chemistry 122 introductory organic chemistry spring quarter 2015 dr. thomas h. schultz

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Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

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Page 1: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Chemistry 122Introductory Organic Chemistry

Spring Quarter 2015

Dr. Thomas H. Schultz

Page 2: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

What is Organic chemistry?

Page 3: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

What is Organic chemistry?

The study of carbon and its compounds.

Page 4: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

What is Organic chemistry?

The study of carbon and its compounds.

First we will talk about compounds just containing carbon and hydrogen, these compounds are called hydrocarbons.

Page 5: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

What is Organic chemistry?

The study of carbon and its compounds.

First we will concentrate on compounds just containing carbon and hydrogen, these compounds are called hydrocarbons.

Hydrocarbon Classification

Hydrocarbons

Alkanes AlkenesCycloalkanes AlkynesCycloalkenes

Page 6: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

1. Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons)

A. General formula of CnH2n+2

B. Examples

a. CH4 b. C2H6 c. C3H?

Page 7: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

1. Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons)

A. General formula of CnH2n+2

B. Examples

a. CH4 b. C2H6 c. C3H8 d. C4H?

Page 8: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

1. Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons)

A. General formula of CnH2n+2

B. Examples

a. CH4 b. C2H6 c. C3H8 d. C4H10

C. Draw Lewis Structures

Page 9: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

1. Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons)

A. General formula of CnH2n+2

B. Examples

a. CH4 b. C2H6 c. C3H8 d. C4H10

C. Draw Lewis Structures

CH4

C

HH

H

H

Page 10: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

1. Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons)

A. General formula of CnH2n+2

B. Examples

a. CH4 b. C2H6 c. C3H8 d. C4H10

C. Draw Lewis Structures

CH4 C2H6

C

HH

H

H

CH C

H

H

H

H

H

Page 11: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

1. Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons)

A. General formula of CnH2n+2

B. Examples

a. CH4 b. C2H6 c. C3H8 d. C4H10

C. Draw Lewis Structures

CH4 C2H6 C3H8

C

HH

H

H

CH C

H

H

H

H

H CH C

H

H

H

H

C

H

H

H

Page 12: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

1. Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons)

A. General formula of CnH2n+2

B. Examples

a. CH4 b. C2H6 c. C3H8 d. C4H10

C. Draw Lewis Structures

CH4 C2H6 C3H8

D. Polarity? Polar or nonpolar?

C

HH

H

H

CH C

H

H

H

H

H CH C

H

H

H

H

C

H

H

H

Page 13: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

1. Alkanes (saturated) hydrocarbons, or aliphatic hydrocarbons)

A. General formula of CnH2n+2

B. Examples

a. CH4 b. C2H6 c. C3H8 d. C4H10

C. Draw Lewis Structures

CH4 C2H6 C3H8

D. Polarity? Polar or nonpolar? Nonpolar

C

HH

H

H

CH C

H

H

H

H

H CH C

H

H

H

H

C

H

H

H

Page 14: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

E. Types of carbon 1. Primary (1◦) Carbon connected to one carbon atoms. 2. Secondary (2◦) Carbon connected to two carbon atoms. 3. Tertiary (3◦) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the

two different structures of C4H10

Page 15: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

E. Types of carbon 1. Primary (1◦) Carbon connected to one carbon atoms. 2. Secondary (2◦) Carbon connected to two carbon atoms. 3. Tertiary (3◦) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the

two different structures of C4H10

C

H

C

H

H

H C C

H

HH H

H

H

Butane, C4H10

Primary carbon = ?Secondary carbon = Tertiary carbon =

Page 16: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

E. Types of carbon 1. Primary (1◦) Carbon connected to one carbon atoms. 2. Secondary (2◦) Carbon connected to two carbon atoms. 3. Tertiary (3◦) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the

two different structures of C4H10

C

H

C

H

H

H C C

H

HH H

H

H

Butane, C4H10

Primary carbon = 2Secondary carbon = ? Tertiary carbon =

Page 17: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

E. Types of carbon 1. Primary (1◦) Carbon connected to one carbon atoms. 2. Secondary (2◦) Carbon connected to two carbon atoms. 3. Tertiary (3◦) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the

