class_10_fouriertransform.pdf

29
Chengbin Ma UM-SJTU Joint Institute Class#10 - Continuous-time periodic signals: the Fourier series (3.5)-An application - Continuous-time nonperiodic signals: the Fourier transform (3.7) Slide 1

Upload: hatetheschool

Post on 06-Sep-2015

215 views

Category:

Documents


0 download

TRANSCRIPT

  • Chengbin Ma UM-SJTU Joint Institute

    Class#10

    - Continuous-time periodic signals: the Fourier series (3.5)-An application

    - Continuous-time nonperiodic signals: the Fourier transform (3.7)

    Slide 1

  • Chengbin Ma UM-SJTU Joint Institute

    Preview of Previous Lecture

    Natural response and forced response

    natural response transient response

    (homogeneous solution), and forced response

    steady-state response (particular solution)

    Fourier Series (FS)

    DC component, fundamental frequency, Nth

    harmonic component

    FS coefficient

    Dirichlet conditions

    Trigonometric FS

    Slide 2

  • Chengbin Ma UM-SJTU Joint Institute

    This Lecture

    A real application of FS in analyzing a power

    electronic circuit

    Extend FS to analyze nonperiodic signals, i.e.,

    Fourier transform (FT).

    Slide 3

  • Chengbin Ma UM-SJTU Joint Institute

    Application: DC-AC Converter

    Slide 4

    Example 3.16, p227

  • Chengbin Ma UM-SJTU Joint Institute

    DC/AC Conversion Efficiency

    Example 3.16, p227

    Slide 5

    0

    0

    ( ) [ ]cos( )k

    x t B k k t

    0[0] 2 /B T T

    02sin( 2 / )[ ] , 0k T T

    B k kk

  • Chengbin Ma UM-SJTU Joint Institute

    Class#10

    - Continuous-time periodic signals: the Fourier series (3.5)-An application

    - Continuous-time nonperiodic signals: the Fourier transform (3.7)

    Slide 6

  • Chengbin Ma UM-SJTU Joint Institute

    The Fourier transform

    The Fourier transform (FT) is used to represent

    a continuous-time nonperiodic signal as a

    superposition of complex sinusoids.

    1( ) ( ) (IFT)

    2

    ( ) ( ) (FT)

    ( ) ( )

    j t

    j t

    FT

    x t X j e d

    X j x t e dt

    x t X j

    T

    tjkdtetx

    TkX

    0

    0)(1

    ][

    k

    tjkekXtx 0][)(

    Frequency-domain representation

  • Chengbin Ma UM-SJTU Joint Institute

    Basic Idea (1)

    Development of the Fourier transform representation of a continuous-time nonperiodic signal - we think of a nonperiodic signal as the limit of a periodic signal as the period becomes arbitrarily large, and we examine the limiting behavior of the Fourier series representation for this signal.

    dejXtx tj)(2

    1)(

  • Chengbin Ma UM-SJTU Joint Institute

    Basic Idea (2)

    Points: T is infinitely large; thus 0 is infinitely

    small and k0 is actually continuous.

    1. Represent w(t) using IFS

    2. Solve W[k] using FS

    3. Further represent w(t) using k

    Eventually

    Slide 9

    T

    tjk

    k

    tjk

    dtetxT

    kX

    ekXtx

    0

    0

    )(1

    ][

    ][)(

    dejXtx tj)(2

    1)(

  • Chengbin Ma UM-SJTU Joint Institute

    Derivations (1) Reference

    0

    0 0

    0

    0

    / 2 / 2

    / 2 / 2

    0

    ( ) [ ]

    1 1[ ] ( ) ( )

    1( )

    , [ ] 0.

