bending in 2 planes parametric form assuming small deflections and no torsion

10
Bending in 2 Planes Parametric form assuming small deflections and no torsion.

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Page 1: Bending in 2 Planes Parametric form assuming small deflections and no torsion

Bending in 2 Planes

Parametric form assuming small deflections and no torsion.

Page 2: Bending in 2 Planes Parametric form assuming small deflections and no torsion

Parametric Form

zzzz

yyyy

xxxx

auauauauz

auauauauy

auauauaux

012

23

3

012

23

3

012

23

3

)(

)(

)(

Where

Condensed:

1,0u

012

23

3)( aaaap uuuu

Page 3: Bending in 2 Planes Parametric form assuming small deflections and no torsion

Deflection in Y & Z

Sensor 1 Sensor 2

x1

x2

L = 15cm

Tip Deflection

y

xz

Page 4: Bending in 2 Planes Parametric form assuming small deflections and no torsion

Cross-section at Sensors

y

zx

Known:

0

0,0

0,,)0,0,0()0(

2

2

2

2

11

000

dx

zd

dx

yd

aadx

dz

dx

dy

aaap

zy

zyx

At u = 0:

At u = 1:

Seven unknowns remain.

Page 5: Bending in 2 Planes Parametric form assuming small deflections and no torsion

Curvature InformationAssuming no torsion, the orientation of the local and global coordinate frames are the same.

From each known curvature component, we have an equation with 5 unknowns.

For example, at u = 1:

Therefore, at each sensor two orthogonal components of curvature are known, and 2 equations with 5 unknowns result. (y”(x) a1x, a2x, a3x, a2y, a3y and z”(x) a1x, a2x, a3x, a2z, a3z). Therefore two sets of curvatures are needed.

02662

0

)(

)/(0

21231312

32

2

yxyxxyxx

uuuuuu

u

uuuuuu

u

uuu

aaaaaaaa

yxyx

x

yxyx

x

xy

dx

yd

Page 6: Bending in 2 Planes Parametric form assuming small deflections and no torsion

To Simplify Math

22

33

22

33

)(

)(

)(

uauauz

uauauy

uLux

L

xu

zz

yy

Assume small deflections in Y and Z, such that

Then,

We have rid of 3 more unknowns (x coefficients).

Page 7: Bending in 2 Planes Parametric form assuming small deflections and no torsion

Simplified Derivatives

zzuu

yyuu

uu

zzu

yyu

u

auauzz

auauyy

uxx

uauauzz

uauauyy

Luxx

23

23

22

3

22

3

26)("

26)("

0)("

23)('

23)('

)('

The parametric slope equations are now:

The parametric curvature equations are now:

Page 8: Bending in 2 Planes Parametric form assuming small deflections and no torsion

Parametric Equations in Terms of x

2

2

3

3

2

2

3

3

)(

)(

L

xa

L

xaxz

L

xa

L

xaxy

L

xu

zz

yy

Substitute in for u:

Page 9: Bending in 2 Planes Parametric form assuming small deflections and no torsion

Parametric Derivatives in Terms of x

22

33

2

2

3

3

222

33

2

223

3

26)("

26)("

23)('

23)('

L

ax

L

axz

L

ax

L

axy

xL

ax

L

axz

xL

ax

L

axy

zz

yy

zz

yy

Slope equations:

Curvature equations:

Now, the equations to solve for the four remaining unknown coefficients are simple.

y”(x) and z”(x) are the known orthogonal components of the curvature at the sensor locations (and at the tip).

Page 10: Bending in 2 Planes Parametric form assuming small deflections and no torsion

Model

• Find y’’(x) at sensor locations. • Calculate a set of unknowns for the region

from the base to x2 (second sensor location.)• Estimate y(x2) and y’(x2).• Use y(x2), y’(x2) and y’’(L) to calculate a set of

unknowns from the region from x2 to the tip of the needle.