atp education ( sa-i) 2015-16 · atp education ( downloaded from: q3. बहुपद 2x - 3...

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AT www.atpeduca Downloaded from: http://www.atp SUMM गणत/ नधारत समय: 3 घंटे Time Allowed : 3 hours समाय नदश: 1. सभी न अनवाय ह | 2. इस न प म 31 न ह, िजह येक 1 अंक का है; खड-6 3 अंक ह ; तथा खड-11 न 3. इस न प म कोई वकप नहं 4. कैलकुलेटर का योग विजत है | General Instructions: 1. All questions are compulsory. 2. The question paper consists o Section-A comprises of 4 questi marks each; section-C comprise questions of 4 marks each. 3. There is no overall choice in 4. Use of calculator is not permi न संया 1 से 4 तक येक Question numbers 1 to 4 Q1. y = 3 का ाफ कस अ The graph of y = 3 will Q2. 2.739 को के प म यत Express 2.739 in the form TP Education (ATP Model Sample Paper ation.com 2015-16 1 peducation.com/downs.php?id=download&var=smp ATP Model Sample Paper संकलत परा I, 2016 MATIVE ASSESSMENT I, 2016-17 / MATHEMATICS (code-15-00152) का IX / CLASS IX अधकतम अंक Maximum Ma चार खड अ, ब, स तथा म बांटा गया है | खंड-ह िजनम येक के 2 अंक ह; खड-10 न ह िजनम येक के 4 अंक ह | है | . of 31 questions divided into four sections A, B, ions of 1 mark each; section-B comprises of 6 es of 10 questions of 3 marks each; section-D this question paper. itted. खड-अ / SECTION-A 1 अंक का है | carry 1 mark each. के समांतर रेखा है ? l be parallel to which axis? त किजए | rm of . r SA-I) p&ch=10&me=2 : 90 arks : 90 4 न ह िजनम ह िजनम येक के , C and D. questions of 2 comprises of 11

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  • ATP Education (www.atpeducation.com

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    SUMMATIVE

    ग�णत/

    �नधा��रत समय: 3 घंटे

    Time Allowed : 3 hours

    समा$य �नद&श:

    1. सभी ��न अ�नवाय� ह� |

    2. इस ��न प� म� 31 ��न ह�, िज�ह�

    ��येक 1 अंक का है; ख-ड-ब म� 6 12न

    3 अंक ह� ; तथा ख-ड-द म� 11 12न ह� िजनम� ��येक के

    3. इस ��न प� म� कोई #वक%प नह&ं है

    4. कैलकुलेटर का �योग विज.त है |

    General Instructions:

    1. All questions are compulsory.

    2. The question paper consists of

    Section-A comprises of 4 questions

    marks each; section-C comprises of

    questions of 4 marks each.

    3. There is no overall choice in this question paper.

    4. Use of calculator is not permitted.

    ख�ड

    ��न सं�या 1 से 4 तक ��येक ��न

    Question numbers 1 to 4 carry 1 mark each.

    Q1. y = 3 का �ाफ �कस अ के समांतर रेखा

    The graph of y = 3 will be parallel to which axis?

    Q2. 2.739 को �

    � के �प म� �य�त क�िजए

    Express 2.739 in the form of

    ATP Education (ATP Model Sample Paperwww.atpeducation.com 2015-16

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    ATP Model Sample Paper

    संक�लत पर�ा – I, 2016

    SUMMATIVE ASSESSMENT – I, 2016-17

    / MATHEMATICS (code-15-00152)

    क�ा – IX / CLASS – IX

    घंटे अ�धकतम अंक

    hours Maximum Marks

    िज�ह� चार ख,ड. अ, ब, स तथा द म� बांटा गया है | खंड-अ

    12न ह� िजनम� ��येक के 2 अंक ह�; ख,ड-स म� 10 12न ह� िजनम� ��येक के

    ह� िजनम� ��येक के 4 अंक ह� |

    इस ��न प� म� कोई वक"प नह#ं है |

    .

    2. The question paper consists of 31 questions divided into four sections A, B, C

    4 questions of 1 mark each; section-B comprises of 6 questions

    comprises of 10 questions of 3 marks each; section-D

    3. There is no overall choice in this question paper.

    4. Use of calculator is not permitted.

    ख�ड-अ / SECTION-A

    तक ��येक ��न 1 अंक का है |

    Question numbers 1 to 4 carry 1 mark each.

