chapter 19 electrochemistry mr. watson hst. mr. watson redox reactions oxidation loss of electrons...
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Chapter 19Chapter 19
Electrochemistry
Mr. Watson HST
Mr. Watson HST
Redox ReactionsRedox ReactionsOxidationloss of electrons
Reductiongain of electrons
oxidizing agentsubstance that cause oxidation by being reduced
reducing agentsubstance that cause oxidation by being oxidized
Mr. Watson HST
ElectrochemistryElectrochemistry
In the broadest sense, electrochemistry is the study of chemical reactions that produce electrical effects and of the chemical phenomena that are caused by the action of currents or voltages.
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Oxidation-Reduction Oxidation-Reduction ReactionsReactions
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Voltaic CellsVoltaic Cells
harnessed chemical reaction which produces an electric current
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Voltaic CellsVoltaic Cells
Cells and Cell Reactions
Daniel's Cell
Zn(s) + Cu+2(aq) ---> Zn+2
(aq) + Cu(s)
oxidation half reaction
anode Zn(s) ---> Zn+2(aq) + 2 e-
reduction half reaction
cathode Cu+2(aq) + 2 e- ---> Cu(s)
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Voltaic CellsVoltaic Cells
copper electrode dipped into a solution of copper(II) sulfate
zinc electrode dipped into a solution of zinc sulfate
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Voltaic CellsVoltaic Cells
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Hydrogen ElectrodeHydrogen Electrode consists of a platinum
electrode covered with a fine powder of platinum around which H2(g) is bubbled. Its potential is defined as zero volts.
Hydrogen Half-Cell
H2(g) = 2 H+(aq) + 2 e-
reversible reaction
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Mr. Watson HST
Mr. Watson HST
Standard Reduction Standard Reduction PotentialsPotentials
the potential under standard conditions (25oC with all ions at 1 M concentrations and all gases at 1 atm pressure) of a half-reaction in which reduction is occurring
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Some Standard Reduction Some Standard Reduction Potentials Table 18-1, pg 837Potentials Table 18-1, pg 837
Li+ + e- ---> Li -3.045 v
Zn+2 + 2 e- ---> Zn -0.763v
Fe+2 + 2 e- ---> Fe -0.44v
2 H+(aq) + 2 e- ---> H2(g) 0.00v
Cu+2 + 2 e- ---> Cu +0.337v
O2(g) + 4 H+(aq) + 4 e- ---> 2 H2O(l) +1.229v
F2 + 2e- ---> 2 F- +2.87v
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If the reduction of mercury (I) in a voltaic cell is desired, the half reaction is:
Which of the following reactions could be used as the anode (oxidation)?
A, B
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Cell PotentialCell Potential
the potential difference, in volts, between the electrodes of an electrochemical cell
Direction of Oxidation-Reduction Reactionspositive value indicates a spontaneous
reaction
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Standard Cell PotentialStandard Cell Potential
the potential difference, in volts, between the electrodes of an electrochemical cell when the all concentrations of all solutes is 1 molar, all the partial pressures of any gases are 1 atm, and the temperature at 25oC
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Cell DiagramCell Diagram
the shorthand representation of an electrochemical cell showing the two half-cells connected by a salt bridge or porous barrier, such as:
Zn(s)/ZnSO4(aq)//CuSO4(aq)/Cu(s)
anode cathode
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Metal Displacement Metal Displacement ReactionsReactions
solid of more reactive metals will displace ions of a less reactive metal from solution
relative reactivity based on potentials of half reactions
metals with very different potentials react most vigorously
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Ag+ + e- --->Ag E°= 0.80 V
Cu2+ + 2e- ---> Cu E°= 0.34 V
Will Ag react with Cu2+?
yes, no
Will Cu react with Ag+?
