CCC-1501 Section I

1.

Answer: A. 252 Solution: In 100 - 199, all 100 numbers contain digit '1'.

In all remaining 8 ranges i.e. 200 - 299, 300 - 399, ...., 900 - 999, there are exactly 19 numbers in each i.e. 8*19 = 152 in all. So total 100 + 152 = 252 three digit numbers are there such that at least one of their digits is 1.

2.

Answer: D. 5 : 8

Solution: 3(twoots) = 4(tweets) i.e.

And 5(tweets) = 6(twits) i.e.

.

So

.

3.

Answer: C. 7

Solution: 5! + 6! + 7! = 5!(72)

Now 5! contains prime factors up to 5 only. So largest prime factor of the expression is 7.

4.

Answer: B. 20

Solution: Number of coins that could be produced is = 5(10/5)(10/5) = 20.

5.

Answer: B. 2014

Solution: (251005)(93)(41006) = (22010 * 52010) (22 * 93) = 2916*102010 = 2916 ⏟

i.e. a 2014

digit number.

6.

Answer: C. 45

Solution: ABD - ACB = BAC = 90

And BEC = EBD - ECB = ½ABD - ½ACB = ½(90) = 45.

7-10:

7.

Solution: Average annual percentage increase = (28-8)/8*1/3*100=83.33%

8.

Solution: 1999-2000—4/3 times

2000-2001—11/8 times

2001-2002—12/11 times

Clearly 11/8 shows the maximum increase.

9.

Solution: Average sale of We the Living =(7+10.5+17.5+21)/4=14

So the required difference would be = 14-10.5=3.5

10.

Solution: We the living , showed the maximum increase in sales from the year 2000-2001 which is

66.67%

11. Answer: D. 80 Solution: Last two digits of a product depends only on the last two digits of all the numbers.

So we need last two digits of 15*27*52*03 = (5*3)(27)*(2*26)(03) = (5*2)(3*27*26*3) i.e. 80

12. Answer: D. 18 Solution: WXZ and ABC are similar triangles such that

i.e.

So BC = 18.

13. Answer: C. Loss of 10 rupees Solution: Cost price of first article = C1 = 120/1.2 = 100,

Cost price of second article = C2 = 120/0.8 = 150. So total cost price of two articles = C1 + C2 = 100 + 150 = 250 rupees,

While total selling price of the two articles = 120 + 120 = 240 rupees Thus overall there is a Loss of 250 – 240 = 10 rupees.

14. Answer: D. 37.5%

Solution: Let’s say there are 100 males in the locality, so as per given situation, 75 of the males are married.

Now, according to custom of the locality, these 75 males are married to 75 females of the locality only. That means 75 married females constitute 25% of all the females in the locality. Hence total

number of females in the locality is 75(100/25) = 300.

So out of total 400 adults (i.e. 100 males + 300 females), exactly 150 (i.e. 75 males + 75 females) are married.

Hence required percentage is = (150 100)/400 = 37.5%

15. Answer: D. 0

Solution: 32 = 25 and 632 = 232 332. Thus 632 is divisible by 32 and required remainder is zero.

16.

Answer C. 4

Solution: ADE is 30-60-90, so AE = 2 AD = 4 and CE = AC – AE = 6 – 4 = 2.

Also FEC = 180 - 30 - 90 = 60. So FEC is equilateral i.e. FE = 2.

So AD = FE, also AD || FE because AD DE and FE DE.

Hence ADFE is a parallelogram and DF = AF = 4.

17-20:

17.

Solution: No of Voters favouring AJP in Opinion Poll 1 = 50%of 15600 =7800

No of Voters favouring AJP in Opinion Poll 1 = 58.33%of (15600+ 3600)=7/12*19200=11200

Clearly 11200 is 43.5% more than 7800.

18.

Solution: The vote distribution would be as

Poll1

Poll2

AJP 7800 11200

BDK 6500 6400

CGR 1300 1600 Considering that the 6400 people are same who were in fovour of BDK but the 100 people who did

not favour BDK in opinion poll 2 move in favour of CGR.

Thus voters shifting from BDK to AJP could also be 0.

19.

