c learn fast

8/10/2019 c learn fast

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void main(){

long int ARR[10], OAR[10], EAR[10];int i,j=0,k=0,n;

printf("Enter the size of array AR\n");scanf("%d",&n);

printf("Enter the elements of the array\n");for(i=0;i


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12345678899900

111The elements of OAR are345899111The elements of EAR are12678900---------------------------------------*/

Sample 3

/* Write a C program to generate Fibonacci sequence ** Fibonacci sequence is 0 1 1 2 3 5 8 13 21 ... */

#include

void main(){

int fib1=0, fib2=1, fib3, limit, count=0;

printf("Enter the limit to generate the fibonacci sequence\n");scanf("%d", &limit);

printf("Fibonacci sequence is ...\n");printf("%d\n",fib1);printf("%d\n",fib2);count = 2; /* fib1 and fib2 are already used */

while( count < limit){fib3 = fib1 + fib2;

count ++;printf("%d\n",fib3);fib1 = fib2;fib2 = fib3;

}

} /* End of main() */


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/*-----------------------------------------------------------Enter the limit to generate the fibonacci sequence7Fibonacci sequence is ...0

112358-----------------------------------------------------------*/

Sample 4

/* Write a C program to insert a particular element in a specified position ** in a given array */

#include #include

void main(){

int x[10];int i, j, n, m, temp, key, pos;

clrscr();

printf("Enter how many elements\n");scanf("%d", &n);

printf("Enter the elements\n");for(i=0; i


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{for(j=i+1; j x[j]){

temp = x[i];x[i] = x[j];x[j] = temp;

}}

}

printf("Sorted list is\n");for(i=0; i


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/*-------------------------------------OutputEnter how many elements5Enter the elements

214678329Input array elements are214678329

Sorted list is214296783Enter the element to be inserted34Final list is21429346783-------------------------------------------------*/

Sample 5

/* Write a C program to accept an integer and reverse it */

#include

void main(){

long num, rev = 0, temp, digit;


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printf("Enter the number\n"); /*For better programming,choose 'long int' */scanf("%ld", &num);

temp = num;

while(num > 0){digit = num % 10;

rev = rev * 10 + digit;num /= 10;

}

printf("Given number = %ld\n", temp);printf("Its reverse is = %ld\n", rev);

}

/* ---------------------------OutputEnter the number123456Given number = 123456Its reverse is = 654321------------------------------*/

Sample 6

/* This program is to illustrate how user authentication ** is made before allowing the user to access the secured ** resources. It asks for the user name and then the ** password. The password that you enter will not be ** displayed, instead that character is replaced by '*' */

#include #include

void main(){

char pasword[10],usrname[10], ch;int i;

clrscr();

printf("Enter User name: ");gets(usrname);


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printf("Enter the password : ");

for(i=0;i


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void main(){

float side, surfArea, volume;

printf("Enter the length of a side\n");scanf("%f", &side);

surfArea = 6.0 * side * side;

volume = pow (side, 3);

printf("Surface area = %6.2f and Volume = %6.2f\n", surfArea, volume);}

/*------------------------------------------

OutputEnter the llngth of a side4Surface area = 96.00 and Volume = 64.00

RUN2Enter the length of a side12.5Surface area = 937.50 and Volume = 1953.12------------------------------------------*/

Sample 9

/* Write a C program to accept a decimal number and conert it binary ** and count the number of 1's in the binary number */

#include

void main(){

long num, dnum, rem, base = 1, bin = 0, no_of_1s = 0;

printf("Enter a decimal integer\n");scanf("%ld", &num);

dnum = num;

while( num > 0 ){

rem = num % 2;


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if ( rem == 1 ) /*To count no.of 1s*/{

no_of_1s++;}bin = bin + rem * base;

num = num / 2 ;base = base * 10;}printf("Input number is = %d\n", dnum);printf("Its Binary equivalent is = %ld\n", bin);printf("No.of 1's in the binary number is = %d\n", no_of_1s);


/*--------------------------------------------------Output

Enter a decimal integer75Input number is = 75Its Binary equivalent is = 1001011No.of 1's in the binary number is = 4

RUN2Enter a decimal integer128Input number is = 128Its Binary equivalent is = 10000000No.of 1's in the binary number is = 1

-----------------------------------------------------*/

Sample 10

/* Write a c program to find whether a given year ** is leap year or not */

#include

void main(){

int year;

printf("Enter a year\n");scanf("%d",&year);


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if ( (year % 4) == 0)printf("%d is a leap year",year);

elseprintf("%d is not a leap year\n",year);

}

/*------------------------------------------OutputEnter a year20002000 is a leap year

RUN2Enter a year20072007 is not a leap year

------------------------------------------*/Sample 11

/* Write a c program to swap the contents of two numbers ** using bitwise XOR operation. Don't use either the ** temporary variable or arithmetic operators */

#include

void main(){

long i,k;

printf("Enter two integers\n");scanf("%ld %ld",&i,&k);

printf("\nBefore swapping i= %ld and k = %ld",i,k);

i = i^k;k = i^k;i = i^k;

printf("\nAfter swapping i= %ld and k = %ld",i,k);

}

/*------------------------------------------Output


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Enter two integers23 34

Before swapping i= 23 and k = 34After swapping i= 34 and k = 23

------------------------------------------*/Sample 12

/* Write a c program to convert given number of days to a measure of time* given in years, weeks and days. For example 375 days is equal to 1 year* 1 week and 3 days (ignore leap year)*/

#include #define DAYSINWEEK 7

void main(){

int ndays, year, week, days;

printf("Enter the number of days\n");scanf("%d",&ndays);

year = ndays/365;week = (ndays % 365)/DAYSINWEEK;days = (ndays%365) % DAYSINWEEK;

printf ("%d is equivalent to %d years, %d weeks and %d days\n",ndays, year, week, days);