yes, no
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Gibbs Free EnergyGibbs Free Energyand Cell Potentialand Cell Potential
G = - nFE
where n => number of electrons changed
F => Faraday’s constant
E => cell potential
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Applications of Applications of Electrochemical CellsElectrochemical Cells
Batteries– device that converts chemical energy into
electricity
Primary Cells– non-reversible electrochemical cell– non-rechargeable cell
Secondary Cells– reversible electrochemical cell– rechargeable cell
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Applications of Applications of Electrochemical CellsElectrochemical Cells
BatteriesPrimary Cells
"dry" cell & alkaline cell 1.5 v/cellmercury cell 1.34 v/cellfuel cell 1.23v/cell
Secondary Cellslead-acid (automobile battery) 2
v/cellNiCad 1.25 v/cell
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““Dry” CellDry” Cell
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““Dry” CellDry” Cell
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““Flash Light” BatteriesFlash Light” Batteries
"Dry" CellZn(s) + 2 MnO2(s) + 2 NH4
+ ----->
Zn+2(aq) + 2 MnO(OH)(s) + 2 NH3
Alkaline CellZn(s) + 2 MnO2(s) ---> ZnO(s) + Mn2O3(s)
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““New” Super Iron BatteryNew” Super Iron Battery
Mfe(VI)O4 + 3/2 Zn 1/2 Fe(III)2O3 + 1/2 ZnO + MZnO2
(M = K2 or Ba)Environmentally friendlier than MnO2 containing batteries.
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Mercury CellMercury Cell
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Lead-AcidLead-Acid(Automobile Battery)(Automobile Battery)
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Lead-AcidLead-Acid(Automobile Battery)(Automobile Battery)
Pb(s) + PbO2(s) + 2 H2SO4 = 2 PbSO4(s) + 2 H2O
2 v/cell
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Nickel-Cadmium (Ni-Cad)Nickel-Cadmium (Ni-Cad)
Cd(s) + 2 Ni(OH)3(s) = Cd(OH)2(s) + 2 Ni(OH)2(s)
NiCad 1.25 v/cell
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Hydrogen-Oxygen Fuel CellHydrogen-Oxygen Fuel Cell
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Automobile Oxygen SensorAutomobile Oxygen Sensor
Air, constant [O ]2
porous Pt electrodes
migrating O ions2-
measured potential difference
exhaust gas, unknown [O ]2
ZrO / CaO2
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Automobile Oxygen SensorAutomobile Oxygen Sensor
see Oxygen Sensor Movie from Solid-State Resources CD-ROM
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pH = (Eglass electrode - constant)/0.0592
pH MeterpH Meter
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Effect of Concentration on Cell Effect of Concentration on Cell Voltage: The Nernst EquationVoltage: The Nernst EquationEcell = Eo
cell - (RT/nF)ln Q
Ecell = Eocell - (0.0592/n)log Q
where Q => reaction quotient
Q = [products]/[reactants]
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EXAMPLE:EXAMPLE: What is the cell potential for What is the cell potential for the Daniel's cell when the the Daniel's cell when the [Zn[Zn+2+2] = 10 [Cu] = 10 [Cu+2+2]] ??
Q = ([ZnQ = ([Zn+2+2]/[Cu]/[Cu+2+2] = (] = (10 [Cu10 [Cu+2+2])/[Cu])/[Cu+2+2]] = 10 = 10
EEoo = (0.34 V) = (0.34 V)Cu coupleCu couple + (-(-0.76 V) + (-(-0.76 V)Zn coupleZn couple
n = 2, 2 electron changen = 2, 2 electron change EEcellcell = E = Eoocellcell - (0.0257/n)ln Q - (0.0257/n)ln Q
thus Ecell = (1.10 - (0.0257/2)ln 10) V
Ecell = (1.10 - (0.0257/2)2.303) V
Ecell = (1.10 - 0.0296) V = 1.07 V
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Nernst EquationNernst Equation
+0.83 V
salt bridge
H in2
1 atm
voltmeter
Pt electrode
Pt electrodeNaOH
1 M
H in2
1 atm
e– e–
anode (–)
HCl 1 M
cathode (+)
pn+
+
+
+
–
–
–
–
[H+]acid side [H+]base side
E = Eo – RTnF ln Q =
– 2.3 RTF log
[H+]base side[H+]acid side
[h+]p-type side [h+]n-type side
E (in volts) = – 2.3 RT
F log [h+]n-type side [h+]p-type side
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ElectrolysisElectrolysis
