circular motion. a 1200-kilogram car traveling at a constant speed of 9.0 m/s turns at an...
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Circular MotionCircular Motion
A 1200-kilogram car A 1200-kilogram car traveling at a constant traveling at a constant speed of 9.0 m/s turns speed of 9.0 m/s turns at an intersection. The at an intersection. The car follows a horizontal car follows a horizontal circular path with a radius circular path with a radius of 25 meters to point of 25 meters to point P. P. At At point point P, the car hits an area of ice and loses P, the car hits an area of ice and loses all all frictional force on its tires. Which path frictional force on its tires. Which path does the car follow on the ice?does the car follow on the ice?
A) A B) B C) C D) DA) A B) B C) C D) D
A ball attached to A ball attached to a string is moved at a string is moved at constant speed in a constant speed in a horizontal circular horizontal circular path. A target is located near the path path. A target is located near the path of the ball as shown in the diagram. At of the ball as shown in the diagram. At which point along the ball’s path which point along the ball’s path should the string be released, if the should the string be released, if the ball is to hit the target?ball is to hit the target?
A) A B) B C) C D) DA) A B) B C) C D) D
An artificial satellite makes 4 An artificial satellite makes 4 complete revolutions about the complete revolutions about the Earth in 8 hours. The period of Earth in 8 hours. The period of revolution of the satellite isrevolution of the satellite is
A) ½ hour A) ½ hour B) 2 hoursB) 2 hoursC) 8 hours C) 8 hours D) 32 hoursD) 32 hours
Centripetal Centripetal AccelerationAcceleration
&&ForceForce
If the velocity of a car traveling If the velocity of a car traveling around a circular track doubles, around a circular track doubles, its centripetal acceleration would its centripetal acceleration would bebeA) 1/2 as great A) 1/2 as great B) 2 times greaterB) 2 times greaterC) 1/4 as great C) 1/4 as great D) 4 times greaterD) 4 times greater
The diagram below shows the elliptical The diagram below shows the elliptical orbit of a comet around the Sun. orbit of a comet around the Sun.
The magnitude of the centripetal The magnitude of the centripetal acceleration of the comet is greatest at acceleration of the comet is greatest at pointpointA) A B) B C) C D) DA) A B) B C) C D) D
A car moves with a A car moves with a constant speed in a constant speed in a clockwise direction clockwise direction around a circular around a circular path of radius path of radius r, as r, as represented in the diagram above. represented in the diagram above. When the car is in the position shown, When the car is in the position shown, its acceleration is directed toward theits acceleration is directed toward theA) north B) west C) south D) eastA) north B) west C) south D) east
The magnitude of the centripetal force The magnitude of the centripetal force acting on an object traveling in a acting on an object traveling in a horizontal, circular path will horizontal, circular path will decrease decrease if theif the
A) radius of the path is increasedA) radius of the path is increasedB) mass of the object is increasedB) mass of the object is increasedC) direction of motion of the object is C) direction of motion of the object is reversedreversedD) speed of the object is increasedD) speed of the object is increased
The centripetal force acting on the The centripetal force acting on the space shuttle as it orbits Earth is space shuttle as it orbits Earth is equal to the shuttle’sequal to the shuttle’s A) inertia A) inertia B) momentumB) momentumC) velocity C) velocity D) weightD) weight
Centripetal force Centripetal force FFcc acts on a car acts on a car
going around a curve. going around a curve. If the speed of If the speed of the car were twice as great, the the car were twice as great, the magnitude of the centripetal force magnitude of the centripetal force necessary to keep the car moving in necessary to keep the car moving in the same path would bethe same path would be
A) FA) Fcc B) 2F B) 2Fcc C) F C) Fcc/2 D) 4F/2 D) 4Fcc
The diagram below The diagram below represents a mass, represents a mass, m, m, being swung being swung clockwiseclockwise at constant speed in at constant speed in a horizontal circle. At the instant a horizontal circle. At the instant shown, the centripetal force acting shown, the centripetal force acting on mass on mass m is directed toward pointm is directed toward pointA) A B) B C) C D) DA) A B) B C) C D) D
A 0.50-kilogram object moves in a horizontal circular path with a radius of 0.25 meter at a constant speed of 4.0 m/s. What is the magnitude of the object’s acceleration?
A) 8.0 m/s2
B) 16 m/s2
C) 32 m/s2
D) 64 m/s2
A 0.50-kilogram object moves in a horizontal circular path with a radius of 0.25 meter at a constant speed of 4.0 m/s. What is the magnitude of the object’s centripetal force?