}

/*-----------------------------------------------OutputEnter the number of days375375 is equivalent to 1 years, 1 weeks and 3 days

Enter the number of dayy423423 is equivalent tt 1 years, 8 weeks and 2 days

Enter the number of days14971497 is equivalent to 4 years, 5 weeks and 2 days---------------------------------------------------*/


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Sample 13

/* Program to accepts two strings and compare them. Finally it prints ** whether both are equal, or first string is greater than the second *

* or the first string is less than the second string */#include#include

void main(){

int count1=0,count2=0,flag=0,i;char str1[10],str2[10];

clrscr();

puts("Enter a string:");gets(str1);

puts("Enter another string:");gets(str2);/*Count the number of characters in str1*/while (str1[count1]!='\0')

count1++;/*Count the number of characters in str2*/while (str2[count2]!='\0')

count2++;i=0;

/*The string comparison starts with thh first character in each string andcontinues with subsequent characters until the corresponding charactersdiffer or until the end of the strings is reached.*/

while ( (i < count1) && (i < count2)){

if (str1[i] == str2[i]){

i++;continue;

}if (str1[i] str2[i])


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{flag = 1;break;

}}

if (flag==0)printf("Both strings are equal\n");

if (flag==1)printf("String1 is greater than string2\n", str1, str2);

if (flag == -1)printf("String1 is less than string2\n", str1, str2);

getch();}/*----------------------------------------Output

Enter a string:happyEnter another string:HAPPYString1 is greater than string2

RUN2Enter a string:HelloEnter another string:HelloBoth strings are equal

RUN3Enter a string:goldEnter another string:silverString1 is less than string2----------------------------------------*/Sample 14

/* Program to accept two strings and concatenate them ** i.e.The second string is appended to the end of the first string */

#include #include


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void main(){

char string1[20], string2[20];int i,j,pos;

strset(string1, '\0'); /*set all occurrences in two strings to NULL*/strset(string2,'\0');

printf("Enter the first string :");gets(string1);fflush(stdin);

printf("Enter the second string:");gets(string2);

printf("First string = %s\n", string1);printf("Second string = %s\n", string2);

/*To concate the second stribg to the end of the stringtravserse the first to its end and attach the second string*/

for (i=0; string1[i] != '\0'; i++){

; /*null statement: simply trvsering the string1*/}

pos = i;

for (i=pos,j=0; string2[j]!='\0'; i++){

string1[i] = string2[j++];}

string1[i]='\0'; /*set the last character of string1 to NULL*/

printf("Concatenated string = %s\n", string1);}

/*---------------------------------------OutputEnter the first string :CD-Enter the second string:ROMFirst string = CD-Second string = ROMConcatenated string = CD-ROM


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----------------------------------------*/

Sample 15

/* Write a c program to find the length of a string *

* without using the built-in function */#include

void main(){

char string[50];int i, length = 0;

printf("Enter a string\n");gets(string);

for (i=0; string[i] != '\0'; i++) /*keep going through each */{ /*character of the string */

length++; /*till its end */}printf("The length of a string is the number of characters in it\n");printf("So, the length of %s =%d\n", string, length);

}

/*----------------------------------------------------OutputEnter a stringhelloThe length of a string is the number of characters in itSo, the length of hello = 5

RUN2Enter a stringE-Commerce is hot nowThe length of a string is the number of characters in itSo, the length of E-Commerce is hot now =21----------------------------------------------------------*/Sample 16

/* Write a c program to find the length of a string* without using the built-in function also check* whether it is a palindrome or not*/


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#include #include

void main(){

char string[25], revString[25]={'\0'};int i,length = 0, flag = 0;

clrscr();fflush(stdin);

printf("Enter a string\n");gets(string);

for (i=0; string[i] != '\0'; i++) /*keep going through each */{ /*character of the string */

length++; /*till its end */}printf("The length of the string \'%s\' = %d\n", string, length);

for (i=length-1; i >= 0 ; i--){

revString[length-i-1] = string[i];}/*Compare the input string and its reverse. If both are equalthen the input string is palindrome. Otherwise it isnot a palindrome */

for (i=0; i < length ; i++){

if (revString[i] == string[i])flag = 1;

elseflag = 0;

}

if (flag == 1)printf ("%s is a palindrome\n", string);

elseprintf("%s is not a palindrome\n", string);

}

/*----------------------------------------------------Output


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Enter a stringmadamThe length of the string 'madam' = 5madam is a palindrome

RUN2Enter a stringgoodThe length of the string 'good' = 4good is not a palindrome----------------------------------------------------------*/

Sample 17

/* Write a C program to accept a string and find the number of times the word 'the'* appears in it*/

#include#include

void main(){

int count=0,i,times=0,t,h,e,space;char str[100];

clrscr();puts("Enter a string:");gets(str);

/*Traverse the string to count the number of characters*/while (str[count]!='\0'){

count++;}/*Finding the frequency of the word 'the'*/for(i=0;i


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}/*-----------------------------------------------------OutputEnter a string:The Teacher's day is the birth day of Dr.S.Radhakrishnan

Frequency of the word 'the' is 2---------------------------------------------------------*/

Sample 18

/* Write a C program to compute the value of X ^ N given X and N as inputs */

#include #include

void main(){long int x,n,xpown;long int power(int x, int n);

printf("Enter the values of X and N\n");scanf("%ld %ld",&x,&n);

xpown = power (x,n);

printf("X to the power N = %ld\n");}

/*Recursive function to computer the X to power N*/

long int power(int x, int n){

if (n==1)return(x);

else if ( n%2 == 0)return (pow(power(x,n/2),2)); /*if n is even*/

elsereturn (x*power(x, n-1)); /* if n is odd*/

}/*-------------------------------------OutputEnter the values of X and N2 5X to the power N = 32


