: 6: : :1. 1.0M CuSO4 2. 3. 4. 50 ml 5. 6. 250 7. 8. 9. 10. 11. :1. Styrofoam .

2. Zn 3.0g .3. 25ml Cu(II) 30 2.5 .4. 3.0 Zn CuSo4 5 .5. 30C

:() (C)

0.026.0

0.526.0

1.026.0

1.526.0

2.026.0

2.526.0

3.0

3.551.0

4.059.0

4.561.0

5.064.0

5.565.5

6.065.0

6.564.0

7.064.0

7.563.5

8.063.0

8.561.5

9.060.5

9.559.5

10.059.0

10.558.0

11.057.5

11.557.0

12.056.0

12.555.0

13.054.5

13.554.0

14.053.0

14.552.5

15.052.0

15.551.0

16.050.5

16.550.0

17.049.5

17.549.0

18.048.5

18.547.5

19.047.0

19.547.0

20.046.8

20.546.5

21.046.0

21.545.5

22.045.0

22.544.8

23.044.0

23.543.8

24.043.5

24.543.2

25.042.8

25.542.5

26.042.2

26.542.0

27.041.8

27.541.2

28.041.0

28.540.8

29.040.2

29.540.0

30.039.8

30.539.5

31.039.2

31.539.0

32.038.8

32.538.8

33.038.5

33.538.2

34.037.8

34.537.5

35.037.5

35.537.2

36.037.0

36.536.8

37.036.5

37.536.2

38.036.0

38.536.0

39.035.8

39.535.5

40.035.2

40.535.0

41.035.0

41.534.8

42.034.8

42.534.5

43.034.2

43.534.2

44.034.0

44.534.0

45.033.8

45.533.5

46.033.5

46.533.2

47.033.0

47.533.0

48.033.0

48.533.0

49.033.0

49.532.5

50.032.5

50.532.5

51.032.5

51.532.2

52.032.2

52.532.0

53.032.0

53.531.8

54.031.8

54.531.8

55.031.5

55.531.5

56.031.5

56.531.5

57.031.5

57.531.5

58.031.2

58.531.2

59.031.2

59.531.0

60.031.0

60.531.0

61.031.0

61.531.0

62.031.0

62.530.8

63.030.8

63.530.5

64.030.5

64.530.5

65.030.5

65.530.5

66.030.5

66.530.2

67.030.0

67.530.0

68.030.0

68.530.0

69.030.0

69.530.0

70.030.0

70.530.0

80.030.0

80.530.0

81.030.0

:The reaction of Zn and CuSo4 is an exothermic reaction. Exothermic reaction release heat so the temperature increases until 65.5C. Then, the temperature decrease within time because heat loss until it reaches a constant temperature of 30C.

Calculation:1.Calculate the T obtained from the graph of the temperature(C) against time(minute). 65.5C 30.0C = 35.5 C2.Calculate the heat gain by the solution. Assume the density of Zinc powder is equal to the density of water, use the specific heat capacity, c as 4.18 J/g C q = mcT = (25g+3g)(4.18 J/g C)(35.5 C) = 4154.92 J

3.Find the number of moles of 25 ml CuSo4. Molarity of the CuSo4 is equal to 1.0 M n = volume x molarity = (25/1000)dm3 x 1.0 M = 0.025 mol

4.Determine the heat release (the enthalpy change, H) per mole of CuSO4 H = -(4154.92 J /0.025 mol) = - 166.1968 kJ/mol

:1.Write the thermo chemical equation for the reaction in the experiment Zn + CuSo4 -> ZnSo4 + Cu

2.Compare your result with the accepted value of -217 kJ/mol by calculating the error of the experiment 217 166.1968 = 50.8032 Kj/mol (50.8032/217) x 100% = 23.41%3. Discuss any possible errors in this experiment Heat loss during the reaction while recording the data. So, a lid is needed to cover the Styrofoam cup. Parallax error might occur while reading the thermometer.