A 0.40-kilogram stone is attached to a A 0.40-kilogram stone is attached to a string. The stone is moving at a string. The stone is moving at a constant speed of 4.0 m/s in a constant speed of 4.0 m/s in a horizontal circle with a radius of 0.80 horizontal circle with a radius of 0.80 m. The magnitude of the centripetal m. The magnitude of the centripetal acceleration of the stone isacceleration of the stone isA) 0.0 m/sA) 0.0 m/s22 B) 2.0 m/sB) 2.0 m/s22
C) 5.0 m/sC) 5.0 m/s22 D) 20. m/sD) 20. m/s22
A 2.0 × 10A 2.0 × 1033-kilogram car travels at a -kilogram car travels at a constant speed of 12 m/s around a circular constant speed of 12 m/s around a circular curve of radius 30 meters. What is the curve of radius 30 meters. What is the magnitude of the centripetal acceleration magnitude of the centripetal acceleration of the car as it goes around the curve?of the car as it goes around the curve? A) 0.40 m/sA) 0.40 m/s22 B) 4.8 m/sB) 4.8 m/s22
C) 800 m/sC) 800 m/s22 D) 9,600 m/sD) 9,600 m/s22
In an experiment, a In an experiment, a 0.028-kilogram rubber 0.028-kilogram rubber stopper is attached to stopper is attached to one end of a string. A one end of a string. A student whirls the stopper student whirls the stopper overhead in a horizontal overhead in a horizontal circle with a radius of circle with a radius of 1.0 meter. The stopper completes 10 1.0 meter. The stopper completes 10
revolutions in 10 seconds. revolutions in 10 seconds. Calculate Calculate the the magnitude of the magnitude of the angular speed or angular speed or frequencyfrequency of the stopper. of the stopper.
In an experiment, a In an experiment, a 0.028-kilogram rubber 0.028-kilogram rubber stopper is attached to stopper is attached to one end of a string. A one end of a string. A student whirls the stopper student whirls the stopper overhead in a horizontal overhead in a horizontal circle with a radius of circle with a radius of 1.0 meter. The stopper completes 10 1.0 meter. The stopper completes 10
revolutions in 10 seconds. revolutions in 10 seconds. Calculate Calculate the the magnitude of the magnitude of the linear or tangential speed linear or tangential speed of the whirling stopper.of the whirling stopper.
In an experiment, a In an experiment, a 0.028-kilogram rubber 0.028-kilogram rubber stopper is attached to stopper is attached to one end of a string. A one end of a string. A student whirls the stopper student whirls the stopper overhead in a horizontal overhead in a horizontal circle with a radius of circle with a radius of 1.0 meter. The stopper completes 10 1.0 meter. The stopper completes 10
revolutions in 10 seconds. revolutions in 10 seconds. Calculate Calculate the the magnitude of the magnitude of the centripetal acceleration centripetal acceleration of of the whirling stopper.the whirling stopper.
In an experiment, a In an experiment, a 0.028-kilogram rubber 0.028-kilogram rubber stopper is attached to stopper is attached to one end of a string. A one end of a string. A student whirls the stopper student whirls the stopper overhead in a horizontal overhead in a horizontal circle with a radius of circle with a radius of 1.0 meter. The stopper completes 10 1.0 meter. The stopper completes 10
revolutions in 10 seconds. revolutions in 10 seconds. Calculate Calculate the the magnitude of the magnitude of the centripetal force centripetal force on the on the whirling stopper.whirling stopper.
A mass of 10 kilograms is A mass of 10 kilograms is revolving at a linear speed of 5 revolving at a linear speed of 5 meters per second in a circle meters per second in a circle with a radius of 10 meters. with a radius of 10 meters. What is the frequency or What is the frequency or angular speed (rps) of the mass?angular speed (rps) of the mass?
A mass of 10 kilograms is A mass of 10 kilograms is revolving at a linear speed of 5 revolving at a linear speed of 5 meters per second in a circle meters per second in a circle with a radius of 10 meters. with a radius of 10 meters. What is the centripetal What is the centripetal acceleration of the mass isacceleration of the mass is
A mass of 10 kilograms is A mass of 10 kilograms is revolving at a linear speed of 5 revolving at a linear speed of 5 meters per second in a circle meters per second in a circle with a radius of 10 meters. The with a radius of 10 meters. The centripetal force acting on the centripetal force acting on the mass ismass isA) 5 N A) 5 N C) 20 N C) 20 N B) 10 N B) 10 N D) 25 ND) 25 N
A 1750-kilogram car travels at a A 1750-kilogram car travels at a constant speed of 15.0 m/s around a constant speed of 15.0 m/s around a horizontal, circular track with a horizontal, circular track with a radius of 45.0 meters. The magnitude radius of 45.0 meters. The magnitude of the centripetal acceleration of the of the centripetal acceleration of the car iscar is
A 1750-kilogram car travels at a A 1750-kilogram car travels at a constant speed of 15.0 m/s around a constant speed of 15.0 m/s around a horizontal, circular track with a horizontal, circular track with a radius of 45.0 meters. The magnitude radius of 45.0 meters. The magnitude of the centripetal force acting on the of the centripetal force acting on the car iscar is
Universal Gravitational LawsUniversal Gravitational Laws
As the distance between two As the distance between two objects increases, the gravitational objects increases, the gravitational force of attraction between them force of attraction between them willwill
A) decrease A) decrease B) increaseB) increaseC) remain the sameC) remain the same
The diagram below The diagram below Shows four Shows four different locations different locations of a satellite in its of a satellite in its elliptical orbit about Earth. At elliptical orbit about Earth. At which location is the magnitude which location is the magnitude of the satellite’s velocity greatest?of the satellite’s velocity greatest?
