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Statistics: Unlocking the Power of Data Lock 5 Section 4.5 Confidence Intervals and Hypothesis Tests

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Statistics: Unlocking the Power of Data Lock5

Section 4.5

Confidence Intervals and Hypothesis Tests

Statistics: Unlocking the Power of Data Lock5

Bootstrap and Randomization Distributions

Bootstrap Distribution Randomization Distribution

Our best guess at the distribution of sample statistics

Our best guess at the distribution of sample statistics, if H0 were true

Centered around the observed sample statistic

Centered around the null hypothesized value

Simulate sampling from the population by resampling from the original sample

Simulate samples assuming H0 were true

Big difference: a randomization distribution assumes H0 is true, while a bootstrap distribution does not

Statistics: Unlocking the Power of Data Lock5

Which Distribution? Let µ be the average amount of sleep college students get

per night. Data was collected on a sample of students, and for this sample �̅�𝑥 = 6.7 hours. A bootstrap distribution is generated to create a

confidence interval for µ, and a randomization distribution is generated to see if the data provide evidence that µ > 7.

Which distribution below is the bootstrap distribution?

(a) is centered around the sample statistic, 6.7

Statistics: Unlocking the Power of Data Lock5

Which Distribution? Intro stat students are surveyed, and we find that 152 out

of 218 are female. Let p be the proportion of intro stat students at that university who are female. A bootstrap distribution is generated for a confidence

interval for p, and a randomization distribution is generated to see if the data provide evidence that p > 1/2. Which distribution is the randomization distribution?

(a) is centered around the null value, 1/2

Statistics: Unlocking the Power of Data Lock5

Body Temperature We created a bootstrap distribution for average

body temperature by resampling with replacement from the original sample (�̅�𝑥 = 92.26):

Statistics: Unlocking the Power of Data Lock5

Body Temperature We also created a randomization distribution to see

if average body temperature differs from 98.6°F by adding 0.34 to every value to make the null true, and then resampling with replacement from this modified sample:

Statistics: Unlocking the Power of Data Lock5

Body Temperature These two distributions are identical (up to

random variation from simulation to simulation) except for the center

The bootstrap distribution is centered around the sample statistic, 98.26, while the randomization distribution is centered around the null hypothesized value, 98.6

The randomization distribution is equivalent to the bootstrap distribution, but shifted over

Statistics: Unlocking the Power of Data Lock5

Body Temperature

Bootstrap Distribution

Randomization Distribution H0: µ = 98.6 Ha: µ ≠ 98.6

98.26 98.6

Statistics: Unlocking the Power of Data Lock5

Body Temperature

Bootstrap Distribution

98.26 98.4

Randomization Distribution H0: µ = 98.4 Ha: µ ≠ 98.4

Statistics: Unlocking the Power of Data Lock5

Intervals and Tests

If a 95% CI misses the parameter in H0, then a two-tailed test should reject H0

at a 5% significance level.

If a 95% CI contains the parameter in H0, then a two-tailed test should not reject H0

at a 5% significance level.

Statistics: Unlocking the Power of Data Lock5

Intervals and Tests A confidence interval represents the range of

plausible values for the population parameter

If the null hypothesized value IS NOT within the CI, it is not a plausible value and should be rejected

If the null hypothesized value IS within the CI, it is a plausible value and should not be rejected

Statistics: Unlocking the Power of Data Lock5

• Using bootstrapping, we found a 95% confidence interval for the mean body temperature to be (98.05°, 98.47°)

• This does not contain 98.6°, so at α = 0.05 we would reject H0 for the hypotheses

H0 : µ = 98.6° Ha : µ ≠ 98.6°

Body Temperatures

Statistics: Unlocking the Power of Data Lock5

Both Father and Mother • “Does a child need both a father and a mother to

grow up happily?” • Let p be the proportion of adults aged 18-29 in

2010 who say yes. A 95% CI for p is (0.487, 0.573).

• Testing H0: p = 0.5 vs Ha: p ≠ 0.5 with α = 0.05, do we reject H0 or not reject H0?

Do not reject H0; 0.5 is within the CI, so is a plausible value for p.

http://www.pewsocialtrends.org/2011/03/09/for-millennials-parenthood-trumps-marriage/#fn-7199-1

Statistics: Unlocking the Power of Data Lock5

Both Father and Mother • “Does a child need both a father and a mother to

grow up happily?” • Let p be the proportion of adults aged 18-29 in

1997 who say yes. A 95% CI for p is (0.533, 0.607).

• Testing H0: p = 0.5 vs Ha: p ≠ 0.5 with α = 0.05, we reject H0 or do not reject H0?

