[email protected] mth55_lec-29_fa08_sec_6-1_rational_fcn_mult-n-div.ppt 1 bruce mayer, pe...
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[email protected] • MTH55_Lec-29_Fa08_sec_6-1_Rational_Fcn_Mult-n-Div.ppt1
Bruce Mayer, PE Chabot College Mathematics
Bruce Mayer, PELicensed Electrical & Mechanical Engineer
Chabot Mathematics
§6.1 Rational Fcn§6.1 Rational FcnMult & DivMult & Div
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Bruce Mayer, PE Chabot College Mathematics
Review §Review §
Any QUESTIONS About• §5.7 → PolyNomial Equation
Applications
Any QUESTIONS About HomeWork• §5.7 → HW-17
5.7 MTH 55
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Bruce Mayer, PE Chabot College Mathematics
Recall Rational FunctionRecall Rational Function
A rational function is a function, f(x), that is a quotient of two polynomials; i.e.
Where• where p(x) and q(x) are polynomials and
where q(x) is NOT the ZERO polynomial.
• The domain of f consists of all inputs x for which q(x) ≠ 0.
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Bruce Mayer, PE Chabot College Mathematics
Rational FUNCTION ExampleRational FUNCTION Example
RATIONAL FUNCTION ≡ a function expressed in terms of rational expressions
Example Find f(3) for this Rational Function:
SOLUTION
2
2
3 7( ) ,
4
x xf x
x
2
2
3 7( )
4
x xf x
x
2
2
3 33( ) 7(3
3)
( ) 4f
9 9 7
9 5
11
4
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Bruce Mayer, PE Chabot College Mathematics
Find the Domain of a Rational FcnFind the Domain of a Rational Fcn
1. Write an equation that sets the denominator of the rational function equal to 0.
2. Solve the denominator equation.
3. Exclude the value(s) found in step 2 from the function’s domain.
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Bruce Mayer, PE Chabot College Mathematics
Example Example Find Domain Find Domain
Find the Domain for 3 2
6( ) .
5 4f y
y y y
SOLUTION
3 25 4 0y y y
2 5 4 0y y y
4 1 0y y y 0 or 4 0 or 1 0y y y
4 1y y
Set the denominator equal to 0.
Factor out the monomial GCF, y.
Use the zero products theorem.
The fcn is undefined for y = 0, −4, or −1, so the domain is {y|y −4, −1, 0}.
FOIL Factor the 2nd Degree polynomial
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Bruce Mayer, PE Chabot College Mathematics
Example Example Find Domain Find Domain
Find the Domain for SOLUTION
• Find the values of x for which the denominator x2 – 6x + 8 = 0, then exclude those values from the domain.
The fcn is undefined for x = 2, or 4, so the domain is {x|x 2, 4}.• Interval Notation: (−∞,2)U(2,4)U(4,∞)
x 2 x 4 0
x 2 0 or x 4 0
x 2 or x 4
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Bruce Mayer, PE Chabot College Mathematics
Example Example Graph Graph3
( )1
f xx
SOLUTION: x 1, so the graph has a vertical asymptote at x = 1. Find ordered pairs around the asymptote and then graph.
x 4 2 0 0.5
y 3/5 1 3 6
x 1.5 2 4 5
y 6 3 1 3/4
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Bruce Mayer, PE Chabot College Mathematics
SimplifyingSimplifying Rational Rational Expressions and FunctionsExpressions and Functions As in arithmetic, rational expressions
are simplified by “removing”, or “Dividing Out”, a factor equal to 1.
example(2 1)( 5) (2 1) ( 5)
( 5( 7)( 5) )( 7)
x x x
x xx x
x
(2 1)
( 7)
x
x
removed the factor that equals 1
equals 1
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Bruce Mayer, PE Chabot College Mathematics
Maintain DomainMaintain Domain
Because rational expressions often appear when we are writing functions, it is important that the function’s domain not be changed as a result of simplifying. For example, the Domain of the function given by
(2 1)( 5)( )
( 7)( 5)
x xF x
x x
is assumed to be all real numbers for which the denominator is NONzero
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Bruce Mayer, PE Chabot College Mathematics
Maintain DomainMaintain Domain
Thus for Rational Fcn: (2 1)( 5)
( )( 7)( 5)
x xF x
x x
In the previous example, we wrote F(x) in simplified form as
Domain of { 7, 5}.F x x x
(2 1).