    , [ ] ( ) ( ) does not

    necessarily approach 0, where ( ) ( )

    jk t

    k

    T T

    jk t jk t

    T T

    jk t

    jk t

    j t

    w t W k e

    W k w t e dt x t e dtT T

    x t e dtT

    T W k

    T W k T x t e dt X jk

    X j x t e dt

    is

    the envelope function of [ ] .W k T

    =

    =

    T

    tjk

    k

    tjk

    dtetxT

    kX

    ekXtx

    0

    0

    )(1

    ][

    ][)(

    In single period

  • Chengbin Ma UM-SJTU Joint Institute

    Derivations (2) Reference

    We can express the periodic signal in terms of the envelope function as

    0

    0 0

    0

    0

    0

    0 0

    ( ) [ ]

    1 1[ ] ( )

    1( )

    2

    1( )

    2

    jk t

    k

    jk t jk t

    k k

    jk t

    k

    jk t

    k

    w t W k e

    W k Te X jk eT T

    X jk e

    X jk e

    0

    0

    2

    )(][

    ][)( 0

    T

    jkXTkW

    ekXtxk

    tjk

    Because T is infinite, 0 is infinitely small!

  • Chengbin Ma UM-SJTU Joint Institute

    Derivations (3) Reference

    We have

    dejX

    dejX

    ejkX

    twtwtx

    tj

    tj

    k

    tjk

    T

    )(2

    1

    )(2

    1

    )(2

    1lim

    )(lim)(lim)(

    0

    00

    2T

    Inverse FT

  • Chengbin Ma UM-SJTU Joint Institute

    IFT and FT

    The Fourier transform pair

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    T

    tjk

    k

    tjk

    dtetxT

    kX

    ekXtx

    0

    0

    )(1

    ][

    ][)(

  • Chengbin Ma UM-SJTU Joint Institute

    Dirichlet conditions

    A continuous-time signal x(t) is Fourier transformable

    if it satisfies the Dirichlet conditions:

    x(t) is absolutely integrable.

    x(t) has finite number of maxima and minima in any finite

    interval.

    x(t) has finite number of discontinuities within any finite

    interval. Furthermore, each of these discontinuities must be

    finite.

  • Chengbin Ma UM-SJTU Joint Institute

    Example (1)

    Example 3.24 FT of a real decaying exponential.

    jaja

    edte

    dtetuedtetxjX

    atuetx

    tjatja

    tjattj

    at

    1

    )(

    )()()(

    0),()(

    0

    )(

    0

    )(

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    MichaelRectangle
  • Chengbin Ma UM-SJTU Joint Institute

    Example (2)

    Figure 3.39 (b) magnitude spectrum. (c) Phase spectrum.

    Low-pass filter

  • Chengbin Ma UM-SJTU Joint Institute

    3.7 The Fourier Transform

    Example 3.24 FT of a rectangular pulse.

    0

    0

    00 0 0 0

    0

    0

    00 0 0 0

    0

    1,( )

    0, otherwise

    ( ) ( )

    2

    2

    sin( )2sin( ) 2 2 ( ) ( )

    T

    j t j t

    T

    Tj T j T j T j Tj t

    T

    t Tx t

    X j x t e dt e dt

    e e e e e

    j j j

    TT T T Sa T Sa f

    T

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    In textbook (page 223), Sa is named as sinc

    sinc(u)

  • Chengbin Ma UM-SJTU Joint Institute

    Example (3)

    Figure 3.40 (b) Spectrum of the rectangular pulse.

  • Chengbin Ma UM-SJTU Joint Institute

    Example (4)

    FT of the unit impulse.

    0

    ( ) 1

    ( ) ( )

    ( ) ( ) 1

    FT

    j t j t

    t

    t

    x t t

    X j t e dt e

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    MichaelRectangle
  • Chengbin Ma UM-SJTU Joint Institute

    Example (5)

    FT of 1.

    0

    1 2 ( )

    ( ) 2 ( )

    1( ) 2 ( ) 1

    2

    FT

    j t j t

    X j

    x t e dt e

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    MichaelRectangle
  • Chengbin Ma UM-SJTU Joint Institute

    Example (6)

    FT of the delayed unit impulse.

    0

    0

    0

    0

    0

    0

    ( )

    ( ) ( )

    ( ) ( )

    FTj t

    j tj t j t

    t t

    t t e

    x t t t

    X j t t e dt e e

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    MichaelRectangle
  • Chengbin Ma UM-SJTU Joint Institute

    Example (7)

    FT of the complex sinusoids.

