cbe 3028 steelwork design assignment 1

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Steelwork Design Assignment Name : Question 1 = 2 = 2(375)(353)(10 โˆ’3 ) = 265 24 8.8 2 = 24 > 22 , โ„Žโ„Ž โ„Ž โ„Ž โˆด = 22 โ„Ž = = 0.5 = 1.5 โ‰ค 2.0 355, = 550 / 2 , = 510 / 2 โ„Ž, = 1.0 , = 24 , = 22 , = 40 = 60 โˆ’ 26 = 34 mm = (1.0)(24)(22)(510)(10 โˆ’3 ) = 230 = (0.5)(1.0)(40)(22)(550)(10 โˆ’3 ) = 242 kN = (1.5)(46)(22)(510)(10 โˆ’3 ) = 606 kN โ‰ค (2.0)(34)(22)(800)(10 โˆ’3 ) = 1197 โˆด = 242.4 = 6 242 = 1452 > 750 โˆด = (150)(22) = 3300 2 = 345 / 2 โˆด = (1.1)(22)(150 โˆ’ 2(24)) = 2468 2 = (345)(2468)(10 โˆ’3 ) = 850 > 750 โˆด

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  • Steelwork Design Assignment

    Name :

    Question 1

    = 2

    = 2(375)(353)(103)

    = 265

    24 8.8

    2 = 24 > 22 ,

    = 22

    =

    = 0.5

    = 1.5 2.0

    355, = 550 /2 , = 510 /

    2

    , = 1.0 , = 24 , = 22 , = 40

    = 60 26 = 34 mm

    = (1.0)(24)(22)(510)(103) = 230

    = (0.5)(1.0)(40)(22)(550)(103) = 242 kN

    = (1.5)(46)(22)(510)(103) = 606 kN

    (2.0)(34)(22)(800)(103) = 1197

    = 242.4

    = 6 242 = 1452 > 750

    = (150)(22) = 3300 2

    = 345 /2

    = (1.1)(22)(150 2(24)) = 2468 2

    = (345)(2468)(103) = 850 > 750

  • = 355 /2

    = (150)(12) = 1800 2

    = (1.1)(12)(150 2(24)) = 1346 2

    = 2(345)(1346)(103) = 952 > 750

    Question 2

    1 = (65 3)(6) = 372 2

    2 = (50 3)(6) = 282 2

    = 372 + 282 = 654 2

    = 355 /2 ( 16 )

    = 2(355)(654 0.3(282))(103) = 404 > 350

    12

    = 2.10 /

    =350

    2.10= 166.67

    , = 20.4

    , = 166.67 (75 20.3)

    75= 99

    10 , = 99 + 10 = 109

    , = 166.67 99 = 67.67

    10 , = 67.67 + 10 = 77.67 ,