chapter 8 molarity part 1. solutions solute the substance that dissolves (the minor component of a...
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Chapter 8
MolarityPart 1
Solutions
Solute • The substance that dissolves (the minor
component of a solution).
KMnO4
Solutions
• Solvent
• The substance that the solute dissolves in (the major component of a solution).
KMnO4 solution
Solution
A homogeneous mixture of the solute and solvent.
Solutions
Dilute Concentrated
Concentration of a solution
Molarity(M) is the moles of solute per liter of solution.
Molarity(M) =moles of soluteLiters of solution
Common Volume Units
= 1000 mL= 1000 mL
Common Volume Units
= 1000 mL= 1000 mL
Units of Molarity
Units of Molarity
2.0 M HCl
Units of Molarity
2.0 M HCl = 2.0 moles HCl
L solution
Units of Molarity
2.0 M HCl = 2.0 moles HCl
L solution
6.0 M HCl
Units of Molarity
2.0 M HCl = 2.0 moles HCl
L solution
6.0 M HCl = 6.0 moles HCl
dm3 solution
Molarity
• Calculate the molarity of an aqueous Ba(NO3)2 solution containing 0.283 grams of barium nitrate in 0.931 L of solution.
Molarity
• Calculate the molarity of an aqueous Ba(NO3)2 solution containing 0.283 grams of barium nitrate in 0.931 L of solution.
0.283 g Ba(NO3)2
0.931 L
Molarity
• Calculate the molarity of an aqueous Ba(NO3)2 solution containing 0.283 grams of barium nitrate in 0.931 L of solution.
0.283 g Ba(NO3)2
0.931 L 261.3 g
mol
Molarity
• Calculate the molarity of an aqueous Ba(NO3)2 solution containing 0.283 grams of barium nitrate in 0.931 L of solution.
0.283 g Ba(NO3)2
0.931 L 261.3 g
mol= 0.00116 mol Ba(NO3)2/L
= 0.00116 M Ba(NO3)2
Molarity Calculation
NaOH is used to open stopped sinks, to treat cellulose in the making of nylon, and to
remove potato peels commercially.
If 4.0 g NaOH are used to make 500.0 mL of NaOH solution, what is the molarity (M) of the solution?
If 4.0 g NaOH are used to make 500.0 mL of NaOH solution, what is the molarity (M) of the solution?
4.0 g NaOH
500.0 mL
If 4.0 g NaOH are used to make 500.0 mL of NaOH solution, what is the molarity (M) of the solution?
4.0 g NaOH
500.0 mL 40.0 g
mol
If 4.0 g NaOH are used to make 500.0 mL of NaOH solution, what is the molarity (M) of the solution?
4.0 g NaOH
500.0 mL 40.0 g
mol
0.001 L
mL
If 4.0 g NaOH are used to make 500.0 mL of NaOH solution, what is the molarity (M) of the solution?
4.0 g NaOH
500.0 mL 40.0 g
mol
0.001 L
mL= 0.20 mol NaOH/L = 0.20M NaOH
Molarity Conversion Factors
An NaOH solution has a molarity of 0.20M.
• Write this molarity in the form of conversion factors (ratios).
Molarity Conversion Factors
0.20 moles NaOH and L solution ____
L solution 0.20 moles NaOH
How many grams of Na2SO4 are required to prepare 1000.0 mL of 1.0000 M Na2SO4 solution?
How many grams of Na2SO4 are required to prepare 1000.0 mL of 1.0000 M Na2SO4 solution?
1000.0 mL1000.0 mL
How many grams of Na2SO4 are required to prepare 1000.0 mL of 1.0000 M Na2SO4 solution?
1000.0 mL 0.001 L1000.0 mL 0.001 L
mLmL
How many grams of Na2SO4 are required to prepare 1000.0 mL of 1.0000 M Na2SO4 solution?
