boundary element analysis of thermo-elastic problems with non-uniform heat sources

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  • 8/3/2019 Boundary Element Analysis of Thermo-elastic Problems With Non-uniform Heat Sources

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    The Journal of Strain Analysis for Engineering

    http://sdj.sagepub.com/content/45/8/605The online version of this article can be found at:

    DOI: 10.1177/030932471004500803

    2010 45: 605The Journal of Strain Analysis for Engineering DesignM Mohammadi, M R Hematiyan and M H Aliabadi

    Boundary element analysis of thermo-elastic problems with non-uniform heat sources

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    Boundary element analysis of thermo-elastic problemswith non-uniform heat sources

    M Mohammadi1, M R Hematiyan1, and M H Aliabadi2*1Department of Mechanical Engineering, School of Engineering, Shiraz University, Shiraz, Iran2Department of Aeronautics, Imperial College, London, UK

    The manuscript was received on 19 November 2009 and was accepted after revision for publication on 12 April 2010.

    DOI: 10.1243/03093247JSA620

    Abstract: A boundary element formulation for the analysis of two-dimensional and three-dimensional steady state thermo-elastic problems involving arbitrary non-uniform heat

    sources is presented. All domain integrals are expressed in terms of a heat source functioninstead of a temperature function. The proposed method alleviates the difficulty associatedwith finding the temperature distribution throughout the domain. A simple, yet robust, methodreferred to as the Cartesian transformation method (CTM) is developed that allows boundary-only evaluation of domain integrals. Unlike other transformation methods the CTM does notrequire the introduction of a domain point for the transformation. Domain heat sourcesdefined either over the whole domain or over a specific part of the domain can be treated by theproposed method. Three examples including different forms of heat sources are analysed toshow the validity and efficiency of the presented methods.

    Keywords: boundary element method, thermo-elasticity, non-uniform heat source,boundary-only formulation

    1 INTRODUCTION

    In some thermo-elastic applications with electrical

    heating, internal chemical reactions, or laser heating,

    a non-uniform heat source must be considered for

    accurate modelling of the problem. Only a few simple

    thermo-elastic problems involving non-uniform heat

    sources can be solved analytically. To solve most

    practical thermo-elastic problems, however, numer-

    ical methods need to be employed. The boundary

    element method (BEM) is an efficient and accuratenumerical technique for the analysis of thermo-

    elastic phenomena. Presenting a BEM formulation

    without domain discretization for the analysis of

    thermo-elastic problems with non-uniform heat

    sources is very attractive, especially from a modelling

    point of view. Such a formulation is also a useful tool

    for optimization in thermo-elastic systems [1].

    Domain integrals that include a temperature rise

    function appear in the conventional BEM formula-

    tion of thermo-elasticity. Most researchers have

    assumed that the temperature rise function is known

    throughout the domain and have attempted to

    evaluate the corresponding domain integrals with

    or without domain discretization [27]. When the

    temperature function is harmonic, i.e. satisfies the

    steady state heat conduction equation without a

    heat source, the domain integral can be exactly

    transformed into a boundary integral [8]; however,

    in cases with a more complicated form of tempera-

    ture function, special techniques must be applied. If

    the displacement and stress integral equations of

    thermo-elasticity can be obtained in a form in which

    domain integrals are expressed in terms of a heat

    source function instead of temperature, then the

    problem can be analysed with no need to find the

    temperature distribution throughout the domain.

    There are a few studies in the literature on the

    BEM analysis of thermo-elastic problems involving

    heat sources. Shiah and Tan [9, 10] presented a BEM

    formulation for two-dimensional (2D) anisotropicsteady state thermo-elasticity involving uniform heat

    *Corresponding author: Department of Aeronautics, Imperial

    College, London, Prince Consort Road, South Kensington, London

    SW7 2BY, UK.email: [email protected]

    605

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    sources. They derived the Somigliana identity of the

    interior strain and transformed the produced do-

    main integrals exactly into boundary integrals. Shiah

    and Lin [11] and Shiah and Huang [12] derived the

    displacement and stress integral equations for 2D

    anisotropic thermo-elasticity involving non-uniform

    heat sources using the multiple reciprocity method.

    They transformed domain integrals into an infinite

    series of boundary integrals and considered several

    first terms of the series in their computations.

    On the other hand, Ochiai [13] presented a BEM

    formulation for three-dimensional (3D) thermo-

    elasticity involving non-uniform heat sources by

    the triple-reciprocity method. A thermo-elastic dis-

    placement potential was used to derive the stress

    integral equation. In the triple-reciprocity method,

    the forcing function is interpolated using additionalboundary integral equations and consideration of

    some internal points [1315].

    In this paper, a new BEM formulation for the

    analysis of 2D and 3D steady state thermo-elastic

    problems involving arbitrary non-uniform heat

    sources is presented. Domain integrals in the

    conventional displacement and stress integral equa-

    tions of thermo-elasticity with arbitrary temperature

    function are, respectively, weakly and strongly

    singular [5, 7, 16]. However, in the present formula-

    tion in which the problem is formulated in terms of a

    heat source function instead of a temperaturefunction, these domain integrals are, respectively,

    regular and weakly singular and therefore, can be

    evaluated more efficiently. Domain integrals related

    to heat source functions are efficiently evaluated by

    boundary-only discretization using a new method.

    There is no need to define any internal point to

    transform the domain integrals into boundary

    integrals. Domain heat sources defined over the

    whole domain or over a specific part of the domain

    can be treated by the proposed method.

    This paper is organized as follows. In section 2, the

    Cartesian transformation method, which is a me-

    thod for the evaluation of domain integrals without

    domain discretization, is described. A general for-

    mula for differentiating a singular domain integral

    with respect to source point coordinates is described

    in section 3. The formula is subsequently used to

    derive the stress integral equation by differentiating

    the displacement integral equation. The temperature

    and displacement integral equations of thermo-

    elasticity involving domain heat sources are derived

    in section 4. The stress integral equation for internal

    points is derived in section 5. The methods for theevaluation of the domain integrals with boundary-

    only discretization for various kinds of heat sources

    are described in section 6. Some numerical examples

    are presented in section 7, and finally concluding

    remarks are made in section 8.

    2 CARTESIAN TRANSFORMATION METHOD FORTHE EVALUATION OF DOMAIN INTEGRALS

    Various methods have been developed for the

    evaluation of the domain integrals in the BEM. Rizzo

    and Shippy [2] and Cruse et al. [17] used a

    divergence theorem to convert domain integrals into

    boundary integrals for a limited range of body forces.

    The Galerkin vector method was presented by

    Danson [18]. A method for exact transformation of

    domain integrals into boundary integrals by employ-

    ing particular integrals was proposed by Pape and

    Banerjee [19]. The dual reciprocity method (DRM)

    [20] is a well-known method for the treatment of

    domain integrals. In this method, the body force

    function is approximated by a series of prescribed

    basis functions. The prescribed basis functions in

    the DRM must be defined in a radial form such that

    it is possible to find corresponding particular

    solutions. In the multiple reciprocity method

    (MRM) [21], the reciprocity theorem is employed

    several times and the domain integrals are trans-

    formed into boundary integrals using integration byparts. The MRM can be employed only for a limited

    number of problems. Another technique for the

    evaluation of domain integrals with boundary-only

    discretization is the radial integration method [22].

