atomic structure
DESCRIPTION
Different models of Atoms and their relavanceTRANSCRIPT
Topic 1Atomic Structure
Bohr’s Model
Theories Of Theories Of Atomic StructureAtomic Structure
Some important Atomic Theories put forth in last two centuries.
• Dalton’s Theory• Thomson Model of Atom• Rutherford model of atom• Bohr Theory• Wave mechanical theory• String Theory
Some Old Models Of Some Old Models Of Atomic StructureAtomic Structure
Dalton ModelAtoms as hard spheres (1808)
Thomson ModelPlum-Pudding Model (1897)
Rutherford ModelNuclear Model (1911)
Bohr ModelDiscrete shells of electron (1913)
• An atomic model should be able to explain the phenomena considered to be related to atomic structure.
Expectations Expectations From An Atomic ModelFrom An Atomic Model
Phenomena Observed By Phenomena Observed By 1910 AD1910 AD
1) Emission of cathode rays by many elements
2) Scattering of (α) alpha particles by thin foil of gold
3) Stability Of An AtomStability Of An Atom• The atom as a whole is electrically neutral with electrons revolving around the
nucleus in various orbits. The centripetal force provided the electrostatic attraction between electrons and the nucleus.
• In spite of Rutherford's atomic model successfully explaining the large angle scattering of a particles and justifying the classifications of elements according to their atomic number in the periodic table, there were certain limitations in this model.
• As the radiating energy of a revolving electron (according to classical electromagnetic theory) continuously decreases the electron should follow a spiral path and fall into the nucleus. So this atomic model could not account for the stability of the atom. The observed spectra of elements cannot be accounted for by the atom model.
4) Emission Spectra Of Elements4) Emission Spectra Of Elements
BohrBohr’’s Postulatess Postulates
i) Electrons revolve in stable discrete orbits E1,E2,E3,E4,…
• Inner orbit corresponds to lower energy• Outer orbits corresponds to higher energy
Cont…
ii) An electron gains energy when it jumps from lower energy orbit to higher energy orbit.
iii) Electron loses energy when it jumps from an outer orbit to inner orbit.
Success Of BohrSuccess Of Bohr’’s Models Model
How does Bohr model explain stability of atom and emission spectra of elements?
Stability of atomic structure:By postulate of Bohr theory electrons occupying
specific allowed, discrete orbits do not lose energy though in the state of accelerated motion. Therefore the question of collapse of atomic structure does not arise.
Cont…
Electronic Excitation Of AtomElectronic Excitation Of Atom
Emission spectrum of an element
Atom of an element is excited by supplying some kind of energy. During this step electron gains energy and is promoted from lower energy level to higher energy level.
The excited atom soon get de-excited. The electron from higher energy level gives away energy and comes down to lower energy level.
E2
E1
Higher energy level
Lower energy level
∆E absorbed
Excitation of atom
E2
E1
Higher energy level
Lower energy level
∆E given out
De-excitation of atom
Additional Features Of Atomic Additional Features Of Atomic Structure Useful In ChemistryStructure Useful In Chemistry
1) Electronic configuration
Electronic orbits have definite capacity to hold electrons given by expression 2n2
(n is the orbit number)
There is a limit on capacity of outermost orbit octet/duplet
2) 32) 3--Dimensional Nature Of Electron Dimensional Nature Of Electron OrbitsOrbits
• Electronic orbits are not planar like planetary orbits. Better word to describe position of electrons around nucleus is ‘shell'. The shells have 3-dimensional shape.
3) Finer Structure Of Shells3) Finer Structure Of Shells
• Electronic shells are made up of subshells which in turn are made up of orbitals.There are different types of orbital depending upon the subshell these are named as s,p,d,f,…
• At this stage it is enough to know thatDifferent orbital have different 3-d shapesEach orbital can accommodate maximum two electrons.Energy of an electron depends upon both the shell number and subshell type.