1000.0 mL 0.001 L 1.0000 mol Na1000.0 mL 0.001 L 1.0000 mol Na22SOSO44
mL LmL L
How many grams of Na2SO4 are required to prepare 1000.0 mL of 1.0000 M Na2SO4 solution?
1000.0 mL 0.001 L 1.0000 mol Na1000.0 mL 0.001 L 1.0000 mol Na22SOSO4 4 142.04 g142.04 g
mL L molmL L mol
How many grams of Na2SO4 are required to prepare 1000.0 mL of 1.0000 M Na2SO4 solution?
1000.0 mL 0.001 L 1.0000 mol Na1000.0 mL 0.001 L 1.0000 mol Na22SOSO4 4 142.04 g142.04 g
mL L molmL L mol
= 142.04 g Na= 142.04 g Na22SOSO44
a
a
How to prepare 1000ml (1.000L) How to prepare 1000ml (1.000L) of a 1.0000M solution of Naof a 1.0000M solution of Na22SOSO44..
Diabetes is a serious medical issue facing our country at this time.
• 23.6 million people in the United States (7.8% of the total population) have diabetes. Of these, 5.7 million have undiagnosed diabetes.
• In 2007, about 1.6 million new cases of diabetes were diagnosed in people aged 20 years or older.
• If current trends continue, 1 in 3 Americans will develop diabetes sometime in their lifetime, and those with diabetes will lose, on average, 10–15 years of life.
• Diabetes is the leading cause of new cases of blindness, kidney failure, and nontraumatic lower-extremity amputations among adults.
• Diabetes was the sixth leading cause of death on U.S. death certificates in 2006. Overall, the risk for death among people with diabetes is about twice that of people without diabetes of similar age.
• In 1999–2000, 7% of U.S. adolescents aged 12–19 years had impaired fasting glucose (prediabetes), putting them at increased risk of developing type 2 diabetes, heart disease, and stroke.
Diabetes Is Preventable and Controllable
• Recent studies show that lifestyle changes can prevent or delay the onset of type 2 diabetes among people at high risk.
• For people with prediabetes, lifestyle changes, including a 5%–7% weight loss and at least 150 minutes of physical activity per week, can reduce the rate of onset of type 2 diabetes by 58%.
• Disability and premature death are not inevitable consequences of diabetes. By working with their support network and health care providers, people with diabetes can prevent premature death and disability by controlling their blood glucose, blood pressure, and blood lipids and by receiving other preventive care in a timely manner.
Blood sugar is a term referring to the amount of glucose (C6H12O6) present in the blood. A normal blood glucose level is about 0.083g in 100.0mL. What is the molarity of normal blood glucose?
0.0046M C0.0046M C66HH1212OO66
In a college chemistry class you are asked to prepare 100.0 mL solution of 0.250 M NiCl2 (gfm = 129.7g/mol).
In a college chemistry class you are asked to prepare 100.0 mL solution of 0.250 M NiCl2 (gfm = 129.7g/mol).
How do you prepare the solution?
In a college chemistry class you are asked to prepare 100.0 mL solution of 0.250 M NiCl2 (gfm = 129.7g/mol).
How do you prepare the solution.
3.24 grams of NiCl3.24 grams of NiCl22
Dissolve 3.24 grams of NiClDissolve 3.24 grams of NiCl22 in water then in water then
dilute to a total volume of 100.0 mL.dilute to a total volume of 100.0 mL.
Information for Mole Quiz
• How does a mole relate to particles and mass? (ie. One mole of H2O is 6.02 x 1023 H2O molecules and has a mass of 18.0 g).
• Be able to use the factor-label method to do metric conversions and mole problems.
• Know how to determine the number of atoms in a molecule. Be able to use this information in factor-label problems.
• Be able to determine the number of grams/molecule.• Identify the diatomic gases.
Homework Molarity Worksheet. (Note that the
answers to problem number 2 must be in sentence form).