b 9 10 b 5 2 b
9 5 9 5 10 2 10 2 b b b b
28 16 b
Answer The expression for the perimeter is .28 16b
Slide 5- 65Copyright © 2011 Pearson Education, Inc.
continuedCheck To check:
1. Choose a value for b and evaluate the original expressions for length and width.2. Determine the corresponding numeric perimeter.3. Evaluate the perimeter expression using the same value for b and verify that we get the same numeric perimeter. Let’s choose b = 2.
Length: 9 10b 9 2 1018 10 8
Width: 5 2b 5 2 2
10 2 12
Perimeter
408 812 12+ + + =
Slide 5- 66Copyright © 2011 Pearson Education, Inc.
continuedNow evaluate the perimeter expression where b = 2 and we should find that the result is 40.
Perimeter expression:28 16b
28 2 1656 16
40
This agrees with our calculation above.
Slide 5- 67Copyright © 2011 Pearson Education, Inc.
Objective 2Subtract polynomials.
Slide 5- 68Copyright © 2011 Pearson Education, Inc.
Subtracting PolynomialsTo subtract polynomials,1. Write the subtraction statement as an equivalent
addition statement.a. Change the operation symbol from a minus sign to a plus sign.b. Change the subtrahend (second polynomial) to its additive inverse. To get the additive inverse, we change the sign of each term in the polynomial.
2. Combine like terms.
Slide 5- 69Copyright © 2011 Pearson Education, Inc.
Example 4
Subtract. 3 2 3 24 6 2 1 2 5 4 6x x x x x x
Solution
Change the minus sign to a plus sign.
3 2 3 24 6 2 1 2 5 4 6x x x x x x
Change all signs in the subtrahend.
3 22 2 5x x x
3 2 3 24 6 2 1 2 5 4 6x x x x x x
Slide 5- 70Copyright © 2011 Pearson Education, Inc.
Example 5Subtract. 3 2 3 28 5 3 1 2 8 4 3 x x x x x x
Solution 3 2 3 28 5 3 1 2 8 4 3 x x x x x x
Change the minus sign to a plus sign.
3 2 3 28 5 3 1 2 8 4 3 x x x x x x
Change all signs in the subtrahend.
3 26 3 4x x x
Subtract.Subtract.
Slide 5- 71Copyright © 2011 Pearson Education, Inc.
Add and write the polynomial in descending order.
a)
b)
c)
d)
3 2 3 25 8 4 3 6 x x x x3 25 5 2 x x
3 26 5 2 x x
3 24 5 2 x x
3 24 11 10 x x
5.3
Slide 5- 72Copyright © 2011 Pearson Education, Inc.
Add and write the polynomial in descending order.
a)
b)
c)
d)
3 2 3 25 8 4 3 6 x x x x3 25 5 2 x x
3 26 5 2 x x
3 24 5 2 x x
3 24 11 10 x x
5.3
Slide 5- 73Copyright © 2011 Pearson Education, Inc.
Subtract and write the polynomial in descending order.
a)
b)
c)
d)
3 2 3 28 2 4 10 5 7 2 u u u u u3 218 7 7 6 u u u
3 218 7 7 2 u u u
3 22 5 5 2 u u u
3 22 3 7 2u u u
5.3
Slide 5- 74Copyright © 2011 Pearson Education, Inc.
Subtract and write the polynomial in descending order.
a)
b)
c)
d)
3 2 3 28 2 4 10 5 7 2 u u u u u3 218 7 7 6 u u u
3 218 7 7 2 u u u
3 22 5 5 2 u u u
3 22 3 7 2u u u
5.3
Copyright © 2011 Pearson Education, Inc.
Exponent Rules and Multiplying Monomials5.45.4
1. Multiply monomials.2. Multiply numbers in scientific notation.3. Simplify a monomial raised to a power.
Slide 5- 76Copyright © 2011 Pearson Education, Inc.
Objective 1Multiply monomials.
Slide 5- 77Copyright © 2011 Pearson Education, Inc.
Consider 23 • 24, which is a product of exponential forms. To simplify 23 • 24, we could follow the order of operations and evaluate the exponential forms first, then multiply. 23 • 24 = 8 • 16 = 128
2 2 2 2 22 2
43 2 2
7 2
However, there is an alternative. We can write the result in exponential form by first writing 23 and 24 in their factored forms.
23 means three 2s.