non-spontaneous reaction is caused by the passage of an electric current through a solution
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Electrolysis of KIElectrolysis of KI(aq)(aq)
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ElectrolysisElectrolysis
Electrolysis of Sodium chloride
(chlor-alkali process)
molten reactants => liquid sodium and chlorine gas
aqueous reactants => caustic soda (sodium hydroxide) and chlorine gas
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Aqueous Reactants => Aqueous Reactants => caustic soda (sodium hydroxide) and chlorine caustic soda (sodium hydroxide) and chlorine
gasgas
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Molten Reactants =>Molten Reactants =>liquid sodium and chlorine gasliquid sodium and chlorine gas
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ElectrolysisElectrolysis
Preparation of Aluminum (Hall process)
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Electrolytic Refining of Electrolytic Refining of CopperCopper
Cu(s) + Cu+2(aq) --> Cu+2
(aq) + Cu(s)
impure pure anode cathode
impurities: anode mud; Ag, Au, Pb
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Copper PurificationCopper Purification
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Copper PurificationCopper Purification
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Hall Process for AluminumHall Process for Aluminum
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Quantitative Aspects of Quantitative Aspects of ElectrolysisElectrolysis
1 coulomb = 1 amp sec1 mole e- = 96,500 coulombs
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ElectroplatingElectroplating
EXAMPLE: How many grams of chromium can be plated from a Cr+6 solution in 45 minutes at a 25 amp current?
Mr. Watson HST
ElectroplatingElectroplating
EXAMPLE: How many grams of chromium can be plated from a Cr+6 solution in 45 minutes at a 25 amp current?
(45 min)#g Cr = ------------
Mr. Watson HST
ElectroplatingElectroplating
EXAMPLE: How many grams of chromium can be plated from a Cr+6 solution in 45 minutes at a 25 amp current?
definition of minute
(45 min)(60 sec)#g Cr = ---------------------
(1 min)
Mr. Watson HST
ElectroplatingElectroplating
EXAMPLE: How many grams of chromium can be plated from a Cr+6 solution in 45 minutes at a 25 amp current?
(45) (60 sec) (25 amp)#g Cr = ---------------------------
(1)
Mr. Watson HST
ElectroplatingElectroplating
EXAMPLE: How many grams of chromium can be plated from a Cr+6 solution in 45 minutes at a 25 amp current?
definition of a coulomb
(45)(60 sec)(25 amp)(1 C)#g Cr = -----------------------------
(1) (1 amp sec)
Mr. Watson HST
ElectroplatingElectroplating
EXAMPLE: How many grams of chromium can be plated from a Cr+6 solution in 45 minutes at a 25 amp current?
Faraday’s constant
(45)(25)(60)(1 C)(1 mol e-)#g Cr = ----------------------------------
(1)(1)(96,500 C)
Mr. Watson HST
ElectroplatingElectroplating
EXAMPLE: How many grams of chromium can be plated from a Cr+6 solution in 45 minutes at a 25 amp current?
atomic weight
(45)(60)(25)(1)(1 mol e-)(52 g Cr)#g Cr = -------------------------------------------
(1)(1)(96,500) (6 mol e-)
Mr. Watson HST
ElectroplatingElectroplating
EXAMPLE: How many grams of chromium can be plated from a Cr+6 solution in 45 minutes at a 25 amp current?
(45)(60)(25)(1)(1 mol e-)(52 g Cr)#g Cr = -------------------------------------------
(1)(1)(96,500)(6 mol e-)
= 58 g Cr
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Rusting of IronRusting of Iron
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CorrosionCorrosion
O2(g) + 4 H+(aq) + 4 e- -----> 2 H2O(l)
Eo = 1.23 V
RustingFe(s) -----> Fe+2
(aq) + 2 e- Eo = 0.44 V
O2(g) + 4 H+(aq) + 4 e- -----> 2 H2O(l) Eo = 1.23 V
------------------------------------------- --------------2 Fe(s) + O2(g) + 4 H+
(aq) ----->
2 H2O(l) + Fe+2(aq) Eo = 1.67 V
Mr. Watson HST
Preventing CorrosionPreventing Corrosion
painting
galvanizing
sacrificial anode