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RUN2Enter the values offX and N4 4X to the power N ==256

RUN3Enter the values of X and N5 2X to the power N = 25

RUN4Enter the values of X and N10 5X to the power N = 100000-----------------------------------------*/

Sample 19

/* Write a C program to accept two matrices and ** find the sum and difference of the matrices */

#include #include

int A[10][10], B[10][10], sumat[10][10], diffmat[10][10];int i, j, R1, C1, R2, C2;

void main(){

/* Function declarations */void readmatA();void printmatA();void readmatB();void printmatB();void sum();void diff();

printf("Enter the order of the matrix A\n");scanf("%d %d", &R1, &C1);

printf("Enter the order of the matrix B\n");scanf("%d %d", &R2,&C2);

if( R1 != R2 && C1 != C2){


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void printmatA(){

for(i=0; i


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3 69 12

Difference matrix is-1 -2-3 -4

-----------------------------------------------------*/

Sample 20

/* Write a C Program to accept two matrices and check if they are equal */

#include #include #include

void main(){int A[10][10], B[10][10];int i, j, R1, C1, R2, C2, flag =1;

printf("Enter the order of the matrix A\n");scanf("%d %d", &R1, &C1);

printf("Enter the order of the matrix B\n");scanf("%d %d", &R2,&C2);

printf("Enter the elements of matrix A\n");for(i=0; i


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for(i=0; i


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}

/*------------------------------------------------------OutputEnter the order of the matrix A

2 2Enter the order of the matrix B2 2Enter the elements of matrix A1 23 4Enter the elements of matrix B1 23 4MATRIX A is

1 2

3 4MATRIX B is1 23 4

Matrices can be comparedTwo matrices are equal-------------------------------------------------------*/

Sample 21

/* Write a C Program to check if a given matrix is an identity matrix */

#include

void main(){

int A[10][10];int i, j, R, C, flag =1;

printf("Enter the order of the matrix A\n");scanf("%d %d", &R, &C);

printf("Enter the elements of matrix A\n");for(i=0; i


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}printf("MATRIX A is\n");for(i=0; i


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2 2Enter the elements of matrix A1 00 1MATRIX A is

1 00 1It is identity matrix------------------------------------------*/

Sample 22

/* Write a C program to accept a matrix of given order and* interchnge any two rows and columns in the original matrix*/

#include void main(){

static int m1[10][10],m2[10][10];int i,j,m,n,a,b,c, p, q, r;

printf ("Enter the order of the matrix\n");scanf ("%d %d",&m,&n);

printf ("Enter the co-efficents of the matrix\n");for (i=0; i


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printf ("Enter the numbers of two columns to be exchnged\n");scanf ("%d %d",&p,&q);

printf ("The given matrix is \n");for (i=0;i


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Enter the numbers of two columns to be exchnged2 3The given matrix is1 2 45 7 9

3 0 6The matix after interchnging the two rows (in the original matrix)5 7 91 2 43 0 6

The matix after interchnging the two columns(in the original matrix)1 4 25 9 73 6 0

-------------------------------------------------------------------------*/

Sample 23

/* Write a C program to display the inventory of items in a store/shop ** The inventory maintains details such as name, price, quantity and ** manufacturing date of each item. */

#include #include

void main(){

struct date{

int day;int month;int year;

};

struct details{

char name[20];int price;int code;int qty;struct date mfg;

};

struct details item[50];int n,i;


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clrscr();

printf("Enter number of items:");scanf("%d",&n);fflush(stdin);

for(i=0;i


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Quantity:23price:40Manufacturing date(dd-mm-yyyy):12-03-2007Item name:Milk PowderItem code:345

Quantity:20price:80Manufacturing date(dd-mm-yyyy):30-03-2007Item name:Soap PowderItem code:510Quantity:10price:30Manufacturing date(dd-mm-yyyy):01-04-2007Item name:Washing SoapItem code:890Quantity:25

price:12Manufacturing date(dd-mm-yyyy):10-03-2007Item name:ShampoItem code:777Quantity:8price:50Manufacturing date(dd-mm-yyyy):17-05-2007

***** INVENTORY *****------------------------------------------------------------------------S.N.| NAME | CODE | QUANTITY | PRICE |MFG.DATE------------------------------------------------------------------------1 Tea Powder 123 23 40 12/3/20072 Milk Powder 345 20 80 30/3/20073 Soap Powder 510 10 30 1/4/20074 Washing Soap 890 25 12 10/3/20075 Shampo 777 8 50 17/5/2007------------------------------------------------------------------------

--------------------------------------------------------------------*/

Sample 24

/* Write a C program to convert the given binary number into its equivalent decimal */

#include

void main(){

int num, bnum, dec = 0, base = 1, rem ;


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OutputEnter an integer1515 x 4 = 60

RUN2Enter an integer262262 x 4 = 1048---------------------------------*/Sample 26

/* Write a C program to find the sum of cos(x) series */

#include

#includevoid main(){

int n,x1,i,j;float x,sign,cosx,fact;

printf("Enter the number of the terms in aseries\n");scanf("%d",&n);

printf("Enter the value of x(in degrees)\n");scanf("%f",&x);

x1=x;

x=x*(3.142/180.0); /* Degrees to radians*/

cosx=1;

sign=-1;

for(i=2;i


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cosx=cosx+(pow(x,i)/fact)*sign;sign=sign*(-1);

}

printf("Sum of the cosine series = %7.2f\n",cosx);printf("The value of cos(%d) using library function = %f\n",x1,cos(x));

} /*End of main() */

/*--------------------------------------------------------OutputEnter the number of the terms in aseries5Enter the value of x(in degrees)60

Sum of the cosine series = 0.50The value of cos(60) using library function = 0.499882--------------------------------------------------------*/Sample 27

