calculating the amount of aluminium roofing sheet for a building
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8/16/2019 Calculating the Amount of Aluminium Roofing Sheet for a Building
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Calculating The Amount Of Aluminium Roofing Sheet For A Building
You have read the calculating the amounts of block to be used for a building from plan, it will interest you
how simple maths can help you safe you form unnecessary stress. Today, I have simple anotherinteresting to calculate the amount of aluminium roofing sheet from the building plan. This will help you topredetermined and know the estimate cost that the roofing will require for our builders. The cost isestimate, and never metto be EX!T, since wastage and the roofing technicality might cost little waste on the part of carpernters
"efer to old articles of aluminium roofing sheets, they come in rolls of average of #$$mm to %&$$mm
depends on the manufacture and specifications. s stated in previous articles, the aluminium sheets
comes in rolls at the factory 'ust like toilet rolls but with different widths and thickness based on
specifications.
!alculating the roof required could be done by calculating the surface area in square meters of the area
covered by the aluminium and for some companies it could be calculated in meter lengths ,knowing the
width which is #$$mm above as constant.
(or a simple gable roof as shown in pic % with length of )*.)m. (irst you must know the height of roof
from the section.
(or this sample we are taken the eight to be &meters +%$ feetto know the length of leaf -/ or -y/
0able "oof
http://www.cloudbuildersnigeria.com/2014/09/how-to-calculate-to-numbers-of-blocks-to-use-for-a-building.htmlhttp://www.cloudbuildersnigeria.com/2014/09/how-to-calculate-to-numbers-of-blocks-to-use-for-a-building.htmlhttp://www.cloudbuildersnigeria.com/2014/09/how-to-calculate-to-numbers-of-blocks-to-use-for-a-building.html
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8/16/2019 Calculating the Amount of Aluminium Roofing Sheet for a Building
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"emember the pythagoras theorem
)1&) 2#.%)
1#.3m
4ence the area of roof is +#.3 i.e 2#.3 i.e y multiply by length )*.)m1&5).6)m)
If the width of the roof comes in #$$mm or $.#m, the length of the roof require will be &5).6)7$.#m
1*6%.) meters length
8o for some companies they could give their quotations in meter length so 'ust ask for the width of the
rols and follow steps above.
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(or a comple roof like pic & above, then you can opt to do a fast estimate based on the linear area
covered as shown by roof plan as it may be a bit comple and difficult, so you can divide the roof plan to
sections of rectangles or squares as it may applies 9+four right angles. Then add the areas together and
add %$: of the same area, because the higher the roof, the more the plates , and the more comple the
roof the higher the numbers of offcuts which will also increase the numbers of aluminium 7plates required .
8o for pic & ,add areas of rectangles ,;,! and < which is the big center.
i.e +3.)m %.)m2+%.)m3.)m2+%.)m3.)m2+)).3m%).)m1&%%.)3m)
dd %$:1&%%.)32&%.%)31&5)m)
=ow for a more accurate and scientific calculation, you must know the height of the roof , have the basic
knowledge of calculating area of a triangle which is > base height . nd ?ythagoras theorem to know
the side of any triangle . lso remember the area for a rectangle is simply length multiplied by breadth.
ssuming the height of roof is &meters as as previous in fig. ), and taken the ma'or part < as a simple
gable roof +check the different sections on plan fig & and ignoring the hipped or bevelled section.
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)1&) 2#.%)
1#.3m
8o area of roof as previous is + #.3m2#.3m multiply by length )).3m1&%$m)
dd areas ,;,!
2&%$m) [email protected]) 2%&.55m) 2 @.35m)
1&5&.%)m)
Aith your estimate is also the "I