two different structures of C4H10

C

H

C

H

H

H C C

H

HH H

H

H

Butane, C4H10

Primary carbon = 2Secondary carbon = 2 Tertiary carbon =

Page 18: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

E. Types of carbon 1. Primary (1◦) Carbon connected to one carbon atoms. 2. Secondary (2◦) Carbon connected to two carbon atoms. 3. Tertiary (3◦) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the

two different structures of C4H10

C

H

C

H

H

H C C

H

HH H

H

H

Butane, C4H10

Primary carbon = 2Secondary carbon = 2 Tertiary carbon = ?

Page 19: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

G. Types of carbon 1. Primary (1◦) Carbon connected to one carbon atoms. 2. Secondary (2◦) Carbon connected to two carbon atoms. 3. Tertiary (3◦) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the

two different structures of C4H10

C

H

C

H

H

H C C

H

HH H

H

H

Butane, C4H10

Primary carbon = 2Secondary carbon = 2 Tertiary carbon = 0

Page 20: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

E. Types of carbon 1. Primary (1◦) Carbon connected to one carbon atoms. 2. Secondary (2◦) Carbon connected to two carbon atoms. 3. Tertiary (3◦) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the

two different structures of C4H10

C

H

C

H

H

H C H

H

HC H

H

H

Primary carbon = ?Secondary carbon = Tertiary carbon =

Isobutane C4H10

Page 21: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

G. Types of carbon 1. Primary (1◦) Carbon connected to one carbon atoms. 2. Secondary (2◦) Carbon connected to two carbon atoms. 3. Tertiary (3◦) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the

two different structures of C4H10

C

H

C

H

H

H C H

H

HC H

H

H

Primary carbon = 3Secondary carbon = ? Tertiary carbon =

Isobutane C4H10

Page 22: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

E. Types of carbon 1. Primary (1◦) Carbon connected to one carbon atoms. 2. Secondary (2◦) Carbon connected to two carbon atoms. 3. Tertiary (3◦) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the

two different structures of C4H10

C

H

C

H

H

H C H

H

HC H

H

H

Primary carbon = 3Secondary carbon = 0 Tertiary carbon = ?

Isobutane C4H10

Page 23: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

G. Types of carbon 1. Primary (1◦) Carbon connected to one carbon atoms. 2. Secondary (2◦) Carbon connected to two carbon atoms. 3. Tertiary (3◦) Carbon connected to three carbon atoms. 4. How many primary, secondary, and tertiary carbons in the

two different structures of C4H10

C

H

C

H

H

H C H

H

HC H

H

H

Primary carbon = 3Secondary carbon = 0 Tertiary carbon = 1

Isobutane C4H10

Page 24: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

1. Alkanes (Continued)

F. There are two different structures for C4H 10 called isomers, because they contain different types of carbon.

Structure 1

Structure 2

C

H

C

H

H

H C H

H

HC H

H

H

Isobutane, C4H10

C

H

C

H

H

H C C

H

HH H

H

H

Butane, C4H10

Page 25: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Constitutional Isomers (Structural Isomers) are different compounds of the same formula. The different structures from the previous slide for the formula C4H10 is an example of Constitutional isomers.

Isomerism

Page 26: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Constitutional Isomers (Structural Isomers) are different compounds of the same formula. The different structures from the previous slide for the formula C4H10 is an example of Constitutional isomers.

How many isomers are there of an alkane containing five carbons (C5H12)?

Isomerism

Isomer Strategy – Draw Lewis possible different length chains of carbons atoms connected with a covalent bond.

Page 27: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Constitutional Isomers (Structural Isomers) are different compounds of the same formula. The different structures from the previous slide for the formula C4H10 is an example of Constitutional isomers.

How many isomers are there of an alkane containing five carbons (C5H12)?

Isomerism

Isomer Strategy – Draw Lewis possible different length chains of carbons atoms connected with a covalent bond.