A)A)A B) B C) C D) DA B) B C) C D) D
Spacecraft S is traveling Spacecraft S is traveling from planet Pfrom planet P11 toward toward
planet Pplanet P22 At the position At the position
shown, the magnitude of shown, the magnitude of the gravitational force of planet Pthe gravitational force of planet P11 on the on the
spacecraft is equal to the magnitude of the spacecraft is equal to the magnitude of the gravitational force of planet Pgravitational force of planet P22 on the spacecraft. on the spacecraft.
If distance If distance X is greater than distance Y, then the X is greater than distance Y, then the mass of mass of P1 must beP1 must beA) less than the mass of PA) less than the mass of P22
B) greater than the mass of PB) greater than the mass of P22
C) equal to the mass of PC) equal to the mass of P22
The diagram below shows The diagram below shows the movement of a planet the movement of a planet around the Sun. Area 1 around the Sun. Area 1 equals area 2. Compared equals area 2. Compared to the time the planet takes to move from to the time the planet takes to move from C C to to D, the time it takes to move from A to B is D, the time it takes to move from A to B is
A) less A) less B) greaterB) greaterC) the sameC) the same
A satellite is in geosynchronous A satellite is in geosynchronous orbit. Compared to Earth’s orbit. Compared to Earth’s period of rotation, the satellite’s period of rotation, the satellite’s period of revolution isperiod of revolution is
A) less A) less B) greaterB) greaterC) the sameC) the same
The shapes of the paths of the planets The shapes of the paths of the planets about the Sun are allabout the Sun are all
A) circles with the Sun at the centerA) circles with the Sun at the centerB) circles with the Sun off centerB) circles with the Sun off centerC) ellipses with the Sun at the centerC) ellipses with the Sun at the centerD) ellipses with the Sun at one focusD) ellipses with the Sun at one focus
Base your answer Base your answer to the following to the following question on question on the diagram the diagram below which below which represents the orbit of a comet about represents the orbit of a comet about the Sun. As the comet moves from point the Sun. As the comet moves from point A to point B, its potential energy A to point B, its potential energy
A) decreases C) remains the sameA) decreases C) remains the sameB) increasesB) increases
The comet Hyakutake, seen in the The comet Hyakutake, seen in the Earth's sky in 1996, will take more than Earth's sky in 1996, will take more than 10,000 years to complete its orbit. 10,000 years to complete its orbit. Which object is at a focus of the comet's Which object is at a focus of the comet's orbit?orbit?
A) Earth A) Earth B) SunB) SunC) Moon C) Moon D) JupiterD) Jupiter
As the planet moves from As the planet moves from point point B to point C, how do B to point C, how do its kinetic energy and its kinetic energy and potential energy change? potential energy change?
A) Its kinetic energy decreases, and its A) Its kinetic energy decreases, and its potential energy decreases.potential energy decreases.B) Its kinetic energy decreases, and its B) Its kinetic energy decreases, and its potential energy increases.potential energy increases.C) Its kinetic energy increases, and its C) Its kinetic energy increases, and its potential energy decreases.potential energy decreases.D) Its kinetic energy increases, and its D) Its kinetic energy increases, and its potential energy increases.potential energy increases.
What is the magnitude of the What is the magnitude of the gravitational force between two gravitational force between two 5.0-kilogram masses separated by 5.0-kilogram masses separated by a distance of 5.0 meters?a distance of 5.0 meters?
A) 5.0 × 10 A) 5.0 × 10 00 N N B) 3.3 × 10 B) 3.3 × 10 –10 –10 NNC) 6.7 × 10 C) 6.7 × 10 –11 –11 N N D) 1.3 × 10 D) 1.3 × 10 –11 –11 NN
An astronaut weighs 8.00 × 10An astronaut weighs 8.00 × 1022 Newton’ on the surface of Earth. Newton’ on the surface of Earth. What is the weight of the astronaut What is the weight of the astronaut 6.37 × 106.37 × 1066 meters above the surface of meters above the surface of Earth (2 radii total)?Earth (2 radii total)?
A) 0.00 N A) 0.00 N B) 2.00 × 10B) 2.00 × 1022 N NC) 1.60 × 10C) 1.60 × 1033 N N D) 3.20 × 10D) 3.20 × 1033 N N