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1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John Levine, P.E. Levine Lectronics and Lectric E-mail: [email protected] GE Multilin / Instrument Transformers, Inc.

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Page 1: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

1

GE Multilin Instrument Transformers, Inc.

Are you using the right CT's and PT's for your application?

John Levine, P.E.

Levine Lectronics and Lectric

E-mail: [email protected] GE Multilin / Instrument Transformers, Inc.

Page 2: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Alternate Title of Presentation

Now I know what I do not know about CT’s and PT’s.

As engineers we do not need to know all the answers just where to get them.

Page 3: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Current & Voltage Transformer Basics (IEEE Standards)

Page 4: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Agenda

Current Transformers

Voltage Transformers

Required Information for Specifying CTs & VTs

Take Home Rules” for CTs & VTs

Applications where used

Page 5: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Why use Instrument Transformers?

Circuit Isolation

Reduce voltage and currents to reasonable working levels.

Phasor combinations for summing and measuring power

Page 6: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

CURRENT TRANSFORMERS

TYPES OF C.T. CONSTRUCTION

The most common type of C.T. construction is the “DOUGHNUT”

type. It is constructed of an iron toroid, which forms the core of the

transformer, and is wound with secondary turns.

Secondary Winding Primary Conductor

Iron Core

Page 7: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Transformer ratio (TR)

Primary Current

(100 amps)

Secondary Current

(5 amps)

Primary Current

Secondary Current Transformer Ratio = _____________________

100

5

___ = 100:5 or 20:1

Page 8: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Polarity

Direction of Primary Current

Direction of Secondary Current

H1

X1

Primary current into “polarity” =

Secondary current out of “polarity”

P1

IEEE

IEC

Primary Polarity Marks

IEEE IEC S1

Secondary Polarity Marks

Remember:

Page 9: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Polarity

Direction of Primary Current

Direction of Secondary Current

H1

X1

P1

IEEE

IEC

Primary Polarity Marks

IEEE IEC S1

Secondary Polarity Marks

Primary current into “non-polarity” =

Secondary current out of “non-polarity”

Remember:

Page 10: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Generator typical wiring

Page 11: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

What is your application?

If your application is metering , how high do I need to go in current? 2 times ?

If your application is protective relaying, how high do I need to go in current? 20 times ? 40 times ?

Page 12: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

CT Rating Factor (RF) -- IEEE

Rated current x (RF) =

Maximum continuous current carrying capability:

Without exceeding temperature limits

Without loss of published accuracy class

Typical rating factors for Metering CTs are: 1.0, 1.33, 1.5, 2.0, 3.0, 4.0

Page 13: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

0.30

0.30

0.60

0.60

Rating Factor

Ac

cu

rac

y C

lass

- %

CT Rating Factor (RF) -- IEEE

10% 100% 200% 300% 400%

1.0 2.0 3.0 4.0

IEEE C57.13 Accuracy 0.3% @ BX.X RF 4.0

0.3% Accuracy Region

0.6% Accuracy

Region

Page 14: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Short-Time Thermal Current Rating

One (1) – second thermal rating Expressed as value of RMS primary current Main influencing factor: CT primary & secondary wire size Can be converted to thermal rating for any time period (t) up to five (5) seconds: (New RF at new Ambient/Stated RF at 30 degrees C)2=

85-New Ambient/New Ambient Example: CT with rating factor of 4 at 30 degrees = rating factor of 2.95 at 55 degrees X2/42=85-55/55 X=2.95

Page 15: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

CT Metering Accuracy

Actual secondary current

Rated secondary current =

Difference in % is known as the “Accuracy”

of the CT

Page 16: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

IEEE CT Metering Accuracy

Accuracy Class ( * )

Application

0.15 High Accuracy Metering

0.15S “Special” High Accuracy Metering

0.3 Revenue Metering

0.6 Indicating Instruments

1.2 Indicating Instruments

* All accuracy classes defined by IEEE C57.13 or C57.13.6

* Accuracy classes include both ratio & phase angle error

Page 17: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

IEEE CT Metering Accuracy

Burden

Load connected to CT secondary

Includes devices & connecting leads

Expressed in ohms

Standard values = B0.1, B0.2, B0.5, B0.9, B1.8

E0.04, E0.2

All burdens defined by IEEE C57.13 or C57.13.6 for 60 Hz only

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GE Multilin Instrument Transformers, Inc.

