BUFFER BUFFER SOLUTIONSSOLUTIONS

A guide for A level studentsA guide for A level students

© 2004 JONATHAN HOPTON & KNOCKHARDY PUBLISHING© 2004 JONATHAN HOPTON & KNOCKHARDY PUBLISHING

Buffer solutionsBuffer solutions

INTRODUCTION

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CONTENTS

• What is a buffer solution?

• Uses of buffer solutions

• Acidic buffer solutions

• Alkaline buffer solutions

• Buffer solutions - ideal concentration

• Calculating the pH of a buffer solution

• Salt hydrolysis

• Check list

Buffer solutionsBuffer solutions

Before you start it would be helpful to…

• know that weak acids and bases are only partly ionised in solution

• be able to calculate pH from hydrogen ion concentration

• be able to construct an equation for the dissociation constant of a weak acid

Buffer solutionsBuffer solutions

Buffer solutions - Buffer solutions - BriefBrief introductionintroduction

Acidic Buffer (pH < 7) made from a weak acid + its sodium or potassium salt ethanoic acid sodium ethanoate

Alkaline Buffer (pH > 7) made from a weak base + its chloride ammonia ammonium chloride

Uses Standardising pH metersBuffering biological systems (eg in blood)Maintaining the pH of shampoos

Definition “Solutions which resist changes in pH when small quantities of acid or alkali are added.”

Buffer solutions - usesBuffer solutions - uses

Definition “Solutions which resist changes in pH when small quantities of acid or alkali are added.”

Biological Uses

In biological systems (saliva, stomach, and blood) it is essential thatthe pH stays ‘constant’ in order for any processes to work properly.e.g. If the pH of blood varies by 0.5 it can lead to unconsciousness and coma

Most enzymes work best at particular pH values.

Other Uses Many household and cosmetic products need to control their pH values.

Shampoo Buffer solutions counteract the alkalinity of the soap and prevent irritation

Baby lotion Buffer solutions maintain a pH of about 6 to prevent bacteria multiplying

Others Washing powder, eye drops, fizzy lemonade

Acidic buffer solutions - Acidic buffer solutions - actionaction

It is essential to have a weak acid for an equilibrium to be present so that ions can be removed and produced. The dissociation is small and there are few ions.

CH3COOH(aq) CH3COO¯(aq) + H+(aq)

relative concs. HIGH LOW LOW

NB A strong acid can’t be used as it is fully dissociated and cannot remove H+(aq)

HCl(aq) ——> Cl¯(aq) + H+(aq)

Adding acidAny H+ is removed by reacting with CH3COO¯ ions to form CH3COOH via the equilibrium. Unfortunately, the concentration of CH3COO¯ is small and only a few H+ can be “mopped up”. A much larger concentration of CH3COO¯ is required.

To build up the concentration of CH3COO¯ ions, sodium ethanoate is added.

It is essential to have a weak acid for an equilibrium to be present so that ions can be removed and produced. The dissociation is small and there are few ions.

CH3COOH(aq) CH3COO¯(aq) + H+(aq)

relative concs. HIGH LOW LOW

NB A strong acid can’t be used as it is fully dissociated and cannot remove H+(aq)

HCl(aq) ——> Cl¯(aq) + H+(aq)

Adding alkaliThis adds OH¯ ions which react with H+ ions H+(aq) + OH¯(aq) H2O(l)

Removal of H+ from the weak acid equilibrium means that, according to Le Chatelier’s Principle, more CH3COOH will dissociate to form ions to replace those being removed.

CH3COOH(aq) CH3COO¯(aq) + H+(aq)

As the added OH¯ ions remove the H+ from the weak acid system, the equilibrium moves to the right to produce more H+ ions. Obviously, there must be a large concentration of undissociated acid molecules to be available.

Acidic buffer solutions - Acidic buffer solutions - actionaction

Alkaline bufferVery similar but is based on the equilibrium surrounding a weak base; AMMONIA

NH3(aq) + H2O(l) OH¯(aq) + NH4+(aq)

relative concs. HIGH LOW LOW

but one needs ; a large conc. of OH¯(aq) to react with any H+(aq) addeda large conc of NH4

+(aq) to react with any OH¯(aq) added

There is enough NH3 to act as a source of OH¯ but one needs to increase the concentration of ammonium ions by adding an ammonium salt.

Use AMMONIA (a weak base) + AMMONIUM CHLORIDE (one of its salts)

Alkaline buffer solutions - Alkaline buffer solutions - actionaction

Buffer solutions - Buffer solutions - ideal concentrationideal concentration

The concentration of a buffer solution is also important

If the concentration is too low, there won’t be enough CH3COOH and CH3COO¯

to cope with the ions added.