ValencyValency
• Valency indicates the number of bonds an atom can form.
• Valency is related to number of electrons in outermost shell.
e.g.H2, HCl ,HBr, NaH, LiH, H2O, H2S, Na2O, Na2S
Cont…
ElementElement Electronic Electronic ConfigurationConfiguration
ValencyValency CompoundsCompounds
Li 2,1 1 LiCl,LiH
Na 2,8,1 1 NaCl,NaH,Na2O
Mg 2,8,2 2 MgCl2,Mg(OH)2
Be 2,2 2 BeCl2
Al 2,8,3 3 AlCl3
B 2,3 3 BH3
C 2,4 4 CCl4,,CH4
Si 2,8,4 4 SiCl4, Si(CH3)4
N 2,5 3 NH3,N(CH3),N2O3
P 2,8,5 3 PH3,PCl3
O 2,6 2 H2O,BeO,CO2
S 2,8,6 2 H2S
ElementElement Electronic Electronic ConfigurationConfiguration
ValencyValency CompoundsCompounds
F 2,7 1 HF
Cl 2,8,7 1 HCl
He 2 0 -
Ne 2,8 0 -
Ar 2,8,8 0 -
Topic 2 Modern Periodic TableTopic 2 Modern Periodic Table
• Four blocks s,p,d,f originate from the subshell being filled.
• s,p-blocks : s & p subshell of valence shell (last shell) gets filled.
• d block : subshell of second last shell gets filled.• f block : f subshell of third last shell gets filled
Characteristics Of PeriodsCharacteristics Of Periods
• Period number indicates last shell in electronic configuration.
• 1st Period : 1H, 2 He(1) (2)
• 2nd period :3Li, 4Be, 5B, 6C, 7N, 8O, 9F, 10Ne(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (2,7) (2,8)
• 3rd Period :
11Na, 12Mg, 13Al, 14Si, 15P, 16S, 17Cl, 18Ar(2,8,1) (2,8,2) (2,8,3) (2,8,4) (2,8,5) (2,8,6) (2,8,7) (2,8,8)
Gradual Variation In Properties Along Gradual Variation In Properties Along Second PeriodSecond Period
3Li 4Be 5B 6C 7N 8O 9F 10Ne
Metal/Nonmetal character
Metal Metal Metalloid Nonmetal Nonmetal Nonmetal Nonmetal Nonmetal
ElectropositiveChracter
Elctronegativity Increases
Atomic Radius
Molecular formula of compound
LiH BeH2 BH3 CH4 NH3 H2O HF -
Valency 1 2 3 4 3 2 1 0
Decreases
Decreases
Characteristics Of GroupsCharacteristics Of Groups
• Group number and valency (for s - and p block elements)
1IA
2IIA
13IIIA
14IVA
15VA
16VIA
17VIIA
18Zero
3Li 4Be 5B 6C 7N 8O 9F 10Ne
Valency 1 2 3 4 3 2 1 0
Electronic Configura
tion
2,1 2,2 2,3 2,4 2,5 2,6 2,7 2,8
Similarities and Gradation in Similarities and Gradation in Properties of Elements in a GroupProperties of Elements in a Group
• Similarity : Due to same number of valence electrons
• Gradation : Due to increased atomic radius
Alkali metalsIAIA Atomic Atomic
RadiusRadiusMolecular Molecular FormulaFormulaChloridesChlorides
ElectropositivElectropositive charactere character
Vigour of Vigour of reaction reaction
with waterwith water
3Li LiCl
11Na NaCl
39K KCl
87Rb RbCl
55Cs CsCl
Increases Increases Increases
2M + 2H2O 2MOH + H2 +Energy
HalogensHalogensVIIAVIIA Atomic Atomic
RadiusRadiusMolecular Molecular FormulaFormula
Compound Compound with with
HydrogenHydrogen
ElectronegatiElectronegativityvity
Physical Physical StateState
9F HF
17Cl HCl
35Br HBr
53I HI
85At
Gas
Gas
Liquid
Solid
Increases Decreases
