calculating the amount of aluminium roofing sheet for a building

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  • 8/16/2019 Calculating the Amount of Aluminium Roofing Sheet for a Building

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    Calculating The Amount Of Aluminium Roofing Sheet For A Building

    You have read the calculating the amounts of block to be used for a building from plan, it will interest you

    how simple maths can help you safe you form unnecessary stress. Today, I have simple anotherinteresting to calculate the amount of aluminium roofing sheet from the building plan. This will help you topredetermined and know the estimate cost that the roofing will require for our builders. The cost isestimate, and never metto be EX!T, since wastage and the roofing technicality might cost little waste on the part of carpernters

    "efer to old articles of aluminium roofing sheets, they come in rolls of average of #$$mm to %&$$mm

    depends on the manufacture and specifications. s stated in previous articles, the aluminium sheets

    comes in rolls at the factory 'ust like toilet rolls but with different widths and thickness based on

    specifications.

    !alculating the roof required could be done by calculating the surface area in square meters of the area

    covered by the aluminium and for some companies it could be calculated in meter lengths ,knowing the

    width which is #$$mm above as constant.

    (or a simple gable roof as shown in pic % with length of )*.)m. (irst you must know the height of roof

    from the section.

    (or this sample we are taken the eight to be &meters +%$ feetto know the length of leaf -/ or -y/

    0able "oof 

    http://www.cloudbuildersnigeria.com/2014/09/how-to-calculate-to-numbers-of-blocks-to-use-for-a-building.htmlhttp://www.cloudbuildersnigeria.com/2014/09/how-to-calculate-to-numbers-of-blocks-to-use-for-a-building.htmlhttp://www.cloudbuildersnigeria.com/2014/09/how-to-calculate-to-numbers-of-blocks-to-use-for-a-building.html

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    "emember the pythagoras theorem

    )1&) 2#.%)

    1#.3m

    4ence the area of roof is +#.3 i.e 2#.3 i.e y multiply by length )*.)m1&5).6)m)

    If the width of the roof comes in #$$mm or $.#m, the length of the roof require will be &5).6)7$.#m

    1*6%.) meters length

    8o for some companies they could give their quotations in meter length so 'ust ask for the width of the

    rols and follow steps above.

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    (or a comple roof like pic & above, then you can opt to do a fast estimate based on the linear area

    covered as shown by roof plan as it may be a bit comple and difficult, so you can divide the roof plan to

    sections of rectangles or squares as it may applies 9+four right angles. Then add the areas together and

    add %$: of the same area, because the higher the roof, the more the plates , and the more comple the

    roof the higher the numbers of offcuts which will also increase the numbers of aluminium 7plates required .

    8o for pic & ,add areas of rectangles ,;,! and < which is the big center.

    i.e +3.)m %.)m2+%.)m3.)m2+%.)m3.)m2+)).3m%).)m1&%%.)3m)

     dd %$:1&%%.)32&%.%)31&5)m)

    =ow for a more accurate and scientific calculation, you must know the height of the roof , have the basic

    knowledge of calculating area of a triangle which is > base height . nd ?ythagoras theorem to know

    the side of any triangle . lso remember the area for a rectangle is simply length multiplied by breadth.

     ssuming the height of roof is &meters as as previous in fig. ), and taken the ma'or part < as a simple

     gable roof +check the different sections on plan fig & and ignoring the hipped or bevelled section.

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    )1&) 2#.%)

    1#.3m

    8o area of roof as previous is + #.3m2#.3m multiply by length )).3m1&%$m)

     dd areas ,;,!

    2&%$m) [email protected]) 2%&.55m) 2 @.35m)

    1&5&.%)m)

    Aith your estimate is also the "I