chem 373- lecture 6: operators and quantum mechanics

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  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    Lecture 6: Operators and Quantum

    Mechanics

    The material in this lecture covers the following in Atkins.

    11.5 The informtion of a wavefunction

    (c) Operators

    Lecture on-line

    Operators in quantum mechanics (PDF)

    Operators in quantum mechanics (HTML)

    Operators in Quantum mechanics (PowerPoint)

    Handout (PDF)Assigned Questions

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    Tutorials on-line

    Reminder of the postulates of quantum mechanicsThe postulates of quantum mechanics (This is the writeup for Dry-lab-II)(

    This lecture has covered postulate 3)

    Basic concepts of importance for the understanding of the postulates

    Observables are Operators - Postulates of Quantum Mechanics

    Expectation Values - More PostulatesForming Operators

    Hermitian Operators

    Dirac Notation

    Use of Matricies

    Basic math backgroundDifferential Equations

    Operator Algebra

    Eigenvalue Equations

    Extensive account of Operators

    Historic development of quantum mechanics from classical mechanics

    The Development of Classical Mechanics

    Experimental Background for Quantum mecahnics

    Early Development of Quantum mechanics

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    Audio-visuals on-lineEarly Development of Quantum mechanics

    Audio-visuals on-line

    Postulates of Quantum mechanics (PDF) (simplified version from Wilson)

    Postulates of Quantum mechanics (HTML) (simplified version from Wilson)

    Postulates of Quantum mechanics (PowerPoint ****)(simplified version from Wilson)

    Slides from the text book (From the CD included in Atkins ,**)

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    (Ia) A Quantum mechanical system is specifiedby the statefunction ( )x

    ( ) (Ib x) contains all

    information about the system we can know

    The state function

    We now have

    Operators and Quantum Mechanics

    (Ic) A system described by thestate function H ( (x) = E x)has exactly the energy E

    Review

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    O

    X

    We have seen that a ' free' particle movingin one dimension in a constant (zero) potential

    has the Hamiltonian

    =h2 2

    22m xE

    ((

    x)x)

    H

    m x= h

    2 2

    22

    The Schrodinger equation is

    with the general solution:

    ( ) exp exp x A Bikx ikx= +

    and energies E =

    2h k

    m

    2

    2

    Operators and Quantum Mechanics

    Review

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    How does the state function (x, t) give usinformation about an observable other thanthe energy such as the position or the momentum ?

    Any observable ' ' can be expressed in classical physicsin terms of x,y, z and p .x

    , ,p py z

    Examples :

    = x, p p T, V(x), Ex x2 , , ,vx

    Operators and Quantum Mechanics

    Good question

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    Classical Mechanics Quantum Mechanics

    ;

    ;

    ;

    x p x x pi x

    y p y y pi y

    z p z z pi z

    x x

    y y

    z z

    > >

    > >

    > >

    h

    h

    h

    We can construct the corresponding operatorfrom the substitution:

    as (x,y,z, i i i

    , , )h h h

    ddx

    ddy

    ddz

    Such as:

    = x, p p T, V(x), Ex x2

    , , ,

    vx

    Operators and Quantum Mechanics Review

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    n n n=

    For an observable with the corresponding

    operator we have the eigenvalue equation :

    Operators and Quantum Mechanics

    (IIIa). The meassurement of the quantity represented byhas as the o n l y outcome one of the values

    n n = 1,2,3 ....

    (IIIb). If the system is in a state described by

    a meassurement of will result in thevalue

    n

    n

    Im tanpor t news

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    Quantum mechanical principle Operators..

    we can solve the eigenvalue problem

    n n n=

    For any such operator

    We obtain eigenfunctions and eigenvalues

    The only possible values that can arise from measurementsof the physical observable are the eigenvalues n

    Postulate 3

    Im tanpor t news

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    The x - component 'p ' of the linear momentumx

    r r r rp p e p e p ex x y y z z= + +

    Is represented by the operator pi

    x =h

    x

    With the eigenfunctions Exp ikx[ ] and eigenvalue kh

    hh

    i

    Exp ikxExp ikx

    x

    = k[ ]

    [ ]

    We note that k can take any value

    > k >

    Operators and Quantum MechanicsIm tanpor t news

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    ( ) exp exp x A Bikx ikx= + and energies E =

    2h k

    m

    2

    2

    For A = 0

    =( ) expx B

    ikx

    this wavefunction is also an eigenfunction to px

    With eigenvalue for p of - kx h

    Thus describes a particle of energy E =

    and momentum p note E =

    P

    2m as it must be.