    In this method, the domain integral is transformed

    into a double integral consisting of a boundary

    integral and a radial integral. Once the radial integral

    is evaluated analytically, the domain integral can be

    transformed exactly to the boundary.

    In this section, the Cartesian transformation

    method (CTM), which is a general and robust

    method for the treatment of the domain integrals,is described. The method is very simple in both

    concept and implementation and can be used for the

    evaluation of regular and singular domain integrals

    with boundary-only discretization. The CTM will be

    used in this paper for the evaluation of the domain

    integrals in the temperature, displacement, and

    stress integral equations of thermo-elasticity.

    Suppose that the following integral is to be com-

    puted

    I~V

    h x dV 1

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    where x represents a point within the domain V or

    on its boundary C. This domain integral can be

    transformed into a boundary integral using Greens

    theorem which in general form, for a 2D or 3D

    domain, can be expressed as follows [23]

    V

    Lp x Lxi

    dV~

    C

    p x ni dC 2

    where ni is the ith component of the unit outward

    normal vector n. This theorem can also be applied to

    multiply connected domains. For example, for the

    multiply connected domain shown in Fig. 1, equa-

    tion (2) can be expressed as follows

    V

    Lp x Lxi

    dV~

    C0,C1,C2

    p x ni dC

    ~

    C0

    p x ni dCzC1

    p x ni dC

    z

    C2

    p x ni dC 3

    Using equation (2), the integral in equation (1) be-

    comes

    I~

    C

    Hi x ni dC, i~1, 2, or 3 no sum on i 4

    where

    Hi x ~

    h x dxi, i~1, 2, or 3 5

    It should be noted that the derivative of Hi with

    respect to xi is h. The one dimensional (1D) integral

    in equation (5) can be evaluated analytically for

    a wide variety of domain integrals [24]. When the

    integrand h is very complicated, the integral in

    equation (5) can be evaluated numerically as

    Hi x ~xi

    a

    h x dxi i~1, 2, or 3 6

    where a is an arbitrary constant. In cases with acomplicated integrand, the 1D integral in equation

    (6) is evaluated numerically. By this approach a

    mesh-free and adaptive technique for the evaluation

    of domain integrals can be developed [25]. The

    method can also be applied for cases in which the

    integrand h is defined by some discrete data points

    [26, 27]. Since the transformation of the domain

    integral is carried out in the Cartesian coordinate

    system, the method is called the CTM [26].

    When the integrand in the domain integral in

    equation (1) has a singularity (weak or higher order)

    at point j, the integral can be written as follows

    I~

    V{Ve

    h j, x dV 7

    where Ve is an infinitesimal spherical (circular)

    region of radius e around the singular point

    (Fig. 2). Using Greens theorem, the domain integral

    in equation (7) can be transformed to a boundary

    integral, as follows

    I~ C, Ce

    Hi j, x

    ni dC, i~1, 2, or 3 no sum on i 8

    where Ce represents the boundary of the domain Ve.

    The boundary integral in equation (8) over Cevanishes for weakly singular integrals. This integral

    also has a constant value for strongly singular

    integrands, and results in constant and divergent

    terms for higher-order singularities. Equation (8) can

    also be written as

    Fig. 1 A multiply connected domain Fig. 2 An infinitesimal domain excluded from themain domain

    BEM analysis of thermoelastic problems 607

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    I~

    C, Ce

    h j, x dxi

    !ni dC,

    i~1, 2, or 3 no sum on i 9

    which includes an outer boundary integral and aninner line integral, independent of the problem

    geometry.

    3 DIFFERENTIATING A SINGULAR DOMAININTEGRAL WITH RESPECT TO THE SOURCEPOINT COORDINATES

    In the BEM formulation of some problems it is

    required to find the derivative of a singular domain

    integral with respect to the source point coordinates.

    In this section, a general formula for differentiating2D and 3D singular domain integrals is described. In

    section 5, this formula will be used to derive the

    stress integral equation from the displacement

    integral equation of thermo-elasticity.

    Consider the following singular domain integral

    I~

    V{Ve

    y x f j, x dV 10

    where y is a regular and f is a singular function. It is

    assumed that f consists of constants or terms in the

    form of r or r,i where r is the Euclidian distancebetween the singular point j and the field point x.

    The domain Ve is an infinitesimal spherical (circular)

    region around the singular point. The integration

    domain includes the main boundary C and the

    infinitesimal boundaryCe. Assume that it is required

    to find the derivative of this singular integral with

    respect to the singular point coordinate ji. It should

    be noted that any change in the location of the

    source point results in a change in the integration

    domain (Fig. 3). The derivative of the domain

    integral in equation (10) with respect to, for example,

    j1, can be written as follows

    LI

    Lj1~ lim

    c?0

    1

    cI j1zc, j2, j3 {I j1, j2, j3

    & '11

    where c is an infinitesimal distance in the x1-direc-

    tion and

    I j1, j2, j3 ~V{Ve

    y x f j1, j2, j3, x dV 12

    I j1zc, j2, j3 ~V{Ve

    y x f j1zc, j2, j3 , x dV 13

    the Ve and Ve~Ve j1zc, j2, j3

    in equations (12) and

    (13) represent the infinitesimal region around thesource point before and after differential change of

    the location of the source point. By following the

    standard procedures for differentiating the singular

    integrals [8, 28], the following formula is obtained

    L

    Lji

    V{Ve

    y(x)f j, x dV~V{Ve

    y x Lf j, x Lji

    dV

    zy j Ce

    f j, x ni dC 14

    A point worth mentioning here is that the order ofthe singularity ofLf j, x =Lji is one more than that off j, x . This means that differentiating a singulardomain integral with respect to the source point

    location, produces a higher-order singular domain

    integral and a boundary integral which should be

    evaluated over an infinitesimal boundary around the

    source point. This boundary integral can be eval-

    uated analytically.

    4 THE TEMPERATURE AND DISPLACEMENT

    INTEGRAL EQUATIONS OF THERMO-ELASTICITY INVOLVING NON-UNIFORM HEATSOURCES

    The governing equations of steady state thermo-

    elasticity can be expressed as

    kH,ii x zs x ~0 15

    sij,j x zbi x ~0 16

    whereH

    is the temperature rise, k is the thermalconductivity, sis the heat source function, sij are theFig. 3 A differential change of source point location

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    components of the stress tensor, bi are the compo-

    nents of the body force vector, and x is a point in the

    domain.

    Strain components eij can be expressed in terms of

    the stress components as follows

    eij~1

    E1zn sij{ndijskk

    zaHdij 17

    where Eis Youngs modulus, n is Poisson ratio, and a

    is the coefficient of linear thermal expansion.