/* Writ a C programme to cyclically permute the elements of an array A. *i.e. the content of A1 become that of A2.And A2 contains that of A3 *& so on as An contains A1 */

#include

void main (){

int i,n,number[30];printf("Enter the value of the n = ");scanf ("%d", &n);printf ("Enter the numbers\n");for (i=0; i


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printf ("%d\n", number[i]);}/*-------------------------------------OutputEnter the value of the n = 5

Enter the numbers1030204518Cyclically permted numbers are given below30204518

10---------------------------------------------------*/Sample 28

/* Write a C program to accept a set of numbers and compute mean, ** varience and standard deviation */

#include #include

void main(){

float x[10];int i, n;float avrg, var, SD, sum=0, sum1=0;

printf("Enter howmany elements\n");scanf("%d", &n);

for(i=0; i


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/* Compute varaience and standard deviation */for(i=0; i


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for (i=0; i


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int number[30];int i,j,a,n;

printf ("Enter the value of N\n");scanf ("%d", &n);

printf ("Enter the numbers \n");for (i=0; i


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67423510

/*------------------------------------------------*/Sample 31

/* Write a C program to accept a list of data items and find the second *largest and second smallest elements in it. And also computer the average *of both. And search for the average value whether it is present in the *array or not. Display appropriate message on successful search. */

#include

void main (){int number[30];int i,j,a,n,counter,ave;

printf ("Enter the value of N\n");scanf ("%d", &n);

printf ("Enter the numbers \n");for (i=0; i


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printf ("The 2nd largest number is = %d\n", number[1]);printf ("The 2nd smallest number is = %d\n", number[n-2]);

ave = (number[1] +number[n-2])/2;

counter = 0;for (i=0; i


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Sample 32

/* Write a C program to accept an array of integers and delete the ** specified integer from the list */

#include

void main(){

int vectx[10];int i, n, pos, element, found = 0;

printf("Enter how many elements\n");scanf("%d", &n);

printf("Enter the elements\n");for(i=0; i


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}

printf("The resultant vector is \n");for(i=0; i


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5581Enter the element to be deleted55The resultant vector is

231081

--------------------------------------------------------*/Sample 33

/* Write a C programme (1-D Array) store some elements in it.Accept key& split from that point. Add the first half to the end of second half*/

#include void main (){

int number[30];int i,n,a,j;

printf ("Enter the value of n\n");scanf ("%d",&n);

printf ("enter the numbers\n");for (i=0; i


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printf ("%d\n",number[i]);}


/*-------------------------------------------------

OutputEnter the value of n5enter the numbers3010405060Enter the position of the element to split the array2

The resultant array is4050603010----------------------------------------------------------*/Sample 34

/* Write a C program to find the frequency of odd numbers ** and even numbers in the input of a matrix */

#include

void main (){static int ma[10][10];int i,j,m,n,even=0,odd=0;

printf ("Enter the order ofthe matrix \n");scanf ("%d %d",&m,&n);

printf ("Enter the coefficients if matrix \n");for (i=0;i


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{++even;

}else

++odd;

}}printf ("The given matrix is\n");for (i=0;i


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#include

void main (){

static int ma[10][10];int i,j,m,n,a;

printf ("Enetr the order of the matix \n");scanf ("%d %d",&m,&n);

if (m ==n ){

printf ("Enter the co-efficients of the matrix\n");for (i=0;i


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}printf ("\n");

}}else

printf ("The givan order is not square matrix\n");} /* end of main() */

/*----------------------------------------------------OutputEnetr the order of the matix3 3Enter the co-efficients of the matrix1 2 34 5 6

7 8 9The given matrix is1 2 34 5 67 8 9

THe matrix after changing themain diagonal & secondary diagonal3 2 14 5 69 8 7

----------------------------------------------------------*/

Sample 36

/* Write a C program to find the sum of first 50 natural numbers ** using for loop */

#include

void main(){

int num,sum=0;

for(num = 1; num


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printf("Sum = %4d\n", sum);

}

/*---------------------------

OutputSum = 1275----------------------------*/ /* End of main() */

/* Write a C program to accept two integers and check if they are equal */


int m,n;

printf("Enter the values for M and N\n");scanf("%d %d", &m,&n);

if(m == n )printf("M and N are equal\n");

elseprintf("M and N are not equal\n");


/*------------------------------------outputEnter the values for M and N34 45M and N are not equal

-------------------------------------*/Sample 37

//* Write a C program to accept the height of a person in centermeter and ** categorize the person based on height as taller, dwarf and ** average height person */


float ht;


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printf("Enter the Height (in centimetres)\n");scanf("%f",&ht);

if(ht < 150.0)printf("Dwarf\n");

else if((ht>=150.0) && (ht=165.0) && (ht 0 && y > 0)printf("point (%d,%d) lies in the First quandrant\n");

else if( x < 0 && y > 0)printf("point (%d,%d) lies in the Second quandrant\n");

else if( x < 0 && y < 0)printf("point (%d, %d) lies in the Third quandrant\n");

else if( x > 0 && y < 0)printf("point (%d,%d) lies in the Fourth quandrant\n");

else if( x == 0 && y == 0)printf("point (%d,%d) lies at the origin\n");


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/*---------------------------------------------Output

RUN 1Enter the values for X and Y3 5point (5,3) lies in the First quandrant

RUN 2Enter the values for X and Y-4-7point (-7, -4) lies in the Third quandrant

---------------------------------------------*/

Sample 39

/* Write a C program to accept a figure code and find the ares of different ** geometrical figures such as circle, square, rectangle etc using switch */

#include

void main(){

int fig_code;float side,base,length,bredth,height,area,radius;

printf("-------------------------\n");printf(" 1 --> Circle\n");printf(" 2 --> Rectangle\n");printf(" 3 --> Triangle\n");printf(" 4 --> Square\n");printf("-------------------------\n");

printf("Enter the Figure code\n");scanf("%d",&fig_code);

switch(fig_code){

case 1: printf("Enter the radius\n");scanf("%f",&radius);area=3.142*radius*radius;