C C C C C

Chains of 5 carbon atoms

H

H

HH

H HHH

HH

H H

Page 28: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Isomerism

Chains of 4 carbon atoms

C C C C

HH

H HCH

HH

H H

H

HH

Page 29: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Isomerism

Chains of 4 carbon atoms

C

HH

H HCH

HH

H H

H

HH

Chains of 3 carbon atoms

C

C C C

HHH

H

H

HCH

H

H

H

H

H

C C C

Page 30: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Isomerism

Chains of 4 carbon atoms

C C C C

HH

H HCH

HH

H H

H

HH

Chains of 3 carbon atoms

There are three isomers of C5H12

C

C C C

HHH

H

H

HCH

H

H

H H

H

Page 31: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

NOMENCLATURE1.Common system

a. Works best for low molecular weight hydrocarbonsb. Steps to give a hydrocarbon a common name:

1. Count the total number of carbon atoms in the molecule.

2. Use the Latin root from the following slide that corresponds to the number of carbon atoms followed by the suffix “ane”.

3. Unbranced hydrocarbons use the prefix normal, or n-, 4. Branched hydrocarbons use specific prefixes, as

shown on a subsequent slide

Page 32: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

NOMENCLATURE

Common system Examples

CH C

H

H

H

H

C

H

H

H

1. Give a name for the following compound

Step #1, count the number of carbons and write down the memorized Latin name for that number (next slide)Step #2, since this structure fits the alkane general formula, use the “ane” suffix

propane

Three carbon Latin root

Alkane suffix

Page 33: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Latin Hydrocarbon

RootsNumber of Carbons

LatinRoot

1 meth

2 eth

3 prop

4 but

5 pent

6 hex

7 hept

8 oct

9 non

10 dec

11 undec

Latin Hydrocarbon

RootsNumber of Carbons

LatinRoot

12 dodec

13 tridec

14 tetradec

15 pentadec

16 hexadec

17 heptadec

18 octadec

19 nonadec

20 eicos

21 unicos

22 doicos

C

H

H

H

C

H

C

H

HH

C

H

H

H

CH

H

H

C

CH H

C

HH

H H

H

n-butane

isobutane

H C C C H

H C H

H C H

H

H

H

H H

H

Examples

neopentane

Page 34: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

2. Systematic System of Nomenclature (IUPAC)

•Find the longest continuous chain of carbon atoms.•Use a Latin root corresponding to the number of carbons in the longest chain of carbons.•Follow the root with the suffix of “ane” for alkanes•Carbon atoms not included in the chain are named as substituents preceding the root name with Latin root followed by “yl” suffix.•Number the carbons, starting closest to the first branch.•Name the substituent's attached to the chain, using the carbon number as the locator in alphabetical order.•Use di-, tri-, etc., for multiples of same substituent.• If there are two possible chains with the same number of carbons, use the chain with the most substituent's.

Page 35: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Substituent Names (Alkyl groups)

Page 36: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

Which one?

Systematic Nomenclature continued.

Page 37: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

Which one?

Systematic Nomenclature continued.

The one with the most number of substituent's

Page 38: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

Which one?

Systematic Nomenclature continued.

The one with the least number of substituent's

The top structure has four substituent's and the bottom has threesubstituent's.

Page 39: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

Which one?

Systematic Nomenclature continued.

The one with the least number of substituent's

The top structure has four substituent's and the bottom has threesubstituent's.

Name = ?

Page 40: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

Which one?

Systematic Nomenclature continued.

The one with the most number of substituent's

The top structure has four substituent's and the bottom has threesubstituent's.

Name = ? heptane

Page 41: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

C

CH3

CH2

CH3

CH CH2 CH2 CH3

CH CH2 CH3H3C

H3C

Which one?

Systematic Nomenclature continued.

The one with the least number of substituent's

The top structure has four substituent's and the bottom has threesubstituent's.