24 means four 2s.
Since there are a total of seven 2s multiplied, we can express the product as 27.
Notice that 27 = 128.
Slide 5- 78Copyright © 2011 Pearson Education, Inc.
Product Rule for ExponentsIf a is a real number and m and n are integers, then am • an = am+n.
Multiplying MonomialsTo multiply monomials:1. Multiply coefficients.2. Add the exponents of the like bases.3. Write any unlike variable bases unchanged in the
product.
Slide 5- 79Copyright © 2011 Pearson Education, Inc.
Example 1Multiply 6 4 .x x
SolutionBecause the bases are the same, we can add the exponents and keep the same base.
6 4x x 6 4x 10x
Slide 5- 80Copyright © 2011 Pearson Education, Inc.
Example 2Multiply.a. b. 4 35 2x x 3 2 2 42 5
3 6
a bc a b
Solution 4 35 2x x 4 35 2 xa.
710 x
b. 3 2 2 42 53 6
a bc a b 3 2 1 4 22 5 3 6
a b c1
3
5 5 259
a b c
Multiply the coefficients and add the exponents of the like bases.
Slide 5- 81Copyright © 2011 Pearson Education, Inc.
Example 3Write an expression in simplest form for the volume of the box shown.
Understand We are given a box with side lengths that are monomial expressions.
3b
5bb
Plan The volume of a box is found by multiplying the length, width, and height.
Slide 5- 82Copyright © 2011 Pearson Education, Inc.
continuedExecute V lwh
3 5V b b b315V b
Answer The expression for volume is 15b3.
Check Since is an identity, substitute 2 for b and solve.
33 5 15b b b b
33 5 15b b b b
33 2 5 2 2 15 2 6 10 2 15 8
120 120
Slide 5- 83Copyright © 2011 Pearson Education, Inc.
Objective 2Multiply numbers in scientific notation.
Slide 5- 84Copyright © 2011 Pearson Education, Inc.
We multiply numbers in scientific notation using the same procedure we used to multiply monomials.
Monomials:
3 6 3 6
9
4 2 4 2
8
a a a
a
Scientific notation:
3 6 3 6
9
4 10 2 10 4 2 10
8 10
Slide 5- 85Copyright © 2011 Pearson Education, Inc.
Example 4aMultiply . Write the answer in scientific notation.
3 44.5 10 5.7 10
Solution Multiply 4.5 and 5.7, then add the exponents for base 10s.
3 44.5 10 5.7 10 3 44.5 5.7 10 725.65 10 82.565 10
Note: The product is not in scientific notation. We must move the decimal point one place to the left and account for this by increasing the exponent by one.
Slide 5- 86Copyright © 2011 Pearson Education, Inc.
Example 4bMultiply . Write the answer in scientific notation.
3 66.2 10 3.1 10
Solution Multiply 6.2 and 3.1, then add the exponents for base 10s.
3 66.2 3.1 10 319.22 10 21.922 10
Note: The product is not in scientific notation. We must move the decimal point one place to the left and account for this by increasing the exponent by one.
3 66.2 10 3.1 10
Slide 5- 87Copyright © 2011 Pearson Education, Inc.
Objective 3Simplify a monomial raised to a power.
Slide 5- 88Copyright © 2011 Pearson Education, Inc.
A Power Raised to a PowerIf a is a real number and m and n are integers, then (am)n = amn.
Raising a Product to a PowerIf a and b are real numbers and n is an integer, then (ab)n = anbn.
Simplifying a Monomial Raised to a PowerTo simplify a monomial raised to a power,1. Evaluate the coefficient raised to that power.2. Multiply each variable’s exponent by the power.
Slide 5- 89Copyright © 2011 Pearson Education, Inc.
Example 5 Simplify. a. b. c.
49 62
3c d
Solution
3 6 36 a
366a 320.8xy
a. 366a
18216a
49 62
3c d
49 4 6 42
3c d
36 241681
c d
3 1 3 2 30.8 x y
3 60.512x y
Slide 5- 90Copyright © 2011 Pearson Education, Inc.
Example 6a Simplify. 32 76 8y y
Solution Since the order of operations is to simplify exponents before multiplying, we will simplify (8y7)3 first, then multiply the result by 6y2.
233072 yMultiply coefficients and add exponents of like variables.
Simplify.