Solution:

Poll1 Poll2 Election

AJP 7800 11200 47500

BDK 6500 6400 32250

CGR 1300 1600 7250

Total votes 87000

% polling

87000/144000*100 60.41666667

20.

Solution: 47500-32250=15250

21. Answer: A. 180

Solution: Let the two positive integers be hx and hy such that HCF(x, y) = 1. So HCF(hx, hy) = h and LCM(hx, hy) = hxy Now, as per given information, we have

hx + hy = h(x + y) = 27, and h + hxy = h(1 + xy) = 63

Clearly ‘h’ has to be a factor of 27 and 63, so ‘h’ can be 9 or 3 or 1 only. Putting the values of h, we get that only h = 3 satisfies and x, y are 4, 5.

So the required product is = (34)(35) = 180.

22.

Answer: D. 50

Solution: The difference between score of top 5 scorers and bottom 5 scorers is = 5 10 = 50. As there are total of 9 test takers only, so lowest scorer of top 5 and top scorer of bottom 5 is same

person. Thus the difference between the score of top four students and bottom four students is same as earlier i.e. 50.

23. Answer: D. None is prime.

Solution: an + bn is divisible by a + b if n is ODD. I. 410 + 1 = (42)5 + 1 is divisible by 42 + 1. II. 411 + 1 is divisible by 4 + 1.

III. 412 + 1 = (44)3 + 1 is divisible by 44 + 1. Thus none is prime.

24.

Answer: A. 13

Solution: TG0TG = TG 1001 = TG 7 11 13. 7, 11, 13 are consecutive prime numbers, so TG (a two digit number) must be product of two prime

numbers so that all five prime numbers are consecutive.

So TG can be 17 5 = 85 OR 5 3 = 15. That is, T + G can be 8 + 5 = 13 OR 1 + 5 = 6.

25.

Answer: D. 100% Solution: Let the label price be 100 rupees. So I was to pay 1% i.e. 1 rupee. And now at 98% discount, I am paying 2% i.e. 2 rupees.

Effectively I am paying (2 - 1)*100/1 = 100% extra.

26. Solution: The shopkeeper sells the mixture at Rs 35/kg and earns a profit of 25%, so the cost price of the mixture is 35/1.25 = Rs 28/kg.

Now we have to determine the ratio in which Rs 24/kg sugar must be mixed with Rs 40/kg sugar so that the average price of the mixture is Rs 28/kg.

Thus, they must be mixed in the ratio of 3:1.

27-30:

27:

Solution:

Total revenue in 1996 = 95.4 (Rs in crores)

Total revenue in 2000 = 133.6 (Rs in crores)

Total growth rate (from 1996-2000) =

Simple annual growth rate = (40.04)/4 = 10.01 % { As number of intervals is equal to 4}

28:

Solution: In this problem we simply have to compare which fraction is highest.

Year Percentage Change

1996-1997 {4.6/18.2} * 100

1997-1998 { 1.8/22.8} * 100

1998-1999 {8.8/24.6}*100

1999-2000 { 5.2/28.6} * 100

Just by looking at these fractions we can say first is greater than the second. Now the third is

approximately equal to 1/3 and the fourth approximately equal to 1/5. Also the first is

approximately equal to ¼. So definitely 1/3 is the greatest and so the year 1998-1999 experienced

the maximum percentage change in revenue generated by the health care segment.

29:

Solution:The total revenue in 2000 was 133.6 ( in crores of Rupees)

Revenue from FMCG sector in 2000 was 45.8 ( in crores of rupees)

Revenue from cooking oil in 2000 was 0.15* 45.8 = 6.87 (in crores)

Percentage represented by cooking oil in the total revenue in 2000 = 5.14%

30:

Solution: Percentage increase in the total revenue from 1999-2000 is equal to approximately 10.8%

So the total revenue in 2001 = 1.108 * 133.6 = 148 { Approximately}

Revenue from FMCG segment in 2001 = 1.2 * 45.8 = 55 { App}

Revenue from perfumes and deodorants in 2001 = 0.24 * 55 = 13.2 crores

31.