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printf("Area of a circle=%f\n", area);break;

case 2: printf("Enter the bredth and length\n");scanf("%f %f",&bredth, &length);

area=bredth *length;printf("Area of a Reactangle=%f\n", area);break;

case 3: printf("Enter the base and height\n");scanf("%f %f",&base,&height);area=0.5 *base*height;printf("Area of a Triangle=%f\n", area);break;

case 4: printf("Enter the side\n");

scanf("%f",&side);area=side * side;printf("Area of a Square=%f\n", area);break;

default: printf("Error in figure code\n");break;

} /* End of switch */

} /* End of main() *//*----------------------------------------------------OutputRun 1-------------------------1 --> Circle2 --> Rectangle3 --> Triangle4 --> Square

-------------------------Enter the Figure code2Enter the bredth and length26Area of a Reactangle=12.000000

Run 2-------------------------1 --> Circle


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2 --> Rectangle3 --> Triangle4 --> Square

-------------------------Enter the Figure code

3Enter the base and height57Area of a Triangle=17.500000

------------------------------------------------------*/Sample 40

/* Write a C Program to accept a grade and declare the equivalent descrption *

* if code is S, then print SUPER ** if code is A, then print VERY GOOD

** if code is B, then print FAIR

** if code is Y, then print ABSENT

** if code is F, then print FAILS

*/


void main(){

char remark[15];char grade;

printf("Enter the grade\n");scanf("%c",&grade);

grade=toupper(grade); /* lower case letter to upper case */

switch(grade){

case 'S': strcpy(remark," SUPER");break;


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case 'A': strcpy(remark," VERY GOOD");break;

case 'B': strcpy(remark," FAIR");break;

case 'Y': strcpy(remark," ABSENT");break;

case 'F': strcpy(remark," FAILS");break;

default : strcpy(remark, "ERROR IN GRADE\n");break;

} /* End of switch */

printf("RESULT : %s\n",remark);


/*-------------------------------------------OutputRUN 1Enter the gradesRESULT : SUPER

RUN 2Enter the gradeyRESULT : ABSENT-----------------------------------------------*/Sample 41

/* Write a C program to find the factorial of a given number */


int i,fact=1,num;

printf("Enter the number\n");scanf("%d",&num);


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if( num


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printf("Sum of all digits=%d\n",sum);


/*-----------------------------------------------------

OutputEnter the string containing both digits and alphabetgoodmorning25NO. of Digits in the string=2Sum of all digits=7

--------------------------------------------------------*/

Sample 43

/* Write a C program to accept an integer find the sum of the digits in it */

#include

void main(){

long num, temp, digit, sum = 0;

printf("Enter the number\n");scanf("%ld", &num);

temp = num;

while(num > 0){

digit = num % 10;sum = sum + digit;

num /= 10;}

printf("Given number =%ld\n", temp);printf("Sum of the digits %ld =%ld\n", temp, sum);

} /* End of main()*/

/*---------------------------------------Enter the number123456Given number =123456Sum of the digits 123456 =21----------------------------------------*/


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Sample 44

/* Write a C program to accept a matrix of order M x N and find the sum ** of each row and each column of a matrix */


static int m1[10][10];int i,j,m,n,sum=0;

printf ("Enter the order of the matrix\n");scanf ("%d %d", &m,&n);printf ("Enter the co-efficients of the matrix\n");

for (i=0;i


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OutputEnter the order of the matrix3 3Enter the co-efficients of the matrix1 2 3

4 5 67 8 9Sum of the 0 row is = 6Sum of the 1 row is = 15Sum of the 2 row is = 24Sum of the 0 column is = 12Sum of the 1 column is = 15Sum of the 2 column is = 18

----------------------------------------------------*/

Sample 45

/* Write a C program to find accept a matric of order M x N and find ** the sum of the main diagonal and off diagonal elements */

#include

void main (){

static int ma[10][10];int i,j,m,n,a=0,sum=0;

printf ("Enetr the order of the matix \n");scanf ("%d %d",&m,&n);

if ( m == n ){

printf ("Enter the co-efficients of the matrix\n");

for (i=0;i


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for (j=0;j


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Sample 46

/* Write a C program to accept a matricx of order MxN and find the trcae and ** normal of a matrix HINT:Trace is defined as the sum of main diagonal ** elements and Normal is defined as squre root of the sum of all *

* the elements */#include #include

void main (){

static int ma[10][10];int i,j,m,n,sum=0,sum1=0,a=0,normal;

printf ("Enter the order of the matrix\n");

scanf ("%d %d", &m,&n);printf ("Enter the ncoefficients of the matrix \n");for (i=0;i


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Trace of the matrix is = 15

Run 2Enter the order of the matrix2 2

Enter the ncoefficients of the matrix2 46 8The normal of the given matrix is = 10Trace of the matrix is = 10

-----------------------------------------------------*/Sample 47

/* Write a C program to accept a matric of order MxN and find its transpose */


static int ma[10][10];int i,j,m,n;

printf ("Enter the order of the matrix \n");scanf ("%d %d",&m,&n);

printf ("Enter the coefiicients of the matrix\n");for (i=0;i


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{for (i=0;i


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{scanf ("%d",&m1[i][j]);if (m1[i][j]==0){

++counter;

}}}if (counter>((m*n)/2)){

printf ("The given matrix is sparse matrix \n");}else

printf ("The given matrix is not a sparse matrix \n");

printf ("There are %d number of zeros",counter);

} /* EN dof main() *//*----------------------------------------------OutputEnter the order of the matix2 2Enter the co-efficients of the matix1 23 4The given matrix is not a sparse matrixThere are 0 number of zeros