Application Burden

Designation

Impedance

(Ohms)

VA @

5 amps

Power

Factor

Metering B0.1 0.1 2.5 0.9

B0.2 0.2 5 0.9

B0.5 0.5 12.5 0.9

B0.9 0.9 22.5 0.9

B1.8 1.8 45 0.9

Standard IEEE CT Burdens (5 Amp) (Per IEEE Std. C57.13-1993 & C57.13.6)

IEEE CT Metering Accuracy

E0.2

E0.04

0.2

0.04

5

1

1.0

1.0

Page 19: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

A current transformer for metering purposes may

typically have an accuracy of 0.3%. The C.T. must

maintain this accuracy for normal load currents,

provided the rated burden on the C.T. is not exceeded.

It is quite acceptable, and in fact desirable, for the C.T.

to saturate when fault current flows. The accuracy for a

typical metering C.T. is specified as:

0.3 M 0.9

O.3% METERING O.9 OHMS BURDEN

This metering C.T. has an accuracy of 0.3% when the

connected burden does not exceed 0.9 OHMS.

CT CLASSIFICATION for Metering

Page 20: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

IEEE CT Metering Accuracy

Accuracy Class (0.3, 0.6, 1.2) (*)

Burden (Ohms) (B0.1, B0.2, B0.5, B0.9, B1.8)

+

“Accuracy” expressed as:

0.3B0.2 0.6B0.9 1.2B1.8

0.15E0.2

=

Typical Examples

* Accuracy class is stated at 100% rated current * At 10% rated current, twice the error is allowed (5% for 0.15 class)

(0.15*, 0.15S^) E0.2, E0.04)

^ Accuracy class is stated at 100% to 5% rated current

Page 21: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

0.30

0.30

0.60

0.60

Rating Factor

Ac

cu

rac

y C

lass

- %

10% 200% 300%

1.0 2.0 3.0 4.0

IEEE C57.13 Accuracy 0.3 @ BX.X; RF 4.0

0.3% Accuracy Region

0.6% Accuracy

Region

IEEE CT Metering Accuracy

100% 400%

No accuracy guaranteed at current levels less than 10%

Page 22: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

IEEE CT Metering Accuracy

Corrected to 0.3% Class

CT Parallelogram – IEEE C57.13 0.3 class parallelogram

0.6 class parallelogram

100%

10%

Note:

Burden must be specified

Page 23: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

IEEE CT Relay Accuracy Protection CT

Standard Relay Accuracy Classes

C or T100

C or T200

C or T400

C or T800

What do these mean?

Page 24: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

IEEE CT Relay Accuracy

Relay class (C or T___ ) designates minimum secondary terminal volts…

At 20 times rated current

Without exceeding 10% ratio error

Into a maximum specified burden

Now that everyone is totally confused let’s look at some simple examples …

Page 25: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

T = Determined by test

CT CLASSIFICATION for RELAYING

10 C 400

Protection Class CT’s - Must supply 20 times rated current

C = Calculated

K = Calculated L = Low internal secondary impedance

H = High internal secondary impedance

Format

Letter Accuracy Voltage at 20 times CT

Page 26: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Primary current 24,000 amps

(20 x 1200)

IEEE CT Relay Accuracy

CT 1200:5

C or T100

X1 X2

Burden of Devices ()

Burden of Leads ()

Secondary current 100 amps (20 x 5)