    -

    2

    x

    x2

    ( )

    ;

    xk

    m

    k

    h

    h

    2

    2

    =

    This system corresponds to a particlemoving with constant velocity

    v

    p

    m - k/mxx

    = =h

    We know nothing about its positionsince | (x)|2 = B

    Operators and Quantum Mechanics New insight

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    ( ) exp exp x A Bikx ikx= + and energies E =

    2h k

    m

    2

    2

    For B = 0

    + =( ) expx A

    ikx

    this wavefunction is also an eigenfunction to px

    With eigenvalue for p of kx h

    Thus describes a particle of energy E =

    and momentum p note E =P

    2m

    as it must be.

    2

    xx2

    ( )

    ;

    xk

    m

    k

    h

    h

    2

    2

    =

    This system corresponds to a particlemoving with constant velocity

    vp

    m

    k/mxx= = h We know nothing about its position

    since | (x)|2 = B

    Operators and Quantum Mechanics New insight

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    What about : ?( ) exp expx A Bikx ikx = +

    It is not an eigenfunction to p since :x

    exp expexp exp

    p (x) = A i B ix

    h h

    h h

    d

    dx

    d

    dxA k B k

    ikx ikx

    ikx ikx+

    =

    How can we find

    p in this case ?x

    Operators and Quantum Mechanics New insight

  • 8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics

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    A linear operator A will have a set of

    eigenfunctions f {n = 1,2,3..etc}

    and associated eigenvalues k such that :n

    n

    ( )x

    The set of eigenfunction {fis orthonormal :

    f f

    n

    ispace

    j

    ( ), ..}

    ( ) ( )*

    x n

    x x dxall

    ij

    =

    =

    1

    ( ) ( )Af fn nx k xn=

    = o if i j

    = 1 if i = j

    Quantum mechanical principles..Eigenfunctions

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    Quantum mechanical principles..Eigenfunctions

    e ei j ij =

    ei

    ei

    ei

    An example of an orthonormal set is the Cartesian unit vectors

    An example of an orthonormal function set is

    nL

    n x

    L(x) =

    n = 1,2,3,4,5....

    1sin

    no

    L

    m nmx x( ) ( )* =

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    That is, any function g(x) thatdepends on the same variablesas the eigenfunctions can be written

    g(x) = ani=1

    allf xn( )

    where

    a f g(x)n n*

    space

    = ( )x dxall

    Quantum mechanical principles..Eigenfunctions

    The set of eigenfunction {fforms a complete set.

    n( ), ..}x n = 1

    ei

    ei

    ei

    rei ; i = 1,2,3 form a complete set

    For any vector vr

    v v e e v e e v e e= + + ( ) ( ) ( )r r r r r r r r r

    1 1 2 2 3 3

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    we can show that : a f g(x)n nV

    = ( )*x dx

    In the expansion: g(x) = a (1)ii=1

    all

    f xi( )

    from the orthonormality : f fi

    V

    j( ) ( )*x x dx ij =

    Quantum mechanical principles..Eigenfunctions

    g(x) = a f (x) g(x)dx = aii=1

    all

    n

    *

    ii=1

    all

    f x f x f x dxi V V n i( ) ( ) ( )

    *

    A multiplication by f (x) on both sides followed by

    integration affordsn

    or : a g(x)fn nspace

    = ( )x dxall ij

    A multiplication by f (x) on both sides followed by

    integration affordsn

    or : a g(x)fn nspace

    = ( )*x dxall

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    is a linear combinationof two eigenfunctions to px( ) exp exp

    x A Bikx ikx= +

    How can we find

    p in this case ?x

    Operators and Quantum Mechanics

    p kx =h

    p kx = h

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    1. Postulate 3

    For an observable with the corresponding operatorwe have the eigenvalue equation :

    ( )

    n n n

    n

    i

    =The meassurement of the quantity represented by

    has as the o n l y outcome one of the values n = 1,2,3 ....(ii) If the system is in a state described by

    a meassurement of will result in the valuen

    n

    What you should learn from this lecture

    Illustrations

    x A

    x A

    mx

    x

    ikx

    ikx

    :

    ( ) exp

    ( ) exp

    )

    ( )

    ( )

    +

    +

    ==

    is an eigenfunction to p with eigenvalue k

    is an eigenfunction to p with eigenvalue - k

    Both are eigenfunctions to the Hamiltonian for a free particle

    H = (p with eigenvalues E = k2m

    represents a free particle of momentum k

    represents a free particle of momentum - k

    x

    x

    2 x 2

    h

    h

    h h

    h

    h

    2 2

    2

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    What you should learn from this lecture

    2. Postulate 4.

    The set of eigenfunction {fforms a complete set.That is, any function g(x) that depends on the samevariables as the eigenfunctions can be written :

    g(x) = a where

    a g(x)f

    n

    ni=1

    all

    n n

    space

    ( ), ..}

    ( )

    ( )

    x n

    f x

    x dx

    n

    all

    =

    =

    1