Name = 3,3,5-trimethyl-4-propylheptane

Page 42: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

CHH3C

CH3

CH

CH2CH3

CH2 CH2 CH

CH3

CH3

Another Example:

Name = 3-ethyl-2,6-dimethylheptane

Page 43: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

CHH3C

CH3

CH

CH2CH3

CH2 CH2 CH

CH3

CH3

Another Example:

Name = 3-ethyl-2,6-dimethylheptane

Notice substituent's are in alphabetical order; di, tri, etc. do not participate in the alphabetical order

Page 44: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Line StructuresA quicker way to write structures'

CHH3C

CH3

CH

CH2CH3

CH2 CH2 CH

CH3

CH3 (Condensed Structure)

(A line structure of the above condensed structure)

ethyl

methyl

methyl

Page 45: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Complex Substituent's•If the branch has a branch, number the carbons from the point of attachment.•Name the branch off the branch using a locator number.•Parentheses are used around the complex branch name.

1-methyl-3-(1,2-dimethylpropyl)cyclohexane

12

13

Page 46: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Alkane Physical PropertiesSolubility: hydrophobic (not water soluble)Density: less than 1 g/mL (floats on water)

Boiling points increase with increasing carbons (little less for branched chains) due to dispersion forces being larger.

Melting points increase with increasing carbons (less for odd-number of carbons).

Page 47: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Boiling Points of AlkanesBranched alkanes have less surface area contact,so weaker intermolecular forces.

Page 48: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Melting Points of AlkanesBranched alkanes pack more efficiently into a crystalline structure, so have higher m.p.

Page 49: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Reactions of AlkanesI. Combustion reaction

CH

H

H

H + O2

heatCO2 + H2O

+ O2

heatCO2 + H2O

II. Cracking reactionheat

catalyst

+

III. Halogenation reaction (substitution reaction)

+ Cl2

+ HCl+

Cl Cl

Butane 2-chlorobutane 1-chlorobutane

sun

Page 50: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Sample problem: Which isomer of C5H12 has the most monochloro isomers?

Problem solving process:Step 1 draw the isomers of C5H12

Step 2 react each isomer with chlorineStep 3 count the products

Page 51: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Sample problem: Which isomer of C5H12 has the most monochloro isomers?

Problem solving process:Step 1 draw the isomers of C5H10

Step 2 react each isomer with chlorineStep 3 count the products

+ Cl2

+ Cl2

+ Cl2

Page 52: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Sample problem: Which isomer of C5H12 has the most monochloro isomers?

Problem solving process:Step 1 draw the isomers of C5H10

Step 2 react each isomer with chlorineStep 3 count the products

+ Cl2

+ Cl2

+ Cl2

Cl

Cl

Cl

+ +

2-chloropentane 1-chloropentane 3-chloropentane

Page 53: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Sample problem: Which isomer of C5H12 has the most monochloro isomers?

Problem solving process:Step 1 draw the isomers of C5H10

Step 2 react each isomer with chlorineStep 3 count the products

+ Cl2

+ Cl2

+ Cl2

Cl

Cl

Cl

+ +

2-chloropentane 1-chloropentane 3-chloropentane

Cl

ClCl

Cl

1-chloro-3-methylbutane 2-chloro-3-methylbutane 2-chloro-2-methylbutane 1-chloro-2-methylbutae

Page 54: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Sample problem: Which isomer of C5H12 has the most monochloro isomers?

Problem solving process:Step 1 draw the isomers of C5H10

Step 2 react each isomer with chlorineStep 3 count the products

+ Cl2

+ Cl2

+ Cl2

Cl

Cl

Cl

+ +

2-chloropentane 1-chloropentane 3-chloropentane

Cl

ClCl

Cl

1-chloro-3-methylbutane 2-chloro-3-methylbutane 2-chloro-2-methylbutane 1-chloro-2-methylbutae

Cl

1-chloro-2,2-dimethylpropane

Page 55: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Sample problem: Which isomer of C5H12 has the most monochloro isomers?

Problem solving process:Step 1 draw the isomers of C5H10

Step 2 react each isomer with chlorineStep 3 count the products

+ Cl2

+ Cl2

+ Cl2

Cl

Cl

Cl

+ +

2-chloropentane 1-chloropentane 3-chloropentane

Cl

ClCl

Cl

1-chloro-3-methylbutane 2-chloro-3-methylbutane 2-chloro-2-methylbutane 1-chloro-2-methylbutae

Cl

1-chloro-2,2-dimethylpropane

Winner!