Total Ext Burden 1.0

C or T100 example

Terminal Volts = (20 times rated) (Total external burden)

100 Volts = (100 amps) (1.0 )

Te

rmin

al V

olt

s =

10

0

Page 27: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Primary current 24,000 amps

(20 x 1200)

IEEE CT Relay Accuracy

CT 1200:5

C or T200

X1 X2

Burden of Devices ()

Burden of Leads ()

Secondary current 100 amps (20 x 5)

Total Ext Burden 2.0

C or T200 example

Terminal volts = (20 times rated) (Total external burden)

200 Volts = (100 amps) (2.0 )

Te

rmin

al V

olt

s =

20

0

Page 28: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Standard IEEE CT Burdens (5 Amp) (Per IEEE Std. C57.13-1993)

IEEE CT Relay Accuracy

Application Burden

Designation

Impedance

(Ohms)

VA @

5 amps

Power

Factor

Relaying B1 1 25 0.5

B2 2 50 0.5

B4 4 100 0.5

B8 8 200 0.5

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GE Multilin Instrument Transformers, Inc.

IEEE CT Relay Accuracy Excitation curve includes voltage required to overcome internal resistance (DCR) of CT. Approximately 32 volts.

10% ratio error = (20 x 5) (10%) = (100) (0.10) = 10 amps

How many terminal volts would you estimate this CT can produce?

Page 30: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

1000:5 CT

1000 Amps 5amps

IE<0.5amps

IB >4.5

amps

With 10% error, IB is anywhere from 4.5 to 5.5 amps

Most Protection CT’s also have a Metering CT accuracy so you could use this value for calculating the error at lower

currents

Page 31: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

CT Burden Calculation

Primary Current

CT

X1 X2

Burden of Devices ()

Burden of Leads ()

Secondary current

Total Burden ZT

How do we calculate this?

Page 32: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

CT Burden Calculation

Assumption: 3 phase CTs are “Y” connected

ZT = RCT + RL + ZB ZT = Total burden in ohms (vector summation of resistance and inductance components)

RCT = CT secondary resistance in ohms @75 deg C (DCR)

RL = Resistance of leads in ohms (Total loop distance)

ZB = Device impedance in ohms

Page 33: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

GE Multilin Electronic Relay Burden

VA = VI. V= IR, So 0.2 = I*I*R.

.2/25 = .008 ohms

Page 34: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

100:5 C.T. Secondary Winding Resistance (DCR) = .062 ohm

Resistance of Cable from C.T. to Relay and back = .1 ohms

Resistance of Relay Coil = .02 ohms

Total Resistance = .182 ohms

If we have a fault of 2,000 amps and the C.T. ratio is 100:5 then the C.T.

secondary current is 100 amps. Therefore we will produce a voltage of 100

amps x .182 ohms = 18.2 Volts. To prevent CT saturation, select a CT with a

knee point above 18.2 Volts.

.062

.1

.02

Page 35: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

780-102 is a 1000 to 5 CT, Class C100

1000:5 C.T. Secondary Winding Resistance (DCR) = .32 ohm

Resistance of Cable from C.T. to Relay and back = .1 ohms

Resistance of Relay Coil = .008 ohms

Total Resistance = .428 ohms

If we have a fault of 20,000 amps and the C.T. ratio is 1000:5 then the C.T.

secondary current is 100 amps. Therefore we will produce a voltage of 100

amps x .428 ohms = 42.8 Volts. To prevent CT saturation, select a CT with a

knee point above 42.8 Volts.

What happens if the fault current is 40,000 amps?

.32

.1

.008

Page 36: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Factors Influencing CT Accuracy

Frequency

Current Ratio

Burden

“Low frequency” and “High accuracy” are not friends!!

“Low ratio” and “high accuracy” are not friends!!

“High burden” and “High Accuracy” are not friends!!

Page 37: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

CT Saturation

What is CT Saturation?