32 76 8y y 2 3 7 36 8 y y
2 216 512 y y2+216 512 y
Slide 5- 91Copyright © 2011 Pearson Education, Inc.
Example 6b Simplify. 22 40.3 2 1.5x xy x y
Solution We follow the order of operations and simplify the monomials raised to a power first, then multiply the monomials.
Multiply coefficients and add exponents of like variables.
Simplify.
2 21 2 4 2 1 20.3 2 1.5x xy x y 22 40.3 2 1.5x xy x y
2 8 20.09 2 2.25x xy x y2 1 8 1 20.09 2 2.25x y
11 30.405x y
Slide 5- 92Copyright © 2011 Pearson Education, Inc.
Simplify.
a)
b)
c)
d)
7 36 3b b
2118b
1018b
219b
109b
5.4
Slide 5- 93Copyright © 2011 Pearson Education, Inc.
Simplify.
a)
b)
c)
d)
7 36 3b b
2118b
1018b
219b
109b
5.4
Slide 5- 94Copyright © 2011 Pearson Education, Inc.
Simplify.
a)
b)
c)
d)
42 34 5y y
920y
2020y
92500y
142500y
5.4
Slide 5- 95Copyright © 2011 Pearson Education, Inc.
Simplify.
a)
b)
c)
d)
42 34 5y y
920y
2020y
92500y
142500y
5.4
Copyright © 2011 Pearson Education, Inc.
Multiplying Polynomials; Special Products5.55.5
1. Multiply a polynomial by a monomial.2. Multiply binomials.3. Multiply polynomials.4. Determine the product when given special polynomial
factors.
Slide 5- 97Copyright © 2011 Pearson Education, Inc.
Objective 1Multiply a polynomial by a monomial.
Slide 5- 98Copyright © 2011 Pearson Education, Inc.
Multiplying a Polynomial by a MonomialTo multiply a polynomial by a monomial, use the distributive property to multiply each term in the polynomial by the monomial.
Slide 5- 99Copyright © 2011 Pearson Education, Inc.
Example 1Multiply.a. 22 6 2 1 p p p
Solution 22 6 2 1 p p pa.
2 2 2 2 2 16 pp pp p3 212 4 2 p p p
2p • 6p2
2p • 2p2p • –1
Slide 5- 100Copyright © 2011 Pearson Education, Inc.
continuedb. 2 3 3 42 3 5 4 a b a b ab a bcSolution
2 3 3 42 3 5 4 a b a b ab a bcb.
2 3 2 3 2 4 2 2 3 2 2 5 2 4 a b a b a b ab a b a a b bc5 2 3 4 6 2 2 6 2 10 8 a b a b a b a b c
Note: When multiplying multivariable terms, it is helpful to multiply the coefficients first, then the variables in alphabetical order.
–2a2b • 3a3b
–2a2b • ab3
–2a2b • – 5a4 –2a2b • 4bc
Slide 5- 101Copyright © 2011 Pearson Education, Inc.
Objective 2Multiply binomials.
Slide 5- 102Copyright © 2011 Pearson Education, Inc.
Multiplying PolynomialsTo multiply two polynomials,1. Multiply every term in the second polynomial by
every term in the first polynomial.2. Combine like terms.
Slide 5- 103Copyright © 2011 Pearson Education, Inc.
Example 2
Multiply. 7 3x x
Solution Multiply each term in x + 7 by each term in x + 3.
7 3x x
+7 3 x x 3x 7 x
7 • x
7 • 3
x • 3
x • x
2= 3 7 21 x x x 2 10 = 21x x
Slide 5- 104Copyright © 2011 Pearson Education, Inc.
Example 3Multiply. 2 1 5 x x
Solution Multiply each term in x – 5 by each term in 2x + 1 (think FOIL).
2 1 5 x x
+1 52 x x 2 5 x 1 xFirst Outer Inner Last
1 • xInner
1 • (–5)Last
2x • (–5)Outer2x •
xFirst
Slide 5- 105Copyright © 2011 Pearson Education, Inc.
continued
22 10 5x x x
22 9 5x x
22 9 5x x
2 2 5 1 1 5 x x x x
2 1 5 x x
Slide 5- 106Copyright © 2011 Pearson Education, Inc.
Example 4Multiply. 3 5 2 7 x x
Solution Multiply each term in 2x + 7 by each term in 3x – 5 (think FOIL).