    �ाफ �कस अ के समांतर रेखा है ?

    3 will be parallel to which axis?

    के �प म� �य�त क�िजए |

    in the form of �

    �.

    ATP Model Sample Paper SA-I)

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    अ�धकतम अंक : 90

    Maximum Marks : 90

    म� 4 ��न ह� िजनम�

    ह� िजनम� ��येक के

    sections A, B, C and D.

    6 questions of 2

    D comprises of 11

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    Q3. बहुपद 2x - 3 का श#ुयक $ात क�िजए

    Find the zero of polynomial 2

    Q4. द% गयी आकृ*त PQR म�,

    In the given fig. PQR,

    ��न स�ंया 5 से 10 तक �येक ��न

    Question numbers 5 to 10 carry 2 marks each.

    Q5. उपयु�त सव1स2मका के 3योग से

    Simplify using suitable identity.

    997 × 995

    Q6. एक समबाहु 45भुज का प7रमाप

    का े5फल $ात क�िजए |

    An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 c

    Find the area of the triangle.

    Q7. द% गई आकृ*त म�, AC = XD, AB

    अ2भगहृ%त के 3योग से ;दखाइए �क

    In the given figure, AC = XD, C is the midpoint of AB and D is the midpoint of

    XY. Using Euclid’s axiom show that AB = XY.

    B

    C ·

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    का श ुयक !ात क�िजए |

    Find the zero of polynomial 2x – 3.

    , QPR = 47o तथा PQR = 63o है तो x मान !ात क�िजए

    , QPR = 47o and PQR = 63o, Then find the value of x.

    खड-ब / SECTION-B

    तक ��येक ��न 2 अंक का है |

    Question numbers 5 to 10 carry 2 marks each.

    उपयु�त सव)स*मका के +योग से सरल क�िजए |

    using suitable identity.

    एक समबाहु /0भुज का प2रमाप 30 cm है और इसक� +9येक समान भुजा 12 cm

    An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 c

    the area of the triangle.

    AC = XD, AB का मा

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    Q8. आकृ*त म�, PQR = PRQ

    In figure, PQR = PRQ, then prove that

    Q9. =व>ता7रत �प म� 2ल?खए |

    Write in expanded form.

    (3x – 2y + 5z)2

    Q10. √3 को सं@या रेखा पर दशा1इए

    Show √3 on the number line.

    ��न स�ंया 11 से 20 तक �येक ��न

    Question numbers 11 to 20 carry 3 marks each.

    Q11. दशा1इए �क;

    Show that;

    �� √��

    √� � √�

    √�

    Q12. 1.32� + 0. 35���� को सरलतम 2भ#न के �प म� 2लखये

    Express 1.32� + 0. 35���� as a fraction in simplest form.

    ATP Education (ATP Model Sample Paperwww.atpeducation.com 2015-16

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    PRQ है, तो *सEध क�िजए �क PQS = PRT है |

    PRQ, then prove that PQS = PRT.

    को सGंया रेखा पर दशा)इए |

    on the number line.

    खड-स / SECTION-C

    तक ��येक ��न 3 अंक का है |

    Question numbers 11 to 20 carry 3 marks each.

    √��

    √�� √��

    √� � � 5

    को सरलतम *भ न के �प म� *लखये |

    � as a fraction in simplest form.

    ATP Model Sample Paper SA-I)

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    |

    PRT.

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    Q13. द% गई आकृ*त म�, रेखा XY

    POY = 90° और a : b = 2 : 3

    In the given figure, lines XY and MN intersect at O.

    If POY = 90° and a :

    Q14. सLया=पत क�िजए �क:

    Verify that:

    x3 + y3 + z3 – 3xyz = �

    Q15. 2सNध क�िजए �क समबाहु 45भुज के बराबर भुजाओ ंके सQमुख कोण बराबर होते है

    Prove that the opposite angles of equal side of an isosceles triangle are equal.

    Q16. गुणनखंड क�िजए ;

    Factorise;

    a3 – b3 + 1 + 3ab

    Q17. एक पाक1 चतुभु1ज ABCD के आकार का है

    CD = 5 m और AD = 8 m

    A park, in the shape of a quadrilateral ABCD, has

    BC = 12 m, CD = 5 m and AD = 8 m. How much area does it occupy?

