chem 373- lecture 6: operators and quantum mechanics
TRANSCRIPT
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8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics
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Lecture 6: Operators and Quantum
Mechanics
The material in this lecture covers the following in Atkins.
11.5 The informtion of a wavefunction
(c) Operators
Lecture on-line
Operators in quantum mechanics (PDF)
Operators in quantum mechanics (HTML)
Operators in Quantum mechanics (PowerPoint)
Handout (PDF)Assigned Questions
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Tutorials on-line
Reminder of the postulates of quantum mechanicsThe postulates of quantum mechanics (This is the writeup for Dry-lab-II)(
This lecture has covered postulate 3)
Basic concepts of importance for the understanding of the postulates
Observables are Operators - Postulates of Quantum Mechanics
Expectation Values - More PostulatesForming Operators
Hermitian Operators
Dirac Notation
Use of Matricies
Basic math backgroundDifferential Equations
Operator Algebra
Eigenvalue Equations
Extensive account of Operators
Historic development of quantum mechanics from classical mechanics
The Development of Classical Mechanics
Experimental Background for Quantum mecahnics
Early Development of Quantum mechanics
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Audio-visuals on-lineEarly Development of Quantum mechanics
Audio-visuals on-line
Postulates of Quantum mechanics (PDF) (simplified version from Wilson)
Postulates of Quantum mechanics (HTML) (simplified version from Wilson)
Postulates of Quantum mechanics (PowerPoint ****)(simplified version from Wilson)
Slides from the text book (From the CD included in Atkins ,**)
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(Ia) A Quantum mechanical system is specifiedby the statefunction ( )x
( ) (Ib x) contains all
information about the system we can know
The state function
We now have
Operators and Quantum Mechanics
(Ic) A system described by thestate function H ( (x) = E x)has exactly the energy E
Review
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O
X
We have seen that a ' free' particle movingin one dimension in a constant (zero) potential
has the Hamiltonian
=h2 2
22m xE
((
x)x)
H
m x= h
2 2
22
The Schrodinger equation is
with the general solution:
( ) exp exp x A Bikx ikx= +
and energies E =
2h k
m
2
2
Operators and Quantum Mechanics
Review
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How does the state function (x, t) give usinformation about an observable other thanthe energy such as the position or the momentum ?
Any observable ' ' can be expressed in classical physicsin terms of x,y, z and p .x
, ,p py z
Examples :
= x, p p T, V(x), Ex x2 , , ,vx
Operators and Quantum Mechanics
Good question
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Classical Mechanics Quantum Mechanics
;
;
;
x p x x pi x
y p y y pi y
z p z z pi z
x x
y y
z z
> >
> >
> >
h
h
h
We can construct the corresponding operatorfrom the substitution:
as (x,y,z, i i i
, , )h h h
ddx
ddy
ddz
Such as:
= x, p p T, V(x), Ex x2
, , ,
vx
Operators and Quantum Mechanics Review
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n n n=
For an observable with the corresponding
operator we have the eigenvalue equation :
Operators and Quantum Mechanics
(IIIa). The meassurement of the quantity represented byhas as the o n l y outcome one of the values
n n = 1,2,3 ....
(IIIb). If the system is in a state described by
a meassurement of will result in thevalue
n
n
Im tanpor t news
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Quantum mechanical principle Operators..
we can solve the eigenvalue problem
n n n=
For any such operator
We obtain eigenfunctions and eigenvalues
The only possible values that can arise from measurementsof the physical observable are the eigenvalues n
Postulate 3
Im tanpor t news
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The x - component 'p ' of the linear momentumx
r r r rp p e p e p ex x y y z z= + +
Is represented by the operator pi
x =h
x
With the eigenfunctions Exp ikx[ ] and eigenvalue kh
hh
i
Exp ikxExp ikx
x
= k[ ]
[ ]
We note that k can take any value
> k >
Operators and Quantum MechanicsIm tanpor t news
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8/3/2019 Chem 373- Lecture 6: Operators and Quantum Mechanics
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( ) exp exp x A Bikx ikx= + and energies E =
2h k
m
2
2
For A = 0
=( ) expx B
ikx
this wavefunction is also an eigenfunction to px
With eigenvalue for p of - kx h
Thus describes a particle of energy E =
and momentum p note E =
P
2m as it must be.