#18. Answer: D. 11.11% profit Solution: Let cost price of 1000g of goods be 1000 rupees. As per given conditions, the shopkeeper sells 900g of goods for 1000 rupees.

So his profit percentage = (100/900)*100 = 11.11% profit.

32. Answer: D. 52 Solution: Last two digits of 2^21 = Last two digits of (2^10)(2^10)(2) = Last two digits of

(24)(24)(2) = 52.

33.

Solution: The amount of curd in first lassi would be 2/5th of 500 = 200 ml.

The amount of curd in second lassi would be 1/6th of 1500 = 250ml.

So, total curd in the final lassi would be 450 ml. Rest 1550 ml would be water.

Thus the required ratio would be 9:31.

34.

Solution:

Buying 50 apples is equivalent to buying 80 bananas.

Thus buying 50 apples and 20 bananas is equivalent to buying 80+20=100 bananas.

Four every 4 banans I buy I would get 1 free.

Hence I would get 25 bananas free with 100 bananas I buy.

35.

Solution: The centre of circle is (-4,3). The distance between the centre of the circle and the

tangent must be equal to the radius of the circle.

Distance of (-4,3) from 3x + 4y + 10 = 0 is

√

So radius of the circle is 2.

So √ or √

Or k = 21

Thus, option (3) is correct.

36. Solution:

Area of a triangle = abc/4R = 1*base*height 3*4*BC/4R = 1/2*BC*2

R=3

37.

Solution: Let the price of the article be P.

Thus P(1+x/100) (1-x/100)=3P/4

x=50 thus x/2=25

Now P(1+25/100)(1-25/100)=P*5/4*3/4=15/16*P

38.

Solution- Let ABC= x and ACB = y

O is the incenter of ABC, so OBC=

, similarly D is the incenter of OBC, so DBC=

.

Similarly DCB=

.

In ABC, x+y+20= 180, so x+y= 1600

In BDC,

+

+ BDC = 1800

After solving and Putting x+y= 160, BDC= 1400

Answer option (C)

39. Solution: The line intersects the X and Y axis at A and B. So, the coordinates of A and B are (15,0)

and (0,8). The coordinates of O are (0,0). Now ΔAOB is right angled triangle. The orthocentre of a right triangle is the point of intersection of the perpendicular sides i.e O. Also the circumcentre is

the midpoint of hypotenuse of a right triangle. Also the circumcentre is equidistant from the three vertices of a right triangle. Thus, the distance between the orthocentre and the circumcentre is

equal to half of the hypotenuse i.e. equal to 8.5 units.

40.

Solution- L.C.M of N1 and N2 is 275 363 570

but L.C.M of N1, N2 and N3 is 275 363 571

So N3 must contain only 571. So total number of solutions= 76 64= 4864. Answer option D.

41.

Solution

So , In triangle DEF, 4x + 4x + 60= 180

8x= 120

X= 150

Answer option (C)

42.

Solution- All numbers which have exactly 5 factors must be in form of a4 where a is the prime

number.

24, 34 and 54 are the only numbers less than 1000 and have 5 factors.

43.

Solution- (11)2+ (22)3+ (33)4+ (44)5+…………… (99)10= (22- 1) + (32- 1) +(42- 1)+ (52-

1)+……..(102-1)

= (12+22+ 32+ 42+52………. +102) – 10 =

44.

Solution- L B= 2(L+ B), (L-2) (B-2) = 4

(L-2) (B-2)= 4 1

2 2

Two pairs (6,3) and (4,4) are possible

45.

Solution- L.C.M of two numbers = 331, H.C.F of two numbers = 31

As H.C.F is not the factor of L.C.M so these type of two numbers can’t exist. Answer option (d)

46.

Solution: Initial and final concentrations are 10% and 20% alcohol. Now since , 10% solution is

mixed with 100% solution to form 20% solution. Their ratio of volumes must be in the ratio (20-10) : (100-20) i.e. 1:8. So, 40ml alcohol must be mixed with 8*40=320ml of solution.

Thus the volume of the solution must be 40+320=360ml

47-50 :

47.

Solution- Total number of matches in a Tournament= . Answer option C.

48.