    ATP Education (ATP Model Sample Paperwww.atpeducation.com 2015-16

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    XY तथा MN एक दसुरे को /बदं ुO पर +KतLछेद करते हN

    = 2 : 3 है तो c का मान !ात क�िजए |

    given figure, lines XY and MN intersect at O.

    : b = 2 : 3, find c.

    ��� � � � ����� ��� � �� ��� � �� ���

    *सEध क�िजए �क समबाहु /0भुज के बराबर भुजाओ ंके सPमुख कोण बराबर होते है

    Prove that the opposite angles of equal side of an isosceles triangle are equal.

    के आकार का है, िजसम� C = 90º, AB = 9 m, BC = 12 m,

    AD = 8 m है | इस पाक) का �कतना े0फल है ? देSखए आकृKत

    A park, in the shape of a quadrilateral ABCD, has C = 90º, AB = 9 m,

    CD = 5 m and AD = 8 m. How much area does it occupy?

    A

    B

    C D

    ATP Model Sample Paper SA-I)

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    पर ��त छेद करते ह# | य$द

    %स'ध क�िजए )क समबाहु ��भुज के बराबर भजुाओ ंके स-मुख कोण बराबर होते है |

    Prove that the opposite angles of equal side of an isosceles triangle are equal.

    = 90º, AB = 9 m, BC = 12 m,

    दे0खए आकृ�त,

    = 90º, AB = 9 m,

    CD = 5 m and AD = 8 m. How much area does it occupy?

  • ATP Education (www.atpeducation.com

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    See figure,

    Q18. आकृ*त म�, ;दया है �क AB = CF, EF = BD

    AFE CBD.

    In given figure, given that

    that AFE CBD.

    Q19. P का मान $ात क�िजए य;द

    है |

    Find the value of p, if (x + 2) is the one of factor of

    Q20. द% गई आकृ*त म�, DAC का समN=वभाजक

    AE || BC है |

    In given figure, AE bisects

    ��न स�ंया 21 से 31 तक �येक ��न

    Question numbers 21 to 31 carry 4 marks each.

    Q21. य;द � � √�√�

    √��√� और � �

    If � � √�√�

    √��√� and �

    Q22. य;द �� � �

    � = 47 हो, तो

    ATP Education (ATP Model Sample Paperwww.atpeducation.com 2015-16

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    AB = CF, EF = BD तथा AFE = CBD, तो *सEध क�िजए �क

    In given figure, given that AB = CF, EF = BD and AFE = CBD, then prove

    का मान !ात क�िजए यDद (x + 2), P(x) = 3x3 – 4x2 + 5x + p बहुपद का एक गुणनखंड

    Find the value of p, if (x + 2) is the one of factor of P(x) = 3x3 –

    का समEYवभाजक AE है तथा B = C है तो *सEध क�िजए �क

    AE bisects DAC and B = C, prove that AE || BC.

    खड-द / SECTION-D

    तक ��येक ��न 4 अंक का है |

    Question numbers 21 to 31 carry 4 marks each.

    � √�√

    √�√ है तो a2 + b2 - 5ab का मान !ात क�िजए

    � � √�√

    √�√ , find the value of a2 + b2 - 5ab

    तो � � �

    �� का मान !ात क�िजए |

    A

    E

    D

    B

    C

    A

    B

    D

    E

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    तो %स'ध क�िजए )क

    CBD, then prove

    बहुपद का एक गुणनखंड

    4x2 + 5x + p.

    है तो %स'ध क�िजए )क

    , prove that AE || BC.

    का मान �ात क�िजए |

    5ab.

    C

    F

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    If �� � �

    � = 47 then find the value of

    Q23. द% गई आकृ*त म�, AB = AD,

    |

    In the given figure, AB = AD,

    Q24. य;द (x + 2) बहुपद x3 + 13x

    If (x + 2) is the one of the factor of polynomial x

    its other factors.

    Q25. बहुपदf x3 + 2x2 – 5ax – 7

    =वभािजत करने पर शषेफल R

    $ात क�िजए |

    On dividing polynomials

    and (x – 2) respectively gives remainder R

    value of a.

