chapter 5 - mechanism
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MECHANISM
Mohd Hadri Mohamed Nor
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Topic Learning Outcome
On completion this topic, you should be able to do the
following:
Describe a mechanism
Describe the inversion of mechanism
Define the velocity
Solve the velocity and acceleration point withinmechanism
Use mathematical and graphical method
Construct velocity and acceleration diagram.
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Introduction
When any one link of kinematics chain isfixed, it is called mechanism.
Primary function: transmit or modifymotion.
2 types of mechanism- simple mechanism
- compound mechanism, >4 links
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Example: Crank, connecting rod and pistonmechanism
Angular motion Linear motion
Input torque Force
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Inversion of Mechanism
It is the method of obtaining different
mechanisms by fixing different links of the
same Kinematics chain.
1. Inversion of four bar chain mechanism
2. Inversion of slider crank mechanism
3. Inversions of double slider crank chain
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Four Bar Chain Mechanism
Consist of four links AB, BC, CD, DA Grashof’s Law (if to be continuous relative motion between two links)
∑ shortest and longest link < ∑ remaining 2 links
AB – crank
CD – rocker/follower
BC – connecting rod
AD – frame of m/c
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Some of the inversion of four bar chainmechanism:
• Crank and follower mechanism – Oscillatory motion
• Pantograph – Instrument used to reproduce samemotion exactly in a reduced or enlarged scale.
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Slider Crank Mechanism
1st inversion – Slider crank
link 1 fixed, link 2 rotates, link 4 reciprocates
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2nd
inversion – Oscillating cylinderwhen link 2 rotates piston reciprocates in piston
cylinder cylinder reciprocates at hinge point C
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3rd
inversion – Crank and slotted lever mechanismlink 2 rotates slider O reciprocates link 4 rotate
block N move linearly
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4th
inversion – Hand pumplink 4 fixed link 2 and 3 can be rotate link 1 move
linearly
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Velocities in Mechanism – Relative Velocity Diagram
Velocity of any point on a link wrt t another point on thesame link is always perpendicular to the link joining these
points in the FBD.
Consider point A and B on a link (Fig a). Let velocity A isVA is known in magnitude and direction. Direction ofvelocity point B is VB. The magnitude of point B can be
found by draw the velocity diagram (Fig b)
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Step in drawing velocity diagram
A convenient point O was selected as the starting point.
From O , line Oa was drawn parallel and equal to magnitudeof V A to some suitable scale.
From ‘a’, a line perpendicular to AB represent velocity of Bwrt A. i.e V BA was drawn.
From ‘O ’ a line parallel to V B was drawn, meeting the V BA at‘b’.
Line ‘Ob ’ was measured to give the required velocity ofpoint B to scale.
The velocity of point C on AB link was determine using ratio
Line ‘Oc ’ was joined. The vector Oc now represent thevelocity of point C wrt O . i.e V
C Note that velocity diagram must be drawn according to suitable scale.
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Example 1
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Rubbing velocity at a Pin Joint
If r = radius at pin joint and ω1 and ω2 = angularvelocities of two links, then;
Angular velocities added if link rotates opposite direction
and subtract if rotate in same direction.
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Example 2
The crank and connecting rod of a theoretical
steam engine are 0.5m and 2.0 m respectively.
The crank makes 180rpm in the clockwisedirection. When it has turned 45° from the
inner dead centre position, determine:
a) Velocity of pistonsb) Angular velocity of connecting rod
c) Velocity of point E on the connecting rod 1.5mfrom the gudgeon pin.
d) Velocities of rubbing at all pins of the crankshaft,crank and cross-head, when the diameter of their
pins are 5cm, 6cm and 3cm respectively.
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Acceleration Diagram for a Link
Consider two point of A and B on rigid link. Let point B moves wrtA with velocity ω rad/s and α be the angular acceleration of linkAB. For an acceleration of a particle whose velocity changes withmagnitudes and directions at any instants has two components:
i. Radial or centripetal components which is parallel to AB
ii. Tangential component, which is perpendicular to AB
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Radial component of acceleration of B wrt A
Tangential component of acceleration of B wrt A
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Example 4
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