che3165 - tute 1

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1.4-1 P = 2.4mm Hg 1 atm = 760mm Hg P = 2.4/760 = 0.00316 atm 1 atm = 33.90 x 12 in. H2O (@ 4C) P = 2.4/760 atm (33.90 x12) = 1.285 in. H2O P = 2.4mm/(10 -3 mm/µm) = 2400µm Hg 1 atm = 1.01325 Pa P = 2.4/760 (1.01325 x 10 5 Pa/atm) = 320 Pa 1.4-4 Log (12) = -2250 (1/T) + 9.05 1/T = 0.003542586 T = 282.3 K = 9.1 C 1.5-5 W kg H2O 14%wt soluble solids Sugar (1.22kg sugar/kg crushed fruit) M kg mixture Pectin (0.0025kg pectin/kg crushed frt) J kg Jam(67% soluble solids 1000kg of crushed fruit should be used as the basis

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1.4-1P = 2.4mm Hg1 atm = 760mm HgP = 2.4/760 = 0.00316 atm

1 atm = 33.90 x 12 in. H2O (@ 4C)P = 2.4/760 atm (33.90 x12) = 1.285 in. H2OP = 2.4mm/(10-3mm/m) = 2400m Hg

1 atm = 1.01325 PaP = 2.4/760 (1.01325 x 105 Pa/atm) = 320 Pa

1.4-4Log (12) = -2250 (1/T) + 9.051/T = 0.003542586T = 282.3 K = 9.1 C

1.5-5W kg H2O14%wt soluble solidsSugar (1.22kg sugar/kg crushed fruit) M kg mixturePectin (0.0025kg pectin/kg crushed frt)

J kg Jam(67% soluble solids1000kg of crushed fruit should be used as the basisSoluble solids balance:1220 + 0.14(1000) + 2.5 = 0.675J + W(0)J = 2033.5 kg JamBalance over mixer:1220 + 1000 + 2.5 = M = 2222.5kg

Balance over evaporator:W = 189kg water

1.5-8