Run 2Enter the order of the matix3 3Enter the co-efficients of the matix1 0 00 0 10 1 0The given matrix is sparse matrixThere are 6 number of zeros

-----------------------------------------------*/

Sample 49

/* Write a C program to accept a amtric of order MxN and sort all rows ** of the matrix in ascending order and all columns in descendng order */

#include


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void main (){

static int ma[10][10],mb[10][10];int i,j,k,a,m,n;

printf ("Enter the order of the matrix \n");scanf ("%d %d", &m,&n);

printf ("Enter co-efficients of the matrix \n");for (i=0;i


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1 32 5

After arranging the columns in descending order5 23 1

-----------------------------------------------------*/Sample 50

/* Write a C program to accept a set of names and sort them in ** an alphabetical order, Use structures to store the names */

#include#include#include

struct person{char name[10];int rno;

};typedef struct person NAME;NAME stud[10], temp[10];

void main(){

int no,i;

void sort(int N); /* Function declaration */

clrscr();fflush(stdin);

printf("Enter the number of students in the list\n");scanf("%d",&no);

for(i = 0; i < no; i++){

printf("\nEnter the name of person %d : ", i+1);fflush(stdin);gets(stud[i].name);

printf("Enter the roll number of %d : ", i+1);scanf("%d",&stud[i].rno);temp[i] = stud[i];

}


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printf("\n*****************************\n");printf (" Names before sorting \n");/* Print the list of names before sorting */for(i=0;i


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Enter the name of person 1 : RajashreeEnter the roll number of 1 : 123

Enter the name of person 2 : John

Enter the roll number of 2 : 222Enter the name of person 3 : PriyaEnter the roll number of 3 : 331

Enter the name of person 4 : AnandEnter the roll number of 4 : 411

Enter the name of person 5 : NirmalaEnter the roll number of 5 : 311

*****************************Names before sortingRajashree 123John 222Priya 331Anand 411Nirmala 311

*****************************Names after sorting

*****************************Anand 411John 222Nirmala 311Priya 331Rajashree 123

*****************************----------------------------------------------------*/Sample 50

/* Write a C Program to convert the lower case letters to upper case ** and vice-versa */



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void main(){

char sentence[100];int count, ch, i;clrscr();

printf("Enter a sentence\n");for(i=0; (sentence[i] = getchar())!='\n'; i++){;

}count = i;

printf("\nInput sentence is : %s ",sentence);

printf("\nResultant sentence is : ");

for(i=0; i < count; i++){ch = islower(sentence[i]) ? toupper(sentence[i]) : tolower(sentence[i]);

putchar(ch);}

} /*End of main()

/*-----------------------------------------OutputEnter a sentencegOOD mORNING

Input sentence is : gOOD mORNING

Resultant sentence is :Good Morning------------------------------------------*/

Sample 51

/* Write a C program to find the sum of two one-dimensional arrays using ** Dynamic Memory Allocation */


void main(){

int i,n;


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89Resultant List is79

1113

----------------------------------------*/Sample 52

/* Write a C program to find the sum of all elements of ** an array using pointersas arguments */

#include

void main(){

static int array[5]={ 200,400,600,800,1000 };int sum;

int addnum(int *ptr); /* function prototype */

sum = addnum(array);

printf("Sum of all array elements = %5d\n", sum);


int addnum(int *ptr){

int index, total=0;

for(index = 0; index < 5; index++){

total += *(ptr+index);}return(total);

}/*-----------------------------------OutputSum of all array elements = 3000------------------------------------*/


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Sample 53

/* Write a C program to accept an array of 10 elements and swap 3rd ** element with 4th element using pointers. And display the results */

#include

void main(){

float x[10];int i,n;

void swap34(float *ptr1, float *ptr2 ); /* Function Declaration */

printf("How many Elements...\n");scanf("%d", &n);

printf("Enter Elements one by one\n");

for(i=0;i


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/*-------------------------------------------OutputHow many Elements...10

Enter Elements one by one102030405060708090100

Resultant Array...X[0] = 10.000000X[1] = 20.000000X[2] = 40.000000X[3] = 30.000000X[4] = 50.000000X[5] = 60.000000X[6] = 70.000000X[7] = 80.000000X[8] = 90.000000X[9] = 100.000000----------------------------------------------------*/

Sample 54

/* Write a C program to illustrate the concept of unions*/

#include #include

void main(){

union number{

int n1;float n2;

};

union number x;


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clrscr() ;

printf("Enter the value of n1: ");scanf("%d", &x.n1);

printf("Value of n1 =%d", x.n1);printf("\nEnter the value of n2: ");scanf("%d", &x.n2);printf("Value of n2 = %d\n",x.n2);


/*------------------------------------OutputEnter the value of n1: 2

Value of n1 =2Enter the value of n2: 3Value of n2 = 0------------------------------------*/Sample 55

/* Write a C program to find the size of a union*/

#include

void main(){

union sample{

int m;float n;

char ch;};

union sample u;

printf("The size of union =%d\n", sizeof(u));

/*initialization */

u.m = 25;printf("%d %f %c\n", u.m, u.n,u.ch);

u.n = 0.2;


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printf("%d %f %c\n", u.m, u.n,u.ch);

u.ch = 'p';printf("%d %f %c\n", u.m, u.n,u.ch);

} /*End of main() */

/*-----------------------------------------OutputThe size of union =425 12163373596672.000000 -13107 0.200000 -13200 0.199999 p------------------------------------------*/Sample 56

/* Write a C program to create a file called emp.rec and store information *

* about a person, in terms of his name, age and salary. */#include

void main(){

FILE *fptr;char name[20];

int age;float salary;

fptr = fopen ("emp.rec", "w"); /*open for writing*/

if (fptr == NULL){

printf("File does not exists\n");return;