3x • 2x3x • 7
(–5) • 2x
3 5 2 7 x x
(–5) • 7
+ 5 7 3 2 x x 3 7 x 5 2 x
First Outer Inner Last
Slide 5- 107Copyright © 2011 Pearson Education, Inc.
continued 3 2 3 7 5 2 5 7 x x x x
2 6 21 10 35 x x x
2 6 11 35 x x
26 11 35 x x
3 5 2 7 x x
Slide 5- 108Copyright © 2011 Pearson Education, Inc.
Example 5Multiply. 4 2 2 3x x
Solution Multiply each term in 4x − 2 by each term in 2x – 3 (think FOIL).
4x • 2x4x • (–3)
(–2) • 2x
4 2 2 3x x
(–2) • (–3)
+ 2 3 4 2x x 4 3x 2 2 x First Outer Inner Last
Slide 5- 109Copyright © 2011 Pearson Education, Inc.
continued
2 8 12 4 6x x x
2 8 16 6x x
28 16 6x x
4 2 2 3x x
+ 2 3 4 2x x 4 3x 2 2 x
Slide 5- 110Copyright © 2011 Pearson Education, Inc.
The product of two binomials can be shown in terms of geometry.
355x
7xx2
Length • width = Sum of the areas of the four internal rectangles
7 5 x x 2 5 7 35 x x x2 12 35 x x Combine like terms.
Slide 5- 111Copyright © 2011 Pearson Education, Inc.
Objective 3Multiply polynomials.
Slide 5- 112Copyright © 2011 Pearson Education, Inc.
Example 6Multiply. 23 2 3 3 x x x
Solution Multiply each term in 2x2 + 3x +3 by each term in x – 3.
23 2 3 3 x x x
2 2 2 3 3 3 2 3 3 3 3x x x x x x x 3 2 2 2 3 3 6 9 9 x x x x x3 2 2 3 6 9x x x
(–3) • 2x2
(–3) • 3x(–3) • 3
x • 2x2
x • 3xx • 3
Slide 5- 113Copyright © 2011 Pearson Education, Inc.
Objective 4Determine the product when given special polynomial factors.
Slide 5- 114Copyright © 2011 Pearson Education, Inc.
Multiplying ConjugatesIf a and b are real numbers, variables, or expressions, then (a + b)(a – b) = a2 – b2.
Conjugates: Binomials that differ only in the sign separating the terms.
x + 9 and x – 9 2x + 3 and 2x – 3
–6x + 5 and –6x – 5
Slide 5- 115Copyright © 2011 Pearson Education, Inc.
Example 7Multiply.a. (x + 5) (x – 5)
b.
Solution 5 5 x x 2 25 x
2 25 xUse (a + b)(a – b) = a2 – b2.
Simplify.
4 3 4 3 a a
Solution 4 3 4 3 a a 2 24 3 a
216 9 a
Use (a + b)(a – b) = a2 – b2.
Simplify.
Slide 5- 116Copyright © 2011 Pearson Education, Inc.
Squaring a BinomialIf a and b are real numbers, variables, or expressions, then (a + b)2 = a2 + 2ab + b2
(a – b)2 = a2 – 2ab + b2
Slide 5- 117Copyright © 2011 Pearson Education, Inc.
Example 8aMultiply.
Solution
2 24 2 4 7 7a a Use (a + b)2 = a2 + 2ab + b2.
Simplify.
24 7a
24 7a 216 56 49a a
Slide 5- 118Copyright © 2011 Pearson Education, Inc.
Example 8bMultiply.
Solution
2 23 2 3 8 8 y y Use (a – b)2 = a2 – 2ab + b2.
Simplify.
23 8y
23 8y29 48 64 y y
Slide 5- 119Copyright © 2011 Pearson Education, Inc.
Multiply.
a)
b)
c)
d)
2 5 3 y y
22 15 y y
22 2 15 y y
22 15 y y
22 11 15 y y
5.5
Slide 5- 120Copyright © 2011 Pearson Education, Inc.
Multiply.
a)
b)
c)
d)
2 5 3 y y
22 15 y y
22 2 15 y y
22 15 y y
22 11 15 y y
5.5
Slide 5- 121Copyright © 2011 Pearson Education, Inc.
Multiply.
a)
b)
c)
d)
25 4x
225 40 8 x x
225 20 8 x x
225 20 16 x x
225 40 16 x x
5.5
Slide 5- 122Copyright © 2011 Pearson Education, Inc.