    Q26. एक खेत समलबं के आकार का है िजसक� समांतर भुजाएँ

    असमांतर भुजाएँ 14 m और 13

    A field is in the shape of a trapezium whose parallel

    The non-parallel sides are 14 m and 13 m. Find the area of the field.

    Q27. गुणनखंड क�िजए;

    Factorise;

    8(a + 1)2 + 2(a + 1)(b + 2)

    A

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    = 47 then find the value of � � �

    ��.

    AB = AD, 1 = 2 और 3 = 4 है | *सEध क�िजए �क

    In the given figure, AB = AD, 1 = 2 and 3 = 4. Prove that AP =

    + 13x2 + 32x + 20 का एक गुणनखडं है तो इसके शषे !ात क�िजए

    is the one of the factor of polynomial x3 + 13x2 + 32x + 20, then find

    7 तथा x3 + ax2 – 12x + 6 ^मश: (x + 1) तथा

    R1 तथा R2 +ाdत होते हN | यDद 2R1 + R2 = 6 हो तो

    polynomials x3 + 2x2 – 5ax – 7 and x3 + ax2 – 12x + 6 by (x + 1)

    2) respectively gives remainder R1 and R2. If 2R1 + R2 = 6 then find the

    एक खेत समलबं के आकार का है िजसक� समांतर भुजाएँ 25 m और 10 m हN

    13 m हN | इस खेत का े0फल !ात क�िजए |

    A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m.

    are 14 m and 13 m. Find the area of the field.

    + 2(a + 1)(b + 2) – 15(b + 2)2

    P

    B

    C

    Q

    D

    1 3 4

    2

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    %स'ध क�िजए )क AP = AQ है

    = AQ

    का एक गुणनखडं है तो इसके शषे �ात क�िजए|

    + 32x + 20, then find

    तथा (x - 2) से

    हो तो a का मान

    12x + 6 by (x + 1)

    = 6 then find the

    ह# | इसक�

    sides are 25 m and 10 m.

    are 14 m and 13 m. Find the area of the field.

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    Q28. द% गई आकृ*त म�, POQ एक रेखा है

    है जो �करण OP तथा OR के बीच ि>थत है

    POS)

    In given figure, POQ is a line. Ray OR is perpendicular to line PQ. OS is another

    ray lying between rays OP and OR. Prove that

    Q29. आकृ*त म�, रेखा l कोण A को समN=वभािजत करती

    BP और BQ कोण A क� भुजाओ ंपर

    (i) APB AQB

    (ii) BP = BQ

    In figure, line l is the bisector of an angle

    BQ are perpendiculars from B

    (i) APB AQB

    (ii) BP = BQ

    Q30. आकृ*त म�, AB और CD चतुभु1ज

    दशा1इए �क A > C और B

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    एक रेखा है | �करण OR रेखा PQ पर लबं है | OS

    के बीच िjथत है | *सEध क�िजए �क ROS = �� (

    In given figure, POQ is a line. Ray OR is perpendicular to line PQ. OS is another

    ray lying between rays OP and OR. Prove that ROS = �

    � (QOS -

    को समEYवभािजत करती है और B रेखा l पर िjथत कोई /बदं ुहै

    क� भुजाओ ंपर B से डाले गए लंब हN | दशा)इए �क

    is the bisector of an angle A and B is any point on

    BQ are perpendiculars from B to the arms of A. Show that:

    चतुभु)ज ABCD के ^मश: सबसे छोटC और बड़ी भुजाएँ हN

    B > D.

    A P

    B

    Q

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    OS एक अEय )करण

    (QOS -

    In given figure, POQ is a line. Ray OR is perpendicular to line PQ. OS is another

    - POS).

    पर िFथत कोई �बदं ुहै |

    point on l. BP and

    सबसे छोटI और बड़ी भजुाएँ ह# |

    l

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    In figure, AB and CD are respectively the smallest and

    quadrilateral ABCD. Show that

    Q31. 2सNध क�िजए �क समबाहु 45भुज के 3Lयेक कोण

    Prove that the each angle of a equilateral triangle is 60

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    and CD are respectively the smallest and longest sides of a

    quadrilateral ABCD. Show that A > C and B > D.

    *सEध क�िजए �क समबाहु /0भुज के +9येक कोण 60o होता है |

    Prove that the each angle of a equilateral triangle is 60o.

    ***(---***----)***

    The Best of Luck

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    longest sides of a