chapter two measurements in chemistry fundamentals of general, organic & biological chemistry

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Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

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Page 1: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

Chapter Two

Measurements inChemistry

Fundamentals of General, Organic & Biological Chemistry

Page 2: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

2

Stating a Measurement

In every measurement, a number is followed by a unit.

Observe the following examples of measurements:

number + unit35 m

0.25 L 225 lb 3.4 hr

Page 3: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

3

The Metric System (SI)

The metric system is A decimal system

based on 10. Used in most of the

world. Used by scientists

and in hospitals.

Page 4: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

4

Units in the Metric SystemIn the metric and SI systems, a basic unit identifies each type of measurement:

Page 5: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

5

Length Measurement

In the metric system, length is measured in meters using a meter stick.

The metric unit for length is the meter (m).

Page 6: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

6

Volume Measurement

Volume is the space occupied by a substance.

The metric unit of volume is the liter (L).

The liter is slightly bigger than a quart.

A graduated cylinder is used to measure the volume of a liquid.

Page 7: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

7

Mass Measurement

The mass of an object is the quantity of material it contains.

A balance is used to measure mass.

The metric unit for mass is the gram (g).

Page 8: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

8

In each of the following, indicate whether the unit describes 1) length 2) mass or 3) volume. ____ A. A bag of tomatoes is 4.6 kg.

____ B. A person is 2.0 m tall.

____ C. A medication contains 0.50 g Aspirin.

____ D. A bottle contains 1.5 L of water.

Learning Check

Page 9: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

9

In each of the following, indicate whether the unit describes 1) length 2) mass or 3) volume.

2 mass A. A bag of tomatoes is 4.6 kg.

1 length B. A person is 2.0 m tall.

2 mass C. A medication contains 0.50 g

Aspirin.

3 volume D. A bottle contains 1.5 L of water.

Solution

Page 10: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

10

Learning Check

Identify the measurement that has a metric unit. A. John’s height is

1) 1.5 yards 2) 6 feet 3) 2 meters

B. The volume of saline in the IV container is1) 1 liter 2) 1 quart 3) 2 pints

C. The mass of a lemon is1) 12 ounces 2) 145 grams 3) 0.6 pounds

Page 11: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

11

Solution

A. John’s height is

3) 2 meters

B. The volume of saline in the IV container is

1) 1 liter

C. The mass of a lemon is

2) 145 grams

Page 12: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

12

Scientific Notation

A number in scientific notation contains a coefficient and a power of 10.

coefficient power of ten coefficient power of ten

1.5 x 102 7.35 x 10-4

Place the decimal point after the first digit. Indicate the spaces moved as a power of ten.

52 000 = 5.2 x 104 0.00378 = 3.78 x 10-3

4 spaces left 3 spaces right

Page 13: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

13

Learning Check

Select the correct scientific notation for each.

A. 0.000 008

1) 8 x 106 2) 8 x 10-6 3) 0.8 x 10-5

B. 72 000

1) 7.2 x 104 2) 72 x 103 3) 7.2 x 10-4

Page 14: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

14

Solution

Select the correct scientific notation for each.

A. 0.000 008

2) 8 x 10-6

B. 72 000

1) 7.2 x 104

Page 15: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

15

Learning Check

Write each as a standard number.

A. 2.0 x 10-2

1) 200 2) 0.02 3) 0.020

B. 1.8 x 105

1) 180 0002) 0.000018 3) 18 000

Page 16: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

16

Solution

Write each as a standard number.

A. 2.0 x 10-2

3) 0.020

B. 1.8 x 105

1) 180 000

Page 17: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

17

Measured Numbers

You use a measuring tool to determine a quantity such as your height or the mass of an object.

The numbers you obtain are called measured numbers.

Page 18: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

18

. l2. . . . l . . . . l3 . . . . l . . . . l4. . cm

To measure the length of the blue line, we read the markings on the meter stick.