Reject H0; 0.5 is not within the CI, so is not a plausible value for p.

http://www.pewsocialtrends.org/2011/03/09/for-millennials-parenthood-trumps-marriage/#fn-7199-1

Statistics: Unlocking the Power of Data Lock5

Intervals and Tests Confidence intervals are most useful when you

want to estimate population parameters

Hypothesis tests and p-values are most useful when you want to test hypotheses about population parameters

Confidence intervals give you a range of plausible values; p-values quantify the strength of evidence against the null hypothesis

Statistics: Unlocking the Power of Data Lock5

Interval, Test, or Neither? • Are the following questions best assessed using a

confidence interval, a hypothesis test, or is statistical inference not relevant?

• Do a majority of adults riding a bicycle wear a helmet?

• On average, how much more do adults who played sports in high school exercise than adults who did not play sports in high school?

• On average, were the 23 players on the 2010 Canadian Olympic hockey team older than the 23 players on the 2010 US Olympic hockey team?

Statistics: Unlocking the Power of Data Lock5

• With small sample sizes, even large differences or effects may not be significant

• With large sample sizes, even a very small difference or effect can be significant

• A statistically significant result is not always practically significant, especially with large sample sizes

Statistical vs Practical Significance

Statistics: Unlocking the Power of Data Lock5

• Example: Suppose a weight loss program recruits 10,000 people for a randomized experiment.

• A difference in average weight loss of only 0.5 lbs could be found to be statistically significant

• Suppose the experiment lasted for a year. Is a loss of ½ a pound practically significant?

Statistical vs Practical Significance

Statistics: Unlocking the Power of Data Lock5

Diet and Sex of Baby

•Are certain foods in your diet associated with whether or not you conceive a boy or a girl?

•To study this, researchers asked women about their eating habits, including asking whether or not they ate 133 different foods regularly

http://www.newscientist.com/article/dn13754-breakfast-cereals-boost-chances-of-conceiving-boys.html

Statistics: Unlocking the Power of Data Lock5

Hypothesis Tests For each of the 133 foods studied, a hypothesis test was conducted for a difference between mothers who conceived boys and girls in the proportion who consume each food State the null and alternative hypotheses If there are NO differences (all null hypotheses

are true), about how many significant differences would be found using α = 0.05?

A significant difference was found for breakfast cereal (mothers of boys eat more), prompting the headline “Breakfast Cereal Boosts Chances of Conceiving Boys”. How might you explain this?

Statistics: Unlocking the Power of Data Lock5

Hypothesis Tests State the null and alternative hypotheses

If there are NO differences (all null hypotheses are true), about how many significant differences would be found using α = 0.05?

A significant difference was found for breakfast cereal (mothers of boys eat more), prompting the headline “Breakfast Cereal Boosts Chances of Conceiving Boys”. How might you explain this?

pb: proportion of mothers who have boys that consume the food regularly pg: proportion of mothers who have girls that consume the food regularly

H0: pb = pg Ha: pb ≠ pg

133 × 0.05 = 6.65

Random chance; several tests (about 6 or 7) are going to be significant, even if no differences exist

Statistics: Unlocking the Power of Data Lock5

Multiple Testing

When multiple hypothesis tests are conducted, the chance that at least one test

incorrectly rejects a true null hypothesis increases with the number of tests.

If the null hypotheses are all true, α of the tests will yield statistically significant

results just by random chance.

Statistics: Unlocking the Power of Data Lock5

www.causeweb.org Author: JB Landers

Statistics: Unlocking the Power of Data Lock5

Multiple Comparisons • Consider a topic that is being investigated by research teams all over the world ⇒ Using α = 0.05, 5% of teams are going to find something significant, even if the null hypothesis is true

Statistics: Unlocking the Power of Data Lock5

Multiple Comparisons •Consider a research team/company doing many hypothesis tests ⇒ Using α = 0.05, 5% of tests are going to be significant, even if the null hypotheses are all true

Statistics: Unlocking the Power of Data Lock5

• This is a serious problem

• The most important thing is to be aware of this issue, and not to trust claims that are obviously one of many tests (unless they specifically mention an adjustment for multiple testing)

•There are ways to account for this (e.g. Bonferroni’s Correction), but these are beyond the scope of this class

Multiple Comparisons

Statistics: Unlocking the Power of Data Lock5

Publication Bias • publication bias refers to the fact that usually only the significant results get published

• The one study that turns out significant gets published, and no one knows about all the insignificant results

• This combined with the problem of multiple comparisons, can yield very misleading results

Statistics: Unlocking the Power of Data Lock5 http://xkcd.com/882/

Jelly Beans Cause Acne!

Statistics: Unlocking the Power of Data Lock5

Statistics: Unlocking the Power of Data Lock5

Statistics: Unlocking the Power of Data Lock5 http://xkcd.com/882/

Statistics: Unlocking the Power of Data Lock5

Summary If a null hypothesized value lies inside a 95% CI, a

two-tailed test using α = 0.05 would not reject H0

If a null hypothesized value lies outside a 95% CI, a two-tailed test using α = 0.05 would reject H0

Statistical significance is not always the same as practical significance

Using α = 0.05, 5% of all hypothesis tests will lead to rejecting the null, even if all the null hypotheses are true