    The temperature integral equation corresponding

    to equation (15) can be written as follows [28, 29]

    C j H j ~C

    H j, x LH x

    Ln{H x LH

    j, x Ln

    !dC

    z 1k

    V{Ve

    H j, x s x dV 18

    where j (with coordinates ji) and x (with coordinates

    xi) are, respectively, the source point and the field

    point, and C is a coefficient related to the local

    geometry of the source point. Ve is an infinitesimal

    sphere (circle) with radius e around the source point,

    as shown in Fig. 2. Since the domain integral in

    equation (18) is weakly singular, V{Ve can be

    replaced with V. H is the fundamental solution ofthe Laplace problem and LH=Ln is its normal

    derivative. The fundamental solution can be writtenas follows [28, 29]

    H

    ~1

    2pln

    1

    r

    , for 2D problems 19

    H

    ~1

    4pr, for 3D problems 20

    By considering the relations ri~xi{ji, Lr=Ln~r,ini,

    and Lr=Lxi~r,i~ri=r, the normal derivative of the

    fundamental solution can be written as follows

    LH

    Ln~

    {1

    2prr,ini, for 2D problems 21

    LH

    Ln~

    {1

    4pr2r,ini, for 3D problems 22

    where ris the Euclidian distance between the source

    point and the field point. The method for the

    evaluation of the domain integral in equation (18)

    will be described in section 6.

    The displacement integral equation of thermo-

    elasticity with bi~0 can be written as follows [8]

    Cij j uj j ~C

    Uij j, x tj x {Tij j, x uj x h i

    dC

    zEa

    1{2n

    V{Ve

    H x Uik,k j, x dV 23

    where Cij represent the coefficient matrix of the free

    term, uj and tj are, respectively, components of

    displacement and traction, and Uij and Tij are the

    Kelvin fundamental solutions for displacement and

    traction, respectively, and can be expressed as

    Uij~1

    8pG 1{n

    3{4n dij ln 1

    rzr,ir,j

    !24

    Tij~{1

    4p 1{n rLr

    Ln1{2n dijz2r,ir,j

    &

    { 1{2n r,inj{r,jni 25

    for 2D plane strain problems and

    Uij~1

    16pG 1{n r 3{4n dijzr,ir,j 26

    Tij~{1

    8p 1{n r2Lr

    Ln1{2n dijz3r,ir,j

    &

    { 1{2n r,inj{r,jni 27

    for 3D problems. Gin these equations represents the

    shear modulus of the rigidity. It should be noted that

    a plane stress problem with material constants E, n,

    and a can be analysed as a plane strain problem, by

    replacing the material constants with E, n, and a as

    follows [30]

    E~1z2n

    1zn 2 E,n~

    n

    1zn, a~

    1zn

    1z2na 28

    The integrand of the domain integral in equation

    (23) is currently expressed in terms of temperature.

    Now this domain integral will be converted to a

    domain integral in terms of heat source function.

    The Uik,k term in the domain integral in equation(23) can be found using equations (24) and (26) as

    follows

    Uik,k~{ 1{2n

    4pG 1{n r,ir , for 2D problems 29

    BEM analysis of thermoelastic problems 609

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    Uik,k~{ 1{2n 8pG 1{n

    r,ir2

    , for 3D problems 30

    The last term in equation (23) will in future be

    denoted as IIi

    IIi~Ea

    1{2n

    V{Ve

    H x Uik,k j, x dV 31

    Substituting Uik,k, obtained from either equation(29) or equation (30), into equation (31) results, after

    some mathematical manipulations, in the following

    expression

    IIi~a 1zn

    8p

    1{n

    V{VeH x

    +

    2vi j, x

    dV

    32

    where vi is given as follows

    vi~{L

    Lxir2 ln r

    ~{ri 2 ln rz1 ,

    for 2D problems 33

    vi~L

    Lxir ~r,i, for 3D problems 34

    It should be noted that +2vi~{4r,i=r for 2D prob-lems, and +2vi~{2r,i

    r2 for 3D problems (see

    appendix 1).

    Now using Greens second identity in the form of

    V{Ve

    H+2vi dV~

    V{Ve

    vi+2HdV

    z

    C, Ce

    HLvi

    Ln{vi

    LH

    Ln

    dC 35

    and noting that +2H~{s x

    =k (equation (15)), then

    equation (32) can be rewritten as follows

    IIi~a 1zn

    8p 1{n {V{Ve

    vis x

    kdV

    z

    C

    HLvi

    Ln{vi

    LH

    Ln

    dC

    !36

    vi in equation (36) is a regular function; therefore,

    V{Ve can be replaced with V in the domain integral.

    For cases where the source point is located on the

    boundaryLvi=Ln~v

    i,kn

    kin equation (36) is a weakly

    singular function and can be expressed as follows

    Lvi

    Ln~{ 2 ln rz1 niz2r,i Lr

    Ln

    !,

    for 2D problems 37

    LviLn

    ~ 1r

    ni{r,i LrLn

    , for 3D problems 38

    It should be noted that the boundary integral over Cein equation (35) vanishes and thus does not appear

    in equation (36). Substituting the right-hand side of

    equation (36) into equation (23) leads to

    Cij j uj j ~C

    Uij j, x tj x {Tij j, x uj x h i

    dC

    za 1zn

    8p 1{n

    C

    HLvi

    Ln{vi

    LH

    Ln

    dC

    {a 1zn

    8p 1{n kV{Ve

    vis x dV 39

    The domain integral in equation (23) has a singu-

    larity of order r{1 and r{2 for 2D and 3D problems

    respectively; however, the domain integral in equa-

    tion (39) is regular. The method for the evaluation of

    the domain integral in equation (39) without domain

    discretization will be described in section 6.

    In order to find the displacements using equation

    (39), the temperature and its gradient at the

    boundary should be known. Therefore, the heatconduction problem should be solved using equa-

    tion (18) prior to the thermo-elastic analysis.

    5 STRESS INTEGRAL EQUATIONS OF THERMO-ELASTICITY INVOLVING NON-UNIFORM HEATSOURCE

    In order to derive the stress integral equations,

    derivatives of the displacement integral equation at

    internal points are found by the formula described in

    section 3 and these derivatives are subsequentlyused to find strains. Stresses are then found using

    the generalized Hookes law.

    The derivative of the displacement components

    with respect to the source point coordinates for an

    internal point j can be found using equation (23).