    0

    0

    0

    0

    0

    0

    2 ( )

    ( ) 2 ( )

    1( ) 2 ( )

    2

    FTj t

    j tj t j t

    e

    X j

    x t e dt e e

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    MichaelRectangle
  • Chengbin Ma UM-SJTU Joint Institute

    Example (8)

    FT of the cosine.

    0 0

    0 0

    0 0 0

    0 0

    0 00

    cos( ) [ ( ) ( )]

    2 ( ), 2 ( )

    2 ( ) 2 ( )cos( )

    2 2

    FT

    FT FTj t j t

    j t j t FT

    t

    e e

    e et

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    Note that the nature of integration is summation, and linearity will automatically follow.

    MichaelRectangle
  • Chengbin Ma UM-SJTU Joint Institute

    Example (9)

    FT of the sine.

    0 0

    0 0

    0 0 0

    0 0

    0 00

    sin( ) [ ( ) ( )]

    2 ( ), 2 ( )

    2 ( ) 2 ( )sin( )

    2 2

    FT

    FT FTj t j t

    j t j t FT

    tj

    e e

    e et

    j j

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    MichaelRectangle
  • Chengbin Ma UM-SJTU Joint Institute

    Example (10)

    FT of the sinc function.

    1,sin( )( ) ( )

    0,2

    ( )2

    1 1( )

    2 2 2

    1 1 1

    2 2 2

    FT

    W

    j t j t

    W

    Wj t jWt jWt jWt jWt

    W

    WWtu W u W

    Wt W

    X jW

    x t e d e dW

    e e e e e

    jt jt t j

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    page 246

    MichaelRectangleMichaelRectangle
  • Chengbin Ma UM-SJTU Joint Institute

    Example (11)

    FT of the signum function.

    ( )

    1, 02

    sign( ) 0, 0

    1, 0

    [PROOF]

    sign( ) ( ) ( )

    1( ) ( ) ( ) ( )

    ( ) ( ) ( ) ( )

    1 1( ) ( ) ( )

    FT

    j t

    j t j

    t

    t tj

    t

    t u t u t

    u t u t e dt U jj

    u t u t e dt u e d U j

    U jj j

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    )(1

    )(

    j

    tu FT

    Refer to the following slides

    MichaelRectangle
  • Chengbin Ma UM-SJTU Joint Institute

    Reference (1.1)

    FT of the unit step function.

    1( ) ( )

    1 1 1( ) ( ) ( ) ( )

    2

    1 1 1( )

    2 2

    1 cos( ) sin( ) 1 1 sin( ) 1

    2 2 2 2

    1 si

    21 sin( )

    2

    FT

    j t

    j t j t

    u tj

    X j x t e dj j

    e d e dj

    t j t td d

    j

    u d duu t du td d

    u

    td

    n( ), 0

    1 sin( ), 0

    2

    udu t

    u

    udu t

    u

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    u is negative

    cos(wt)/(jw) is odd function, therefore its integration from inf to inf is zero

    MichaelRectangleMichaelRectangle
  • Chengbin Ma UM-SJTU Joint Institute

    Reference (1.2)

    1, 1, 1sin( ) sin( )

    0, 0, 12 2

    sin( ) sin( ) 1 sin( ) 01

    2 2

    1, 0

    sin( ) 1 sin( ) 2

    12, 0

    2

    j t

    WWt t

    Wt W t

    t t te dt dt dt

    t t t

    tu t

    du du

    t

    x

    1, 01 sin( ) 1( )

    0, 02 2

    ttt d

    t

    )()(

    )()(

    )(2

    1)(

    jXtx

    dtetxjX

    dejXtx

    FT

    tj

    tj

    FT of the unit step function (Continue).

    =0

    let W = 1

    This is exactly the definition of u(t)

  • Chengbin Ma UM-SJTU Joint Institute

    Homework

    None

    Read the PPTs and try to solve the examples

    by yourself carefully!

    Slide 29