cbe 3028 steelwork design assignment 1
TRANSCRIPT
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Steelwork Design Assignment
Name :
Question 1
= 2
= 2(375)(353)(103)
= 265
24 8.8
2 = 24 > 22 ,
= 22
=
= 0.5
= 1.5 2.0
355, = 550 /2 , = 510 /
2
, = 1.0 , = 24 , = 22 , = 40
= 60 26 = 34 mm
= (1.0)(24)(22)(510)(103) = 230
= (0.5)(1.0)(40)(22)(550)(103) = 242 kN
= (1.5)(46)(22)(510)(103) = 606 kN
(2.0)(34)(22)(800)(103) = 1197
= 242.4
= 6 242 = 1452 > 750
= (150)(22) = 3300 2
= 345 /2
= (1.1)(22)(150 2(24)) = 2468 2
= (345)(2468)(103) = 850 > 750
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= 355 /2
= (150)(12) = 1800 2
= (1.1)(12)(150 2(24)) = 1346 2
= 2(345)(1346)(103) = 952 > 750
Question 2
1 = (65 3)(6) = 372 2
2 = (50 3)(6) = 282 2
= 372 + 282 = 654 2
= 355 /2 ( 16 )
= 2(355)(654 0.3(282))(103) = 404 > 350
12
= 2.10 /
=350
2.10= 166.67
, = 20.4
, = 166.67 (75 20.3)
75= 99
10 , = 99 + 10 = 109
, = 166.67 99 = 67.67
10 , = 67.67 + 10 = 77.67 ,