Topic 3Percent Composition Of Elements
In A Compound(1) Theoretical Exercise
Name Symbol Total Mass % Composition
H2O (2 x1) +16 =18
2H 2 x1 = 2 2/18 x 100 = 11.11%
O 16 16/18 x 100 = 88.89%
CO2 12+(2 x 16)=44
C 12 12/44 x 100 = 27.27 %
2O 2 x 16 =32 32/44 x 100 = 72.73%
Carbondioxide
Carbon
Oxygen
Water
Hydrogen
Oxygen
Name Symbol Total mass % composition
CH4 12 + (4 x1)=16
C 12 72/16 x 100 = 75%
4H 4x1=4 4/16 x 100 = 25%
H2S (2 x 1)+32 =34
2H 2 x 1 =2 2/34 x 100 = 5.89%
S 32 32/34 x 100 = 94.11%
Hydrogen Sulphide
Hydrogen
Sulphur
Methane
Carbon
Hydrogen
Name Symbol Total mass % composition
Benzene C6H6 (6 x 12) +(6 x 1) = 78
Hydrogen 6H 6 x 1 = 6 6/78 x 100 = 7.69%
Carbon 6C 6 x 12 = 72 72/78 x100 = 92.30%
2) Applications Of Experimental Values 2) Applications Of Experimental Values Of %Composition Of Elements In Of %Composition Of Elements In
CompoundsCompounds
(a) To find out empirical formula of compound
Hydrocarbon 1 C Hydrocarbon 1 C HH
% composition 75% 25%
Atomic mass 12 1
Relative number of atoms in one molecule
75/12 = 6.25 25/1=25
Proportion of Atoms 6.25/6.25 = 1 25/6.25 = 4
Empirical Formula CH4
Hydrocarbon 2Hydrocarbon 2
Hydrocarbon 2 C H
% composition 92.30% 7.69%
Atomic mass 12 1
Relative number of atoms in one molecule
92.30/12 = 7.69 7.69/1 = 7.69
Proportion of Atoms 7.69/7.69 = 1 7.69/7.69 = 1
Empirical Formula CH
b) To Find Out Molecular Formulab) To Find Out Molecular Formula(If molecular mass is determined by some (If molecular mass is determined by some
method)method)Illustration 1
Consider the hydrocarbon -1 in the above illustration with empirical formula CH4.
• Its molecular mass is determined by some method and found to be 16. Now, empirical formula:CH4Therefore,
• Empirical formula mass =12+ (4 x 1)=16 but, molecular mass = 16
= empirical formula mass. Therefore, Molecular formula = CH4
Illustration 2
Now consider Hydrocarbon-2 having empirical formula CH. The hydrocarbon - 2 has molecular mass = 78.
• Now, empirical formula :CHTherefore,
Empirical formula mass = 12+1 = 13But, molecular mass = 78
= 6 x13= 6 x empirical formula mass
Therefore, molecular formula = 6 x empirical formula= 6 x CH= C6H6
c) To Find Molecular Massc) To Find Molecular Mass(If number of atoms of one of the constituent elements in (If number of atoms of one of the constituent elements in
the molecule is known by some method)the molecule is known by some method)
Compound C Total
A hydrocarbon containing two carbon atoms in the molecule
92.3% 100%
Atomic mass 12 u
Number of atoms in Mass 100 u
92.3/12 = 7.69
Mass containing two carbon atoms
100 x 2/ 7.69 = 26.07 u
Molecular mass 26 u
C2H2 (H C C H)
≅
Compound S Total
An Organic compound containing one sulphur
atom
29.1% 100%
Atomic mass 32
Number of atoms in Mass 100 u
29.1/32 = 0.9093
Mass containing one sulphur atoms
100 x 1/0.909 = 110.02 u
Molecular mass 110 u≅
C6H6S