SummaryFor an acidic buffer solution one needs ...

large [CH3COOH(aq)] - for dissociating into H+(aq) when alkali is added

large [CH3COO¯(aq)] - for removing H+(aq) as it is added

This situation can’t exist if only acid is present; a mixture of the acid and salt is used.

The weak acid provides the equilibrium and the large CH3COOH(aq) concentration.

The sodium salt provides the large CH3COO¯(aq) concentration.

One uses a WEAK ACID + its SODIUM OR POTASSIUM SALT

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of a buffer whose [HA] is 0.1 mol dm-3 and [A¯] of 0.1 mol dm-3.

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of a buffer whose [HA] is 0.1 mol dm-3 and [A¯] of 0.1 mol dm-3.

Ka = [H+(aq)] [A¯(aq)]

[HA(aq)]

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of a buffer whose [HA] is 0.1 mol dm-3 and [A¯] of 0.1 mol dm-3.

Ka = [H+(aq)] [A¯(aq)]

[HA(aq)]

re-arrange [H+(aq)] = [HA(aq)] x Ka

[A¯(aq)]

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of a buffer whose [HA] is 0.1 mol dm-3 and [A¯] of 0.1 mol dm-3.

Ka = [H+(aq)] [A¯(aq)]

[HA(aq)]

re-arrange [H+(aq)] = [HA(aq)] x Ka

[A¯(aq)]

from information given [A¯] = 0.1 mol dm-3

[HA] = 0.1 mol dm-3

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of a buffer whose [HA] is 0.1 mol dm-3 and [A¯] of 0.1 mol dm-3.

Ka = [H+(aq)] [A¯(aq)]

[HA(aq)]

re-arrange [H+(aq)] = [HA(aq)] x Ka

[A¯(aq)]

from information given [A¯] = 0.1 mol dm-3

[HA] = 0.1 mol dm-3

If the Ka of the weak acid HA is 2 x 10-4 mol dm-3.

[H+(aq)] = 0.1 x 2 x 10-4 = 2 x 10-4 mol dm-3

0.1

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of a buffer whose [HA] is 0.1 mol dm-3 and [A¯] of 0.1 mol dm-3.

Ka = [H+(aq)] [A¯(aq)]

[HA(aq)]

re-arrange [H+(aq)] = [HA(aq)] x Ka

[A¯(aq)]

from information given [A¯] = 0.1 mol dm-3

[HA] = 0.1 mol dm-3

If the Ka of the weak acid HA is 2 x 10-4 mol dm-3.

[H+(aq)] = 0.1 x 2 x 10-4 = 2 x 10-4 mol dm-3

0.1

pH = - log10 [H+(aq)] = 3.699

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of the solution formed when 500cm3 of 0.1 mol dm-3 of weak acid HX is mixed with 500cm3 of a 0.2 mol dm-3 solution of its salt NaX. Ka = 4 x 10-5 mol dm-3.

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of the solution formed when 500cm3 of 0.1 mol dm-3 of weak acid HX is mixed with 500cm3 of a 0.2 mol dm-3 solution of its salt NaX. Ka = 4 x 10-5 mol dm-3.

Ka = [H+(aq)] [X¯(aq)]

[HX(aq)]

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of the solution formed when 500cm3 of 0.1 mol dm-3 of weak acid HX is mixed with 500cm3 of a 0.2 mol dm-3 solution of its salt NaX. Ka = 4 x 10-5 mol dm-3.

Ka = [H+(aq)] [X¯(aq)]

[HX(aq)]

re-arrange [H+(aq)] = [HX(aq)] Ka

[X¯(aq)]

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of the solution formed when 500cm3 of 0.1 mol dm-3 of weak acid HX is mixed with 500cm3 of a 0.2 mol dm-3 solution of its salt NaX. Ka = 4 x 10-5 mol dm-3.

Ka = [H+(aq)] [X¯(aq)]

[HX(aq)]

re-arrange [H+(aq)] = [HX(aq)] Ka

[X¯(aq)]

The solutions have been mixed; the volume is now 1 dm3

therefore [HX] = 0.05 mol dm-3 and

[X¯] = 0.10 mol dm-3

Calculating the pH of an acidic buffer solutionCalculating the pH of an acidic buffer solution

Calculate the pH of the solution formed when 500cm3 of 0.1 mol dm-3 of weak acid HX is mixed with 500cm3 of a 0.2 mol dm-3 solution of its salt NaX. Ka = 4 x 10-5 mol dm-3.