Page 56: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Conformers of Alkanes

•Structures resulting from the free rotation of a C-C single bond•May differ in energy. The lowest-energy conformer is most prevalent.•Molecules constantly rotate through all the possible conformations.

Page 57: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Ethane ConformersStaggered conformer has lowest energy.Dihedral angle = 60 degrees

model

H

H

H

H

H H

Newmanprojection sawhorse

Dihedral angle

Page 58: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Ethane Conformers (2)Eclipsed conformer has highest energyDihedral angle = 0 degrees

=>

Page 59: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Conformational Analysis•Torsional strain: resistance to rotation.•For ethane, only 12.6 kJ/mol

=>

Page 60: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Propane ConformersNote slight increase in torsional straindue to the more bulky methyl group.

Page 61: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Butane Conformers C2-C3Highest energy has methyl groups eclipsed.Steric hindranceDihedral angle = 0 degrees

=>totally eclipsed (methyl groups)

Page 62: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Butane Conformers (2)Lowest energy has methyl groups anti.Dihedral angle = 180 degrees

=>Staggered-anti

Page 63: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Butane Conformers (3)•Methyl groups eclipsed with hydrogens•Higher energy than staggered conformer•Dihedral angle = 120 degrees

=>Eclipsed (hydrogen and methyl)

Page 64: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Butane Conformers (4)•Gauche, staggered conformer•Methyls closer than in anti conformer•Dihedral angle = 60 degrees

=>Staggered-gauche

Page 65: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Conformational Analysis

Page 66: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Cycloalkanes

•Rings of carbon atoms (-CH2- groups)

•Formula: CnH2n

•Nonpolar, insoluble in water•Compact shape•Melting and boiling points similar to branched alkanes with same number of carbons•Slightly unsaturated compared to alkanes

Page 67: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Naming Cycloalkanes•Count the number of carbons in the cycle•If the bonds are single then use the suffix “ane”•First substituent in alphabet gets lowest number.•May be cycloalkyl attachment to chain.

cyclopropane cyclobutane cyclopentane cyclohexane cycloheptane

mehtylcyclopropane 1-ethyl-2-methylcyclobutane

CH3 H3CH2C CH3

2-cyclopropylheptane

Page 68: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Cis-Trans Isomerism(a type of stereoisomerism)

Cis: like groups on same side of ringTrans: like groups on opposite sides of ring

Page 69: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Cycloalkane Stability• 6-membered rings most stable• Bond angle closest to 109.5• Angle (Baeyer) strain• Measured by heats of combustion per -CH2 -

Page 70: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Heats of Combustion/CH2 Alkane + O2 CO2 + H2O

658.6

697.1 686.1664.0 663.6 kJ/mol

662.4658.6 kJ

Long-chain

Page 71: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Cyclopropane

• Large ring strain due to angle compression• Very reactive, weak bonds

=>

Page 72: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Cyclopropane (2)

Torsional strain because of eclipsed hydrogens

Page 73: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Cyclobutane• Angle strain due to compression• Torsional strain partially relieved by ring puckering

=>

Page 74: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Cyclopentane• If planar, angles would be 108, but all hydrogens would be eclipsed.• Puckered conformer reduces torsional strain.

Page 75: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Cyclohexane• Combustion data shows it’s unstrained.• Angles would be 120, if planar.

• The chair conformer has 109.5 bond angles and all hydrogen's are staggered.

• No angle strain and no torsional strain.

Page 76: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Chair Conformer

Page 77: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Boat Conformer

Page 78: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Conformational Energy

Page 79: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Axial and Equatorial Positions

Page 80: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Monosubstituted Cyclohexanes

Page 81: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

1,3-Diaxial Interactions

Page 82: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Disubstituted Cyclohexanes

Page 83: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Cis-Trans IsomersBonds that are cis, alternate axial-equatorial around the ring.

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CH3

CH3

One axial, one equatorial

Page 84: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

Bulky Groups• Groups like t-butyl cause a large energy difference between the axial and equatorial conformer. • Most stable conformer puts t-butyl equatorial regardless of other substituents.

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Page 85: Chemistry 122 Introductory Organic Chemistry Spring Quarter 2015 Dr. Thomas H. Schultz

End of Chapter 2