chapter-01 - matrices and determinants

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  • 8/2/2019 Chapter-01 - Matrices and Determinants

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    Topic: Algebra Sub-topic: Matrices and Determinants

    Very Short Answer Questions

    1Obj! Spec!Difflevel

    1 2 3 7 20 29 KGiven that A = = 2 5 7 and I : l . ' = 2 5 7 without Easy

    3 9 13 3 9 13expanding, prove that A = = A' .

    Hint/Key:Take R: 7 R, + 2R;" for A.2

    If A = [ n f i n d A A ' .Hint/Key:

    A A ' = U

    KEasy

    2 3 ]4 66 9

    3 . d . [ 1in the inverse of the matrix 2Hint/Key:1 [ 0 3 ]6 -2 1

    UEasy

    4 If A [3 - X Y - 3 ] . al . F' d d:::: 0 2 IS a sc ar matnx. m X an y.HintlKey:x =1 andy=3.

    KEasy

    5 If A = U ~ l B = [ ~ a find A - y, B.HintlKey:[ : ~]

    KEasy

    115

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    6 KEasy

    HintIKey :IABI=-l.7 [ 1 1 ] 4If A = 1 1 ' then find A . KEasy8 I f A = = [ 0 2 ] is skew symmetric, find x and y.y x+4 KEasy

    HintlKey : x = = 4 an~ y = = -2.9 U

    E a s ya 1 b+cProve that b 1 c + a =O.c 1 a+b

    HintIKey: Expect C: -7 C1 + C2 + C3 and then a = O .10 If A ~ [~] and B ~ [1 6 7]. find AB.

    HintIKey:A B ~ [ 1 63 18

    UE a s y

    11 Find a matrix X such that 2A - 3B +X = 0 whereA=[O 3] B=[-2 1]2 5 ' 0 4

    UEasy

    HintIKey:X = [ - 6 - 3 ]-4 2

    12 A is a matrix of order 3 x 4 and B is a matrix of order 4 x 2. KWhat is the order ofrnatrix AS'?HintIKey: AS' does not exist

    E a s y

    1 1,:;;

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    13[-1IfA= 3

    HintIKey :2 ] B _ _[ - 1 2x + 1 ] .1 andB=A'. Fmdx.1 ' 2xx=1

    KE a s y

    [6 X - X 2 ] UFind the value for x for which the matrix 3 has no E a s yinverse.HintIKey: x =-2.

    14

    15[ a c d b ] , B = [0 1 01].ind the adjoint of (AB) where A =

    HintIKey :

    [: ~ ]Adj (AB) = [~c16 IfB + A = [ 1 - 1 3 ] , B _ A = [ 2 3 2 1 ] . Find B.23434

    HintIKey:

    Short Answer Questions17 If A = [~ ~ ] and IA'I = 125, find the value ofa.

    HintIKey:IAI=a2-4Given, 1 A31 = 125 => 1 A 13 = 125(a3 -4/ =125a2-4= 5a=3

    18 If A and B are square matrices of the same order andA, then evaluate AB and BA.HintIKey:Given, B" 1 =AOperating B on both sides, we get AB =BA = 1.

    KE a s y

    KE a s y

    KAverage

    S-1 = KE a s y

    1 1 '7

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    19 abc a+2b b cIf Al = x Y Z , A2 = x+2y Y z and also Al : ; < ! : 0,

    P q r p+2q q rAA2 ' * 0, then find _A2

    HintIKey:In A2 , operate el 7 C, - 2C2to get Al = A2

    20 If A = [ 2 -1] , prove that A2 - 4A + 31= O.-1 2HintIKey:Find A2, Then substitute in A2 - 4A + 31.RHS=O,

    21

    HintIKey :2x = -, y= -2,3

    22If2A+B~ [~ !~l3A +2B~ [~ ~ afind A' and B',HintIKey:

    A ' = [~ ~ ] , B ' = [~ _ 1 6 ]1 - 5 -1 10

    23

    HintIKey:x = I, Y= 1 and z =-3.

    24 For positive values ofx,y, z evaluate1 log",y log", z

    logy x 1 logy zlog, X log, y 1

    KEasy

    KEasy

    UEasy

    KEasy

    KEasy

    uDifficult

    110

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    HintIKey:Use properties of logarithms.ORReplace1 -7 log, x in R!1 -7 log.y in R21 -7 log.z in R)and use properties of determinant.

    25 UAverage

    HintlKey:Use mathematical induction

    26is independent of 9.

    x sine cose UAverageProve that - sin B - x Icose' 1 x

    HintIKey:By expanding such that result does not contain 8.

    27 [ 1 - 1 ] [ 2fA= andB=2 3 -1HintIKey :(AB)"i = . ! . [ 05 1

    KEasy], find (AB)"!.-2

    28is singular. Find x.

    UEasyIfthe matrix

    HintIKey: x =329 Find the eigen values of the matrices

    a) [-83

    -72]. b) [~ :]

    HintIKey:a) 1..=-1,1. .=5b ) 1 ..= -1 ,1 ..= 5

    KEasy

    30 Solve by using Cramer's rule: x + 3y =5, 2x - y = 3. KEasyHintIKey: x =2 , Y = 1

    1 1(l

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    31 Solve the equations using matrix method5x + 2y =4, 7x + 3y = 5HintIKey:x =2, y = -3.

    KEasy

    32 If A is a square matrix of order 2 x2, then show that AA' and UA' A are both symmetric. Easy

    If A ~ [~ !]nd B ~ [-24 :3] prove that AB is a null : t . . ymatrix.

