Chemical Equilibrium Labs p208. Thymol Blue Equilibrium Thymol Blue (Yellow Form) Thymol Blue (Yellow Form)   Thymol Blue + H + (Blue)

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<ul><li> Slide 1 </li> <li> Chemical Equilibrium Labs p208 </li> <li> Slide 2 </li> <li> Thymol Blue Equilibrium Thymol Blue (Yellow Form) Thymol Blue (Yellow Form) Thymol Blue + H + (Blue) </li> <li> Slide 3 </li> <li> Thymol Blue Equilibrium Stresses and Results Thymol Blue (Yellow Form) Thymol Blue (Yellow Form) Thymol Blue + H + (Blue) Green Colour 1.Stress: Add HCl (H + ). Result: Green Colour Yellow Colour 2.Stress: Add more HCl. Results: Yellow Colour 3.Stress: Add NaOH (OH - ) reacts with H + to form H 2 O) Green Colour Result: Green Colour Blue Colour 4.Stress: Add more NaOH. Results: Blue Colour </li> <li> Slide 4 </li> <li> Equilibrium Involving Thiocyanatoiron III Ion Amber Fe(H 2 O) 6 3+ (Amber) + SCN 1- Fe(SCN)(H 2 O) 5 2+ (D. Red) </li> <li> Slide 5 </li> <li> Equilibrium Involving Thiocyanatoiron III Ion Amber Fe(H 2 O) 6 3+ (Amber) + SCN 1- Fe(SCN)(H 2 O) 5 2+ (D. Red) a)Add KCl (Fe 3+ forms an insoluble ppt [FeCl 3 ] with Cl 1- ) Amber Colour Result: Amber Colour b)Add Fe(NO 3 ) 3 Possible Stresses: Fe +3 and NO 3 Darker Red Result: Darker Red c)Add KSCN Possible Stresses: K + and SCN - Darker Red Result: Darker Red d)Add NaOH (Fe 3+ forms ins. ppt [Fe(OH) 3 ] with OH 1- ) First OrangeAmber Colour Result: First Orange and then Amber Colour </li> <li> Slide 6 </li> <li> Equilibrium Involving Cobalt II Complexes Co(H 2 O) 6 2+ Co(H 2 O) 4 Cl 2 Co(H 2 O) 6 2+ (aq) + 2 Cl 1- (aq) Co(H 2 O) 4 Cl 2 (aq) + H 2 O () Purple Colour a) Add HCl. Result: Purple Colour Pink Colour b) Add H 2 O. Result: Pink Colour Purple Colour c) Add Heat. Result: Purple Colour Pink Colour d) Remove Heat (Cool). Result: Pink Colour </li> <li> Slide 7 </li> <li> Equilibrium Involving Chromate and Dichromate Ions Cr 2 O 7 2- 2 CrO 4 2- Cr 2 O 7 2- (aq) + 2 OH 1- (aq) 2 CrO 4 2- (aq) + H 2 O () (Orange)(Yellow) (Orange) (Yellow) </li> <li> Slide 8 </li> <li> Equilibrium Involving Chromate and Dichromate Ions Cr 2 O 7 2- 2 CrO 4 2- Cr 2 O 7 2- (aq) + 2 OH 1- (aq) 2 CrO 4 2- (aq) + H 2 O () (Orange)(Yellow) (Orange) (Yellow) a)Add NaOH. Result: Orange turns Yellow (yellow stays yellow) b)Add HCl. Result: Yellow turns Orange (orange stays orange) c)Add K 2 CrO 4 Result: Colour in both is Orange d)Add K 2 Cr 2 O 7 Result: Colour in both is Yellow e)Add Ba(NO 3 ) 2 (BaCrO 4 is insoluble while BaCr 2 O 7 is soluble) Result: Chr. sol. Yellow, Dichr. Sol. Orange Ba(NO 3 ) 2 in beaker Ba(NO 3 ) 2 in beaker K 2 CrO 4 in graduate K 2 CrO 4 in graduate </li> <li> Slide 9 </li> <li> Equilibrium With Copper II Complexes Cu(H 2 O) 4 2+ Cu(H 2 O) 4 2+ (aq) + 4 NH 4 + + 4 OH - Cu(NH 3 ) 4 2+ (aq) + 4 H 2 O (Light Blue) (Light Blue) (Deep Blue) </li> <li> Slide 10 </li> <li> Equilibrium With Copper II Complexes Cu(H 2 O) 4 2+ Cu(H 2 O) 4 2+ (aq) + 4 NH 4 + + 4 OH - Cu(NH 3 ) 4 2+ (aq) + 4 H 2 O (Light Blue) (Light Blue) (Deep Blue) a)Add NH 3 (aq) (NH 3 (aq) is NH 4 + + OH - ) Result: The light blue colour turns a deeper blue Yet Deeper Blue b)Add more NH +. Result: The colour Yet Deeper Blue deep BlueLight Blue c)Add HCl (Yields H + and Cl - ). The deep Blue Light Blue </li> <li> Slide 11 </li> <li> End of Lab Results </li> <li> Slide 12 </li> <li> A A </li> </ul>

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