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DESIGN OF COLUMNS :h = 12 (inch)

d = 10 (inch)d' = 2 (inch) As'(comp) = 1.5 (in^2)b = 12 (inch) As(tsionen) = 1.5 (in^2)fc' = 2.2 (ksi)fy = 40 (ksi)

step 1 : for balanced condition:

Pn = Pb = 163.06440945 (kips)

Mn = Mb= 1013.1678315 (kips-in)84.430652629 (kips-ft)

Cb = 6.8503937008 (inch)0.85

ab = 5.8228346457 (inch)

fs' = 61.6 (ksi) COMP STEEL IS YIEDING

fs' (taken) = 61.6 (ksi) ENTER THE VALUE OF fy AS GIVEN IN QuESTION

U must enter the value of fs' here

eb = 6.213298383 (inch)

STEP 2 : Pn & Mn FOR A REPRESETATIVE POINT IN THE TENSION FAILURE REGION C < Cb:choose the value of c less than Cb and enter here

Let c = 4 (inch) a = 3.4 (inch)

COMPRESSION STEEL :

fs' = 43.5 (ksi) COMP STEEL IS YIELDING(NOT OK)

fs'(taken)= 43.5 (ksi) ENTER THE VALUE OF fy AS GIVEN IN QuESTION

u must enter the value of fs' here

TENSION STEEL :

fs = 130.5 (ksi) TENSION STEEL IS YIELDING(OK)fs(taken)= 40 (ksi) ENTER THE VALUE OF fs AS GIVEN IN QuESTION

STEP 3 : Pn & Mn FOR REPRESTATIVE POINT IN COMPRESSION FAILIURE REGION C > Cb :choose the value of c greater than cb

let c = 13 (inch) a = 11.05 (inch)

fs' = 73.615384615 (ksi) COMP STEEL IS YIELDING(OK)

fs'(taken)= 40 (ksi) ENTER THE VALUE OF fs' AS GIVEN IN QUESTION

fs = -20.076923077 (ksi) TENSION STEEL IS NOT YIELDING(OK)fs(taken)= 40 (ksi) ENTER THE VALUE OF fs As FINDED

STEP 4 : Pn WHEN e=0 :

pn = 389.28 (kips)

BY ENGR ABDUL RAZIQUET PESHAWAR

FOR GRAPH :Mn pn e

69.0894 81.546 10.16693 tension failure region84.43065 163.0644 6.213298 balanced failure49.81516 247.962 2.41078 compression failure region

0 389.28 0 e=0

STRENGTH INTERACTION CURVE :

Pn = 163.064 (kips)ENTER THE VALUE OF fy AS GIVEN IN QuESTION Mn = 1013.17 (kips-in)

84.4307 (kips-ft)

e = 6.2133 (in)

STEP 2 : Pn & Mn FOR A REPRESETATIVE POINT IN THE TENSION FAILURE REGION C < Cb: Cb= 6.850394

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Mn (kips-ft)

pn (k

ips)

Pn = 81.546 (kips)Mn = 829.073 (kips-in)

ENTER THE VALUE OF fy AS GIVEN IN QuESTION 69.0894 (kips-ft)

e = 10.1669 (in)

ENTER THE VALUE OF fs AS GIVEN IN QuESTION

STEP 3 : Pn & Mn FOR REPRESTATIVE POINT IN COMPRESSION FAILIURE REGION C > Cb : Cb= 6.850394

pn= 247.962 (kips)Mn= 597.782 (kips-in)

ENTER THE VALUE OF fs' AS GIVEN IN QUESTION 49.8152 (kips-ft)

e = 2.41078 (in)

pn = 389.28 (kips)Mn = 0

e = 0 (in)

tension failure region

compression failure region