chapter 2 matter and atoms 2.3 mixtures and solutions
TRANSCRIPT
CHAPTER 2
Matter and Atoms
2.3 Mixtures and Solutions
2 2.3 Mixtures and Solutions
A recipe calls for you to “mix until homogeneous.”
What does that mean?
3 2.3 Mixtures and Solutions
A mixture that is uniform throughout.
4 2.3 Mixtures and Solutions
A mixture that is uniform throughout. Different samples may have different compositions.
5 2.3 Mixtures and Solutions
6 2.3 Mixtures and Solutions
What happens when sugar is added to water?
7 2.3 Mixtures and Solutions
What happens when sugar is added to water?
A solution is obtained.
8 2.3 Mixtures and Solutions
Is orange juice a solution?
Hint: Are things dissolved in orange juice?
9 2.3 Mixtures and Solutions
Is orange juice a solution?
It is partially a solution because some chemicals are
dissolved in water, but some bits (like pulp) are not.
10 2.3 Mixtures and Solutions
These four solutions contain the same solvent and solute.
Which one is the most concentrated solution?Which one is the most dilute solution?
11 2.3 Mixtures and Solutions
concentration: the amount of each solute compared to the total solution.
12 2.3 Mixtures and Solutions
• Can you dissolve salt in water?
Variables
Amount of saltAmount of water
13 2.3 Mixtures and Solutions
• Can you dissolve salt in water?
• Can you continue adding more and more salt, and still get a solution?
Variables
Amount of saltAmount of water
14 2.3 Mixtures and Solutions
• Can you dissolve salt in water?
• Can you continue adding more and more salt, and still get a solution?
• Can you dissolve more salt when you increase the temperature?
Variables
Amount of saltAmount of water
Amount of saltAmount of waterTemperature
15 2.3 Mixtures and Solutions
solubility: the amount of a solute that will dissolve in a particular solvent at a particular temperature and pressure.
Solubility of common substances in water at 25oC
16 2.3 Mixtures and Solutions
If the concentration of a sugar solution is 75 g/L, how much solution do you need if you want 10 g of sugar?
17 2.3 Mixtures and Solutions
If the concentration of a sugar solution is 75 g/L, how much solution do you need if you want 10 g of sugar?
Asked: Volume of solution
Given: 10 g of solute and concentration of 75 g/L
Relationships:mass of solute
Liters of solutionconcentration in g L
18 2.3 Mixtures and Solutions
If the concentration of a sugar solution is 75 g/L, how much solution do you need if you want 10 g of sugar?
Asked: Volume of solution
Given: 10 g of solute and concentration of 75 g/L
Relationships:
Solve:
mass of soluteLiters of solution
concentration in g L
100.1 13333
75
gL or
gL
Lm
19 2.3 Mixtures and Solutions
How much menthol do you need to make 10 kg of mouthwash if the concentration of menthol must be 0.05%?
20 2.3 Mixtures and Solutions
How much menthol do you need to make 10 kg of mouthwash if the concentration of menthol must be 0.05%?
Asked: Mass of solute
Given: 10 kg of solution, solute concentration of 0.05%
Relationships: %
100
concentration inmass of solute mass of solution
21 2.3 Mixtures and Solutions
How much menthol do you need to make 10 kg of mouthwash if the concentration of menthol must be 0.05%?
Asked: Mass of solute
Given: 10 kg of solution, solute concentration of 0.05%
Relationships:
Solve:
%
100
concentration inmass of solute mass of solution
0.05%10 0.005
105
0kg kg or g
22 2.3 Mixtures and Solutions
molarity: the number of moles of solute per liter of solution.
( )
( )
amount of solute moles molesmolarity
volume of solvent liters L
molesM
L
23 2.3 Mixtures and Solutions
If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?
24 2.3 Mixtures and Solutions
Asked: The molarity of a solution
Given: The amount of solute (citric acid) and the volume of solution
Relationships:
moles solutemolarity
volume of solution L
If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?
25 2.3 Mixtures and Solutions
Asked: The molarity of a solution
Given: The amount of solute (citric acid) and the volume of solution
Relationships:
Solve: Start by calculating the formula mass of C6H8O7:
moles solute
molarityvolume of solution L
6 12.011 8 1.0079 7 1 192.5. 12999 g mole
If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?
26 2.3 Mixtures and Solutions
Asked: The molarity of a solution
Given: The amount of solute (citric acid) and the volume of solution
Relationships:
Solve: Start by calculating the formula mass of C6H8O7:
Next we calculate the number of moles in 10.0 g of C6H8O7:
moles solute
molarityvolume of solution L
6 12.011 8 1.0079 7 15.999 192.12 g mole
1# 10.0
192.120.0521
molemoles g
gmoles
If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?