( 7)
x
x
There is a serious problem with stating that these are equivalent; The Domains are NOT the same
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Bruce Mayer, PE Chabot College Mathematics
Maintain DomainMaintain Domain
Why (2 1)( 5)( )
( 7)( 5)
x xF x
x x
The domain of the function given by
Thus the domain of G includes 5, but the domain of F does not. This problem can be addressed by specifying
≠(2 1)
.( 7)
x
x
(2 1)( ) is assumed to be { 7}.
( 7)
xG x x x
x
(2 1)( 5) (2 1) 5.
( 7)( 5) ( 7)
x x xwith x
x x x
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Bruce Mayer, PE Chabot College Mathematics
Example Example Maintain Domain Maintain Domain
Write this Fcn in Simplified form
SOLUTION: first factor the numerator and denominator, looking for the largest factor common to both. Once the greatest common factor is found, use it to write 1 and simplify as shown on the next slide
2
2
3 13 10( )
3 19 14
x xg x
x x
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Bruce Mayer, PE Chabot College Mathematics
Example Example Maintain Domain Maintain Domain2
2
3 13 10( )
3 19 14
x xg x
x x
( 5)(3 2)
(3 2( 7) )
x
x
x
x
(3 2) ( 5)
(3 2) ( 7)
x x
x x
Note that the domain of g = {x | x 2/3 and x −7}by Factoring (see next)Factoring. The greatest common factor is (3x − 2).
Rewriting as a product of two rational expressions.
( 5)1
( 7)
x
x
For x 2/3, we have (3x − 2)/(3x − 2) = 1.
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Bruce Mayer, PE Chabot College Mathematics
Example Example Maintain Domain Maintain Domain
Thus the simplified form of
23
( 5), .
( 7)
xx
x
Removing the factor 1. To keep the same domain, we specify that x 2/3.
2
2
3 13 10( )
3 19 14
x xg x
x x
23
5( ) , .
7
xg x with x
x
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Bruce Mayer, PE Chabot College Mathematics
““Canceling” Confusion Canceling” Confusion
The operation of Canceling is a ShortHand for DIVISION between Multiplication Chains
Canceling can ONLY be done when we have PURE MULTIPLICATION CHAINS both ABOVE & BELOW the Division Bar`
11
34
7
214
7
214 22
x
x
xx
x
xx
3
7
73
7
2142
xx
xx
x
xx
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Bruce Mayer, PE Chabot College Mathematics
Canceling CaveatCanceling Caveat “Canceling” is a shortcut often used for removing a
factor equal to 1 when working with fractions. Canceling removes multiplying factors equal to 1 in products. It cannot be done in sums or when adding expressions together. Simplifying the expression from the previous example might have been done faster as follows:
2
2
3 13 10 (3 2)( 5)
3 19 14 ( 7)(3 2)
x x x x
x x x x
( 5)
( 7)
x
x
When a factor that equals 1 is found, it is “canceled” as shown.
Removing a factor equal to 1.
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Bruce Mayer, PE Chabot College Mathematics
Canceling CaveatCanceling Caveat
Caution! Canceling is often performed incorrectly:
Incorrect! Incorrect! Incorrect!
In each situation, the expressions canceled are not both factors. Factors are parts of products. For example, 5 is not a factor of the numerator 5x – 2. If you can’t factor, you can’t cancel! When in doubt, do NOT cancel!
7 5 2 2 3 17, ,
15 3 3
x x x
x x x
To check that these are not equivalent, substitute a number for x.
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Bruce Mayer, PE Chabot College Mathematics
Simplifying Rational Expressions Simplifying Rational Expressions
1. Write the numerator and denominator in factored form.
2. Divide out all the common factors in the numerator and denominator; i.e., remove factors equal to ONE
3. Multiply the remaining factors in the numerator and the remaining factors in the denominator.
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Bruce Mayer, PE Chabot College Mathematics
Example Example Simplify Simplify
SOLUTION:
2
2
3 9 12
6 30 24
x x
x x
Factor out the GCF.