Solution- Minimum number of matches won by the team who is winner of the tournament= 0+ 2(

semi finals)+ 1= 3. Answer option B

49.

Solution- To find out minimum number of points scored by the team who reached the semi finals,

Maximize Points of Top three teams.

Max. Points scored by top three teams are 14, 12 and 10 so total 36 points.

Total points distributed = 2= 56,

So total points scored by Bottom 5 teams = 56- 36= 20 which can be divided equally among them.

So minimum number of points scored by the team who reached the semi finals =4

Answer option B

50.

Solution-To maximize number of points scored by the team who did not reach the semifinals, we

have to maximize score of top five teams.

Let all top five teams won from bottom 3 teams so each team in Top 5 get 6 points and let matches

among them ends in draw such that each team gets 4 more points. Therefore Each team in Top five

gets total of 10 points.

Maximum number of points scored by the team who did not reach the semifinals= 10.

Answer option (C )

CCC-1501 Section II

1-4:

1. Solution: ‘2’. The author has not compared the works of Swift and Pope anywhere to show the

superiority of one over the other; hence 1 can be ruled out. Nowhere does the author dwell upon the difficulty OR ease of the poems in terms of comprehension; hence 3 is ruled out. It was Pope who had used personification in the treatment of Belinda, not Swift. Refer to the line, “Swift’s A

Modest Proposal, however, is a quintessential Juvenalian satire, shockingly revealing an often-overlooked dimension of British colonialism with regard to the Irish through savage ridicule and

disdainful contempt.” Hence 2. 2.

Solution: ‘1’. Refer to the opening line of the passage, “The 18th century was one in which exaltation of wit and reason came to the forefront of literature…. exposed the superficial follies and

moral corruption of society during the neoclassical period in Britain”. In the passage, the author has tried to show how both Pope and Swift led this movement of exaltation of wit. However, if option 1 is correct, then it would go directly against the author’s attempts to prove that what Swift and Pope

did was a change from the erstwhile practices; since it can be inferred from the passage that Paradise Lost was an older work.

3. Solution: ‘4’. The author has not used any humourous incidents in the passage. The author has not

been violent in either words or any generic expressions. The author is not telling us a tale either. So options 1,2, and 3 can be safely ruled out. Throughout the passage the author has tried to convince

the reader as to why and how Pope and Swift have been influential in their era. Hence 4. 4.

Solution: ‘4’. Option 1 is extremely narrow, since ‘personification’ has been talked about in the last paragraph only. Option 2 is also erroneous, since it cannot be inferred from the passage whether

Pope and Swift were the ‘pioneers’ of satire or not. Milton has been used as a reference point in only one context, thereby making option 3 narrow as well. Option 4 captures the overall idea of the

passage, as throughout the passage the author has used Pope and Swift and their works to bring out his argument. Hence 4.

5-8:

5.

Solution: ‘2’. Read the first 3 lines of the fourth paragraph to understand that the author here

means to say that the jobs that one could earlier get with a mere high school degree now demand

college degree.

6.

Solution: ‘1’. D is what is talks about in the fourth paragraph and is pretty much the theme of the

passage whereas B is something that he wonders in the last paragraph.

7.

Solution: ‘4’. The author talks about ‘the moral commitment’ in the second paragraph, hence 3. He

talks about inequality in the third paragraph, hence 1. In the same paragraph he talks about the

indirect financial benefit the rich will reap in terms of less money needed to maintain prisons and

social security nets, hence 2. The author does not talk about political factors.

8.

Solution: ‘1’. Though the author has invoked morals and been somewhat compassionate, his overall

tone has been primarily analytical and has reasoned out all factors well throughout the passage.

9-10:

9. Solution: ‘2’. We need the noun ‘practice’ in A, not the verb ‘practise’. Article ’an’ is missing before ‘impressive’ in C.

10.

Solution: ‘1’. C does not continue the idiomatic expression of experience (experience A as B). The correct sentence would read (might experience her encounter…as burdensome and onerous). ‘Momentarily’ has been misspelt in D. ‘Debate about’ is redundant.

