chem 161.1 ex12

35
EXERCISE 12 PURITY DETERMINATION OF POLYSACCHARIDES Jovale Vincent V. Tongco CHEM 161.1 1L

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Page 1: CHEM 161.1 ex12

EXERCISE 12

PURITY

DETERMINATION OF

POLYSACCHARIDES

Jovale Vincent V. Tongco

CHEM 161.1 1L

Page 2: CHEM 161.1 ex12

Polysaccharides

Are polymers of

monosaccharides

Formed by three or more

monosaccharides

Page 3: CHEM 161.1 ex12

Polymers of D-Glucose

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Common Polysaccharides

CELLULOSE Is a straight chain

polymer of D-glucose

Monomeric units are

connected together

by β-1,4 linkages.

STARCHMixed polysaccharide with

two main components, -

amylose and amylopectin

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Adopt a helical structure

Joined together by -1,4 linkages.

Typical chain lengths are approximately 1000 units.

-Amylose

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Also linked by -1,4 linkages

Is a highly branched polymer of glucose found in PLANTS.

Branching takes place with -1,6 bonds occurring every 24 to 30 glucose units.

Amylopectin

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Counterpart of amylopectin in ANIMALS

Extensive branching that occurs every 8 to 12 glucose units

Highest concentration found in liver and muscle cells.

Glycogen

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Purity of Sample

From Nelson’s Assay for glucose

Calculated to be 6.17 µmoles/mg

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Percent Purity

% Purity = actual µmoles glucose/mg of glycogen x 100

theoretical µmoles glucose/mg of glycogen

Where:

Actual µmoles glucose = µmoles glucose in the hydrolyzed

sample x DF

Page 12: CHEM 161.1 ex12

Percent Purity

Theoretical µmol glucose = mass of glycogen x 180 x 1 x 1000

mg glycogen 162 180_______ _

mass of glycogen (mg)

Where:

Mass of glycogen is the amount of glycogen used in the

experiment (50 mg)

Page 13: CHEM 161.1 ex12

The Conversions

The molar mass of free glucose is

180 g/mole

The molar mass of glucose residue

is 162 g/mole

Page 14: CHEM 161.1 ex12

The Conversions

The factor 180/162 – converts the mass of glucose residue into mass of free glucose

The factor 1/ 180 – converts amount of free glucose from mg to mmoles

Factor 1000- converts mmoles to moles

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Percent Purity

Substituting the amount of isolate:

Theoretical µmol glucose = 50 x 180 x 1 x 1000

mg glycogen 162 180_______ _

50

Theoretical µmol glucose = 6.17

mg glycogen

% purity

Page 16: CHEM 161.1 ex12

The Theoretical µmol glucose/

mg glycogen is the same for

amylopectin and glycogen

since structurally glycogen is

very similar to amylopectin

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Standard Curve

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Acid Hydrolysis of Glycogen

Back Actual

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Acid Hydrolysis of Amylopectin

Back

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Dilution Factor

Actual glucose concentrations after

hydrolysis of glycogen and amylopectin

were determined by multiplying

interpolated glucose concentration to the

DF.

DF = (10/0.4)(1/0.5)

= 50

Page 24: CHEM 161.1 ex12

Sample Calculations

Calculating glucose concentration after

hydrolysis:

Use dilution factor (DF=50)

Example:

glucose concn = -0.05165 µmole glucose/ml (1/0.5)(10/0.4)

= -0.78236 µmol glucose/ml glycogen stock

Glycogen

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Upon Acid Hydrolysis

Polysaccharide Incubation

timeCorrected

Absorbance

Glucose

conc. after

hydrolysis

Glycogen 90 0.144 0.189189

Amylopectin 90 0.433 0.600284

Page 26: CHEM 161.1 ex12

Actual mol of glucose

Polysaccharide Glucose conc.

after

hydrolysis

DF Actual moles

after hydrolysis

Glycogen 0.189189 50 9.46

Amylopectin 0.600284 50 30.01

Glycogen AmylopectinBack

Page 27: CHEM 161.1 ex12

Actual µmoles glucose/mg of

glycogen

Actual µmoles glucose = mol glucose in

the hydrolyzed sample

For glycogen:

The actual μmoles glucose / mg of glycogen

is 9.46. This is the μmoles glucose in the

hydrolyzate after 90 minutes of heating.

Page 28: CHEM 161.1 ex12

Actual µmoles glucose/mg of

glycogen

For amylopectin:

The actual μmoles glucose / mg of

amylopectin is 30.01. This is the

μmoles glucose in the hydrolyzate

after 90 minutes of heating.

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Note:

In the preparation of glycogen/amylopectin

solution 50 mg glycogen/amylopectin and was

dissolved in 5 mL dH20.

The actual μmoles glucose / mg of glycogen

should be divided by 10

50 mg glycogen / 5 mL = 10 mg glycogen.

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The actual μmoles glucose / mg of

amylopectin should be divided by 10

50 mg amylopectin / 5 mL = 10 mg

amylopectin

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Percent purity

For glycogen isolate

% Purity = 9.46 μmoles glucose / 10 mg glycogen x 100

6.17 μmoles glucose / mg of glycogen

= 15.33 %

Actual Theo

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Percent purity

For amylopectin sample:

% Purity = 30.01 μmoles glucose / 10 mg glycogen x 100

6.17 μmoles glucose / mg of glycogen

= 48.64 %

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Percent purity

Polysaccharide Percent Purity,

%

Glycogen 15.33

Amylopectin 48.64

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The Possible Sources of Errors

Prolong Heating/ Excessive

water evaporation

Limitations of the

spectrophotometric method /

Improper instrument reading

Incomplete hydrolysis

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END