Page 38: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Power Systems Relay Committee (PSRC) Saturation Calculator

Page 39: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Factors Affecting Degree of Saturation and Time to Saturation

DC Offset

Fault Magnitude (symmetrical current) •100 to 5 CT@20 times= 2000 amps, at 20,000 amps we have 200 times CT

CT Turns Ratio

Secondary Burden

CT Accuracy

Remanence Flux • Can occur if current interrupted when core is saturated

• If DC flows in windings during testing

• Need a voltage above 60% of knee point to reduce the remanence to less than 10% of saturation flux density.

Page 40: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Tips for Avoiding CT Saturation

Use higher ratio CTs

Use separate set of high ratio CTs for high fault current tripping

Reduce secondary burden Select low burden relays & meters Distribute single phase burdens among phases Increase size of secondary leads Reduce length of secondary leads

Use “step down” auxiliary CTs

Page 41: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Potential Transformers

Page 42: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

Definitions

Voltage Transformer (VT)

An instrument transformer used to reflect a primary voltage into a secondary voltage through a magnetic medium. Always connected in parallel with primary conductor across a circuit load.

Secondary (measuring) voltage is usually 115 or 120 volts nominally. The secondary voltage level is selected for ease of measurement and safety.

Control Power Transformer (CPT)

Designed to provide power for contractors, relays and devices with high inrush currents, Regulation is not as critical.

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GE Multilin Instrument Transformers, Inc.

Page 44: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

POTENTIAL TRANSFORMERS

VP

Vs

Relay

14,400/120 = 120/1

4200/120 = 35/1

2400/120 = 20/1

Page 45: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

IEEE VT Accuracy Class

Metering Accuracy Classes (% error)

0.3

0.6

1.2

0.15

Defined by IEEE C57.13

Applicable from 90% to 110% rated voltage

Defined by IEEE C57.13.6

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GE Multilin Instrument Transformers, Inc.

IEEE VT Accuracy Class

These standard burden designations have no significance

at frequencies other than 60 Hz.

Burden VA PF

W 12.5 0.10

X 25 0.70

M 35 0.20

Y 75 0.85

Z 200 0.85

ZZ 400 0.85

Metering Accuracy Class Burdens

Page 47: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

IEEE VT Accuracy Class

Expressed as:

Accuracy Class + Burden Code

0.3 W,X,Y 0.6 Z

1.2 ZZ

These standard designations have no significance at frequencies other than 60 Hz.

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GE Multilin Instrument Transformers, Inc.

Page 49: Are you using the right CT's and PT's for your application? · PDF file1 GE Multilin Instrument Transformers, Inc. Are you using the right CT's and PT's for your application? John

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GE Multilin Instrument Transformers, Inc.

VT Installation Guidelines Caution:

Rated voltage: Do not operate above 110%

Line to ground rated:

Do not connect line to line

Do not use on ungrounded systems w/o consulting factory

Rated Frequency: Do not operate below rated frequency w/o consulting factory

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GE Multilin Instrument Transformers, Inc.

IEEE VT Groups VT

Group No. of

Bushing Connection

Method

Neutral Grounding

Notes

1 2 open

Y-Y possible

Any Withstand 25% over rated voltage on an emergency basis

2 2 open

Y-Y possible

Any Withstand 10% over rated voltage continuously. Primary rated for line to line voltage.

3 1 Y-Y-Y Any Outdoor, two secondary windings. Withstand 10% over rated voltage continuously.

4A 1 Y-Y Effectively Withstand 10% over rated voltage continuously & 25% on an emergency basis. For operation at 100% rated voltage.

4B 1 Y-Y

Y-Broken Corner

Non-effectively

Withstand 10% overvoltage continuously. For operation at 58% rated voltage.

5 1 Y-Y Effectively Outdoor. Withstand 40% over rated voltage for 1 minute and 10% over rated voltage continuously

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GE Multilin Instrument Transformers, Inc.