-
2
x
x2
( )
;
xk
m
k
h
h
2
2
=
This system corresponds to a particlemoving with constant velocity
v
p
m - k/mxx
= =h
We know nothing about its positionsince | (x)|2 = B
Operators and Quantum Mechanics New insight
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( ) exp exp x A Bikx ikx= + and energies E =
2h k
m
2
2
For B = 0
+ =( ) expx A
ikx
this wavefunction is also an eigenfunction to px
With eigenvalue for p of kx h
Thus describes a particle of energy E =
and momentum p note E =P
2m
as it must be.
2
xx2
( )
;
xk
m
k
h
h
2
2
=
This system corresponds to a particlemoving with constant velocity
vp
m
k/mxx= = h We know nothing about its position
since | (x)|2 = B
Operators and Quantum Mechanics New insight
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What about : ?( ) exp expx A Bikx ikx = +
It is not an eigenfunction to p since :x
exp expexp exp
p (x) = A i B ix
h h
h h
d
dx
d
dxA k B k
ikx ikx
ikx ikx+
=
How can we find
p in this case ?x
Operators and Quantum Mechanics New insight
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A linear operator A will have a set of
eigenfunctions f {n = 1,2,3..etc}
and associated eigenvalues k such that :n
n
( )x
The set of eigenfunction {fis orthonormal :
f f
n
ispace
j
( ), ..}
( ) ( )*
x n
x x dxall
ij
=
=
1
( ) ( )Af fn nx k xn=
= o if i j
= 1 if i = j
Quantum mechanical principles..Eigenfunctions
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Quantum mechanical principles..Eigenfunctions
e ei j ij =
ei
ei
ei
An example of an orthonormal set is the Cartesian unit vectors
An example of an orthonormal function set is
nL
n x
L(x) =
n = 1,2,3,4,5....
1sin
no
L
m nmx x( ) ( )* =
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That is, any function g(x) thatdepends on the same variablesas the eigenfunctions can be written
g(x) = ani=1
allf xn( )
where
a f g(x)n n*
space
= ( )x dxall
Quantum mechanical principles..Eigenfunctions
The set of eigenfunction {fforms a complete set.
n( ), ..}x n = 1
ei
ei
ei
rei ; i = 1,2,3 form a complete set
For any vector vr
v v e e v e e v e e= + + ( ) ( ) ( )r r r r r r r r r
1 1 2 2 3 3
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we can show that : a f g(x)n nV
= ( )*x dx
In the expansion: g(x) = a (1)ii=1
all
f xi( )
from the orthonormality : f fi
V
j( ) ( )*x x dx ij =
Quantum mechanical principles..Eigenfunctions
g(x) = a f (x) g(x)dx = aii=1
all
n
*
ii=1
all
f x f x f x dxi V V n i( ) ( ) ( )
*
A multiplication by f (x) on both sides followed by
integration affordsn
or : a g(x)fn nspace
= ( )x dxall ij
A multiplication by f (x) on both sides followed by
integration affordsn
or : a g(x)fn nspace
= ( )*x dxall
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is a linear combinationof two eigenfunctions to px( ) exp exp
x A Bikx ikx= +
How can we find
p in this case ?x
Operators and Quantum Mechanics
p kx =h
p kx = h
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1. Postulate 3
For an observable with the corresponding operatorwe have the eigenvalue equation :
( )
n n n
n
i
=The meassurement of the quantity represented by
has as the o n l y outcome one of the values n = 1,2,3 ....(ii) If the system is in a state described by
a meassurement of will result in the valuen
n
What you should learn from this lecture
Illustrations
x A
x A
mx
x
ikx
ikx
:
( ) exp
( ) exp
)
( )
( )
+
+
==
is an eigenfunction to p with eigenvalue k
is an eigenfunction to p with eigenvalue - k
Both are eigenfunctions to the Hamiltonian for a free particle
H = (p with eigenvalues E = k2m
represents a free particle of momentum k
represents a free particle of momentum - k
x
x
2 x 2
h
h
h h
h
h
2 2
2
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What you should learn from this lecture
2. Postulate 4.
The set of eigenfunction {fforms a complete set.That is, any function g(x) that depends on the samevariables as the eigenfunctions can be written :
g(x) = a where
a g(x)f
n
ni=1
all
n n
space
( ), ..}
( )
( )
x n
f x
x dx
n
all
=
=
1