2
2
3 9 12
6 30 24
x x
x x
2
2
3 3 4
6 5 4
x x
x x
3 4 1
6 4 1
x x
x x
4
2 4
x
x
Factor the polynomial factors.
Divide out common factors.
1432
143
xx
xx
1 and x
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Bruce Mayer, PE Chabot College Mathematics
Multiply Rational ExpressionsMultiply Rational Expressions
The Product of Two Rational Expressions
To multiply rational expressions, multiply numerators and multiply denominators:
QS
PR
S
R
Q
P
Then factor and simplify the result if possible.
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Bruce Mayer, PE Chabot College Mathematics
Example Example Multiplication Multiplication
Multiply and, if possible, simplify.
a) b)2
2
5 4 3
9 4
x x x
x x
46 5
10 6
a
a
SOLUTION a)4 46 (5)
10(
6 5
6 610 )
aa
a a
2 3 5
2 5 2 3
a a a a
a
2
3 a 5a a a 2 5 2 3 a
3
2
a
MULTIPLICATIONChains → Canceling OK
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Bruce Mayer, PE Chabot College Mathematics
Example Example Multiplication Multiplication SOLUTION b)
2 2
2 2
5 4 3 ( 5 4)( 3)
9 4 ( 9)( 4)
x x x x x x
x x x x
2
2
5 4 3
9 4
x x x
x x
( 3)( 4)( 1)
()( 4)( 3 3)
x x
x xx
x
( 4)x
( 1) ( 3)x x
( 3) ( 3)x x ( 4)x
1
3
x
x
MULTIPLICATIONChains → Canceling OK
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Bruce Mayer, PE Chabot College Mathematics
Example Example Multiply & Simplify Multiply & Simplify
Multiply and,if possible, simplify.
SOLUTION
( 4)( 5)
7(3)(3 1 )
7
)( 4
x x
x x
( 4)x
( 5) 7x
7 (3)(3 1) ( 4)x x ( 5)
3(3 1)
x
x
411321
720
4113
7
21
202
2
2
2
xx
xx
xx
xx
4113
7
21
202
2
xx
xx
MULTIPLICATIONChains → Canceling OK
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Bruce Mayer, PE Chabot College Mathematics
Divide Rational ExpressionsDivide Rational Expressions
The Quotient of Two Rational Expressions
To divide by a rational expression, multiply by its reciprocal
WY
VZ
Y
Z
W
V
Z
Y
W
V
Then factor and, if possible, simplify.
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Bruce Mayer, PE Chabot College Mathematics
Example Example Division Division
Divide and, if possible, simplify.
a) b)
SOLUTION
8
9
x
y
23
5
xx
x
9 9 8
8x x
y
y
72
xy
Multiplying by the reciprocal of the divisor
Multiplying rational expressions
a)
b) 5 23
52 3
1
x xx
x
x
x
( 3)( 5)
2
x x
x
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Bruce Mayer, PE Chabot College Mathematics
Example Example Division Division
Divide and, if possible, simplify.
SOLN
2 2
2 2
4 4 4
x x
x x x
2
2 2 2
2 2 2 4 4
4 4 4 4 2
x x x x x
x x x x x
( 2)( 2)
(
( 2)
( 22 ) ))( 2
x x
x
x
x x
( 2)x
( 2)x ( 2)
( 2)
x
x
( 2)x ( 2)x
2
2
x
x
MULTIPLICATIONChains → Canceling OK
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Bruce Mayer, PE Chabot College Mathematics
Example Example Division Division
Divide and, if possible, simplify.
2 2
2 2
3 2 5 6
5 4 10 24
x x x x
x x x x
SOLUTION ( 1)( 2)( 6)( 4)
( 4)( 1)( 2)( 3)
x x x x
x x x x
2 2 2 2
2 2 2 2
3 2 5 6 3 2 10 24
5 4 10 24 5 4 5 6
x x x x x x x x
x x x x x x x x
( 1)x
( 2)x ( 6) ( 4)x x
( 4)x ( 1)x ( 2)x ( 3)x
( 6)
( 3)
x
x
MULTIPLICATIONChains → Canceling OK
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Bruce Mayer, PE Chabot College Mathematics
Example Example Division Division
Divide and, if possible, simplify.