The first digit 2 plus the second digit 2.7

Estimating the third digit between 2.7–2.8gives a final length reported as

2.75 cm

or 2.76 cm

Reading a Meter Stick

Page 19: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

Chapter 01 Slide 19

Accuracy – how close a measurement is to the true value

Precision – how close a set of measurements are to each other

accurate&

precise

precisebut

not accurate

not accurate&

not precise

Page 20: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

20

good accuracygood precision

Mass of a Tennis Ball

Page 21: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

21

good accuracypoor precision

Mass of a Tennis Ball

Page 22: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

22

poor accuracypoor precision

Mass of a Tennis Ball

Page 23: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

23

Known + Estimated Digits

In the length measurement of 2.76 cm,

the digits 2 and 7 are certain (known).

the third digit 5(or 6) is estimated (uncertain). all three digits (2.76) are significant including

the estimated digit.

Page 24: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

24

Learning Check

. l8. . . . l . . . . l9. . . . l . . . . l10. . cm

What is the length of the red line?

1) 9.0 cm

2) 9.03 cm

3) 9.04 cm

Page 25: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

25

Solution

. l8. . . . l . . . . l9. . . . l . . . . l10. . cm

The length of the red line could be reported as

2) 9.03 cm

or 3) 9.04 cm

The estimated digit may be slightly different.

Both readings are acceptable.

Page 26: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

26

. l3. . . . l . . . . l4. . . . l . . . . l5. . cm

The first and second digits are 4.5. In this example, the line ends on a mark. Then the estimated digit for the hundredths

place is 0. We would report this measurement as 4.50 cm.

Zero as a Measured Number

Page 27: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

27

Exact Numbers

An exact number is obtained when you count objects or use a defined relationship.Counting objects

2 soccer balls4 pizzas

Defined relationships1 foot = 12 inches1 meter = 100 cm

An exact number is not obtained with a measuring tool.

Page 28: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

28

Learning Check

A. Exact numbers are obtained by 1. using a measuring tool

2. counting3. definition

B. Measured numbers are obtained by 1. using a measuring tool

2. counting3. definition

Page 29: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

29

Solution

A. Exact numbers are obtained by

2. counting

3. definition

B. Measured numbers are obtained by

1. using a measuring tool

Page 30: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

30

Learning Check

Classify each of the following as an exact (1) or a

measured (2) number.

A.__Gold melts at 1064°C.

B.__1 yard = 3 feet

C.__The diameter of a red blood cell is 6 x 10-4 cm.

D.__There are 6 hats on the shelf.

E.__A can of soda contains 355 mL of soda.

Page 31: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

31

Classify each of the following as an exact (1) or a

measured(2) number.

A. 2 A measuring tool is required.

B. 1 This is a defined relationship.

C. 2 A measuring tool is used to determine

length.

D. 1 The number of hats is obtained by counting.

E. 2 The volume of soda is measured.

Solution

Page 32: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

32

2.4 Measurement and Significant FiguresEvery experimental measurement, no matter how precise, has a degree of uncertainty to it because there is a limit to the number of digits that can be determined.

Page 33: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

Chapter 01

Slide 33

Accuracy, Precision, and Significant Figures

length = 1.74 cm

0 1 2 43cm

1.7 cm < length < 1.8 cm

Page 34: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

34

Rules for determining significant figures

1. Zeroes in the middle of a number are significant. 69.08 g has four significant figures, 6, 9, 0, and 8.

2. Zeroes at the beginning of a number are not significant. 0.0089 g has two significant figure, 8 and 9.

3. Zeroes at the end of a number and after the decimal points are significant. 2.50 g has three significant figures 2, 5, and 0.

25.00 m has four significant figures 2, 5, 0, and 0.

Page 35: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

35

4. Zeroes at the end of a number and before an implied decimal points may or may not be significant. 1500 kg may have two, three, or four significant figures. Zeroes here may be part of the measurements or for simply to locate the unwritten decimal point.

Page 36: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

36

Which of the following measurements has three significant figures?

a. 1,207 g

b. 4.250 g

c. 0.006 g

d. 0.0250 g

e. 0.03750 g

Page 37: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

37

Which of the following measurements has three significant figures?

a. 1,207 g

b. 4.250 g

c. 0.006 g

d. 0.0250 g

e. 0.03750 g

Page 38: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

38

Which of the following numbers contains four significant figures?

a. 230,110

b. 23,011.0

c. 0.23010

d. 0.0230100

e. 0.002301

Page 39: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

39

Which of the following numbers contains four significant figures?

a. 230,110

b. 23,011.0

c. 0.23010

d. 0.0230100

e. 0.002301

Page 40: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

40

2.6 Rounding off Numbers

Often calculator produces large number as a result of a calculation although the number of significant figures is good only to a fewer number than the calculator has produced – in this case the large number may be rounded off to a smaller number keeping only significant figures.

