chapter 2 matter and atoms 2.3 mixtures and solutions

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CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

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Page 1: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

CHAPTER 2

Matter and Atoms

2.3 Mixtures and Solutions

Page 2: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

2 2.3 Mixtures and Solutions

A recipe calls for you to “mix until homogeneous.”

What does that mean?

Page 3: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

3 2.3 Mixtures and Solutions

A mixture that is uniform throughout.

Page 4: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

4 2.3 Mixtures and Solutions

A mixture that is uniform throughout. Different samples may have different compositions.

Page 5: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

5 2.3 Mixtures and Solutions

Page 6: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

6 2.3 Mixtures and Solutions

What happens when sugar is added to water?

Page 7: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

7 2.3 Mixtures and Solutions

What happens when sugar is added to water?

A solution is obtained.

Page 8: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

8 2.3 Mixtures and Solutions

Is orange juice a solution?

Hint: Are things dissolved in orange juice?

Page 9: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

9 2.3 Mixtures and Solutions

Is orange juice a solution?

It is partially a solution because some chemicals are

dissolved in water, but some bits (like pulp) are not.

Page 10: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

10 2.3 Mixtures and Solutions

These four solutions contain the same solvent and solute.

Which one is the most concentrated solution?Which one is the most dilute solution?

Page 11: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

11 2.3 Mixtures and Solutions

concentration: the amount of each solute compared to the total solution.

Page 12: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

12 2.3 Mixtures and Solutions

• Can you dissolve salt in water?

Variables

Amount of saltAmount of water

Page 13: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

13 2.3 Mixtures and Solutions

• Can you dissolve salt in water?

• Can you continue adding more and more salt, and still get a solution?

Variables

Amount of saltAmount of water

Page 14: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

14 2.3 Mixtures and Solutions

• Can you dissolve salt in water?

• Can you continue adding more and more salt, and still get a solution?

• Can you dissolve more salt when you increase the temperature?

Variables

Amount of saltAmount of water

Amount of saltAmount of waterTemperature

Page 15: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

15 2.3 Mixtures and Solutions

solubility: the amount of a solute that will dissolve in a particular solvent at a particular temperature and pressure.

Solubility of common substances in water at 25oC

Page 16: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

16 2.3 Mixtures and Solutions

If the concentration of a sugar solution is 75 g/L, how much solution do you need if you want 10 g of sugar?

Page 17: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

17 2.3 Mixtures and Solutions

If the concentration of a sugar solution is 75 g/L, how much solution do you need if you want 10 g of sugar?

Asked: Volume of solution

Given: 10 g of solute and concentration of 75 g/L

Relationships:mass of solute

Liters of solutionconcentration in g L

Page 18: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

18 2.3 Mixtures and Solutions

If the concentration of a sugar solution is 75 g/L, how much solution do you need if you want 10 g of sugar?

Asked: Volume of solution

Given: 10 g of solute and concentration of 75 g/L

Relationships:

Solve:

mass of soluteLiters of solution

concentration in g L

100.1 13333

75

gL or

gL

Lm

Page 19: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

19 2.3 Mixtures and Solutions

How much menthol do you need to make 10 kg of mouthwash if the concentration of menthol must be 0.05%?

Page 20: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

20 2.3 Mixtures and Solutions

How much menthol do you need to make 10 kg of mouthwash if the concentration of menthol must be 0.05%?

Asked: Mass of solute

Given: 10 kg of solution, solute concentration of 0.05%

Relationships: %

100

concentration inmass of solute mass of solution

Page 21: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

21 2.3 Mixtures and Solutions

How much menthol do you need to make 10 kg of mouthwash if the concentration of menthol must be 0.05%?

Asked: Mass of solute

Given: 10 kg of solution, solute concentration of 0.05%

Relationships:

Solve:

%

100

concentration inmass of solute mass of solution

0.05%10 0.005

105

0kg kg or g

Page 22: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

22 2.3 Mixtures and Solutions

molarity: the number of moles of solute per liter of solution.

( )

( )

amount of solute moles molesmolarity

volume of solvent liters L

molesM

L

Page 23: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

23 2.3 Mixtures and Solutions

If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?

Page 24: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

24 2.3 Mixtures and Solutions

Asked: The molarity of a solution

Given: The amount of solute (citric acid) and the volume of solution

Relationships:

moles solutemolarity

volume of solution L

If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?

Page 25: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

25 2.3 Mixtures and Solutions

Asked: The molarity of a solution

Given: The amount of solute (citric acid) and the volume of solution

Relationships:

Solve: Start by calculating the formula mass of C6H8O7:

moles solute

molarityvolume of solution L

6 12.011 8 1.0079 7 1 192.5. 12999 g mole

If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?

Page 26: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

26 2.3 Mixtures and Solutions

Asked: The molarity of a solution

Given: The amount of solute (citric acid) and the volume of solution

Relationships:

Solve: Start by calculating the formula mass of C6H8O7:

Next we calculate the number of moles in 10.0 g of C6H8O7:

moles solute

molarityvolume of solution L

6 12.011 8 1.0079 7 15.999 192.12 g mole

1# 10.0

192.120.0521

molemoles g

gmoles

If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?