}

printf("Enter the name\n");scanf("%s", name);

fprintf(fptr, "Name = %s\n", name);

printf("Enter the age\n");scanf("%d", &age);

fprintf(fptr, "Age = %d\n", age);

printf("Enter the salary\n");scanf("%f", &salary);

fprintf(fptr, "Salary = %.2f\n", salary);


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fclose(fptr);

}

/*---------------------------------------------------------------------------

OutputEnter the namePrabhuEnter the age25Enter the salary25000-------------------------------------Please note that you have to open the file called emp.rec in the directory

Name = Prabhu

Age = 25Salary = 25000.00-----------------------------------------------------------------------------*/

Sample 57

/*Write a C program to illustrate as to how the data stored on the disk is read */

#include #include

void main(){

FILE *fptr;char filename[15];char ch;

printf("Enter the filename to be opened\n");gets(filename);

fptr = fopen (filename, "r"); /*open for reading*/

if (fptr == NULL){

printf("Cannot open file\n");exit(0);

}

ch = fgetc(fptr);


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while (ch != EOF){

printf ("%c", ch);ch = fgetc(fptr);

}

fclose(fptr);} /* End of main () *//*----------------------------------------------OutputEnter the filename to be openedemp.recName = PrabhuAge = 25Salary = 25000.00------------------------------------------------*/

Sample 58

/* This program accepts an array of N elements and a key. ** Then it searches for the desired element. If the search ** is successful, it displays "SUCCESSFUL SEARCH". ** Otherwise, a message "UNSUCCESSFUL SEARCH" is displayed. */


int table[20];int i, low, mid, high, key, size;

printf("Enter the size of an array\n");scanf("%d", &size);

printf("Enter the array elements\n");for(i = 0; i < size; i++){

scanf("%d", &table[i]);}

printf("Enter the key\n");scanf("%d", &key);

/* search begins */

low = 0;high = (size - 1);


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while(low


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int num;struct node *ptr;

};

typedef struct node NODE;

NODE *head, *first, *temp=0;int count = 0;int choice = 1;first = 0;

while(choice){

head =(NODE*) malloc(sizeof(NODE));printf("Enter the data item\n");scanf("%d", &head-> num);

if(first != 0){

temp->ptr = head;temp = head;

}else{

first = temp = head;}fflush(stdin);printf("Do you want to continue(Type 0 or 1)?\n");scanf("%d", &choice);

} /* End of while */

temp->ptr = 0;temp = first; /* reset temp to the beginning*/printf("\nstatus of the linked list is\n");

while(temp!=0){

printf("%d=>", temp->num);count++;temp = temp -> ptr;

}printf("NULL\n");printf("No. of nodes in the list = %d\n", count);

} /* End of main*/


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/*-----------------------------------------------OutputEnter the data item10Do you want to continue(Type 0 or 1)?

1Enter the data item34Do you want to continue(Type 0 or 1)?1Enter the data item56Do you want to continue(Type 0 or 1)?0

status of the linked list is

10=>34=>56=>NULLNo. of nodes in the list = 3----------------------------------------------*/Sample 60

/* Write a C program to illustrate the operations of singly linked list */

#include #include #include #include #define MAX 30

struct EMP{

int empno;char empName[MAX];char designation[MAX];struct EMP *next;

};

/*********************************************************************//* Function to insert a node at the front of the linked list. *//* front: front pointer, id: employee ID, name: employee name *//* desg: Employee designation *//* Returns the new front pointer. *//*********************************************************************/


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struct EMP* insert(struct EMP *front, int id, char name[], char desg[]){

struct EMP *newnode;

newnode = (struct EMP*) malloc(sizeof(struct EMP));

if (newnode == NULL){

printf("\nAllocation failed\n");exit(2);

}newnode->empno = id;strcpy(newnode->empName, name);strcpy(newnode->designation, desg);newnode->next = front;front = newnode;

return(front);} /*End of insert() */

/* Function to display a node in a linked list */void printNode(struct EMP *p){

printf("\nEmployee Details...\n");printf("\nEmp No : %d", p->empno);printf("\nName : %s", p->empName);printf("\nDesignation : %s\n", p->designation);printf("-------------------------------------\n");

} /*End of printNode() */

/* ********************************************************//* Function to deleteNode a node based on employee number *//* front: front pointer, id: Key value *//* Returns: the modified list. *//* ********************************************************/

struct EMP* deleteNode(struct EMP *front, int id){

struct EMP *ptr;struct EMP *bptr; /* bptr is pointing to the node behind ptr */

if (front->empno == id){

ptr = front;printf("\nNode deleted:");

printNode(front);


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front = front->next;free(ptr);

return(front);}

for(ptr=front->next, bptr=front; ptr!=NULL; ptr=ptr->next, bptr=bptr->next){if (ptr->empno == id){

printf("\nNode deleted:");printNode(ptr);bptr->next = ptr->next;free(ptr);return(front);

}}

printf("\nEmployee Number %d not found ", id);return(front);} /*End of deleteNode() */

/*****************************************************************//* Function to search the nodes in a linear fashion based emp ID *//* front: front pointer, key: key ID. *//*****************************************************************/void search(struct EMP *front, int key){

struct EMP *ptr;

for (ptr = front; ptr != NULL; ptr = ptr -> next){

if (ptr->empno == key){

printf("\nKey found:");printNode(ptr);return;

}}printf("\nEmployee Number %d not found ", key);

} /*End of search() */

/* Function to display the linked list */void display(struct EMP *front){

struct EMP *ptr;

for (ptr = front; ptr != NULL; ptr = ptr->next)


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{printNode(ptr);

}} /*End of display() */

/* Function to display the menu of operations on a linked list */void menu(){

printf("---------------------------------------------\n");printf("Press 1 to INSERT a node into the list \n");printf("Press 2 to DELETE a node from the list \n");printf("Press 3 to DISPLAY the list \n");printf("Press 4 to SEARCH the list \n");printf("Press 5 to EXIT \n");printf("---------------------------------------------\n");