11-12:

11. Solution: ‘1’. ‘That’ in A refers to the description of Greece’s beauty in D. Hence DA is a mandatory

pair. However, placing D somewhere in the middle would break the continuity as all other sentences talks about Greek food and just D is a digression.

12. Solution: ‘4’. ‘It’ in A refers to immunity, not the immune system in C. However, the options make

the question unsolvable.

13-14 : 13.

Solution: ‘4’. The first part of 1 is true but no comparison has been made between the acceptance of flower-derived medicines and traditional medicines. 2, however true, is not what the thrust of the

argument is on. 3 is true and mentioned but only as an example to present 4, which is the bigger generalization which the paragraph seems to purport. One cannot generalize the role of a few flowers that have been mentioned in the paragraph to all flowers, but the presence of ‘can’ in 4

makes the statement viable.

14. Solution: ‘2’. ‘Notions of atheists’ is unknown to us and no flaw in either conceptions has been pointed out or can be inferred. The second conception does not attribute the order of the universe

to God. 2 is the only point that is common in both the conceptions.

15-18:

15.

Soln: 2. The author has, towards the end, repeatedly expressed that the economy is not bad as it

has been made to look and that the path to correction is not impossible. Sanguine = hopeful.

16.

Soln: 3. Refer to the second paragraph.

17.

Soln: 3. Option 1 talks about ‘social problems’. Option 2 is opposite to the idea expressed. Option 4

is Prime Minister-centric.

18.

Soln: 4. Between 2 and 4, option 4 is more specific to the statement’s context.

19-22:

19.

Soln: 1.

20.

Soln: 2. Option 1 is wrong since the ‘immediacy’ of publication and success cannot be calculated

from the passage. Option 3 is wrong because the passage says that the novel has been ‘interpreted’

with many perspectives, not that it ‘is’ any particularly. Option 4 has been stated already. Option 2

finds a hint in the 3rd last paragraph… “Orwell was freed from financial worries for the first time in

his life…”

21.

Soln: 1.

22.

Soln: 1. Try to establish the idea similarity from the stem to the representation. The inherent idea is

hidden in the usage of ‘turning ITSELF into’.

23-24:

23.

Solution: ‘2’. B follows C so only options 2 and 4 are left. A is used as a concluding statement while D makes more sense when used as an opening statement. It is a question which is difficult to solve.

24. Solution: ‘3’. B, which has the complete name of ADHD, is the obvious opener. Three major

symptoms mentioned in C find detailed in A, hence A will follow C. 25-26:

25.

Solution: ‘4’. ‘A little’ in C modifies ‘exceptions’, a countable noun, which is a grammatical infraction. In D, we need preposition ‘of’ after ‘because’.

26. Solution: ‘2’. A has a modifier error since the initial phrase would modify Leibniz and not hi talent.

‘Desires’ in B violates tense consistency (it should be ‘desired’). ‘That’, a singular pronoun, in C refers to ‘conditions’, a plural noun.

27 – 28:

27. Solution: ‘4’. The author calls ban on the import of the cars absurd because the ban is based on the

belief that black colour is unlucky. 28.

Solution: ‘3’. 3 is the gist of the paragraph. 1 and 3 are either stated or can be derived but that is not the central part of the argument. ‘Success’ in 4 is beyond what has been stated in the

paragraph. 29-32:

29. Solution: ‘4’ The first three statements talk about the way the experiment was conducted by

the researchers and the results of the experiment, while the fourth statement talks about the researchers hypothesis.

30. Solution: ‘4’. The focus of all other sentences is on Cleopatra whereas 4 talks primarily about milk.

31. Solution: ‘3’. All other options question the health-related aspects of artificial sweeteners whereas 3

talks about people’s loyalty to these artificial sweeteners. This is a tricky one and could be left.

32. Solution: ‘1’. The focus of all other statements is on the series and its contents, whereas 1 focuses

on the person who wrote it.

33–34: 33.

Solution: ‘2’. 2 is the gist of the paragraph and can be inferred from third sentence alone. 1 cannot be derived from the paragraph (ancient does not mean oldest). Immune system , a foreign variable

itself, deals with resisting diseases whereas paragraph talks about cure. 4 is too farfetched and cannot be an inference here.