VT Typical Connections

Open Delta Connection (2) Double Bushing VTs

Y – Y Connection (3) Single Bushing VTs

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GE Multilin Instrument Transformers, Inc.

Required Information for Specifying CTs & VTs

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GE Multilin Instrument Transformers, Inc.

Current Transformer (CT) RFQ Specification

Environment: ___Indoor ___Outdoor

System Voltage (kV)

0.6

0.72

3.6

5.0

7.2

8.7

12

15

24

25

34.5

34.5

Power Frequency (kV)

4

3

10

19

20

26

28

34

50

40

70

70

BIL (kV)

10

40

60

60

75

75

110

125

125

150

200

Standard (Check one)

IEEE __

IEC __

IEC __

IEEE __

IEC __

IEEE __

IEC __

IEEE __

IEC __

IEEE __

IEEE __

IEEE __

CT Application: ___Metering ___Protection

Dimensions: ___ Inches ___ mm

Max. Outside: L ______ x W ______ x D ______

CT Window: Round: ______ Diameter; Rectangular: L ______ x W ______ ; Primary Bar: _____

Current Ratio: _______ : 5 _______ : 1

Continued next slide

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GE Multilin Instrument Transformers, Inc.

Current Transformer (CT) RFQ Specification (Continued) Accuracy:

Indication Only: _____ %, _____VA (Skip metering & protection selections)

Metering Class:

IEEE: ___0.3 ___0.6 ___1.2 ___2.4 ________Other

IEC: ___0.2 ___0.5 ___1.0 ________Other

Metering Burden:

IEEE (Ohms): ___B0.1 ___B0.2 ___B0.5 ___B0.9 ___B1.8 ______Other

IEC (VA): ___2.5 ___5.0 ___10 ___15 ___30 ______Other

Protection Class: C______(IEEE) ___VA, ___P___(IEC)

Operating Frequency: ___60HZ ___50HZ

Rating Factor: ___1.0 ___1.33 ___1.5 ___2.0 ______Other

Secondary Connections: ___Terminals ___24 inch leads

Outer Insulation: ___Standard ___Cotton tape & varnish ___Polyester tape

Insulation Class: ___105 0C (Standard) _____Other

Other Special Requirements (dimensional constraints, mounting requirements, …etc):

______________________________________________________________________________

______________________________________________________________________________

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Voltage Transformer (VT) RFQ Specification

Environment: ___Indoor ___Outdoor

System Voltage (kV)

0.6

0.72

3.6

5.0

7.2

8.7

12

15

24

25

34.5

34.5

Power Frequency (kV)

4

3

10

19

20

26

28

34

50

40

70

70

BIL (kV)

10

40

60

60

75

75

110

125

125

150

200

Standard (Check one)

IEEE __

IEC __

IEC __

IEEE __

IEC __

IEEE __

IEC __

IEEE __

IEC __

IEEE __

IEEE __

IEEE __

Continued next slide

Operating Frequency: ___60HZ ___50HZ

Accuracy:

IEEE: ___W ___X ___M ___Y ___Z ___ZZ ________Other

(Enter 0.3, 0.6, 1.2, or leave blank)

IEC: ___10VA ___25VA ___50VA ___100VA ___200VA ___500VA ______Other

(Enter 0.2, 0.5, 1.0, or leave blank)

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Voltage Transformer (VT) RFQ Specification (Continued)

Thermal Rating: _______VA (Optional)

Primary Voltage: ___1 bushing _________VAC - Phase to neutral

___2 bushing _________VAC - Phase to phase

Secondary Voltage: ___120V ___115V ___110V ___100V

___120/3 ___115/3 ___110/3 ___100/3 ___Other _________________

Rated Voltage Factor (RVF) (1 bushing only): ___1.9 for 30s ___1.9 for 8 hours ___Other____________

Fuses:

___Primary ___Secondary ___None (600 – 720 V)

___Primary ___Live parts only ___Switchgear Style ___Unfused (2.5kV – 15kV)

Note integral fusing not available above 15kV

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Take Home Rule # 1

CTs are intended to be proportional current devices. Very high voltages can result from open circuiting the secondary circuit of an energized CT. Even very small primary currents can cause damage… Consult the factory if you have questions.