    Since for internal points Cijuj~ui, it is possible to

    write that

    L

    Ljjui j ~

    C

    LUik j, x Ljj

    tk x {LTik j, x

    Ljjuk x

    !dC

    z

    Ea

    1{2n L

    Ljj

    V{Ve

    H x Uik,k j, x dV 40

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    The last term in equation (40) contains the derivative

    of a singular domain integral. This term with the aid

    of equation (14), can be written as

    L

    LjjV{Ve

    H(x)Uik,k j, x dV

    ~

    V{Ve

    H x LUik,k j, x Ljj

    dV

    zH j Ce

    Uik,k j, x nj dC 41

    The last integral in equation (41), which is defined

    over Ce, can be evaluated analytically. For 2D pro-

    blems Uik,k is given by equation (29) and dC~rdh,r1~r cos h, and r2~r sin h in the polar coordinate

    system. Since nj~{r,j over Ce, it is possible to writethat

    H j Ce

    Uik,k j,x nj dC

    ~H j 1{2n 4pG 1{n

    2p0

    r,ir

    r,j rdh

    ~1{2n

    4G 1{n H j dij 42

    For 3D problems, Uik,k is given by equation (30) and

    the following relationships apply in the spherical co-ordinate system:dC~r2 sinwdwdh, r1~r sinw cos h,

    r2~r sinw sin h, and r3~r cosw. Therefore, it can be

    written that

    H j Ce

    Uik,k j, x nj dC

    ~H j 1{2n 8pG 1{n

    2p0

    p0

    r,ir2

    r,j r2 sinwdwdh

    ~1{2n

    6G 1{n

    H j dij 43

    A useful formula for the derivation of equations (42)

    and (43) is

    Ce

    r,ir,j dC~1

    3p cz2 ecdij 44

    where c~1 for 2D problems and c~2 for 3D

    problems.

    Substituting equations (42) and (43) into equation

    (41), and the resulting relation into equation (40),

    and noting that LUikLjj~{U

    ik,j

    , LTikLjj~{T

    ik,j

    ,

    and LUik,k.Ljj~{Uik,kj , leads to

    L

    Ljjui j ~

    C

    {Uik,jtk x zTik,juk x h i

    dC

    {Ea

    1{2n V{Ve

    H x Uik,kj j, x dV

    za 1zn b 1{n H j dij 45

    where b~2 for 2D problems and b~3 for 3D prob-

    lems.

    The integrand of the domain integral in equation

    (45) is expressed in terms of temperature. A

    procedure will now be presented that converts this

    domain integral into an integral in terms of the heat

    source function. The Uik,kj term in the domainintegral in equation (45) can be found using

    equations (29) and (30). This can be expressed asfollows (see appendix 2)

    Uik,kj~{ 1{2n

    16pG 1{n +2 r2 ln r

    ,ij

    h i,

    for 2D problems 46

    Uik,kj~1{2n

    16pG 1{n +2 r,ij

    , for 3D problems 47

    Denoting the second term on the right-hand side ofequation (45) by IIIij

    IIIij ~Ea

    1{2n V{Ve

    H x Uik,kj j, x dV 48

    and using Greens second identity over the region

    V{Ve (with boundaries C and Ce) and noting that

    +2H~{s x =k, leads to

    IIIij ~a 1zn

    8p 1{n

    | {

    V{Ve

    lijs x

    kdVz

    C

    HLlij

    Ln{lij

    LH

    Ln

    dC

    z

    Ce

    HLlij

    Ln{lij

    LH

    Ln

    dC

    !49

    where

    lij~{ r2 ln r

    ,ij

    ~{ 2 ln rz1 dijz2r,ir,j 50

    Llij

    Ln ~2

    r 2r,ir,j{dij Lr

    Ln { r,injzr,jni ! 51

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    for 2D problems, and

    lij~r,ij~1

    rdij{r,ir,j 52

    Llij

    Ln~

    1

    r23r,ir,j{dij Lr

    Ln{ r,injzr,jni

    ! 53

    for 3D problems.

    The boundary integral over Ce in equation (49) can

    be evaluated analytically. It can show thatCelij LH=Ln dC~0 and the other integral

    IIIij ~CeH Llij

    Ln

    dC can be evaluated analytically

    as follows. Since L=Ln~{L=Lr over Ce and r,ir,j isindependent of r, it is possible to write that

    LlijLn

    ~ 2rdij, on Ce for 2D problems 54

    Llij

    Ln~

    dij{r,ir,j

    r2, on Ce for 3D problems 55

    Using polar coordinates for 2D problems and

    spherical coordinates for 3D problems, the final

    form of IIIij is obtained as follows

    IIIij ~4pH j dij, for 2D problems 56

    IIIij ~8

    3pH j dij, for 3D problems 57

    Substituting the obtained expressions for IIIij into

    equation (49) and the resulting relation into equa-

    tion (45) then, after some mathematical manipula-

    tions, the following expression can be obtained for

    the derivatives of the displacement components

    LuiLj

    j

    ~ C {Uik,jtkzT

    ik,juk dC

    {k

    C

    HLlij

    Ln{lij

    LH

    Ln

    dC

    zk

    V{Ve

    lijs x

    kdV 58

    where

    k~a 1zn

    8p 1{n 59

    The thermo-elastic stressstrain relation can befound using equation (17) which can be expressed

    as follows

    sij~2G

    1{2n1{2n eijznekkdij{ 1zn aHdij

    60

    Equation (60) is valid for 3D problems as well asplane strain problems. The strain for an internal

    point j can be expressed as follows

    eij j ~ 12

    LuiLjj

    zLuj

    Lji

    61

    Substituting equation (61) into equation (60) results

    in

    sij j ~ 2Gn1{2n

    LukLjk

    dijzGLuiLjj

    zLuj

    Lji

    {Ea

    1{2n H j dij 62

    Substituting equation (58) into equation (62) then,

    after some mathematical manipulations, the follow-

    ing stress integral equation in terms of heat source

    function is obtained

    sij j ~C

    Uijktk{Tijkuk

    dCz

    C

    lijLH

    Ln{lijH

    dC

    z1

    kV{Ve

    lijs x

    dV{Ea

    1{2n H j

    dij

    63

    where Uijk and T

    ijk are the commonly used singular

    functions in elastostatic analysis [8, 29] and

    lij~Ea

    4p 1{n ln1

    r{

    1z2n

    2

    dij

    1{2n {r,ir,j !

    64

    lij ~Ea

    4p 1{n r 2r,ir,j{dij

    1{2n

    Lr

    Ln

    { r,injzr,jni 65for 2D problems, andlij~

    Ea

    8p 1{n rdij

    1{2n{r,ir,j

    66

    lij ~Ea

    8p 1{n r2 3r,ir,j{dij

    1{2n

    Lr

    Ln

    { r,injzr,jni

    67

    for 3D problems.

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    The domain integral in the stress integral equation

    (63) is weakly singular but the domain integral in

    equation (45) is strongly singular. The method for

    the evaluation of the domain integral in equation

    (63) with boundary-only discretization is described

    in the next section.

    It can be seen from equation (63) that in order to

    find the stresses, the temperature and its gradient at

    the boundary should be known. Therefore, the heat

    conduction problem should be solved before the

    evaluation of the stresses.

    6 THE EVALUATION OF THE DOMAININTEGRALS WITHOUT INTERNALDISCRETIZATION USING THE CTM

    In this section, the methods for the evaluation of the

    domain integrals appearing in the developed integral

    equations are described. First, it is shown that

    domain integrals corresponding to a wide variety of

    non-uniform heat sources can be exactly trans-

    formed into boundary integrals using the CTM.

    Then, it is shown that for cases with very compli-

    cated non-uniform heat sources the domain inte-

    grals can also be evaluated using the CTM without

    internal discretization.

