Malla 15100*i1+12*i1-12*i3+23*i1-23*i2=5.03 v5135*i1-23*i2-12*i3=5.03

Malla 236*i3-36*i2+12*i3-12*i1=0-12*i1-36*i2+48*i3=0Malla 310*i2+23*i2-23*i1+36*i2-36*i3=0-23*i1+69*i2-36*i3=0

Resolviendo el sistema de ecuaciones:i1 = 0.9848 mAi2 = 0.7503 mAi3 = 0.8089 mACORRIENTESCorriente R1i = 0.9848 mACorriente R2i = i1 i3i = 0.9848 0.8089i = 0.1759 mA

Corriente R3i= i1 i2i = 0.9848 -0.7503i = 0.2345 mACorriente R4i = i3 i2i = 0.8089 - 0.7503i = 0.0586 mACorriente R5i = 0.7503 mAVOLTAJESVoltaje R1v = i*R1v = 0.9848 mA * 5100v = 5.02 vVoltaje R2v = i*R2v = 0.1759 mA * 12v = 2.11 mVVoltaje R3v = i*R3v = 0.2345 mA * 23v = 5.39 mVVoltaje R4v = i*R1v = 0.0586 mA * 36v = 2.10 mVVoltaje R5v = i*R1v = 0.7503 mA * 10v = 7.50 mVDATOS TEORICOS

Voltaje Corriente

R15.02 v0.9848 mA

R22.11 mV0.1759 mA

R35.39 mV0.2345 mA

R42.10 mV0.0586 mA

R57.50 mV0.7503 mA