Page 41: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

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Rules for Rounding off Numbers: Rule 1 (For multiplication and divisions): The answer can’t have more significant figures than either of the original numbers.

Page 42: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

42

Rule 2 (For addition and subtraction): The answer should have minimum decimal places.

Page 43: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

43

How many significant figures should be shown for the calculation?

1 2 3 4 5

1.25 0.45

2.734

Page 44: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

44

How many significant figures should be shown for the calculation?

1 2 3 4 5

1.25 0.45

2.734

Page 45: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

45

How many significant figures are there in the following number: 1.200 X 109?

1. 4

2. 3

3. 2

4. 1

5. Cannot deduce from given information.

Page 46: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

46

Correct Answer:

Zeros that fall both at the end of a number and after the decimal point are always significant.

1.200 109

1. 4

2. 3

3. 2

4. 1

5. Cannot deduce from given information.

Page 47: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

47

6.220 1.0

+ 125

How many significant figures are there in the following summation:

1. 22. 33. 44. 55. 6

Page 48: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

48

6.220 1.0

+ 125 132.220

Correct Answer:

In addition and subtraction the result can have no more decimal places than the measurement with the fewest number of decimal places.

1. 22. 33. 44. 55. 6

Page 49: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

49

How many significant figures are there in the result of the following multiplication:

(2.54) (6.2) (12.000)

1. 22. 33. 44. 5

Page 50: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

50

Correct Answer:

In multiplication and division the result must be reported with the same number of significant figures as the measurement with the fewest significant figures.

(2.54) (6.2) (12.000) = 188.976 = 190

1. 22. 33. 44. 5

Page 51: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

51

2.7 Problem Solving: Converting a Quantity from One Unit to Another

Factor-Label-Method (Unit Conversion Factor): A quantity in one unit is converted to an equivalent quantity in a different unit by using a conversion factor that expresses the relationship between units.

Page 52: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

52

Page 53: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

53

When solving a problem, set up an equation so that all unwanted units cancel, leaving only the desired unit. For example, we want to find out how many kilometers are there in 26.22 mile distance. We will get the correct answer if we multiply 26.22 mi by the conversion factor km/mi.

Page 54: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

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In working a problem, start with the initial unit.

Write a unit plan that converts the initial unit to the final unit.

Unit 1 Unit 2 Select conversion factors that cancel the

initial unit and give the final unit.Initial x Conversion = Final

unit factor unitUnit 1 x Unit 2 = Unit 2

Unit 1

Problem Setup

Page 55: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

55

Setting up a Problem

How many minutes are 2.5 hours?Solution: Initial unit = 2.5 hrFinal unit = ? minUnit Plan = hr min

Setup problem to cancel hours (hr). Inital Conversion Final

unit factor unit2.5 hr x 60 min = 150 min (2 SF)

1 hr

Page 56: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

56

A rattlesnake is 2.44 m long. How long is the snake in cm?

1) 2440 cm

2) 244 cm

3) 24.4 cm

Learning Check

Page 57: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

57

A rattlesnake is 2.44 m long. How long is the snake in centimeters?

2) 244 cm

2.44 m x 100 cm = 244 cm

1 m

Solution

Page 58: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

58

Often, two or more conversion factors are required to obtain the unit of the answer.

Unit 1 Unit 2 Unit 3 Additional conversion factors are placed in

the setup to cancel the preceding unitInitial unit x factor 1 x factor 2 = Final unit

Unit 1 x Unit 2 x Unit 3 = Unit 3 Unit 1 Unit 2

Using Two or More Factors

Page 59: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

59

How many minutes are in 1.4 days?Initial unit: 1.4 days

Unit plan: days hr min

Set up problem: 1.4 days x 24 hr x 60 min = 2.0 x 103 min

1 day 1 hr 2 SF Exact Exact = 2 SF

Example: Problem Solving

Page 60: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

60

Be sure to check your unit cancellation in the setup.