    Three domain integrals appeared in the formula-

    tions presented in the previous sections. The firstone is the domain integral in the temperature

    integral equation (equation (18))

    I1~

    V{Ve

    Hs x dV 68

    The second one is the domain integral in the

    displacement integral equation (equation (39))

    I2~

    V{Ve

    vis x dV 69

    The third one is the domain integral in the stress

    integral equation (equation (63))

    I3~

    V{Ve

    lijs x dV 70

    The kernels H, vi, and lij for 2D and 3D problemsare given in equations (19), (20), (33), (34), (64), and

    (66). Since I1 and I3 are weakly singular and I2 is a

    regular integral, V{Ve can be replaced with V in the

    corresponding equations; however, these integrals

    are expressed and used in the original form to showthe correctness of the proceeding operations.

    6.1 Exact transformation of the domain integralsinto boundary integrals for a wide variety ofnon-uniform heat sources

    In this section, it is shown that for cases where the

    heat source function s x , has a quadratic variationin one Cartesian direction and arbitrary variations in

    other directions, all domain integrals can be exactly

    transformed into boundary integrals. With no loss of

    generality, only 3D cases are considered in this work.

    Suppose that the heat source function has a

    quadratic variation in the x1-direction and arbitrary

    variations in the x2 and x3 directions, as follows

    s x ~f0 x2,x3 zf1 x2,x3 x11zf2 x2,x3 x21 71

    where f0, f1, and f2 are arbitrary functions. Substitut-

    ing this expression in equation (68) and using theCTM, equation (9) with i~1, results in

    I1~

    C,Ce

    f0H

    zf1x

    11H

    zf2x

    21H

    dx1 !

    n1 dC

    72

    In this equation H is weakly singular; therefore, theboundary integral over Ce vanishes. Since the

    functions f0, f1, and f2 are independent of x1, it is

    possible to write that

    I1~C

    f0H dx1zf1

    x11H dx1zf2

    x21H dx1

    n1 dC

    73or

    I1~

    C

    f0F0zf1F1zf2F2 n1 dC 74

    where

    Fc~

    xc1H

    dx1, c~0, 1, 2

    F0, F1, and F2 can simply be evaluated analytically

    (see Appendix 3). The boundary integral in equation(74) can be found numerically with little difficulty.

    Similarly, it can be shown that the 1D integralsxx1vi dx1 and

    xx1l

    ij dx1 can also be evaluated

    analytically (see appendix 3) and therefore, the

    domain integrals in equations (69) and (70) can be

    exactly transformed into boundary integrals.

    A heat source function with a quadratic variation

    in the x2-direction and arbitrary variations in the x1and x3 directions or another function with a

    quadratic variation in the x3-direction and arbitrary

    variations in the x1 and x2 directions can also betreated with the same procedure. This means that all

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    domain integrals corresponding to a heat source

    function with the following form, can be exactly

    transformed into boundary integrals

    s x

    ~f0 x2,x3

    zf1 x2,x3

    x11 zf2 x2,x3

    x21

    zg0 x1,x3 zg1 x1,x3 x12 zg2 x1,x3 x22zh0 x1,x2 zh1 x1,x2 x13 zh2 x1,x2 x23 75

    Similarly, for 2D problems with a heat source

    function with the following form, the same proce-

    dure can be applied

    s x ~f0 x2 zf1 x2 x11zf2 x2 x21 zg0 x1 zg1 x1 x12zg2 x1 x22 76

    Most heat source functions can be expressed interms of equations (75) and (76). For very compli-

    cated non-uniform heat sources the domain inte-

    grals must be evaluated by another version of the

    CTM, which is described in the next section.

    6.2 The evaluation of the domain integrals without internal cells for non-uniform heatsources with very complicated forms

    Suppose that the heat source function is too

    complicated to be expressed or approximated in

    the form of equations (75) and (76). In such cases theCTM is again employed, but the inner line integral,

    in equation (9), is evaluated numerically. To evaluate

    the domain integral (68), it is regularized as follows

    I1~

    V{Ve

    H j, x s x dV

    ~s j V{Ve

    H j, x dV

    z

    V{Ve

    H j, x s x {s j dV 77

    Using the CTM, it is possible to rewrite equation (77)

    in the following form

    I1~s j C

    H

    dx1

    n1 dC

    z

    C

    x1a

    H s x {s j dx1

    & 'n1 dC 78

    The inner line integral in the first integral in

    equation (78) can be evaluated analytically using

    the procedure described in the previous section. The

    line integral in the second integral in equation (78) isindependent of domain geometry and can be

    evaluated numerically. It should be noted that the

    boundary integrals over Ce in equation (78) are equal

    to zero and have been removed. The constant a, the

    lower bound of the inner 1D integral in equation

    (78), is arbitrary. It is suggested to set

    a~x1 minzx1 max

    279

    where x1 min and x1 max are, respectively, the mini-

    mum and maximum values of x1 over the boundary

    of the problem.

    The domain integral in equation (69) is regular

    and can be evaluated by the same method (CTM)

    with no need for any regularization. It can be

    expressed as follows

    I2~V{Ve vis

    x dV

    ~

    C

    x1a

    vis x dx1 !

    n1 dC 80

    The domain integral in equation (70) is weakly

    singular and can be expressed as follows

    I3~

    V{Ve

    lijs x dV

    ~s j C

    lij dx1

    n1 dC

    z

    C

    x1

    a

    lij s(x){s j dx1& '

    n1 dC 81

    The inner line integrals in equations (78), (80), and

    (81) are written with respect to the x1-direction.

    Alternatively, these equations can be written with

    respect to either the x2 or x3 directions. The

    boundary integrals in equations (78), (80), and (81)

    are evaluated using the Gaussian quadrature

    method, while the inner line integrals are evaluated

    using the composite Gaussian quadrature method

    with an arbitrary number of integration intervals and

    integration points.

    When the heat source function is defined at

    discrete data points, the domain integrals can be

    evaluated by the same method without internal cells.

    In such cases an appropriate mesh-free interpolation

    method must be employed for evaluation of the heat

    source function at integration points. In this man-

    ner, the radial point interpolation method [31],

    moving least-squares method [32], or one of several

    other methods [3336] can be used. An important

    advantage of the present method is that there is no

    need for the existence of any particular solutions forthe interpolating functions.

    614 M Mohammadi, M R Hematiyan, and M H Aliabadi

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    7 EXAMPLES

    Three examples including different forms of heat

    sources are analysed to demonstrate the validity and

    efficiency of the present methods. In all examples,

    regular integrals over the boundary elements are

    evaluated using the four-point Gaussian quadrature

    method and singular integrals over the boundary

    elements are evaluated analytically.

    7.1 Example 1: a 2D domain subjected todifferent forms of heat sources

    In this example, a rectangular domain with the

    structural and thermal boundary conditions shown

    in Fig. 4 is considered. The problem is analysed

    under a plane strain condition with E~200GPa,n~0:3, a~11:7|10{6 uC21, k~60 W=m uC. The sides

    of the rectangle are a~0:15m and b~0:3 m.