Never open circuit a current transformer secondary while the primary is energized

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Never short circuit the secondary of an energized VT

Take Home Rule # 2

VTs are intended to be used as proportional voltage

devices. Damaging current will result from short

circuiting the secondary circuit of an energized VT.

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Take Home Rule # 3

Metering applications do not require a “C” class CT

“C” class ratings are specified for protection purposes only. With some exceptions metering class CTs are typically smaller and less expensive.

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Take Home Rule # 4

CT secondary leads must be added to the CT burden

Electronic relays usually represent very little burden to the CT secondary circuit. In many cases the major burden is caused by the CT secondary leads.

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Take Home Rule # 5

Never use a 60 Hz rated VT on a 50 Hz System

60 Hz VTs may saturate at lower frequencies and exceed temperature limitations. VT failure is likely…severe equipment damage is possible.

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Take Home Rule # 6

Exercise caution when connecting grounded VTs to ungrounded systems

Line to ground voltage on any VT may exceed the primary voltage rating during a fault condition… VT must be designed for application.

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Take Home Rule # 7

It is common practice to apply 600 Volt CT to systems with higher voltages.

This practice is done by passing fully insulated conductors through the Window.

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QUESTIONS?

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LV Switchboards LV Panelboards

5 Series

8SHT 19RT

Typical CT Models

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LV Switchboards LV Panelboards

Typical VT Models

460, 467, 475, 2VT460, 3VT460

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L.V. MCC’s

8SHT

19RT

5 Series

3P85

Typical CT Models

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L.V. Switchgear

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L.V. Switchgear Current Transformers GE 2000 amp frame Model 560 Metering Model 561 Protection

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Current Transformers GE 4000 amp frame Model 562 Metering Model 563 Protection

L.V. Switchgear

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L.V. Switchgear

No more room in the front? We can recommend a different model CT for the rear bus area.

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L.V. Switchgear Typical 3 Phase VT Installation

3VTL460 3 Phase VT

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M.V. Switchgear

Typical Line Up

Where are the CTs,

VTs, and CPTs?

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Current Transformers 778 / 779 680 /780 Series Typical IEEE Metering & Protection

M.V. Switchgear

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M.V. Switchgear Current Transformers Metering & Protection

Model 780, 778

Model 785

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M.V. Switchgear

Model 203 CTs mounted in rear bus compartment

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M.V. Switchgear

Zero Sequence CT Model 593, 594

Is this better than a Residual Connection?

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M.V. Switchgear Typical VT Rollout Drawer

Installed in enclosure

Withdrawn from enclosure

(2) PTG5’s in open delta configuration

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M.V. Switchgear Typical CPT Rollout Drawer

Installed in enclosure Withdrawn from enclosure

CPT 5 & 15 kV 5 to 15 kVA

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MV MCC’s

Let’s open a door and see what’s inside

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MV MCC’s

Typical CT Models 112 113 114 115 117

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Generators

Board Mounted Generator CT

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Station Class Circuit Breakers

Polyester Taped Bushing CT on Outdoor Circuit Breaker

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Station Class Circuit Breakers

Outdoor BO7 - Replaces BCT’s in shielded aluminum housing

Ground Shield

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Outdoor Type BO7 for Retrofit

Power Transformers Slip over current transformer for installation over exterior of outdoor bushing

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Power Transformers Metering applications for indoor instrument transformers on outdoor power transformers

Air terminal chamber Indoor PT and Bar type CT

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Questions?