Multiply.
a)
b)
c)
d)
25 4x
225 40 8 x x
225 20 8 x x
225 20 16 x x
225 40 16 x x
5.5
Copyright © 2011 Pearson Education, Inc.
Exponent Rules and Dividing Polynomials5.65.6
1. Divide exponential forms with the same base.2. Divide numbers in scientific notation.3. Divide monomials.4. Divide a polynomial by a monomial.5. Use long division to divide polynomials.6. Simplify expressions using rules of exponents.
Slide 5- 124Copyright © 2011 Pearson Education, Inc.
Objective 1Divide exponential forms with the same base.
Slide 5- 125Copyright © 2011 Pearson Education, Inc.
Quotient Rule for Exponents
If m and n are integers and a is a real number, where a 0, then .
mm n
n
a aa
Slide 5- 126Copyright © 2011 Pearson Education, Inc.
Example 1Divide.
8
4
xx
Solution Because the exponential forms have the same base, we can subtract the exponents and keep the same base.
8 4x x 8 4 4 x x8
4
xx
Slide 5- 127Copyright © 2011 Pearson Education, Inc.
Example 2Divide and write the result with a positive exponent.
6
2
yy
Solution6 ( 2) y6 2 y
4y
4
1
y
Subtract the exponents and keep the same base.
Rewrite the subtraction as addition.
Simplify.
Write with a positive exponent.
6
2
yy
Slide 5- 128Copyright © 2011 Pearson Education, Inc.
Objective 2Divide numbers in scientific notation.
Slide 5- 129Copyright © 2011 Pearson Education, Inc.
Example 3Divide and write the result in scientific notation.
7
3
2.34 103.6 10
Solution The decimal factors and powers of 10 can be separated into a product of two fractions, allowing separate division. 7
3
2.34 103.6 10
7
3
2.34 103.6 10
7 30.65 10 40.65 10
36.5 10
Note: This is not in scientific notation. We must move the decimal point one place to the right and account for this by decreasing the exponent by one.
Slide 5- 130Copyright © 2011 Pearson Education, Inc.
Objective 3Divide monomials.
Slide 5- 131Copyright © 2011 Pearson Education, Inc.
Dividing MonomialsTo divide monomials,1. Divide the coefficients or simplify them to fractions
in lowest terms.2. Use the quotient rule for the exponents with like
bases.3. Do not change unlike variable bases in the quotient.4. Write the final expression so that all exponents are
positive.
Slide 5- 132Copyright © 2011 Pearson Education, Inc.
Example 4Divide.
3 6 2
4 3
1824
x y zx y
Solution3 6 2
4 3
1824
x y zx y
3 6 2
4 3
18 24 1
x y zx y
3 4 6 3 218 24
x y z
1 3 234
x y z3 23 1
4 1 1
y zx
3 234
y z
x
Slide 5- 133Copyright © 2011 Pearson Education, Inc.
Objective 4Divide a polynomial by a monomial.
Slide 5- 134Copyright © 2011 Pearson Education, Inc.
If a, b, and c are real numbers, variables, or expressions with c 0, then
Dividing a Polynomial by a Monomial
To divide a polynomial by a monomial, divide each term in the polynomial by the monomial.
.
a b a bc c c
Slide 5- 135Copyright © 2011 Pearson Education, Inc.
Example 5Divide.
6 2 3
2
36 9 63 x y x y xx y
Solution6 2 3
2
36 9 63 x y x y xx y
6 2 3
2 2 2
36 9 63 3 3
x y x y xx y x y x y
14 1 0 212 3 xx y x y
y
4 212 3x y xxy
Divide each term in the polynomial by the monomial.
Slide 5- 136Copyright © 2011 Pearson Education, Inc.
Objective 5Use long division to divide polynomials.
Slide 5- 137Copyright © 2011 Pearson Education, Inc.
To divide a polynomial by a polynomial, we can use long division.
Divide: 15712
157
12 37 36
1
1
1
23
Divisor
Quotient
Remainder
Quotient 13
Divisor 12
Remainder 1
= Dividend=157
•++
•
Slide 5- 138Copyright © 2011 Pearson Education, Inc.
Example 6Divide.
2 8 163
x xx
Solution Begin by dividing the first term in the dividend by the first term in the divisor: x2 + 8x + 16.