    In the first case, the heat source function is con-

    sidered to be as follows

    s~kH02p

    b

    2sin

    2py

    b

    82

    where H0~50 uC. It can be shown that the exact

    temperature distribution for this problem can be

    expressed as follows

    H~H0 sin2py

    b

    Displacement, stress, and strain fields can also be

    found analytically as follows

    ux~0, uy~1zn

    1{n

    aH0b

    2p1{ cos

    2py

    b

    !

    exx~0, eyy~1zn

    1{n aH0 sin2py

    b

    , exy~0

    sxx~{E

    1{naH0 sin

    2py

    b

    , syy~0, sxy~0

    The results obtained by the proposed BEM are

    compared with those obtained using the finite

    element method (FEM) and also exact solutions.

    The FEM analysis of the problem was carried out

    with a developed code. For the FEM analysis, four-

    node quadrilateral elements were used. In eachelement the heat source function was interpolated

    by the FEM shape functions. For the BEM analysis of

    the problem, linear boundary elements were used

    for the discretization of the boundary. The domain

    integrals corresponding to the heat source function

    were exactly transformed into boundary integrals.

    Two different meshes, mesh I and mesh II, as

    shown in Figs 5 and 6, were considered in the

    analyses. The results obtained for the temperature,

    vertical displacement, and horizontal stress along

    Fig. 4 A 2D thermo-elastic problem

    Fig. 5 Mesh I for the FEM and BEM discretization ofthe domain in example 1: (a) FEM mesh and (b)BEM mesh

    Fig. 6 Mesh II for the FEM and BEM discretization of

    the domain in example 1: (a) FEM mesh and (b)BEM mesh

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    the line AB, shown in Fig. 4, with mesh I are shown

    in Fig. 7. The results obtained with mesh II are

    shown in Fig. 8. It can be observed that the results

    obtained by mesh II (finer mesh) are better than

    those obtained by mesh I. Also, it can be seen that

    the results obtained by the BEM are better than

    those obtained by the FEM with the same order of

    discretization.

    In the second case, a more complicated heatsource function with the following form was con-

    Fig. 7 Results obtained by the FEM and BEM for theheat source function given by equation (82)using mesh I, in comparison with the exact

    solution, example 1: (a) temperature, (b) dis-placement, and (c) stress

    Fig. 8 Results obtained by the FEM and BEM for theheat source function given by equation (82)using mesh II, in comparison with the exactsolution, example 1: (a) temperature, (b) dis-placement, and (c) stress

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    sidered

    s~4|105 1z3xz10x2

    sin 2py

    b

    2 !83

    In this case, no exact solution exists and the results

    obtained by the proposed BEM are compared with

    the accurate FEM solutions. The FEM solutions were

    obtained using a fine mesh with 4608 four-node

    quadrilateral elements. Since the heat source func-

    tion has a quadratic variation in the x-direction, the

    corresponding domain integrals are transformed

    exactly into boundary integrals in the BEM analysis.

    The results obtained for the temperature, vertical

    displacement, and horizontal stress along the line AB

    are shown in Fig. 9. It can be seen that the BEM

    results with the coarse mesh (only 12 linearelements) are in good agreement with the accurate

    FEM solutions.

    In the third case, a very complicated heat source

    function with the following form was considered

    s~8|105 cosp

    2

    x

    a

    h isin 2p

    y

    b

    2 !84

    Since it does not have a quadratic variation in either

    the x or y directions, it must be treated with the

    method described in section 6.2. The resultsobtained for this case in comparison with the

    accurate FEM solutions (4608 elements) are shown

    in Fig. 10. It can be seen that the BEM results with

    only 24 linear elements are in excellent agreement

    with the accurate FEM solutions.

    In the fourth case, it was assumed that the heat

    source was distributed over a portion of the main

    domain. As shown in Fig. 11, a heat source with

    uniform intensity of 2 MW

    m3 was considered

    over a circular region with radius of 0.04m and

    centred at (0.085, 0.065). The problem boundary

    was discretized using 24 linear elements and the

    boundary of the circular region was discretized

    using 16 linear elements. It should be noted that

    the nodes and elements on the circle are only used

    for the evaluation of the domain integrals and they

    do not introduce any additional unknowns into the

    problem. This point is an important advantage of

    the BEM in comparison with the FEM. For the

    FEM modelling of the problem, the circular region

    and the other portion of the domain must be

    discretized with a compatible mesh and a large

    number of elements and nodes must be employed.The results obtained for this case in comparison

    with the accurate FEM solutions (4929 elements)

    are shown in Fig. 12. It can be observed that the

    BEM results are again in a very good agreement

    with the accurate FEM solutions.

    Fig. 9 Results obtained by the BEM (12 elements) forthe heat source function given by equation (83),in comparison with the accurate FEM solution(4608 elements), example 1: (a) temperature,(b) displacement, and (c) stress

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    7.2 Example 2: a 2D multiply connected domainsubjected to a non-uniform heat source

    In this example, a 2D multiply connected domain

    with the structural and thermal boundary conditions

    shown in Fig. 13 is considered. It was analysed under

    a plane stress condition with E~200GPa, n~0:3,

    a~11:7|10{6 uC21, k~60 W=m uC. The considered

    heat source function had the following form

    s~106 xz3y 85

    For the BEM analysis of the problem, the outerboundary (rectangle) was discretized using 80 linear

    boundary elements and the inner boundary (circle)

    was discretized using 36 linear boundary elements.

    Since this problem has no exact solution, the results

    obtained by the proposed BEM are compared with

    the accurate FEM solutions. The FEM solutions were

    obtained using a fine mesh with 13 512 four-node

    quadrilateral elements. All domain integrals were

    transformed exactly into boundary integrals in the

    BEM analysis. The results obtained for the tempera-

    ture, horizontal displacement, and vertical stress

    along the line y~0:05 are shown in Fig. 14. It can beseen that the BEM results are in a very good

    agreement with the accurate FEM solutions.

    7.3 Example 3: a 3D domain subjected todifferent forms of heat sources

    In this example, a cube with edge length of

    a~10 mm, as shown in Fig. 15, is considered. The

    used material properties were E~210 GPa, n~0:3,

    a~11|10{6 uC21 . The temperature at the surface

    y~

    0 was taken to be zero and the other surfaces ofthe boundary were insulated. The surface y~0 was

    Fig. 11 The BEM discretization of the domain inexample 1 for a heat source distributed overthe circular region with radius of 0.04 m andcentred at (0.085, 0.065)

    Fig. 10 Results obtained by the BEM (24 elements) forthe heat source function given by equation(84), in comparison with the accurate FEMsolution (4608 elements), example 1: (a)temperature, (b) displacement, and (c) stress

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    assumed to be traction free and the displacement of

    the other surfaces in the normal direction was taken

    to be zero.

    In the first case, the heat source function wasconsidered to be

    s~s0 exp {my 86

    with s0=k~1 and m~0:2. The boundary of the

    problem was discretized using 600 constant bound-

    ary elements as shown in Fig. 15. A similar problem

    was analysed by Ochiai [13] with the same number

    of boundary elements and 64 internal points. There

    is no need to consider any internal points to analyse

    the problem by the proposed method.