34. Solution: ‘3’. 1 is too general and 2 can be ruled out as it has nowhere been mentioned that alcohol

causes sleeplessness. 4 is simply incorrect as no alternate ways of rejuvenation have been recommended. The purpose of the paragraph is to highlight that harmful effect of consuming alcohol before sleeping.

35 – 38:

Solution- From statement (i) -

Number of Persons to the left of Randeep is same as the number of persons to the right of Pradeep

Case 1

Case 2

Case 3-

From statement (IV)-

Pradeep is exactly in-between Navdeep and Gagandeep both of whom are not at extreme ends.

Case 1 and Case 2 is not valid now

Let’s analyze case 3- Two possibilities are there-

Possibility 1-

Possibility 2-

From statement (ii) and (iii)-

Sandeep is immediate left of Navdeep. Jagdeep is to the immediate right of Randeep

Second Possibility is not valid now

We are left with only first Possibilty –

Solution 1-

Solution 1- Four persons are to the left of Randeep. Answer option C

Solution 2- only one arrangement is possible. Answer option A.

Solution 3- Navdeep is standing three places away to the left of Randeep. Answer option B.

Solution 4- From the given options, Sandeep is at the extreme end .Answer option D

39 – 42:

Solution: There are eight delegates sitting around a circular table. So we first draw a circle and

mark eight equally spaced points on it. From (5) we get the one who made a commitment of 40% is

sitting opposite to 5%, 35% is sitting opposite to 10%, 15 % is sitting opposite to 30% and 20% is

sitting opposite to 25%.

From (1) we get:

From (4), The delegate from India sat three places to the left of the American delegate who had

made a commitment of 10% reduction and who didn’t sit next to the Chinese delegate. Here we get

two cases:

Case1: Case2:

But as the one sitting opposite to the Chinese delegate must have made a commitment of 15%, so

case 2 gets eliminated and so we get:

From (3) we get the Russian delegate sat three places to the right of the Australian delegate and

committed a greater percentage reduction in GHG emissions than the Australian delegate. So,

definitely the Russian delegate couldn’t have made a commitment of 15% and so the arrangement

further becomes:

From (2) we get the percentage reduction in GHG emissions committed by the German delegate

was more than that committed by his American counterpart and less than that committed by his

Japanese counterpart. Thus, the Japanese delegate made a commitment of 35%. And so the final

arrangement becomes:

1. The Australian delegate made a commitment of 15% reduction in the GHG emissions.

2. The Russian delegate sat to the left of the Chinese delegate.

3. None of the statements is true.

4. If the one who committed a 25% reduction in GHG emissions sat next to the one who made the

commitment of minimum percentage reduction i.e. 5%, so, the German delegate made a

commitment of 25% and the Russian delegate made a commitment of 20%. So, the Russian

delegate is sitting two places to the left of the one who made a commitment of 35%.

43 – 46:

Solution:

Name of the student

QA

LR

DI

Verbal

Lazy Lad 5 or 6 8 or 9 7 or 6 9 or 5

Dreamer 8 or 6 7 or 9 9 or 5 8 or 6

Couch Potato 7 or 9 6 or 8 8 or 9 5 or 7

Grumpy Dude 6 or 8 9 or 6 5 or 7 7 or 6

Lethargic Hunk 9 or 5 6 or 5 7 or 6 6 or 8

If we look at the QA marks of Dreamer and Grumpy Dude, then they obtained 6 or 8, so this

definitely means Lazy Lad got 5 marks in QA and so, Lethargic Hunk obtained 9 marks in QA. This

further means Couch Potato obtained 7 marks in QA.