} /*End of menu() */

/* Function to select the option */char option(){

char choice;

printf("\n\n>> Enter your choice: ");switch(choice=getche()){

case '1':case '2':

case '3':case '4':

case '5': return(choice);default : printf("\nInvalid choice.");

}return choice;

} /*End of option() */

/* The main() program begins */void main(){

struct EMP *linkList;char name[21], desig[51];char choice;int eno;

linkList = NULL;

printf("\nWelcome to demonstration of singly linked list\n");


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menu(); /*Function call */

do {choice = option(); /*to choose oeration to be performed */

switch(choice){

case '1': printf("\nEnter the Employee Number : ");scanf("%d", &eno);

printf("Enter the Employee name: ");

fflush(stdin);gets(name);

printf("Enter the EmployeeDesignation : ");gets(desig);

linkList = insert(linkList, eno, name,desig);

break;

case '2': printf("\n\nEnter the employee number to bedeleted: ");

scanf("%d", &eno);

linkList = deleteNode(linkList, eno);break;

case '3': if (linkList == NULL){

printf("\nList empty.");break;

}display(linkList);break;

case '4': printf("\n\nEnter the employee number to besearched: ");

scanf("%d", &eno);

search(linkList, eno);break;


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case '5': break;}

} while (choice != '5');} /*End fo main()*/

/*------------------------------------------------------------------------------Output

Welcome to demonstration of singly linked list---------------------------------------------Press 1 to INSERT a node into the listPress 2 to DELETE a node from the listPress 3 to DISPLAY the listPress 4 to SEARCH the listPress 5 to EXIT---------------------------------------------

>> Enter your choice: 1Enter the Employee Number : 1234Enter the Employee name : KeerthiEnter the Employee Designation : Engineer

>> Enter your choice: 1Enter the Employee Number : 2345Enter the Employee name : SrinivasanEnter the Employee Designation : Specilist

>> Enter your choice: 1Enter the Employee Number : 4567Enter the Employee name : AnnapoornaEnter the Employee Designation : Project Manager

>> Enter your choice: 3Employee Details...

Emp No : 4567Name : AnnapoornaDesignation : Project Manager-------------------------------------

Employee Details...


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Emp No : 2345Name : SrinivasanDesignation : Specilist-------------------------------------

Employee Details...Emp No : 1234Name : KeerthiDesignation : Engineer-------------------------------------

>> Enter your choice: 2

Enter the employee number to be deleted: 2345

Node deleted:Employee Details...

Emp No : 2345Name : SrinivasanDesignation : Specilist-------------------------------------

>> Enter your choice: 3Employee Details...

Emp No : 4567Name : AnnapoornaDesignation : Project Manager-------------------------------------

Employee Details...

Emp No : 1234Name : KeerthiDesignation : Engineer-------------------------------------


Enter the employee number to be searched: 2345


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Employee Number 2345 not found


------------------------------------------------------------------------------*/

Sample 61

/* Write a C program to implement stack. Stack is a LIFO data strcuture ** LIFO - Last in First Out ** Perform PUSH(insert operation), POP(Delete operation) and Display stack */

#include #include #define MAXSIZE 5

struct stack /* Structure definition for stack */{

int stk[MAXSIZE];int top;

};

typedef struct stack STACK;STACK s;

/* Function declaration/Prototype*/

void push (void);int pop(void);void display (void);

void main (){

int choice;int option = 1;

clrscr ();

s.top = -1;

printf ("STACK OPERATION\n");while (option){

printf ("------------------------------------------\n");printf (" 1 --> PUSH \n");


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printf (" 2 --> POP \n");printf (" 3 --> DISPLAY \n");printf (" 4 --> EXIT \n");printf ("------------------------------------------\n");

printf ("Enter your choice\n");scanf ("%d", &choice);

switch (choice){

case 1: push();break;

case 2: pop();break;

case 3: display();break;

case 4: return;}

fflush (stdin);printf ("Do you want to continue(Type 0 or 1)?\n");scanf ("%d", &option);

}}

/*Function to add an element to the stack*/void push (){

int num;if (s.top == (MAXSIZE - 1)){

printf ("Stack is Full\n");return;

}else{

printf ("Enter the element to be pushed\n");scanf ("%d", &num);s.top = s.top + 1;s.stk[s.top] = num;

}return;

}

/*Function to delete an element from the stack*/


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int pop (){

int num;if (s.top == - 1){

printf ("Stack is Empty\n");return (s.top);}else{

num = s.stk[s.top];printf ("poped element is = %d\n", s.stk[s.top]);s.top = s.top - 1;

}return(num);

}

/*Function to display the status of the stack*/void display (){

int i;if (s.top == -1){

printf ("Stack is empty\n");return;

}else{

printf ("\nThe status of the stack is\n");for (i = s.top; i >= 0; i--){

printf ("%d\n", s.stk[i]);}

}printf ("\n");

}

/*---------------------------------------------------------------------------OutputSTACK OPERATION------------------------------------------

1 --> PUSH2 --> POP

3 --> DISPLAY4 --> EXIT

------------------------------------------


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Enter your choice1Enter the element to be pushed23Do you want to continue(Type 0 or 1)?

1------------------------------------------1 --> PUSH

2 --> POP3 --> DISPLAY

4 --> EXIT------------------------------------------Enter your choice1Enter the element to be pushed45

Do you want to continue(Type 0 or 1)?1------------------------------------------

1 --> PUSH2 --> POP


------------------------------------------Enter your choice1Enter the element to be pushed78Do you want to continue(Type 0 or 1)?1------------------------------------------

1 --> PUSH2 --> POP


------------------------------------------Enter your choice3

The status of the stack is784523

Do you want to continue(Type 0 or 1)?1


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