    The exact solution of this problem for the

    temperature, displacement in the y direction, and

    stresses in x and z directions are, respectively

    H~s0

    km21{ exp {my { s0 exp {ma

    kmy

    uy~s0a 1zn km2 1{n y{az

    m exp {ma 2

    a2{y2 &

    z1

    mexp {my { exp {ma

    '

    sxx~szz~{s0aE

    km2 1{n 1{exp {my {m exp {ma y

    For the BEM analysis of the problem, all domain

    integrals were exactly transformed into boundaryintegrals. The results obtained for H, uy, and szz

    Fig. 12 Results obtained by the BEM (24 elements) forthe heat source over a portion of the domain(Fig. 11), in comparison with the accurateFEM solution (4929 elements), example 1: (a)temperature, (b) displacement, and (c) stress

    Fig. 13 A 2D thermo-elastic problem with multiply-connected domain

    BEM analysis of thermoelastic problems 619

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    along the line x~z~a=2 are shown in Fig. 16. It can

    be seen that the BEM results are in very good

    agreement with the exact solutions.

    In the second case, a more complicated heat source

    function with the following form was considered

    s~s0 1z0:1xz0:2x2

    exp {myz 87

    where s0=k~1 and m~0:2. In this case, no exact

    solution exists and the results obtained by the

    proposed BEM are compared with the accurate FEM

    solutions. The FEM solutions were obtained using a

    fine mesh with 64 000 eight-node elements. Since the

    heat source function has a quadratic variation in thex

    direction, the corresponding domain integrals are

    transformed exactly into boundary integrals in the

    BEM analysis. The obtained results for H, uy, and szzalong the line x~z~a=2 are shown in Fig. 17.

    In the third case, the following heat source func-

    tion was considered

    s~s0 exp {mffiffiffiffiffiffiffiffi

    xyzp 88

    where s0=k~1 and m~0:2. Since this function cannot

    be expressed with a quadratic variation in anydirection, it must be treated with the method

    described in section 6.2. The results obtained for

    this case in comparison with the accurate FEM

    solutions (64 000 elements) are shown in Fig. 18. It

    can be observed that the BEM results are very good.

    8 CONCLUSIONS

    A BEM formulation for the analysis of steady state

    thermo-elastic problems involving arbitrary non-

    uniform heat sources was presented. Both 2D and

    Fig. 14 Results obtained by the BEM (116 elements) incomparison with the accurate FEM solution(13 512 elements), example 2: (a) temperature,(b) displacement, and (c) stress

    Fig. 15 A 3D domain with heat source, discretized byboundary elements

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    3D thermo-elastic problems with various kinds of

    heat sources can be analysed by the proposed BEM

    with boundary-only discretization and there is no

    need to define any internal points. It was seen that

    the results obtained by the proposed BEM are

    accurate and better than those obtained by the

    FEM with the same order of discretization. It can

    also be claimed that the present formulation is very

    efficient from a modelling viewpoint.

    Fig. 16 Results obtained by the BEM for the heatsource function given by equation (86), incomparison with the exact solution, example3: (a) temperature, (b) displacement, and (c)stress

    Fig. 17 Results obtained by the BEM for the heatsource function given by equation (87), incomparison with the accurate FEM solution,example 3: (a) temperature, (b) displacement,and (c) stress

    BEM analysis of thermoelastic problems 621

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    ACKNOWLEDGEMENT

    The second author would like to acknowledge thefinancial support from the Vice Chancellor of

    Research at Shiraz University under grant 88-GR-ENG-54.

    F Authors 2010

    REFERENCES

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    12 Shiah, Y. C. and Huang, J. H. Boundary elementmethod interior stress/strain analysis for two-dimensional static thermoelastic involving nonuni-form volume heat sources. J. Thermal Stresses,2005, 23, 363390.

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    Fig. 18 Results obtained by the BEM for the heatsource function given by equation (88), incomparison with the accurate FEM solution,example 3: (a) temperature, (b) displacement,and (c) stress

    622 M Mohammadi, M R Hematiyan, and M H Aliabadi

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    26 Hematiyan, M. R., Mohammadi, M., Fazeli, R.,and Khosravifard, A. Cartesian transformationmethod for evaluation of regular and singular

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    22, 113118.

    APPENDIX 1

    In this appendix, the Laplacian ofvi is evaluated.

    2D problems

    vi~{L

    Lxir2 ln r

    ~{ri 2 ln rz1 89

    vi,k~{dik 2 ln rz1 {ri 2r,kr

    90

    +2vi~vi,kk~{dik

    2r,kr

    {dik

    2r,kr

    {2rir,kkr{r,kr,k

    r2

    91

    Noting that r,kr,k~1 and r,kk~1=r, the following

    result is obtained

    +2vi~{4r,i=r 92

    3D problems

    vi~L

    Lxir ~r,i 93

    +2vi~+2r,i~ +2r

    ,i 94

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    Noting that +2r~2=r, the following result is obtained

    +2vi~

    {2r,ir2

    95

    APPENDIX 2

    In this appendix, the expression for Uik,kj is found.

    2D problems

    Uik,k~{ 1{2n 4pG 1{n

    r,ir

    96

    Using equation (92) the following equation isobtained

    Uik,k~1{2n

    16pG 1{n +2vi 97

    Substitutingvi~{ r2 ln r

    ,i

    from equation (89) into

    equation (97) leads to

    Uik,k~{ 1{2n

    16pG 1{n +2 r2 ln r

    ,i

    h i98

    and therefore

    Uik,kj~{ 1{2n

    16pG 1{n +2 r2 ln r

    ,ij

    h i99

    3D problems

    Uik,k~{ 1{2n 8pG 1{n

    r,ir2

    100

    Using equation (95), the following equation isobtained

    Uik,k~1{2n

    16pG 1{n +2vi 101

    Substitutingvi~r,i from equation (93) into equation

    (101) the following result is obtained

    Uik,k~1{2n

    16pG 1{n +2 r,i 102

    and therefore

    Uik,kj~1{2n

    16pG 1{n +2 r,ij 103

    APPENDIX 3

    For the exact transformation of the domain integrals

    into boundary integrals by the CTM, the integralsxc1H

    dx1,

    xc1vi dx1, and

    xc1lij dx1 (c~0, 1, 2) must

    be evaluated analytically. All possible integrals in 2D

    and 3D thermo-elastic problems are given as follows.