SOLUTION
2
2
3 4 1
25 6
x x x
x x
2 2
2 2
3 4 1 3 4 6
25 6 25 1
x x x x x x
x x x x
( 6)( 4)( 1)
()( 1)( 5 5)
x x
x xx
x
( 4) ( 1)x x
( 6)
( 5)( 5) ( 1)
x
x x x
( 4)( 6)
( 5)( 5)
x x
x x
MULTIPLICATIONChains → Canceling OK
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Bruce Mayer, PE Chabot College Mathematics
Example Example Manufacturing Engr Manufacturing Engr
The function given by
gives the time, in hours, for two machines, working together to complete a job that the 1st machine could do alone in t hours and the 2nd machine could do in 3t − 2 hours. • How long will the two machines, working
together, require for the job if the first machine alone would take (a) 2 hours? (b) 5 hours?
23 2( )
4 2
t tM t
t
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Bruce Mayer, PE Chabot College Mathematics
Example Example Manufacturing Engr Manufacturing Engr
SOLUTION23 2
( )4
2 2
22
2M
(a)
13
12 4 8 4or 1 hr
8 2 6 3
23 2( )
4
5 5
25
5M
1118
75 10 65or 3 hr
20 2 18
(b)
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Bruce Mayer, PE Chabot College Mathematics
WhiteBoard WorkWhiteBoard Work
Problems From §6.1 Exercise Set• 22 (ppt), 26 (ppt), 114 , 16, 46, 66, 86
More Rational Division Since we are dividing fractions,
we multiply by the reciprocal Now, we follow the rule for
multiplication Factor and then cancel
Don't leave the numerator empty - put a one to hold the place.
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P6.1-22 P6.1-22 Rational fcn Graph Rational fcn Graph
Describe end-behavior of Graph at Far-Right
ANS: As x becomes large y = f(x) approaches, but never reaches, a value of 3
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P6.1-22 P6.1-22 Rational fcn Graph Rational fcn Graph
What is the Eqn for the Horizontal Asymptote:
ANS: y = f(x) approaches, but never reaches, a value of 3, to the Asymptote eqn
y = 3
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Bruce Mayer, PE Chabot College Mathematics
P6.1-26 P6.1-26 Rational fcn Graph Rational fcn Graph
List 2 real No.s that are NOT function values of f
ANS: y = f(x) does not have a graph between y > 0 and y < 3. Thus two values for which there is NO f(x):• y = 1 or y = 2
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P6.1-114 P6.1-114 Smoking Diseases Smoking Diseases
Find P(9). Describe Meaning. ID pt on Graph
ANS: An incidence ratio of 9 indicates that 88.9% of Lung Cancer deaths are associated with Cigarette smoking
988
9
800
9
191009 .
P
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P6.1-114 P6.1-114 Smoking Diseases Smoking Diseases
ID P(9) on Graph
988.
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Bruce Mayer, PE Chabot College Mathematics
All Done for TodayAll Done for Today
Diophantus of
Alexandria
The FIRST Algebraist• In the 3rd century, the
Greek mathematician Diophantus of Alexandria wrote his book Arithmetica. Of the 13 parts originally written, only six still survive, but they provide the earliest record of an attempt to use symbols to represent unknown quantities.
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Bruce Mayer, PE Chabot College Mathematics
Bruce Mayer, PELicensed Electrical & Mechanical Engineer
Chabot Mathematics
AppendiAppendixx
–
srsrsr 22
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Bruce Mayer, PE Chabot College Mathematics
Graph Graph yy = | = |xx||
Make T-tablex y = |x |
-6 6-5 5-4 4-3 3-2 2-1 10 01 12 23 34 45 56 6
x
y
-6
-5
-4
-3
-2
-1
0
1
2
3
4
5
6
-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
file =XY_Plot_0211.xls
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Bruce Mayer, PE Chabot College Mathematics
x
y
-3
-2
-1
0
1
2
3
4
5
-3 -2 -1 0 1 2 3 4 5
M55_§JBerland_Graphs_0806.xls -10
-9
-8
-7
-6
-5
-4
-3
-2
-1
0
1
2
-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
file =XY_Plot_0211.xls
xy