What is wrong with the following setup?1.4 day x 1 day x 1 hr 24 hr 60 min Units = day2/min is Not the final unit needed Units don’t cancel properly.

The units in the conversion factors must cancel to give the correct unit for the answer.

Check the Unit Cancellation

Page 61: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

61

An adult human has 4650 mL of blood. How many gallons of blood is that?

Unit plan: mL qt gallon

Equalities: 1 quart = 946 mL

1 gallon = 4 quarts

Learning Check

Page 62: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

62

Unit plan: mL qt gallon

Setup:

4650 mL x 1 qt x 1 gal = 1.23 gal

946 mL 4 qt

3 SF exact exact 3 SF

Solution

Page 63: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

63

Identify the initial and final units. Write out a unit plan. Select appropriate conversion factors. Convert the initial unit to the final unit. Cancel the units and check the final unit. Do the math on a calculator. Give an answer using significant figures.

Typical Steps in Problem Solving

Page 64: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

64

If a ski pole is 3.0 feet in length, how long is the ski pole in mm?

Learning Check

Page 65: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

65

3.0 ft x 12 in x 2.54 cm x 10 mm =

1 ft 1 in. 1 cm

Check factor setup: Units cancel properly

Check final unit: mm

Calculator answer: 914.4 mm

Final answer: 910 mm (2 SF rounded)

Solution

Page 66: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

66

If your pace on a treadmill is 65 meters per minute, how many minutes will it take for you to walk a distance of 7500 feet?

Learning Check

Page 67: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

67

7500 ft x 12 in. x 2.54 cm x 1 m

1 ft 1 in. 100 cm

x 1 min = 35 min 65 m final answer (2 SF)

Solution

Page 68: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

68

Clinical Factors

Conversion factors are also possible when working with medications.

A drug dosage such as 20 mg Prednisone per tablet can be written as

20 mg Prednisone and 1 tablet

1 tablet 20 mg Prednisone

Page 69: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

69

Learning Check

The dosage ordered is 400 mg of Erythromycin four times a day (q.i.d)*. If the oral suspension contains 200 mg Erythromycin/5 mL, how many mL will be given each time?

1) 5 mL

2) 10 mL

3) 40 mL

*:Latin quater in die

Page 70: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

70

Solution

The dosage ordered is 400 mg of Erythromycin four times a day (q.i.d). If the oral suspension contains 200 mg Erythromycin/5 mL, how many mL will be given each time?

2) 10 mL

400 mg x 5 mL = 10 mL

200 mg

Page 71: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

71

Temperature Scales

Temperature is measured using the Fahrenheit, Celsius, and Kelvin temperature scales.

The reference points are the boiling and freezing points of water.

Page 72: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

72

A. What is the temperature of freezing water?

1) 0°F 2) 0°C 3) 0 K

B. What is the temperature of boiling water?

1) 100°F 2) 32°F 3) 373 K

C. How many Celsius units are between the boiling and freezing points of water?

1) 100 2) 180 3) 273

Learning Check

Page 73: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

73

A. What is the temperature of freezing water?

2) 0°C

B. What is the temperature of boiling water?

3) 373 K

C. How many Celsius units are between the

boiling and freezing points of water?

1) 100

Solution

Page 74: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

74

On the Fahrenheit scale, there are are 180°F between the freezing and boiling points and on the Celsius scale, there are 100 °C. 180°F = 9°F = 1.8°F 100°C 5°C 1°C

In the formula for Fahrenheit, the value of 32 adjusts the zero point of water from 0°C to 32°F.

°F = 9/5 T°C + 32

or °F = 1.8 T°C + 32

Fahrenheit Formula

Page 75: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

75

The equation for Fahrenheit is rearranged to calculate T°C.

°F = 1.8 T°C + 32 Subtract 32 from both sides and divide by 1.8.

