balance design criteria for non-rectangular section

BALANCE DESIGN CRITERIA FOR NON-RECTANGULAR SECTION Given: kN-m 0.00E+00 N-mm kN-m 0.00E+00 N-mm 14.6 kN-m 1.46E+07 N-mm Span (L) = 15 m n = 0.85 Loss of prestress= 15 in % 1-n = 0.15 llowable Stresses: Fct = 19.3 MPa Fcw = 22.1 MPa Ftt = -1 MPa Ftw = -1.4 MPa Solution: 5 kN/m *Compute Bending Moments Mo = 140.625 kN-m 1.41E+08 N-mm 0 kN-m 0.00E+00 N-mm 410.625 kN-m 4.11E+08 N-mm (1-n)Mo + Md + Ml = 4.32E+08 1.88E+07 Fcw - nFtt = 22.95 2.42E+07 (1-n)Mo +Md +Ml = 4.32E+08 nFct - Ft 17.805 C1 > C2 Wo = WD = WL = *Assume Wt of Beam, WB: WB = MD = ML = *Calculate Ideal Z1 & Z2 Z1 = mm 3 Z2 = mm 3

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Balance Design Criteria for Non-rectangular Section

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Sheet1* Section Properties*Section Properties (Trial):AydIxBALANCE DESIGN CRITERIA FOR NON-RECTANGULAR SECTIONC1 =0.56hb(t or b) =200mm36000810381.825.35E+09C2 =0.44hbr =125mm67500450201.824.39E+09Given:A =1.49E+05mm24500090338.185.27E+09Wo =kN-m 0.00E+00N-mm*Assume Concrete Cover, Ccover(mm):C1 =471.82mmWD =kN-m 0.00E+00N-mmCcover =0.075h C2 =428.18mmWL =14.6kN-m 1.46E+07N-mme =0.36h I =1.50E+10mm4Mo + Md + Ml =5.51E+08Z1 =3.18E+07mm3Span (L) =15m* Find Ae:Fct - Ftt =20.3Z2 =3.50E+07mm3n =0.85Ae =3.41E+07mm3Mo(Fcw -Ftw)=3304687500e =325.69mmLoss of prestress=15in %1-n =0.15FcwFct =426.53* Set Ratio Ae/(Z1) :FtwFtt =1.4*Compare the ratio:Allowable Stresses:Fct =19.3MPa5.014.20 C2

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