bayesian3 (1)-1

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MTH 3408 INTRODUCTION TO BAYESIAN METHOD STUDENT CENTERED LEARNING III Name : Punitha A/P Linganathan 157395 Tham Wendy 159281 Wong Hui Shein 159353 Solution: xθN ( θ, 4 ) θN ( 110 , 0.4 ) f ( x i | θ ) = 1 2 π ( 4) exp { −( x i θ) 2 2 ( 4) } exp { 1 2( 4 ) ( x i 2 2 x i θ +θ 2 ) } ¿ exp ( 1 2 ( 4) x i 2 ) exp ( 1 4 x i θ1 2( 4) θ 2 ) exp ( 1 2( 4 ) θ 2 + 1 4 x i θ ) f ( x | θ) =L ( θ;x) = i f ( x i | θ ) i exp ( 1 2 ( 4) θ 2 + 1 ( 4) x i θ ) ¿ exp [ i 1 2 ( 4) θ 2 + 1 4 x i θ ] ¿ exp [ n 2 ( 4) θ 2 + ( 1 4 i x i ) θ ]

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Bayesian Statistics

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MTH 3408 INTRODUCTION TO BAYESIAN METHODSTUDENT CENTERED LEARNING III

Name: Punitha A/P Linganathan157395 Tham Wendy 159281 Wong Hui Shein159353

Solution:

Question 1:

Question 2: