computer aided thermal fluid analysis lecture 10 dr. ming-jyh chern me ntust
TRANSCRIPT
Computer Aided Thermal Computer Aided Thermal Fluid AnalysisFluid Analysis
Lecture 10Lecture 10
Dr. Ming-Jyh ChernDr. Ming-Jyh Chern
ME NTUSTME NTUST
Road Map for TodayRoad Map for Today
• What is turbulence?What is turbulence?• Reynolds Averaged Navier-Stokes (RAReynolds Averaged Navier-Stokes (RA
NS) equationsNS) equations• Turbulence modelsTurbulence models• Boundary conditions for turbulence mBoundary conditions for turbulence m
odelsodels
What is turbulence? Part IIWhat is turbulence? Part II
Let us see a movie regarding a turbulent flow in a valve.
What is turbulence? Part III – What is turbulence? Part III – Its natureIts nature
• RandomRandom
• Effective MixingEffective Mixing
• High Reynolds numberHigh Reynolds number
• 3-D3-D
• Energy DissipationEnergy Dissipation
• Eddy MotionsEddy Motions
Reynolds Averaged Navier-StoReynolds Averaged Navier-Stokes (RANS) equationskes (RANS) equations
is the so-called Reynolds stress.
Zero equation model Zero equation model
t is assumed to be a constant and depends on various flow fields.
Example – Sudden Expansion Example – Sudden Expansion Flow – Laminar Flow CaseFlow – Laminar Flow Case
• Working fluids – airWorking fluids – air• Density = 1.205 mDensity = 1.205 m33/s/s• Dynamics viscosity = 1.81e-5 kg/msDynamics viscosity = 1.81e-5 kg/ms• Characteristic length = 0.1 mCharacteristic length = 0.1 m• If we consider a laminar channel flow at If we consider a laminar channel flow at
Re = 100, then the magnitude of inlet velRe = 100, then the magnitude of inlet velocity must be 0.015 m/s. ocity must be 0.015 m/s.
Example – Sudden Expansion Example – Sudden Expansion Flow – Boundary setupFlow – Boundary setup
Inlet boundary
Symmetry boundary
Symmetry boundary
Outlet or constant pressure boundary
Example – Sudden Expansion Example – Sudden Expansion Flow – Results of laminar FlowFlow – Results of laminar Flow
Example – Sudden Expansion Example – Sudden Expansion Flow – Turbulent Flow CaseFlow – Turbulent Flow Case
• Working fluids – airWorking fluids – air• Density = 1.205 mDensity = 1.205 m33/s/s• Dynamics viscosity = 1.81e-5 kg/msDynamics viscosity = 1.81e-5 kg/ms• Characteristic length = 0.1 mCharacteristic length = 0.1 m• If we consider a turbulent channel flow at Re = If we consider a turbulent channel flow at Re =
30,000, then the magnitude of inlet velocity m30,000, then the magnitude of inlet velocity must be 4.5 m/s. ust be 4.5 m/s.
• kk and and at the inlet boundary ( at the inlet boundary (kk = 0.30375, = 0.30375, = 7. = 7.859).859).
Example – Sudden Expansion Example – Sudden Expansion Flow – Results of Turbulent Flow – Results of Turbulent FlowFlow
Contours of k
Simulation of Heat Transfer Simulation of Heat Transfer
• Forced convection or natural Forced convection or natural convection?convection?
• Boundary conditions, a. isothermal Boundary conditions, a. isothermal boundary, b. constant heat flux. boundary, b. constant heat flux.
• Conjugate heat transfer? Heat Conjugate heat transfer? Heat sources should be imposed inside sources should be imposed inside solids. solids.
Example – Forced convection Example – Forced convection with isothermal boundarywith isothermal boundary
ui0.1 m
0.13 m
1 m
2.5 m
T = 313 K
The constant wall temperature is 293 K, except for the orange region at which the temperature is 313 K.
Example – Forced convection Example – Forced convection with isothermal boundarywith isothermal boundary
Example – Forced convection Example – Forced convection with isothermal boundarywith isothermal boundary
Example – Forced convection Example – Forced convection with isothermal boundarywith isothermal boundary
Example – Forced convection Example – Forced convection with isothermal boundarywith isothermal boundary
Example – Forced convection Example – Forced convection with isothermal boundarywith isothermal boundary
Example – Forced convection Example – Forced convection with isothermal boundarywith isothermal boundary
Example – Forced convection Example – Forced convection with isothermal boundarywith isothermal boundary
Isothermal contours
Example – Natural convection Example – Natural convection with isothermal boundarywith isothermal boundary
T = 294 K
T = 293 K
Adiabatic boundaryAdiabatic boundary
g
0.01 m
0.01 m
Example – Natural convection Example – Natural convection with isothermal boundarywith isothermal boundary
3LTTgRa LH
01.0
then
8.9
10216.2
10569.1
293
11
K 1
10 If
5
5
4
L
g
T
TT
Ra
L
LH
Example – Natural convection Example – Natural convection with isothermal boundarywith isothermal boundary
• Boussinesq’s approximation: assume the buoBoussinesq’s approximation: assume the buoyant force yant force ff in N-S equations is in N-S equations is
refTTgf
Example – Natural convection Example – Natural convection with isothermal boundarywith isothermal boundary
Example – Natural convection Example – Natural convection with isothermal boundarywith isothermal boundary
Example – Natural convection Example – Natural convection with isothermal boundarywith isothermal boundary
Example – Natural convection Example – Natural convection with isothermal boundarywith isothermal boundary
Isothermal contours
Example – Conjugate Heat Example – Conjugate Heat TransferTransfer
• Heat conduction in a solid and Heat conduction in a solid and convection in a fluid are considered convection in a fluid are considered in conjugate heat transfer. in conjugate heat transfer.
• At least, two materials shall be At least, two materials shall be defined as a fluid and a solid in the defined as a fluid and a solid in the model, respectively. model, respectively.
Example – Conjugate Heat Example – Conjugate Heat TransferTransfer
T = 294 K
T = 293 K
Adiabatic boundaryAdiabatic boundary
g
0.01 m
0.01 m
air
Al
Example – Conjugate Heat TransferExample – Conjugate Heat Transfer
4. Choose a solid material from the table or creat a new one. Do not forget to click apply.
Example – Conjugate Heat TransferExample – Conjugate Heat Transfer
5. Use C> /NEW / Zone to select cells into cset.
Example – Conjugate Heat TransferExample – Conjugate Heat Transfer
6. Click Tools/Cell Tools to set Type 2 Solid to Material 2
Example – Conjugate Heat TransferExample – Conjugate Heat Transfer
7. Use cell list to change cells in cset to the type 2 solid
Example – Conjugate Heat TransferExample – Conjugate Heat Transfer
8. Check if there are two different kinds of cells. Red one is fluid 1. Green one is solid 2.
Example – Conjugate Heat TransferExample – Conjugate Heat Transfer
9. Go back to STAR Guide. Click Thermal Options. Click Heat Transfer ON.
10.The rest procedures for simulation of natural convection are as same as the previous example.