2
2
3 8 16
3
xx x x
x x
Change signs.
2
2
3 8 16
3
xx x x
x x
5 16x
Slide 5- 139Copyright © 2011 Pearson Education, Inc.
continuedThe next term in the quotient is found by dividing the term 5x + 16 by x + 3 .
Change signs.
Answer 153
xx
2
2
3 8 16
3
xx x x
x x
5 16x
5
5 15x
The next term in the quotient is found by dividing the term 5x + 16 by x + 3 .
2
2
3 8 16
3
xx x x
x x
5 15x 5 16x
1
5
Slide 5- 140Copyright © 2011 Pearson Education, Inc.
Dividing a Polynomial by a PolynomialTo divide a polynomial by a polynomial, use long division. If there is a remainder, write the result in the following form:
remainderquotientdivisor
Slide 5- 141Copyright © 2011 Pearson Education, Inc.
Example 7Divide.
26 5 282 1
b b
b
Solution Begin by dividing the first term in the dividend by the first term in the divisor: 6b2 + 5b – 28.
2
2
3 2 1 6 5 28
6 3
bb b b
b b
2
2
3 2 1 6 5 28
6 3 8 28
bb b b
b bb
Change signs.
Slide 5- 142Copyright © 2011 Pearson Education, Inc.
continuedDetermine the next part of the quotient by dividing 8b by 2b, which is 4, and repeat the multiplication and subtraction steps.
Change signs.
2
2
3 4 2 1 6 5 28
6 3 8 28 8 4
bb b b
b bbb
2
2
3 4 2 1 6 5 28
6 3 8 28 8 4 2
4
bb b b
b bbb
Answer 243 42 1
bb
Slide 5- 143Copyright © 2011 Pearson Education, Inc.
Example 8Divide.
4 28 10 2 94 2
x x xx
Solution Use a place holder for the missing terms.
4 3 2
4 2 8 0 10 2 9x x x x x
Slide 5- 144Copyright © 2011 Pearson Education, Inc.
continuedSolution 4 3 2
4 3
3 2
3 2
2
2
4 2 8 0 10 2 9
8 4
4 10
4 2
12 2
12 6 4 9 4 2
x x x x x
x x
x x
x x
x x
x xxx
11
3 2 2 3 1x x x
3 2 11 2 3 14 2
x x xx
Answer
Remember to change signs when subtracting.
Slide 5- 145Copyright © 2011 Pearson Education, Inc.
Objective 6Simplify expressions using rules of exponents.
Slide 5- 146Copyright © 2011 Pearson Education, Inc.
Exponents SummaryAssume that no denominators are 0, that a and b are real numbers, and that m and n are integers.
Zero as an exponent: a0 = 1, where a 0.00 is indeterminate.
Negative exponents:
Product rule for exponents:Quotient rule for exponents:Raising a power to a power:Raising a product to a power:Raising a quotient to a power:
1 1, ,n nn n
a aa a
m n m na a am
m nn
a aa
nm mna a
n n nab a b
n na bb a
n
n
na ab b
Slide 5- 147Copyright © 2011 Pearson Education, Inc.
Example 9Simplify. Write all answers with positive exponents.a.
Solution
37
3
xx
37
3
xx
37 3 x
310 x10 3 x30x
30
1
x
a.
Slide 5- 148Copyright © 2011 Pearson Education, Inc.
continued b.
32
54
6
3
m
m
Solution
32
54
6
3
m
m
3 2 3
5 4 5
63
mm
6
20
216243
mm
6 208 9
m
148 9
m
14
89m
Use the quotient rule for exponents.
Write with a positive exponent.
Slide 5- 149Copyright © 2011 Pearson Education, Inc.
Simplify.
a)
b)
c)
d)
25
3
aa
16
1a
4
1a
16a
4a
5.6
Slide 5- 150Copyright © 2011 Pearson Education, Inc.
Simplify.
a)
b)
c)
d)
25
3
aa
16
1a
4
1a
16a
4a
5.6
Slide 5- 151Copyright © 2011 Pearson Education, Inc.
Divide.
a)
b)
c)
d)
2 6 102
y yy
1842
yy
242
yy
652
yy
282
yy
5.6
Slide 5- 152Copyright © 2011 Pearson Education, Inc.
Divide.
a)
b)
c)
d)
2 6 102
y yy
1842
yy
242
yy
652
yy
282
yy
5.6