27 2.3 Mixtures and Solutions
If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?
Asked: The molarity of a solution
Given: The amount of solute (citric acid) and the volume of solution
Relationships:
Solve: Start by calculating the formula mass of C6H8O7:
Next we calculate the number of moles in 10.0 g of C6H8O7:
Answer:
moles solute
molarityvolume of solution L
6 12.011 8 1.0079 7 15.999 192.12 g mole
1# 10.0 0.0521
192.12
molemoles g moles
g
0.0521
0.5000.104
molesmolarity
LM
28 2.3 Mixtures and Solutions
Ascorbic acid = Vitamin C
Vitamin C acts as a food preservative by reacting with oxygen (O2)
Ascorbic acid
C6H8O6
29 2.3 Mixtures and Solutions
30 2.3 Mixtures and Solutions
How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?
31 2.3 Mixtures and Solutions
Asked: Volume of solution
Given: Concentration (1M) and balanced reaction
Relationships:
According to the balanced reaction we need 2 moles of ascorbic acid for every mole of O2.
moles solute
molarityvolume of solution L
How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?
32 2.3 Mixtures and Solutions
Asked: Volume of solution
Given: Concentration (1M) and balanced reaction
Relationships:
According to the balanced reaction we need 2 moles of ascorbic acid for every mole of O2.
Solve: That means we need 0.04 moles of ascorbic acid:
0.040 4
10.04
moles solute molesvolume L L or
molaritL
Mm
y
moles solute
molarityvolume of solution L
How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?
33 2.3 Mixtures and Solutions
Asked: Volume of solution
Given: Concentration (1M) and balanced reaction
Relationships:
According to the balanced reaction we need 2 moles of ascorbic acid for every mole of O2.
Solve: That means we need 0.04 moles of ascorbic acid:
Answer: 40 mL of the solution contains 0.04 moles of ascorbic acid, which is enough to react with 0.02 moles of oxygen (O2).
0.040 4
10.04
moles solute molesvolume L L or
molaritL
Mm
y
moles solute
molarityvolume of solution L
How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?
34 2.3 Mixtures and Solutions
The air you breathe is a mixture!
35 2.3 Mixtures and Solutions
Air takes up less space under high pressure.
36 2.3 Mixtures and Solutions
Standard
Temperature and
Pressure
molar volume: the amount of space occupied by a mole of gas at STP. It is equal to 22.4 L.
0oC
1 atm
37 2.3 Mixtures and Solutions
Partial pressures
The total pressure in a mixture of gases is the
sum of the partial pressures
of each individual gas in the mixture.
38 2.3 Mixtures and Solutions
Gas A
Gas BGas C
Gas A Gas B
Gas CTotal pressure
=
+
+
Partial pressure of A
Partial pressure of C
Partial pressure of B
Partial pressures
39 2.3 Mixtures and Solutions
If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?
40 2.3 Mixtures and Solutions
Asked: Partial pressure of helium
Given: 75% He and 25% Ne at STP conditionsStandard pressure is 101,325 Pa or 1 atm
Relationships: The total pressure is the sum of the partial pressures of each gas.
If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?
41 2.3 Mixtures and Solutions
Asked: Partial pressure of helium
Given: 75% He and 25% Ne at STP conditionsStandard pressure is 101,325 Pa or 1 atm
Relationships: The total pressure is the sum of the partial pressures of each gas.
Solve: 75,9940.75 101,3
0.75
25
0.75 1
Pa
or
Pa
atmatm
or
If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?
42 2.3 Mixtures and Solutions
Asked: Partial pressure of helium
Given: 75% He and 25% Ne at STP conditionsStandard pressure is 101,325 Pa or 1 atm
Relationships: The total pressure is the sum of the partial pressures of each gas.
Solve:
Answer: The partial pressure of helium is 75,994 Pa or 0.75 atm.
75,9940.75 101,3
0.75
25
0.75 1
Pa
or
Pa
atmatm
or
If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?
43 2.3 Mixtures and Solutions
STP conditions:
Standard
Temperature (0oC)
Pressure (1 atm)
Air is a mixture of gases. Based on Dalton’s law of partial pressures:
2 2...air N O ArP P P P
Concentration of a solution can be expressed in:
mass per volume
mass percent
molarity moles of solute
molarity Mliters of solvent