    2D problem

    I1~

    ln

    1

    r

    dx1~{r1 ln r{r2 tan{1 r1

    r2

    zr1

    I2~

    x1 ln

    1

    r

    dx1~{

    1

    2r2z2j1r1

    ln r

    {j1r2 tan{1 r1

    r2

    z

    1

    4r2zj1r1

    I3~

    x21 ln

    1

    r

    dx1~{

    1

    3r31 zj1r

    2zj21r1

    ln r

    z1

    3r3

    2{j2

    1r2 tan{1 r1

    r2

    {1

    3r1r

    22 z

    1

    9r31 z

    1

    2j1r

    2zj21r1

    I4~

    r1 ln

    1

    r

    dx1~{

    1

    2r2 ln rz

    1

    4r2

    I5~

    x1r1 ln

    1

    r

    dx1~{

    1

    3r31 z

    1

    2j1r

    2

    ln r

    z1

    3

    r32 tan{1 r1

    r2 z

    1

    9

    r31

    {1

    3r1r

    22 z

    1

    4j1r

    2

    I6~

    x21r1 ln

    1

    r

    dx1

    ~{1

    4r41 {r

    42 z

    8

    3j1r

    31 z2j

    21r

    2

    ln r

    z2

    3j1r

    32 tan

    {1 r1r2

    z

    1

    16r41

    { 18

    r21 r22 z 29j1r31 { 23

    j1r1r22 z 14j21r2

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    I7~

    r2 ln

    1

    r

    dx1~r2I1

    I8~

    x1r2 ln1r

    dx1~r2I2

    I9~

    x21r2 ln

    1

    r

    dx1~r2I3

    I10~

    r1 dx1~

    1

    2r21

    I11~

    x1r1 dx1~ 13

    r31 z 12j1r21

    I12~

    x21r1 dx1~

    1

    4r41 z

    2

    3j1r

    31 z

    1

    2j21r

    21

    I13~

    r2 dx1~x1r2

    I14~

    x1r2 dx1~1

    2x2

    1r2

    I15~

    x21r2 dx1~

    1

    3x31r2

    I16~

    r,1r,2 dx1~

    r1r2r2

    dx1~r2 ln r

    I17~ x1r,1r,2 dx1~ x1r1r2

    r2

    dx1

    ~r2 j1 ln r{r2 tan{1 r1

    r2

    zr1

    !

    I18~

    x21r,1r,2 dx1~

    x21

    r1r2r2

    dx1

    ~r2 j21{r

    22

    ln r{2j1r2 tan

    {1 r1r2

    z

    1

    2r21z2j1r1

    !

    I19~

    r,1r,1 dx1~r21

    r2 dx1~{r2 tan{1 r1

    r2

    zr1

    I20~

    x1r,1r,1 dx1~

    x1

    r21r2

    dx1

    ~{r22 ln r{j1r2 tan{1 r1

    r2 z

    1

    2

    r21 zj1r1

    I21~

    x21r,1r,1 dx1~

    x21

    r21r2

    dx1

    ~{2j1r22 ln r{ j

    21r2{r

    32

    tan{1

    r1r2

    z1

    3r31 zj1r

    21 zj

    21r1{r1r

    22

    I22~

    r,2r,2 dx1~

    r2

    2r2

    dx1~r2 tan{1 r1r2

    I23~

    x1r,2r,2 dx1~

    x1

    r22r2

    dx1

    ~r22 ln rzj1r2 tan{1 r1

    r2

    I24~ x21r,2r,2 dx1~ x21r22

    r2dx1

    ~2j1r22 ln rz j

    21r2{r

    32

    tan{1

    r1r2

    zr1r

    22

    3D problem

    V1~

    1

    rdx1~ ln r1zr

    V2~

    x1

    1

    rdx1~j1 ln r1zr zr

    V3~

    x21

    1

    rdx1~

    1

    22j21{r

    2zr21

    ln r1zr

    zr1

    2r1z2j1

    V4~

    r,1 dx1~r1

    r dx1~r

    BEM analysis of thermoelastic problems 625

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    V5~

    x1r,1 dx1~

    x1

    r1r

    dx1

    ~{1

    2

    r2{r21 ln r1zr z

    1

    2

    r r1z2j1

    V6~

    x21r,1 dx1~

    x21

    r1r

    dx1

    ~{j1 r2

    {r21

    ln r1zr

    z1

    3r 3r21 {2r

    2z3j1r1z3j

    21

    V7~ r,2 dx1~ r2r

    dx1~r2V1

    V8~

    x1r,2 dx1~

    x1

    r2r

    dx1~r2V2

    V9~

    x21r,2 dx1~

    x21

    r2

    rdx1~r2V3

    V10~

    r,3 dx1~

    r3r

    dx1~r3V1

    V11~

    x1r,3 dx1~

    x1

    r3r

    dx1~r3V2

    V12~

    x21r,3 dx1~

    x21

    r3r

    dx1~r3V3

    V13~

    r,1r,1

    rdx1~

    r21r3

    dx1~ ln r1zr {r,1

    V14~

    x1

    r,1r,1r

    dx1~

    x1

    r21r3

    dx1

    ~j1 ln r1zr z2r{r1r,1{j1r,1

    V15~

    x21

    r,1r,1r

    dx1~

    x21

    r21r3

    dx1

    ~1

    23r21 {3r

    2z2j21

    ln r1zr

    z

    1

    2 r,1 3r2{2r21 {2j21

    z2j1 2r{r1r,1

    V16~

    r,1r2

    dx1~

    r1r3

    dx1~{1

    r

    V17~

    x1

    r,1r2

    dx1~

    x1

    r1r3

    dx1~ ln r1zr {x1r

    V18~

    x21

    r,1r2

    dx1~

    x21

    r1r3

    dx1

    ~2j1 ln r1zr z2r{x21

    r

    V19

    ~ r,1r,2r

    dx1

    ~ r1r2r3

    dx1

    ~r2

    V16

    V20~

    x1

    r,1r,2r

    dx1~

    x1

    r1r2r3

    dx1~r2V17

    V21~

    x21

    r,1r,2

    rdx1~

    x21

    r1r2

    r3dx1~r2V18

    V22~r,1r,3

    r dx1~

    r1r3r3 dx

    1~r3V16

    V23~

    x1

    r,1r,3

    rdx1~

    x1

    r1r3

    r3dx1~r3V17

    V24~

    x21

    r,1r,3r

    dx1~

    x21

    r1r3r3

    dx1~r3V18

    V25~ 1r3

    dx1~r,1

    r2{r21

    V26~

    x1

    1

    r3dx1~

    j1r,1

    r2{r21{

    1

    r

    V27~

    x21

    1

    r3dx1~ ln r1zr {r,1z j

    21r,1

    r2{r21{2

    j1

    r

    V28~ r,2r,2

    r dx1~ r

    22

    r3 dx1~

    r

    2

    2 V25

    626 M Mohammadi, M R Hematiyan, and M H Aliabadi

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    V29~

    x1

    r,2r,2r

    dx1~

    x1

    r22r3

    dx1~r22 V26

    V30~

    x21r,2r,2

    rdx1~

    x21

    r22r3

    dx1~r22 V27

    V31~

    r,3r,3

    rdx1~

    r23r3

    dx1~r23 V25

    V32~

    x1

    r,3r,3r

    dx1~

    x1

    r23r3

    dx1~r23 V26

    V33~

    x21

    r,3r,3r

    dx1~

    x21

    r23r3

    dx1~r23 V27

    V34~

    r,2r,3r

    dx1~

    r2r3r3

    dx1~r2r3V25

    V35~

    x1

    r,2r,3

    rdx1~

    x1

    r2r3

    r3dx1~r2r3V26

    V36~

    x21

    r,2r,3r

    dx1~

    x21

    r2r3r3

    dx1~r2r3V27

    BEM analysis of thermoelastic problems 627

    JSA620 J. Strain Analysis Vol. 45