°F – 32 = 1.8T°C ( +32 – 32)°F – 32 = 1.8 T°C

1.8 1.8°F – 32 = T°C

1.8

Celsius Formula

Page 76: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

76

A person with hypothermia has a body temperature of 34.8°C. What is that temperature in °F? °F = 1.8 (34.8°C) + 32 exact tenth's exact

= 62.6 + 32= 94.6°F

tenth’s

Solving A Temperature Problem

Page 77: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

77

The normal temperature of a chickadee is 105.8°F. What is that temperature in °C?

1) 73.8 °C

2) 58.8 °C

3) 41.0 °C

Learning Check

Page 78: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

78

3) 41.0 °C

°C = (°F – 32)

1.8

= (105.8 – 32)

1.8

= 73.8°F

1.8° = 41.0°C

Solution

Page 79: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

79

A pepperoni pizza is baked at 455°F. What temperature is needed on the Celsius scale?

1) 437 °C

2) 235°C

3) 221°C

Learning Check

Page 80: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

80

A pepperoni pizza is baked at 455°F. What temperature is needed on the Celsius scale?

2) 235°C

(455 – 32) = 235°C 1.8

Solution

Page 81: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

81

On a cold winter day, the temperature is –15°C.

What is that temperature in °F?

1) 19°F

2) 59°F

3) 5°F

Learning Check

Page 82: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

82

3) 5°F

°F = 1.8(–15°C) + 32

= – 27 + 32

= 5°F

Note: Be sure to use the change sign key on your calculator to enter the minus – sign. 1.8 x 15 +/ – = –27

Solution

Page 83: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

83

2.10 Energy and HeatEnergy: Capacity to do work or supply energy.Classification of Energy:1. Potential Energy: stored energy. Example: a coiled spring have potential

energy waiting to be released. 2. Kinetic Energy: energy of motion.

Example, when the spring uncoil potential energy is converted to the kinetic energy.

Page 84: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

84

Learning Check

Identify the energy as 1) potential or 2) kinetic

A. Roller blading.

B. A peanut butter and jelly sandwich.

C. Mowing the lawn.

D. Gasoline in the gas tank.

Page 85: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

85

Solution

Identify the energy as 1) potential or 2) kinetic

A. Roller blading. (2 kinetic)

B. A peanut butter and jelly sandwich. (1 potential)

C. Mowing the lawn. (2 kinetic)

D. Gasoline in the gas tank. (1 potential)

Page 86: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

86

Energy has many forms: Mechanical Electrical Thermal (heat) Chemical Solar (light) Nuclear

Forms of Energy

Page 87: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

87

Heat energy flows from a warmer object to a colder object.

The colder object gains energy when it is heated.

During heat flow, the loss of heat by a warmer object is equal to the heat gained by the colder object.

Heat

Page 88: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

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Heat is measured in calories or joules.

1 kilocalorie (kcal) = 1000 calories (cal)

1 calorie = 4.18 Joules (J)

1 kJ = 1000 J

Some Equalities for Heat

Page 89: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

89

Specific heat is the amount of heat (calories or Joules) that raises the temperature of 1 g of a substance by 1°C.

Specific Heat

Page 90: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

90

A. A substance with a large specific heat 1) heats up quickly 2) heats up slowly

B. When ocean water cools, the surrounding air 1) cools 2) warms 3) stays the same

C. Sand in the desert is hot in the day and cool at night. Sand must have a

1) high specific heat 2) low specific heat

Learning Check

Page 91: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

91

A. A substance with a large specific heat

2) heats up slowly

B. When ocean water cools, the surrounding air

2) warms

C. Sand in the desert is hot in the day and cool

at night. Sand must have a

2) low specific heat

Solution

Page 92: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

92

When 200 g of water are heated, the water temperature rises from 10°C to 18°C.

If 400 g of water at 10°C are heated with the same amount of heat, the final temperature would be1) 10 °C 2) 14°C 3) 18°C

200 g400 g

Learning Check

Page 93: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

93

When 200 g of water are heated, the water temperature rises from 10°C to 18°C.

If 400 g of water at 10°C are heated with the same amount of heat, the final temperature would be2) 14°C

200 g400 g

Solution

Page 94: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

94

To calculate the amount of heat lost or gained by a substance, we need the Specific Heat of substance, T, and the mass of the substance.

