bellringer

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Bellringer Find the slope going through the points. Use the given information to write an equation for each line. 1. 2. (2, 3), (1, 6) 1. m=-2/3 2.m=3 3. slope 1/3 , y- intercept 2 4. 3. y=-1/3x-2 4.y=-3/2x+2

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Bellringer . Find the slope going through the points. Use the given information to write an equation for each line. 1. 2. (2, 3), (  1,  6) 1. m=-2/3 2.m=3. 3. slope 1/3 , y-intercept  2 4. 3. y=-1/3x-2 4.y=-3/2x+2. Geometry: Chapter 3 Parallel and Perpendicular lines . - PowerPoint PPT Presentation

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Page 1: Bellringer

Bellringer Find the slope going through the points.

Use the given information to write an equation for each line.

1.

2. (2, 3), (1, 6) 1. m=-2/3 2.m=3

3. slope 1/3 , y-intercept 2

4.

3. y=-1/3x-2 4.y=-3/2x+2

Page 2: Bellringer

3-5 PARALLEL LINES AND TRIANGLES

Geometry: Chapter 3 Parallel and Perpendicular lines

Page 3: Bellringer

Connections

Page 4: Bellringer

Lesson Purpose

Objective Essential Question To use parallel lines to

prove a theorem about triangles.

To find measures of angles of triangles.

How do the postulates and theorem for proving triangles congruent shorten the time and work involved?

Page 5: Bellringer

Postulate 3-3 Parallel Postulate Through any point not on a line,

there is one and only one line parallel to the given line.

There is exactly one line through Parallel to m.

P•

m

Page 6: Bellringer

Triangle Angle-Sum Theorem 3-10

The sum of the measures of the angle of a triangle is 180.

Page 7: Bellringer

Example #1 So we have

A+B+C=180 Using the angle measures we were given, we can substitute those values into our equation to get.

120+34+mC=180

mC=26

(1) Find the measure of ∠C.

. Using the diagram, we are given that mA= 120 mB=34

Page 8: Bellringer

Example #2 (2) Find the

value of x in the diagram below.

mS=61 mT=73 mP=mQ=x

mS+mT+mSRT=180

61+73+mSRT=180 mSRT= 46 SRTQRP thus, QRP=46 P+Q+46=180 x+x+46=180 2x+46=180 P=Q=67

Page 9: Bellringer

Key Concepts The angle formed by one

side of a triangle with the extension of another side is called an exterior angle of the triangle.

Page 10: Bellringer

Key Concepts

Exterior angles get their name because they lie on the outsides of triangles.

The two angles that are not adjacent, or next to, the exterior angle of the triangle are called remote interior angles.

Page 11: Bellringer

Triangle Exterior Angle Theorem 3-11 The Measure of

each exterior angle of a triangle equals the sum of the measures of its two remote interior angles.

Page 12: Bellringer

Example #31) Find the measures of ∠1 and ∠2 in the figure below.

Solution mS=42, and

mA=30 mS+mA+1=180 42+30+1=180 72+1=180 1=108 mS+mA= 2 42+30=2 2=72

Page 13: Bellringer

Example #42) Find m∠B. Solution

R=93, and JEB=132

B=9x+3 R+B=JEB 93+(9x+3)= 132 96+9x=132 9x=36 x=4 B=39

Page 14: Bellringer

Real World Connections

Page 15: Bellringer

Summary-Recap The sum of the measures of the

angles of a triangle is equal to 180.

The measure of each exterior angle of a triangle equals the sum of the measures of its two remote interior angles.

Page 16: Bellringer

Ticket Out and Homework

Ticket Out Homework pg.184-185 #s

10,14,20,24,25 What is true about the

measures of angles in a triangle?

By the Triangle Angle Sum theorem, The sum of the measures of the angles of a triangle are equal to 180