Page 27: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

27 2.3 Mixtures and Solutions

If 10.0 g of citric acid (C6H8O7) is added to 500 mL of water, what is the molarity of the resulting solution?

Asked: The molarity of a solution

Given: The amount of solute (citric acid) and the volume of solution

Relationships:

Solve: Start by calculating the formula mass of C6H8O7:

Next we calculate the number of moles in 10.0 g of C6H8O7:

Answer:

moles solute

molarityvolume of solution L

6 12.011 8 1.0079 7 15.999 192.12 g mole

1# 10.0 0.0521

192.12

molemoles g moles

g

0.0521

0.5000.104

molesmolarity

LM

Page 28: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

28 2.3 Mixtures and Solutions

Ascorbic acid = Vitamin C

Vitamin C acts as a food preservative by reacting with oxygen (O2)

Ascorbic acid

C6H8O6

Page 29: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

29 2.3 Mixtures and Solutions

Page 30: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

30 2.3 Mixtures and Solutions

How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?

Page 31: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

31 2.3 Mixtures and Solutions

Asked: Volume of solution

Given: Concentration (1M) and balanced reaction

Relationships:

According to the balanced reaction we need 2 moles of ascorbic acid for every mole of O2.

moles solute

molarityvolume of solution L

How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?

Page 32: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

32 2.3 Mixtures and Solutions

Asked: Volume of solution

Given: Concentration (1M) and balanced reaction

Relationships:

According to the balanced reaction we need 2 moles of ascorbic acid for every mole of O2.

Solve: That means we need 0.04 moles of ascorbic acid:

0.040 4

10.04

moles solute molesvolume L L or

molaritL

Mm

y

moles solute

molarityvolume of solution L

How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?

Page 33: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

33 2.3 Mixtures and Solutions

Asked: Volume of solution

Given: Concentration (1M) and balanced reaction

Relationships:

According to the balanced reaction we need 2 moles of ascorbic acid for every mole of O2.

Solve: That means we need 0.04 moles of ascorbic acid:

Answer: 40 mL of the solution contains 0.04 moles of ascorbic acid, which is enough to react with 0.02 moles of oxygen (O2).

0.040 4

10.04

moles solute molesvolume L L or

molaritL

Mm

y

moles solute

molarityvolume of solution L

How much (volume) of a 1 M ascorbic acid solution will completely react with 0.02 moles of oxygen (O2)?

Page 34: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

34 2.3 Mixtures and Solutions

The air you breathe is a mixture!

Page 35: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

35 2.3 Mixtures and Solutions

Air takes up less space under high pressure.

Page 36: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

36 2.3 Mixtures and Solutions

Standard

Temperature and

Pressure

molar volume: the amount of space occupied by a mole of gas at STP. It is equal to 22.4 L.

0oC

1 atm

Page 37: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

37 2.3 Mixtures and Solutions

Partial pressures

The total pressure in a mixture of gases is the

sum of the partial pressures

of each individual gas in the mixture.

Page 38: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

38 2.3 Mixtures and Solutions

Gas A

Gas BGas C

Gas A Gas B

Gas CTotal pressure

=

+

+

Partial pressure of A

Partial pressure of C

Partial pressure of B

Partial pressures

Page 39: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

39 2.3 Mixtures and Solutions

If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?

Page 40: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

40 2.3 Mixtures and Solutions

Asked: Partial pressure of helium

Given: 75% He and 25% Ne at STP conditionsStandard pressure is 101,325 Pa or 1 atm

Relationships: The total pressure is the sum of the partial pressures of each gas.

If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?

Page 41: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

41 2.3 Mixtures and Solutions

Asked: Partial pressure of helium

Given: 75% He and 25% Ne at STP conditionsStandard pressure is 101,325 Pa or 1 atm

Relationships: The total pressure is the sum of the partial pressures of each gas.

Solve: 75,9940.75 101,3

0.75

25

0.75 1

Pa

or

Pa

atmatm

or

If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?

Page 42: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

42 2.3 Mixtures and Solutions

Asked: Partial pressure of helium

Given: 75% He and 25% Ne at STP conditionsStandard pressure is 101,325 Pa or 1 atm

Relationships: The total pressure is the sum of the partial pressures of each gas.

Solve:

Answer: The partial pressure of helium is 75,994 Pa or 0.75 atm.

75,9940.75 101,3

0.75

25

0.75 1

Pa

or

Pa

atmatm

or

If 1 L of helium (75%) and neon (25%) is at STP, what is the partial pressure of helium?

Page 43: CHAPTER 2 Matter and Atoms 2.3 Mixtures and Solutions

43 2.3 Mixtures and Solutions

STP conditions:

Standard

Temperature (0oC)

Pressure (1 atm)

Air is a mixture of gases. Based on Dalton’s law of partial pressures:

2 2...air N O ArP P P P

Concentration of a solution can be expressed in:

mass per volume

mass percent

molarity moles of solute

molarity Mliters of solvent