Heat = g x T x cal (or J) = cal ( or J) g °C

Calculation with Specific Heat

Page 95: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

95

A hot-water bottle contains 750 g of water at 65°C. If the water cools to body temperature (37°C), how many calories of heat could be transferred to sore muscles?

The temperature change is 65°C - 37°C = 28°C.heat (cal) = g x T x Sp. Ht. (H2O)

750 g x 28°C x 1.00 cal g°C

= 21 000 cal

Sample Calculation for Heat

Page 96: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

96

How many kcal are needed to raise the temperature of 120 g of water from 15.0°C to 75.0°C?

1) 1.8 kcal

2) 7.2 kcal

3) 9.0 kcal

Learning Check

Page 97: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

97

How many kcal are needed to raise the temperature of 120 g of water from 15.0°C to 75.0°C?

2) 7.2 kcal

Learning Check

Page 98: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

98

In chemical reactions, the potential energy is often converted into heat. Reaction products have less potential energy than the reactants – the products are more stable than the reactants.

Stable products have very little potential energy remaining as a result have very little tendency to undergo further reaction.

SI unit of energy is Joules (J) and the metric unit of energy is calorie (cal).

Page 99: Chapter Two Measurements in Chemistry Fundamentals of General, Organic & Biological Chemistry

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2.11 Density

Density relates the mass of an object with its volume. Density is usually expressed in units as - Gram per cubic centimeter (g/cm3) for solids, and Gram per milliliter (g/mL) for liquids.

Density = Mass (g)

Volume (mL or cm3)

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Osmium is a very dense metal. What is its density in g/cm3 if 50.00 g of the metal occupies a volume of 2.22 cm3?

1) 2.25 g/cm3

2) 22.5 g/cm3

3) 111 g/cm3

Learning Check

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Place the mass of the osmium metal in the numerator of the density setup and its volume in the denominator.

D = mass = 50.00 g volume 2.22 cm3

calculator = 22.522522 g/cm3

final answer = 22.5 g/cm3

Solution

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Density Using Volume Displacement

The volume of zinc is calculated from the displaced volume 45.0 mL - 35.5 mL = 9.5 mL = 9.5 cm3

Density zinc = mass = 68.60 g = 7.2 g/cm3

volume 9.5 cm3

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What is the density (g/cm3) of 48 g of a metal if the metal raises the level of water in a graduated cylinder from 25 mL to 33 mL?

1) 0.2 g/ cm3 2) 6 g/cm3 3) 252 g/cm3

25 mL 33 mL

object

Learning Check

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2) 6 g/cm3

Calculate the volume difference. 33 mL – 25 mL = 8 mL

Convert the volume in mL to cm3.

8 mL x 1 cm3 = 8 cm3

1 mL

Set up the density calculationDensity = mass = 48 g = 6 g = 6 g/cm3

volume 8 cm3 cm3

Solution

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Sink or Float

Ice floats in water because the density of ice is less than the density of water. Aluminum sinks because it has a density greater than the density of water.

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Which diagram correctly represents the liquid layers in the cylinder? Karo (K) syrup (1.4 g/mL), vegetable (V) oil (0.91 g/mL,) water (W) (1.0 g/mL)

1 2 3

K

K

W

W

W

V

V

V

K

Learning Check

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1) vegetable oil 0.91 g/mL

water 1.0 g/mL

Karo syrup 1.4 g/mLK

W

V

Solution

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Density represents an equality for a substance. The mass in grams is for 1 mL. For a substance with a density of 3.8 g/mL, the equality is:

3.8 g = 1 mL

For this equality, we can write two conversion factors.

Conversion 3.8 g and 1 mL factors 1 mL 3.8 g

Density as a Conversion Factor

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The density of octane, a component of gasoline, is 0.702 g/mL. What is the mass, in kg, of 875 mL of octane?

1) 0.614 kg

2) 614 kg

3) 1.25 kg

Learning Check

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1) 0.614 kg

Unit plan: mL g kg

Equalities: density 1 mL = 0.702 g

and 1 kg = 1000 g

Setup: 875 mL x 0.702 g x 1 kg = 0.614 kg 1 mL 1000 g

density metric factor factor

Solution

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If blood has a density of 1.05 g/mL, how many liters of blood are donated if 575 g of blood are given?

