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Page 1: Chapter 13 Slides - UCA€¦ · Chapter 13 Slides SU2014 CHEM1451. 0.000 0.500 1.000 1.500 2.000 2.500 3.000 3.500 0 20 40 60 80 100 120 140 160 180) time(s) ... 12.0 1 0.8 0.6 0.4

Chapter 13 SlidesSU2014 CHEM1451

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Co

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Time dependence of component concentration for the reaction:A+2B → 3C+D

[A] [B] [C] [D]

Note that the rate of concentration change slows as the reaction progresses.

STOICHIOMETRY!

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Time dependence of component concentration for the reaction:A+2B → 3C+D

[A] [B] [C] [D]

Zoom in!

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nce

ntr

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Time dependence of component concentration for the reaction:A+2B → 3C+D

[A] [B] [C] [D]

time [A] [B] [C] [D]0 1.000 2.000 0.000 0.0005 0.882 1.765 0.353 0.118

10 0.779 1.558 0.664 0.22115 0.687 1.375 0.938 0.313

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0 5 10 15 20 25 30 35 40

Co

nce

ntr

atio

n (

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time(s)

Time dependence of component concentration for the reaction:A+2B → 3C+D

[A] [B] [C] [D]

time [A] [B] [C] [D]0 1.000 2.000 0.000 0.0005 0.882 1.765 0.353 0.118

10 0.779 1.558 0.664 0.22115 0.687 1.375 0.938 0.313

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Reaction Rate Terms

• Reaction Rate is one positive number. You can calculate a specific rate of formation or consumption from that number.• Always units of concentration per unit time (M/s)

• Average Rate vs. Instantaneous Rate

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Things that Affect Reaction Rate

• Reactant Concentration

• Temperature

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A→Products Rate=k[A]x

0.5, 2.5

0.0

2.0

4.0

6.0

8.0

10.0

12.0

00.20.40.60.81

Re

acti

on

Rat

e (

M/s

)

Concentration of A (M)

The reaction order changes how the reaction rate depends on reactant concentration

Zero Order Rate =k[A]0

First Order Rate =k[A]1

Second Order Rate =k[A]2

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Writing a Rate Law

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How to Determine the Reaction Order

• You can only determine a reaction rate experimentally!

• Two common ways:1. Method of Initial Rates

• (Effect of Concentration on the rate)

2. Integrated Rate Laws• (Effect of time on the reactant concentration)

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Find the rate law and the value for the rate constant (k) using the data above.

Step 1: Write the rate law for the reaction using place holders for order and for k.

Rate = k[NO2]x[CO]Y

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Step 2: Examine the data and determine relationships between the experiments.

Step 3: Use those relationships to deduce the values for the orders with respect to the specific reactants. (Solve for X and Y)

Step 4: Determine a value for the rate constant(k) and include units.

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1)

2)

3)

4)

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Determine the rate law and the value of k for the following reaction using the data provided.

2 NO(g) + O2(g) → 2 NO2(g)

[NO]i (M) [O2]i (M) Initial Rate (M/s)

0.030 0.0055 8.55 x 10-3

0.030 0.0110 1.71 x 10-2

0.060 0.0055 3.42 x 10-2

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Integrated Rate Laws

• Experimentally, you follow a concentration of a reactant from the beginning of a reaction until the reaction slows.

• A second method for determining reaction order and k. For the SAME reaction, these methods would produce the SAME results.• Why do this another way?

• Often, it is experimentally easier to do this.

• Get all the info from one run.

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[𝐴]𝑡= −𝑘𝑡 + [𝐴]0

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𝑙𝑛[𝐴]𝑡 = −𝑘𝑡 + 𝑙𝑛[𝐴]0

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1

[𝐴]𝑡= 𝑘𝑡 +

1

[𝐴]0

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y = -0.0039x + 0.9034R² = 0.9545

y = -0.0078x - 0.0002R² = 1

y = 0.0183x + 0.636R² = 0.9546

-2

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1

2

3

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0 50 100 150 200

Time (s)

[N2O5] ln[N2O5] 1/[N2O5]

Linear ([N2O5]) Linear (ln[N2O5]) Linear (1/[N2O5])

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Half-Life

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Equations provided on the exam

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If the concentration of a reactant is 6.25%, how many half-lives has it gone through?

A) 7

B) 6

C) 3

D) 4

E) 5

The rate constant for the first-order decomposition of N2O is 3.40 s-1. What is the half-life

of the decomposition?

A) 0.491 s

B) 0.204 s

C) 0.236 s

D) 0.424 s

E) 0.294 s

The half-life for the second-order decomposition of HI is 15.4 s when the initial

concentration of HI is 0.67 M. What is the rate constant for this reaction?

A) 1.0 × 10-2 M-1s-1

B) 4.5 × 10-2 M-1s-1

C) 9.7 × 10-2 M-1s-1

D) 2.2 × 10-2 M-1s-1

E) 3.8 × 10-2 M-1s-1

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The Effect of Temperature on the Reaction Rate

𝑘 = 𝐴 ∙ 𝑒−𝐸𝑎𝑅𝑇

Frequency FactorExponential Factor

𝐴 = 𝑝 ∙ 𝑧

• Orientation Factor: “p”– the fraction of collisions that are

actually successful due to colliding in the correct way.

– NOT temperature dependent!• Collision frequency: “z”

– The number of collisions per unit time. Can be calculated.

– VERY temperature dependent!

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Orientation Factor

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The temperature doesn’t change the Ea, BUT it changes how many molecules have enough thermal energy to get over the barrier.

Think about what would make an activation barrier large or small…

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Rate=k[A]X[B]Y

• Reaction Order can be only be determined experimentally!

1. Method of Initial Rates2. Integrated Rate Laws

• But, either way, these would give you the SAME result.

• Reaction order is Temp-independent.

• The rate constant is calculated using the Method of Initial Rates or the Integrated rate law.

• BUT, unlike order, these are very temperature dependent!

• After they are measured at many temperatures, you can use the Arrhenius equation to relate temperature to the rate constant.

• The Arrhenius equation describes how increasing thermal energy increases rate by increasing the number of collisions (A), and by increasing the number of collisions that have enough energy to overcome the activation energy.

The Reaction rate can be related to the rates of formation or consumption of individual species

through stoichiometry.

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Mechanisms: One collision at a time…

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Energy Diagrams for mechanisms

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The effect of a Catalyst

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Types of Catalysts

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Hydrogenation of ethene

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Biological Catalysts: Enzymes