binomial expansion and more
DESCRIPTION
Binomial Expansion And More. Jeffrey Bivin Lake Zurich High School [email protected]. Last Updated: May 2, 2011. Let’s look at (x + y) p. (x + y) 0 = 1. Look at the exponents!. (x + y) 1 = 1x + 1y. (x + y) 2 = 1x 2 + 2xy + 1y 2. (x + y) 3 = 1x 3 + 3x 2 y + 3xy 2 +1y 3. - PowerPoint PPT PresentationTRANSCRIPT
Jeff Bivin -- LZHS
Binomial Expansion And More
Last Updated: May 2, 2011
Jeffrey Bivin
Lake Zurich High School
Jeff Bivin -- LZHS
(x + y)0 = 1
(x + y)1 = 1x + 1y
(x + y)2 = 1x2 + 2xy + 1y2
(x + y)3 = 1x3 + 3x2y + 3xy2 +1y3
(x + y)4 = 1x4 + 4x3y + 6x2y2 + 4xy3 + 1y4
(x + y)5 = 1x5 + 5x4y + 10x3y2 + 10x2y3 + 5xy4 + 1y5
(x + y)6 = 1x6 + 6x5y + 15x4y2 + 20x3y3 + 15x2y4 + 6xy5 + 1y6
Let’s look at (x + y)p
(x + y)7 = _x7 + _x6y + _x5y2 + _x4y3 + _x3y4 + _x2y5 + _xy6 + _y7
Jeff Bivin -- LZHS
(x + y)0 = 1
(x + y)1 = 1x + 1y
(x + y)2 = 1x2 + 2xy + 1y2
(x + y)3 = 1x3 + 3x2y + 3xy2 +1y3
(x + y)4 = 1x4 + 4x3y + 6x2y2 + 4xy3 + 1y4
(x + y)5 = 1x5 + 5x4y + 10x3y2 + 10x2y3 + 5xy4 + 1y5
(x + y)6 = 1x6 + 6x5y + 15x4y2 + 20x3y3 + 15x2y4 + 6xy5 + 1y6
Let’s look at (x + y)p
Jeff Bivin -- LZHS
(x + y)0 = 1
(x + y)1 = 1x + 1y
(x + y)2 = 1x2 + 2xy + 1y2
(x + y)3 = 1x3 + 3x2y + 3xy2 +1y3
(x + y)4 = 1x4 + 4x3y + 6x2y2 + 4xy3 + 1y4
(x + y)5 = 1x5 + 5x4y + 10x3y2 + 10x2y3 + 5xy4 + 1y5
(x + y)6 = 1x6 + 6x5y + 15x4y2 + 20x3y3 + 15x2y4 + 6xy5 + 1y6
Let’s look at (x + y)p
Jeff Bivin -- LZHS
(x + y)7 = 1 7 21 35 35 21 7 1
(x + y)0 = 1
(x + y)1 = 1 1
(x + y)2 = 1 2 1
(x + y)3 = 1 3 3 1
(x + y)4 = 1 4 6 4 1
(x + y)5 = 1 5 10 10 5 1
(x + y)6 = 1 6 15 20 15 6 1
(x + y)8 = 1 8 28 56 70 56 28 8 1
Let’s look at (x + y)p
Jeff Bivin -- LZHS
(x + y)7 = 1x7 + 7x6y + 21x5y2 + 35x4y3 + 35x3y4 + 21x2y5 + 7xy6 + 1y7
(x + y)0 = 1
(x + y)1 = 1x + 1y
(x + y)2 = 1x2 + 2xy + 1y2
(x + y)3 = 1x3 + 3x2y + 3xy2 +1y3
(x + y)4 = 1x4 + 4x3y + 6x2y2 + 4xy3 + 1y4
(x + y)5 = 1x5 + 5x4y + 10x3y2 + 10x2y3 + 5xy4 + 1y5
(x + y)6 = 1x6 + 6x5y + 15x4y2 + 20x3y3 + 15x2y4 + 6xy5 + 1y6
Let’s look at (x + y)p
Jeff Bivin -- LZHS
12! 47900160019,958,400
2! 3! 2! 24
In how many ways can you arrange the letters in the word MATHEMATICAL ?
Jeff Bivin -- LZHS
52 yx
35144
5040
!3!4
!7
21240
5040
!5!2
!7
34 yx
In how many ways can you arrange the letters in the non-word xxxxyyy?
In how many ways can you arrange the letters in the non-word xxyyyyy?
