chapter 8 multivariable calculus section 2 partial derivatives
TRANSCRIPT
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Chapter 8
Multivariable Calculus
Section 2
Partial Derivatives
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Learning Objectives for Section 8.2 Partial Derivatives
The student will be able to evaluate partial derivatives and second-order partial derivatives.
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Introduction to Partial Derivatives
We have studied extensively differentiation of functions of one variable. For instance, if
C(x) = 100 + 500x,
then
C ´(x) = 500.
If we have more than one independent variable, we can still differentiate the function if we consider one of the variables independent and the others fixed. This is called a partial derivative.
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Example
For a company producing only one type of surfboard, the cost function is C(x) = 500 + 70x, where x is the number of boards produced.
Differentiating with respect to x, we obtain the marginal cost function C ´(x) = 70.
Since the marginal cost is constant, $70 is the change in cost for a one-unit increase in production at any output level.
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Example(continued)
For a company producing two types of boards, a standard model and a competition model, the cost function is
C(x, y) = 700 + 70x + 100y,
where x is the number of standard boards, and y is the number of competition boards produced.
Now suppose that we differentiate with respect to x, holding y fixed, and denote this by Cx(x, y); or suppose we differentiate with respect to y, holding x fixed, and denote this by Cy(x, y).
Differentiating in this way, we obtain Cx(x, y) = 70, and Cy(x, y)= 100.
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Example(continued)
Each of these is called a partial derivative, and in this example, each represents marginal cost.
The first is the change in cost due to a one-unit increase in production of the standard board with the production of the competition board held fixed.
The second is the change in cost due to a one-unit increase in production of the competition board with the production of the standard board held fixed.
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Partial Derivatives
If z = f (x, y), then the partial derivative of f with respect to x is defined by
h
yxfyhxf
x
zh
),(),(lim
0
and is denoted by ),(oror yxffx
zxx
The partial derivative of f with respect to y is defined by
k
yxfkyxf
y
zk
),(),(lim
0
and is denoted by ),(oror yxffy
zyy
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Example
Let f (x, y) = 3x2 + 2xy – y 3 .
a. Find f x(x, y). [This is the derivative with respect to x, so consider y as a constant.]
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Example
Let f (x, y) = 3x2 + 2xy – y 3 .
a. Find f x(x, y). [This is the derivative with respect to x, so consider y as a constant.]
f x(x, y) = 6x + 2y
b. Find f y(x, y). [This is the derivative with respect to y, so consider x as a constant.]
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Example
Let f (x, y) = 3x2 + 2xy – y 3 .
a. Find f x(x, y). [This is the derivative with respect to x, so consider y as a constant.]
f x(x, y) = 6x + 2y
b. Find f y(x, y). [This is the derivative with respect to y, so consider x as a constant.]
f y(x, y) = 2x – 3y2
c. Find f x(2,5).
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Example
Let f (x, y) = 3x2 + 2xy – y 3 .
a. Find f x(x, y). [This is the derivative with respect to x, so consider y as a constant.]
f x(x, y) = 6x + 2y
b. Find f y(x, y). [This is the derivative with respect to y, so consider x as a constant.]
f y(x, y) = 2x - 3y2
c. Find f x(2,5).
f x(2,5) = 6 · 2 + 2 · 5 = 22.
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Example Using the Chain Rule
Let f (x, y) = (5 + 2xy 2) 3.
Hint: Think of the problem as z = u3 and u = 5 + 2xy2.
a. Find f x(x, y)
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Example Using the Chain Rule
Let f (x, y) = (5 + 2xy 2) 3.
Hint: Think of the problem as z = u3 and u = 5 + 2xy2.
a. Find f x(x, y)
f x(x, y) = 3 (5 + 2xy2)2 · 2y2
b. Find f y(x, y)
The chain.
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Example Using the Chain Rule
Let f (x, y) = (5 + 2xy 2) 3.
Hint: Think of the problem as z = u3 and u = 5 + 2xy2.
a. Find f x(x, y)
f x(x, y) = 3 (5 + 2xy2)2 · 2y2
b. Find f y(x, y)
f y(x, y)) = 3 (5 + 2xy2)2 · 4xy
The chain.
The chain.
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Second-Order Partial Derivatives
Taking a second-order partial derivative means taking a partial derivative of the first partial derivative. If z = f (x, y), then
x
z
yxy
z (x, y) f f yxyx
2
y
z
xyx
z (x, y) f f xyxy
2
y
z
yy
z (x, y) f f yyyy 2
2
x
z
xx
z (x, y) f f xxxx 2
2
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Example
Let f (x, y) = x3 y3 + x + y2.
a. Find f x(x, y).
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Example
Let f (x, y) = x3 y3 + x + y2.
a. Find f xx(x, y).
f x(x, y) = 3x2 y3 + 1
f xx(x, y) = 6xy3
b. Find f xy(x, y).
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Example
Let f (x, y) = x3 y3 + x + y2.
a. Find f x(x, y).
f x(x, y) = 3x2 y3 + 1
f xx(x, y) = 6xy3
b. Find f xy(x, y).
f x(x, y) = 3x2 y3 + 1
f xy(x, y) = 9x2 y2
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Summary
■ If z = f (x, y), then the partial derivative of f with respect to x is defined by
■ If z = f (x, y), then the partial derivative of f with respect to y is defined by
■ We learned how to take second partial derivatives.
h
yxfyhxf
x
zh
),(),(lim
0
k
yxfkyxf
y
zk
),(),(lim
0