b1213 exponential logs
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kalkulusTRANSCRIPT
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B1.2 & B1.3Derivatives of
Exponential and Logarithmic
Functions
IB Math HL/SL - Santowski
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(A) Derivatives of Exponential
FunctionsGraphic Perspective
Consider the graph of
f(x) = axand then
predict what the
derivative graphshould look like
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(A) Derivatives of Exponential
FunctionsGraphic Perspective
Our exponential fcn isconstantly increasing, it isconcave up and has nomax/min points
So our derivative graphshould be positive,increasing and have no x-intercepts
So then our derivativegraph should look verysimilar to anotherexponential fcn!!
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(A) Derivatives of Exponential
FunctionsGraphic Perspective
So when we usetechnology to graphan exponentialfunction and itsderivative, we seethat our prediction iscorrect
Now lets verify thisgraphic predicationalgebraically
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(B) Derivatives of Exponential
FunctionsAlgebraic Perspective
Lets go back to the limitcalculations to find the derivativefunction for f(x) = bx
So we see that the derivative is infact another exponential function
(as seen by the bxequation) whichis simply being multiplied by someconstant (which is given by thelimit expression)
But what is the value of the limit??
So then, the derivative of anexponential function isproportional to the function itself
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1lim)(
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lim)(
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(C) Investigating the Limits
Investigate lim h0(2h1)/h
numerically with a table ofvalues
x y
-0.00010 0.69312 -0.00007 0.69313
-0.00003 0.69314
0.00000 undefined
0.00003 0.69316
0.00007 0.69316
0.00010 0.69317
And we see the value of 0.693as an approximation of the limit
Investigate lim h0(3h1)/h
numerically with a table ofvalues
x y
-0.00010 1.09855 -0.00007 1.09857
-0.00003 1.09859
0.00000 undefined
0.00003 1.09863
0.00007 1.09865
0.00010 1.09867
And we see the value of1.0986 as an approximation ofthe limit
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(C) Investigating the Limits
Investigate lim h0 (4h1)/hnumerically with a table ofvalues
x y
-0.00010 1.38620 -0.00007 1.38623
-0.00003 1.38626
0.00000 undefined
0.00003 1.38633
0.00007 1.38636
0.00010 1.38639
And we see the value of 1.386as an approximation of the limit
Investigate lim h0 (eh1)/hnumerically with a table ofvalues
x y
-0.00010 0.99995 -0.00007 0.99997
-0.00003 0.99998
0.00000 undefined
0.00003 1.00002
0.00007 1.00003
0.00010 1.00005
And we see the value of 1.000as an approximation of the limit
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(D) Special Limits - Summary
The number 0.693 (coming from our
exponential base 2), 1.0896 (coming from
base = 3), 1.386 (base 4) are, as it turns
out, special numberseach is thenatural logarithm of its base
i.e. ln(2) = 0.693
i.e. ln(3) = 1.0896
i.e. ln(4) = 1.386
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(E) Derivatives of Exponential
Functions - Summary
The derivative of an exponential function was
Which we will now rewrite as
And we will see one special derivativewhen theexponential base is e, then the derivative becomes:
h
bbxf
h
h
x 1lim)(0
)ln()( bbxf x
xx eeexf )ln()(
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(F) Examples
Find the equation of the line normal to f(x)
= x2exat x = 1
Find the absolute maximum value of f(x) =
xe-x
Where is f(x) = ex^2 increasing?
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(G) Derivatives of Logarithmic
FunctionsGraphic Perspective
Consider the graph of
f(x) = logax and then
predict what the
derivative graphshould look like
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(G) Derivatives of Logarithmic
FunctionsGraphic Perspective
Our log fcn is
constantly increasing,
it is concave down
and has no max/minpoints
So our derivative
graph should be
positive, decreasingand have no x-
intercepts
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(G) Derivatives of Logarithmic
FunctionsGraphic Perspective
So when we usetechnology to graph alogarithmic functionand its derivative, wesee that ourprediction is correct
Now lets verify thisgraphic predicationalgebraically
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(H) Derivatives of Logarithmic
FunctionsAlgebraic Perspective Let logbx = y so then b
y= x
So now we have an exponential equation (forwhich we know the logarithm), so we simply useimplicit differentiation to find dy/dx
d/dx (by) = d/dx (x) [ln(b)] x byx dy/dx = 1
dy/dx = 1/[byln(b)] but recall that by= x
Dy/dx = 1/[x ln(b)]
And in the special case where b = e (i.e. wehave ln(x)), the derivative is 1/[x ln(e)] = 1/x
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(I) Derivatives of Logarithmic
Functions - Summary
The derivative of a logarithmic function is
And we will see one special derivativewhen
the exponential base is e, then the derivative of
f(x) = ln(x) becomes
)ln(
1)(
bx
xf
xexxf
1
)ln(
1)(
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(J) Examples
Find the maximum value of f(x) = [ln(x)] x
Find f `(x) if f(x) = log10(3x + 1)10
Find where the function y = ln(x2
1) isincreasing and decreasing
Find the equation of the tangent line to y =
ln(2x1) at x = 1
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(K) Internet Links
Calculus I (Math 2413) - Derivatives -
Derivatives of Exponential and Logarithm
Functions from Paul Dawkins
Visual Calculus - Derivative of Exponential
Function
From pkving
http://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asphttp://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asphttp://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asphttp://archives.math.utk.edu/visual.calculus/2/exp.2/index.htmlhttp://archives.math.utk.edu/visual.calculus/2/exp.2/index.htmlhttp://www.geocities.com/pkving4math2tor4/4_the_elem_transc_func/4_02_03_gen_exp_and_log_func.htmhttp://www.geocities.com/pkving4math2tor4/4_the_elem_transc_func/4_02_03_gen_exp_and_log_func.htmhttp://archives.math.utk.edu/visual.calculus/2/exp.2/index.htmlhttp://archives.math.utk.edu/visual.calculus/2/exp.2/index.htmlhttp://archives.math.utk.edu/visual.calculus/2/exp.2/index.htmlhttp://archives.math.utk.edu/visual.calculus/2/exp.2/index.htmlhttp://archives.math.utk.edu/visual.calculus/2/exp.2/index.htmlhttp://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asphttp://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asphttp://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asphttp://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asphttp://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asphttp://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asphttp://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asphttp://tutorial.math.lamar.edu/AllBrowsers/2413/DiffExpLogFcns.asp -
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(L) Homework
Stewart, 1989, Chap 8.2, p366, Q4-10
Stewart, 1989, Chap 8.4, p384, Q1-7