(x + y)7 = 1x7 + 7x6y + 21x5y2 + 35x4y3 + 35x3y4 + 21x2y5 + 7xy6 + y7
Jeff Bivin -- LZHS
Let’s look closer(x + y)7 = 1x7 + 7x6y + 21x5y2 + 35x4y3 + 35x3y4 + 21x2y5 + 7xy6 + y7
071!0!7
!7yx 167
!1!6
!7yx 2521
!2!5
!7yx
3435!3!4
!7yx 4335
!4!3
!7yx 5221
!5!2
!7yx
617!6!1
!7yx 701
!7!0
!7yx
Jeff Bivin -- LZHS
An alternate look(x + y)7 = 1x7 + 7x6y + 21x5y2 + 35x4y3 + 35x3y4 + 21x2y5 + 7xy6 + y7
77!0!7
!7C 67!1!6
!7C 57!2!5
!7C
47!3!4
!7C 37!4!3
!7C 27!5!2
!7C
17!6!1
!7C 07!7!0
!7C
Jeff Bivin -- LZHS
(2x - y)4 = 16x4 - 32x3y + 24x2y2 - 8xy3 + y4
40444 161)()2(1
!0!4
!4xyxC
)(84)()2(4!1!3
!4 31334 yxyxC
)(46)()2(6!2!2
!4 222224 yxyxC
)(24)()2(4!3!1
!4 33114 yxyxC
)(1)()2(1!4!0
!4 44004 yyxC
Jeff Bivin -- LZHS
(3x + 2y)5 = 243x5 + 810x4y + 1080x3y2 + 720x2y3 + 240xy4 + 32y5
50555 2431)2()3(1
!0!5
!5xyxC
yxyxC 2815)2()3(5!1!4
!5 41445
222335 42710)2()3(10
!2!3
!5yxyxC
323225 8910)2()3(10
!3!2
!5yxyxC
44115 1635)2()3(5
!4!1
!5yxyxC
55005 3211)2()3(1
!5!0
!5yyxC
Jeff Bivin -- LZHS
Given: (x + y)15
In how many ways can you arrange the
letters in the non-word
xxxxxyyyyyyyyyy ?
105515 3003
!10!5
!15yxC
1053003 yx
What is the coefficient of the term ____ x5y10 ?
Jeff Bivin -- LZHS
Given: (4x - 3y)10
In how many ways can you arrange the
letters in the non-word
xxxxxxxyyy ?
37710 )3()4(120
!3!7
!10yxC
37 2716384120 yx
What is the coefficient of the term ____ x7y3 ?
37160,084,53 yx
Jeff Bivin -- LZHS
Expand: (x + y + z)2
(x + y + z) (x + y + z)
x2 + xy + xz + yx + y2 + yz + zx + zy + z2
x2 + 2xy + 2xz + y2 + 2yz + z2
Jeff Bivin -- LZHS
x3 + 3x2y + 3x2z + 3xy2 + 6xyz + 3xz2 + y3 + 3y2z + 3yz2 + z3
(x + y + z)2 (x + y + z)
x3 + x2y + x2z + 2x2y + 2xy2 + 2xyz + 2x2z + 2xzy + 2xz2 + y2x + y3 + y2z
+2yzx + 2y2z + 2yz2 + z2x + z2y + z3
Expand: (x + y + z)3
(x2 + 2xy + 2xz + y2 + 2yz + z2)(x + y + z)
We did this in the last example
Jeff Bivin -- LZHS
zyx 6!1!1!1
!3
x3 + 3x2y + 3x2z + 3xy2 + 6xyz + 3xz2 + y3 + 3y2z + 3yz2 + z3
Given: (x + y + z)3
In how many ways can you arrange the letters in the non-word xyz ?
What is the coefficient of the term ____ xyz ?
In how many ways can you arrange the letters in the non-word xxz ?
zx 23!1!0!2
!3
What is the coefficient of the term ____ x2z ?
Jeff Bivin -- LZHS
Given: (x + y + z)15
In how many ways can you arrange the
letters in the non-word
xxyyyyyyyzzzzzz ?
672180180!6!7!2
!15zyx
672180,180 zyx
What is the coefficient of the term ____ x2y7z6 ?
Jeff Bivin -- LZHS
Given: (2x + 3y - z)9
In how many ways can you arrange the
letters in the non-word
xxxyyyyzz ?
243 )()3()2(1260!2!4!3
!9zyx
243480,816 zyx
What is the coefficient of the term ____ x3y4z2 ?
243 8181260 zyx
Jeff Bivin -- LZHS
Given: (a + b + c + d)20
In how many ways can you arrange the
letters in the non-word
aaaaabbbbbbcccccccdd ?
2765720,510,793,2!2!7!6!5
!20dcba
2765720,510,793,2 dcba
What is the coefficient of the term ____ a5b6c7d2 ?
Jeff Bivin -- LZHS
Binomial ProbabilityCan be determined in a binomial experiment that meets the following criteria:
► There are n independent trials.
► Each trial has only two possible outcomes:■ Success■ Failure
► The probability of success (s) is the same for each trial and the probability for failure (f) is the same for each trail.
knkkn fsCtrialsninsuccessesk Pr
Jeff Bivin -- LZHS
Binomial Probability
A die is rolled 5 times. What is the probability of rolling exactly 3 ones?
2653
61
35C
3888125
7776250
3625
216110
2
653
61
!2!3!5
Jeff Bivin -- LZHS
Binomial Probability
A bent coin has a probability of heads of 4/7. If the coin is tossed 10 times, what is the probability of tossing exactly 6 heads?
4736
74
610C
247.0210 249,475,282960,672,69
240181
1176494096
Jeff Bivin -- LZHS
A bent coin has a probability of heads of 4/7. If the coin is tossed 10 times, what is the probability of tossing at least 8 heads?
Binomial Probability
07310
74
10101
739
74
9102
738
74
810 CCC
126.0249,475,282976,454,35
07310
741
739
742
738
74 11045
Jeff Bivin -- LZHS
A bent coin has a probability of heads of 4/7. If the coin is tossed 10 times, what is the probability of tossing at least 3 heads?
8
732
74
2109
731
74
11010
730
74
0101 CCC
HHHHHHHHHHH 109876543210
Binomial Probability
980.0249,475,282960,904,276
8732
749
731
7410
730
74 451011
10
8291100
7
344534103411