Name of the student

QA

LR

DI

Verbal

Lazy Lad 5 8 or 9 7 or 6 9 or 5

Dreamer 8 or 6 7 or 9 9 or 5 8 or 6

Couch Potato 7 6 or 8 8 or 9 5 or 7

Grumpy Dude 6 or 8 9 or 6 5 or 7 7 or 6

Lethargic Hunk 9 6 or 5 7 or 6 6 or 8

As each of them got a different score in all the four subjects, this further leads us to:

Name of the

student

QA

LR

DI

Verbal

Lazy Lad 5 8 7 or 6 9

Dreamer 8 or 6 7 9 or 5 8 or 6

Couch Potato 7 6 8 or 9 5

Grumpy Dude 6 or 8 9 5 or 7 7 or 6

Lethargic Hunk 9 5 7 or 6 6 or 8

If we look at the DI section, Lazy Lad and Lethargic Hunk both got either 7 or 6, so Grumpy Dude

got 5 marks in DI and so Dreamer got 9 and Couch Potato got 8 in DI.

Similarly if we look at the Verbal section, then Dreamer and Lethargic Hunk both obtained either 8

or 6, so definitely Grumpy Dude obtained 7 in marks in Verbal. This can be further represented as:

Name of the

student

QA

LR

DI

Verbal

Lazy Lad 5 8 7 or 6 9

Dreamer 8 or 6 7 9 8 or 6

Couch Potato 7 6 8 5

Grumpy Dude 6 or 8 9 5 7

Lethargic Hunk 9 5 7 or 6 6 or 8

1. Definitely Dreamer obtained the highest score i.e. 30.

2. Couch Potato obtained the lowest marks i.e. 26

3. If Dreamer scored more marks than Grumpy Dude in QA, then the distribution becomes:

Name of the student

QA

LR

DI

Verbal

Lazy Lad 5 8 7 or 6 9

Dreamer 8 7 9 6

Couch Potato 7 6 8 5

Grumpy Dude 6 9 5 7

Lethargic Hunk 9 5 7 or 6 8

Still we won’t be able to determine the total score obtained by Lethargic Hunk.

4. 4. If Lazy Lad got a total of 28marks, then we would have obtained 7 marks in DI and Lethargic

Hunk would have obtained 6 marks in DI

Name of the student

QA

LR

DI

Verbal

Lazy Lad 5 8 7 9

Dreamer 8 7 9 6

Couch Potato 7 6 8 5

Grumpy Dude 6 9 5 7

Lethargic Hunk 9 5 6 8

So, Grumpy Dude obtained the second lowest total.

47 – 50:

Solution: From (1) we get that both India and Korea won three matches , lost one match each and

one match resulted in a draw for both these teams.

From (4), we get Germany scored 10 points. This means Germany won 2 matches, lost 2 matches

and one of its matches resulted in a draw.

Also on the basis of the information given we can draw the table as:

Teams Australia India Pakistan Germany Korea Malaysia

Australia x Won Lost

India Lost x Won Won

Pakistan Lost x Won

Germany Won Lost x

Korea x

Malaysia Lost x

A total of 15 matches were played between these six teams and out of which 2 matches resulted in

a draw. This means 13 other matches resulted in 13 wins and 13 losses for these teams.

From (3) , Australia, Pakistan and Malaysia lost equal number of matches. Also India and Korea lost

one match each while Germany lost 2 matches, this means Australia, Pakistan and Malaysia each

lost three matches.

Also we see that Pakistan scored the least points and as it has already won one match against

Malaysia, this implies that one of its match resulted in a draw. So, Pakistan finally won a match, lost

three matches and one match resulted in a draw. For Australia and Malaysia, they won two matches

and lost three matches.

So the two matches that resulted in a draw were played amongst India, Pakistan, Korea and

Germany.

As the match between India and Pakistan didn’t result in a draw and the match between India and

Germany also didn’t result in a draw, this means the match between India and Korea resulted in a

draw and so was the match between Pakistan and Germany. Further the information can be filled as

shown in the table:

Teams Australia India Pakistan Germany Korea Malaysia

Australia x Won Won Lost Lost Lost

India Lost x Won Won Draw Won

Pakistan Lost Lost x Draw Lost Won

Germany Won Lost Draw x

Korea Won Draw Won x

Malaysia Won Lost Lost x

1. As it is evident that India won the match against Malaysia, so option (1) is correct.

2. Australia won two matches and lost three matches, so Australia scored 8 points. So,

option (3) is correct.

3. As the outcome of the match played between Germany cannot be figured out, so option

(4) is correct.

4. Only option (1) is definitely true.