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RolJ No. .~..................... [Total No. of Pages: 03 Total No. of Questions: 091 B.Tech. (Sem. - 7th/8th) ENVIRONMENTAL ENGINEERING - II SUBJECTCODE: CE - 406" . Paper ID : [A0626] . (Note: Plc[isc fill subject code and paper ID on OMR]' Maximum Marks: 60 Time': 03 Hours Instruction to Candidates: 1) Section - A is Compulsory. 2) Attempt any Four questions from Section - B. . 3) Attempt any Two questions trom Section - C. Section. - A (10 x2= 20) Characteristics of freshwater are not similar to that of septic sewage. Variationsin sewageflow is nece~sarilyconsideredin the design of sewers and treatment plants. Reciproc~til1gpumps offer better performance than centrifugal pumps fo~pumping sewage. Preparing drainage plans before initiating plumbing wprks serves no objectives. - Some appurtenances are compulsory whereas some other appurtenances, are obselete over sewers. Colloidal solids pose less problems for remov~l than suspended solids during sewage treaqnent. Aerobic treatment is common and easier than anaerobic treatment of sewage. Performance of oxidation ponds are majofly influenced by surface area of ponds and also climate changes. ' flow through velocity in gritchamber'is purposefully kept very large. Sample collection for dissolved oxygen estimation .requires sufficient care. M-938 [1859] P. T. O. Q1) a) b) c) d) e) f) g) h) i) j)

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RolJ No. .~.....................

[Total No. of Pages: 03Total No. of Questions: 091

B.Tech. (Sem. - 7th/8th)

ENVIRONMENTAL ENGINEERING -IISUBJECTCODE: CE -406" .

Paper ID : [A0626]. (Note: Plc[isc fill subject code and paper ID on OMR]'

Maximum Marks: 60Time': 03 HoursInstruction to Candidates:

1) Section - A is Compulsory.2) Attempt any Four questions from Section - B. .

3) Attempt any Two questions trom Section - C.

Section. - A(10 x 2 = 20)

Characteristics of freshwater are not similar to that of septic sewage.

Variationsin sewageflow isnece~sarilyconsideredin the designof sewersand treatment plants.

Reciproc~til1gpumps offer better performance than centrifugal pumpsfo~pumping sewage.

Preparing drainage plans before initiating plumbing wprks serves noobjectives. -

Some appurtenances are compulsory whereas some other appurtenances,are obselete over sewers.

Colloidal solids pose less problems for remov~l than suspended solidsduring sewage treaqnent.

Aerobic treatment is common and easier than anaerobic treatment of

sewage.

Performance of oxidation ponds are majofly influenced by surface areaof ponds and also climate changes. '

flow through velocity in gritchamber'is purposefully kept very large.

Sample collection for dissolved oxygen estimation .requires sufficientcare.

M-938 [1859] P.T.O.

Q1)

a)

b)

c)

d)

e)

f)

g)

h)

i)

j)

Section -a(4x 5 = 20)

Q2) State the merits a?d demerits of separate system and combin~d system ofsewerage.

Q3) Discuss the safety equipment employed in rehabilitation of sewers~

Q4) '"" A.main combiued se\ver is to be designed to serve an area of 20 sq. km with" population density 300 persons/hectare. The average rate of sewage flow is

325 Ipcd. The maximum flow is 50 percent in excess of average, together"with rainfall equivalent to 15mm in 24 hours, all of which appears ~snmoff.Det~rmine the capacity of sewer. Taking the maximum "velocityof flow as3 mis, detennine the size of the circular sewer.-

. "

Q5) If the 3 day 25°C BOD of sample of sewage is 225 mg/l, what will be its 5

day 30°C BOD? k20= O.ld-l, temperature coefficient = 1.047.

" t

. Q6) Traps are essential in plumbing work of ~10uses.Explain by sketching twocommon traps.

Section - C(2 x 10 = 20)

Q7) Add notes on the following:

(a) Egg shaped sewer and hydraulically equivale"ntsewer.(b) Sewer corrosion.

Q8) '(a) The a~rage operating data for conventional activated sludge processtreatment is as follows: "

Sewage flow = 60,000 m3/d;Vol. of aeratioll tank = 18,000m3.

Influent BOD = 300 mg/l; Effluent BOD = 25 mg/I.

Mixed liquor suspended solids = 2500 mg/I.Effluent suspended solids = 35 mg/I.

Waste sludge suspended solids = 13,000 mg/I.

Quantity of waste slu~ge = 300 m3/d. ..

M-938 2

(b)

Q9) (a)

M-938

Calculate:

(i) Aeration period in hours.

(ii) Food to microorganism ratio (kg BOD per day/kg MLSS)

(iii) Percent BOD removal.

What do you understand by

(i) Recirculation

(ii) Two stage trickling filters.

(b)

Design a septic tank for a hotel with th~ data.Number of users =: 125

Peak discharge =: 170 litres per minute.

Desludging period =: 1 year.

Distinguish between an oxidation ditch and oxidation pond. .

...++++

II

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