Ka = [H+(aq)] [X¯(aq)]

[HX(aq)]

re-arrange [H+(aq)] = [HX(aq)] Ka

[X¯(aq)]

The solutions have been mixed; the volume is now 1 dm3

therefore [HX] = 0.05 mol dm-3 and

[X¯] = 0.10 mol dm-3

Substituting [H+(aq)] = 0.05 x 4 x 10-5 = 2 x 10-5 mol dm-3

0.1

pH = - log10 [H+(aq)] = 4.699

SALT HYDROLYSISSALT HYDROLYSIS

Many salts dissolve in water to produce solutions which are not neutral. This is because the ions formed react with the hydroxide and hydrogen ions formed when water dissociates. There are four distinct systems.

All dissociated ions are aqueous ions. When mixed, the ions of strong acids and bases remain apart. Ions of weak acids and bases associate.

SALT HYDROLYSISSALT HYDROLYSIS

Many salts dissolve in water to produce solutions which are not neutral. This is because the ions formed react with the hydroxide and hydrogen ions formed when water dissociates. There are four distinct systems.

All dissociated ions are aqueous ions. When mixed, the ions of strong acids and bases remain apart. Ions of weak acids and bases associate.

Salts of strong acids and strong bases - SODIUM CHLORIDE

NaCl dissociates completely in water Na+ Cl¯ ——> Na+ + Cl¯ Water only ionises to a very small extent H2O OH¯ + H+

Na+ and OH¯ are ions of a strong base so remain apart H+and Cl¯ are ions of a strong acid so remain apart

all the OH¯ and H+ ions remain in solution

therefore [H+] = [OH¯] and the solution will be NEUTRAL

SALT HYDROLYSISSALT HYDROLYSIS

Many salts dissolve in water to produce solutions which are not neutral. This is because the ions formed react with the hydroxide and hydrogen ions formed when water dissociates. There are four distinct systems.

All dissociated ions are aqueous ions. When mixed, the ions of strong acids and bases remain apart. Ions of weak acids and bases associate.

Salts of strong acids and weak bases - AMMONIUM CHLORIDE

NH4Cl dissociates completely in waterNH4+ Cl¯ ——> NH4

+ + Cl¯

Water only ionises to a very small extent H2O OH¯ + H+

NH3 + H2O

Na+ and OH¯ are ions of a strong base so tend to be associatedH+and Cl¯ are ions of a strong acid so remain apart

all the H+ ions remain in solution

therefore [H+] > [OH¯] and the solution will be ACIDIC

SALT HYDROLYSISSALT HYDROLYSIS

Many salts dissolve in water to produce solutions which are not neutral. This is because the ions formed react with the hydroxide and hydrogen ions formed when water dissociates. There are four distinct systems.

All dissociated ions are aqueous ions. When mixed, the ions of strong acids and bases remain apart. Ions of weak acids and bases associate.

Salts of weak acids and strong bases - SODIUM ETHANOATE

CH3COONa dissociates completely in water CH3COO ¯ Na + ——> Na+ + CH3COO¯

Water only ionises to a very small extent H2O OH¯ + H+

CH3COOH

Na+ and OH¯ are ions of a strong base so remain apartH+and CH3OO¯ are ions of a weak acid so tend to be associated

all the OH¯ ions remain in solution

therefore [OH¯] > [H+] and the solution will be ALKALINE

SALT HYDROLYSISSALT HYDROLYSIS

Many salts dissolve in water to produce solutions which are not neutral. This is because the ions formed react with the hydroxide and hydrogen ions formed when water dissociates. There are four distinct systems.

All dissociated ions are aqueous ions. When mixed, the ions of strong acids and bases remain apart. Ions of weak acids and bases associate.

Salts of weak acids and weak bases - AMMONIUM ETHANOATE

CH3COONH4 dissociates completely in water CH3COO ¯ NH4 + ——> NH4+ + CH3COO¯

Water only ionises to a very small extent H2O OH¯ + H+

NH3 + H2O CH3COOH

Na+ and OH¯ are ions of a weak base so tend to be associatedH+and CH3OO¯ are ions of a weak acid so tend to be associated

the solution might be alkaline or acidic i.e. APPROXIMATELY NEUTRAL

REVISION CHECKREVISION CHECK

What should you be able to do?

Recall the definition of a buffer solution

Recall the difference between an acidic and an alkaline buffer solution

Recall the uses of buffer solutions

Understand the action of buffer solutions

Calculate the pH of an acidic buffer solution

Recall and understand the reactions due to salt hydrolysis

CAN YOU DO ALL OF THESE? CAN YOU DO ALL OF THESE? YES YES NONO

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BUFFER BUFFER SOLUTIONSSOLUTIONS

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© 2004 JONATHAN HOPTON & KNOCKHARDY PUBLISHING© 2004 JONATHAN HOPTON & KNOCKHARDY PUBLISHING