chapter 6 electronic structure of atoms

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CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

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CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS. Almost everything we now know about electrons came from the study of light. Light is a type of electromagnetic radiation. Types of Electromagnetic Radiation. Three complete cycles of wavelength (l ). - PowerPoint PPT Presentation

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Page 1: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

CHAPTER 6

ELECTRONIC STRUCTURE OF ATOMS

Page 2: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

Almost everything we now know about electrons came

from the study of light.

Light is a type of electromagnetic radiation.

Page 3: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

Types of Electromagnetic Radiation

Page 4: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

Three complete cycles of wavelength

Page 5: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

The product of the frequency and its

wavelength equals the speed of light (c).

c =

Page 6: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

C =

Since the speed of light is 3 x 108 m/s, there must be an inverse relationship between wavelength and frequency

Page 7: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

The yellow light given off by a sodium vapor lamp

used for public lighting has a wavelength of 589 nm. What is the frequency of

this radiation?

Page 8: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

The yellow light given off by a sodium vapor lamp

used for public lighting has a wavelength of 589 nm. What is the frequency of

this radiation? c = = 5.09 x 1014 s-1

Page 9: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

Max Planck assumed that small quantities of energy (quantum) can be emitted or absorbed as

electromagnetic radiation.

E = hv Planck’s constant (h) = 6.63 x 10-34 joule-seconds (J-s)

Page 10: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

Since yellow light has a wavelength of 589 nm, what is the smallest quantum of

energy that can be absorbed from yellow light?

Page 11: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

Since yellow light has a wavelength of 589 nm, what is the smallest quantum of

energy that can be absorbed from yellow light?

E=hv E=(6.63 x 10-34)(5.09 x 1014)

E = 3.37 x 10-19 J

Page 12: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS
Page 13: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

Johann Balmer observed the 4 lines of the hydrogen

spectrum to come up with a formula:

v=C(1/22-1/n2) n= 3,4,5,6

Page 14: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS
Page 15: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

Niels Bohr assumed that electrons orbit in circular paths around the nucleus.

He also said that orbits of certain radii correspond to

certain energies.

Page 16: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

En=(-RH)(1/n2)

n= 1, 2, 3, 4, …

n= the principal quantum number

RH = 2.18 x 10-18 J

Page 17: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

Bohr assumed that electrons could “jump” from one

energy state to another by absorbing or emitting energy

of certain frequencies.

E= Ef - Ei = hv

Page 18: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

By combining some equations:

v= E/h = (RH/h)(1/ni2-1/nf

2)Calculate the wavelength of light that

corresponds to the transition of the electron from the n=4 to n=2 state of the

H atom.

Page 19: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

Heisenberg’s Uncertainty Principle:

It is impossible for us to know the exact velocity or

exact location of an electron

Page 20: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

This is a probability

density of the location of the electron in a H atom.

This represents the shape of the s orbital.

Page 21: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

The p Orbitals

Page 22: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS

The d Orbitals

Page 23: CHAPTER 6 ELECTRONIC STRUCTURE OF ATOMS