    33

    34

    35If MBC of [ l+s~nA

    sin A + sin? AProve that AABC is isosceles.HintIKey:

    1l+sinB

    sinB+sin2 B1 ]+sinC =0

    sin Cu- sin ' C

    /:1= [ S ~ A S ~ B S i ~ C ]sin 2 A sin 2 B sin 2 C

    =(sin A - sin B) (sin B - sin C) (sin C - sin A) =0~A=BorB=C.

    KAverage

    UAverage

    36 If A is amatrix of order 3 x 3 and det IA 1 = 6, find IA-II and KI adj A I . EasyHintIKey: IA-I I = 6 and I adj (A) I =36.

    37 Ifthe characteristic equation of a matrix is ' ) , , 1 + 3 A - 2 =0. FindAI in terms of A.

    38 1 cosA sinAProve that 1 cos B sin B =

    1 cosC sinC. B - C . C - A . A-B4 sm . Sin . sm --2 2 2

    UAverageUAverage

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    Long Answer questions39 Ifthe maximum and minimum values of determinant A

    l+sin" x cos? x sin2x Averagesin? x 1+cos ' x sin2x are a and p ,sin? x cos' x l+sin2x

    find a2 + p 2 .HintlKey:C1 7 C1 +C2R2 -7 R2-R.:. d= 2 + sin 2x

    40 Verify Cayley Hamilton theorem [: ~ll Hence find itsinverse.HintlKey:Inverse ~ ~ [~l:]

    AAverage

    41 Solve by matrix method 3x - y + 2z =13, 2x + Y- z =3, x + U3y - 5z =-8. AverageHintIKey:x =3, Y =-2 , z = 1

    42 Using Cayley Hamilton theorem, find the inverse ofA =[~ -2

    2 _ 1]. Hence find A3 0 -2HintIKey:Characteristic roots ' ) . . _ J - ' ) . . ? - 4 t . . + U = O.:. A3 =A2 + 4A-4 IA-I = -1 [A2-A-4I]

    4-148o

    UAverage

    1'l1

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    43V,erify Cayley Hamilton Theorem for [ ~

    -2

    13-4

    HintIKey:Find characteristic equation.Verify C.H.T. substituting A by A.

    44 -be b2 +bc e2 + beProve that a2 +ae -ae e2 +ae = = (ab + bc + ca)3

    a2 +bc b2 +ab - abHintlKey: Multiply RJ R2 R3 by a . b. c respectively.Taking a, b, c from Cr, C2, C3.

    45[

    y+z xFind k if y z +xz z

    ; ] = k ( X Y Z )x+y

    HintIKey: k =-4Evaluate using properties of determinants.

    46[ 1 1 1 ]IfA = 1 1 1 , show that A2=3A hence deduce that A4 =1 1 1

    27A and A' -A =2A (A + I).HintlKey :Multiplication of A and B =3A.

    :. A4=9A2=27AA3 -A=A (A2)-A = 2A2 + 3A-A=2A (A + I)

    47 (b+C)2 ab eaProve that ab (e+a)2 be =2 abc (a+b+c)3

    ca be (a + b)2HintIKey:Hint: Multiply RJ R2R3by a,b,c and taking abc from cr, C2,C3

    48

    UAverage

    UDifficult

    UEasy

    UAverage

    UAverage

    uDifficult

    KEasy

    1 ' l ' l

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    49

    50

    51

    52

    HintIKey:

    Find A2 , then A3 = [ 537

    -90

    IIpuc

    1 a a2 - beProve that 1 b b 2 ca = O.

    1 c e2-abHintIKey:R2 ~ R2-RR3 ~ R3-RJ

    [cosx

    IfF(x) = s~x-smxcosx

    o ~how that F(x) F(y) ~ F(x+y)Hint/Key: Show by actual multiplication of two matrices.f(x) . f(y) = Qx + y)

    2aProve that

    a-b-c2b2c

    2ab - c - a 2b = (a+ b + c/

    2e 2c

    a+b b+e e+a cabProve that c + a a +b b +c = 2 b c a withoutexpansion.

    b+c c+a a+b abc

    Hint/Key: C1 7 CJ + C2 + C3Take 2 from CJ then C1 7 C1 - C2 ..53 x + 1 x + 2 x + aShow x+2 x+3 x+b =Owherea,b,careinA.P.

    x+3 x+4 x+cHintIKey: R2 ~ 2R2 then R2 ~ R2 - (R\ + R3)

    54 Ifa,h,c are pth, qth, rth terms ofG.P. Prove that

    UAverage

    KEasy

    UAverage

    UAverage

    ADifficult

    uDifficult

    . . . . "

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    1 p loga1 q 10gb = 01 r loge

    Hint/Key:a =ARP-Jb =ARq-lC = ARr-1Apply log substitute log a log b.

    55 UAverage-be ab+ac ac+abProvethat ab+bc -ae bc+ab = (ab +bc s-acj'ac+bc bc+ ac -ab

    56 Find the general solution for x.1 cos 2x sin 2x1 cos5x sin5x = O .1 cos7x sin 7x

    AAverage

    Hi t/K 4' . 5x . 3x 0lD ey : sm x . sm - . sm - =2 2.'. x = nn, 2 n 1{ , 2 n 1{ , n E Z.5 3

    57 p b e uIfa#- b, b q. c r, and a q e =0, then find the value of Difficult

    a b rp q r--+--+--.p -a q - b r - c

    HintIKey:Operate Rll -7 R J -7 R2 and then R~ -7 R2 -7 R3 to getb-a b-q 0

    o q-b c-r =0a b r

    Expanding along C1 and simplify to getr b a-- +-- +-- =0r - c q - b p-aAdd '2' on both sides, to get the value 2.