1) 0.548 L

2) 1.25 L

3) 1.83 L

Learning Check

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1) 0.548 L

Unit Plan: g mL L

575 g x 1 mL x 1 L = 0.548 L 1.05 g 1000 mL

density metric factor factor

Solution

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Density Using Volume Displacement

The volume of zinc is calculated from the displaced volume 45.0 mL - 35.5 mL = 9.5 mL = 9.5 cm3

Density zinc = mass = 68.60 g = 7.2 g/cm3

volume 9.5 cm3

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A group of students collected 125 empty aluminum cans to take to the recycling center. If 21 cans make 1.0 pound of aluminum, how many liters of aluminum (D=2.70 g/cm3) are obtained from the cans?

1) 1.0 L 2) 2.0 L 3) 4.0 L

Learning Check

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1) 1.0 L

125 cans x 1.0 lb x 454 g x 1 cm3

21 cans 1 lb 2.70 g

x 1 mL x 1 L = 1.0 L 1 cm3 1000 mL

Solution

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You have 3 metal samples. Which one will displace the greatest volume of water?

1 2 3

25 g of aluminum2.70 g/mL

45 g of gold19.3 g/mL

75 g of lead11.3 g/mL

Learning Check

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1)

Calculate the volume for each metal and select the metal that has the greatest volume.

1) 25 g x 1 mL = 9.3 mL aluminum2.70 g

2) 45 g x 1 mL = 2.3 mL gold19.3 g

3) 75 g x 1 mL = 6.6 mL lead11.3 g

Solution

25 g of aluminum2.70 g/mL

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2. 12 Specific Gravity

Specific Gravity (sp gr): density of a substance divided by the density of water at the same temperature. Specific Gravity is unitless. At normal temperature, the density of water is close to 1 g/mL. Thus, specific gravity of a substance at normal temperature is equal to the density.

Density of substance (g/ml)

Density of water at the same temperature (g/ml)Specific gravity =

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The specific gravity of a liquid can be measured using an instrument called a hydrometer, which consists of a weighted bulb on the end of a calibrated glass tube, as shown in the following Fig 2.6. The depth to which the hydrometer sinks when placed in a fluid indicates the fluid’s specific gravity.

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Learning Check

Corn oil has a density of 0.92 g/mL. What is the specific gravity of corn oil?

1) 0.92 2) 0.92 g 3) 1.1

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Solution

Corn oil has a density of 0.92 g/mL. What is the specific gravity of corn oil?

1) 0.92

specific gravity = 0.92 g/mL = 0.92

1.00 g/mL

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Learning Check

A bone sample has a mass of 52 g. If bone has a specific gravity of 1.8, what is the volume in milliliters of the bone sample?

1) 1.8 mL 2) 29 mL 3) 94 mL

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Solution

2) 29 mLConvert the specific gravity to its densityusing the density of water1.8 x 1.00 g/mL = 1.8 g/mL

Use the density factor to cancel the initial unit.Volume = 52 g x 1 mL = 29 mL

1.8 g

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Chapter Summary

Physical quantity, a measurable properties, is described by both a number and a unit.

Mass, an amount of matter an object contains, is measured in kilograms (kg) or grams (g).

Volume is measured in cubic meters (m3) or in liter (L) or milliliters (mL).

Temperature is measured in Kelvin (K) in SI system and in degrees Celsius (oC) in the metric system.

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Chapter Summary Contd.

Measurement of small or large numbers are usually written in scientific notation, a product of a number between 1 and 10 and a power of 10.

A measurement in one unit can be converted to another unit by multiplying by a conversion factor.

Energy: the capacity to supply heat or to do work.

Potential energy – stored energy. kinetic energy – energy of moving particles.

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Chapter Summary Contd. Heat: kinetic energy of moving particles in a

chemical reaction. Temperature: is a measure of how hot or cold an

object is. Specific heat: amount of heat necessary to raise

the temperature of 1 g of the substance by 1oC. Density: grams per milliliters for a liquid or

gram per cubic centimeter for a solid. Specific gravity: density of a liquid divided by

the density of water.

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End of Chapter 2