application equipment and calibration g. s. manual - chap. 7 workbook - pp. 22-26 application...

Application Equipment and Calibration

G. S. Manual - Chap. 7Workbook - pp. 22-26

Application Calibration & Calculations

1998-99


Calibrating The Sprayer:Selecting Nozzle Size

Variables

1. Nozzle flow rate (GPM)

2. Ground speed (MPH)

3. Effective sprayed width (W)-inches

4. Application rate (GPA)


Measuring Ground Speed

Speed(MPH)Distance(ft) x 60

Time(seconds) x 88

Where 1 MPH = traveling 88 feet in 60

seconds


Application Rate Equation

GPAGPM X 5940

MPH X W

Equation # 1

• Calculates for application rate

• Represents total amount applied for an acre

• Calculates for application rate

• Represents total amount applied for an acre


Flow Rate Equation

GPMGPA x MPH x W

5940

Equation # 2

• Calculates for amount of flow from one nozzle

• Represents the size of nozzle to put on the sprayer

• Calculates for amount of flow from one nozzle

• Represents the size of nozzle to put on the sprayer


Where: gallons per acre

gallons per minute

miles per hour

GPA = ______________________

GPM = ______________________

MPH = ______________________

W = ______________________nozzle spacing - inches

5940 = a constant to convert gallons per minute, miles per hour,

and inches to gallons per acre

5940 = a constant to convert gallons per minute, miles per hour,

and inches to gallons per acre


Affect of variables on rate:

• Pressure • Pressure

How would the listed variables be adjusted to double the flow in gallons per minute from a spray nozzle or to double the application rate in gallons per acre?

Decrease by 1/2 (GPA)Decrease by 1/2 (GPA)

• Nozzle spacing • Nozzle spacing

Increase 4 times (GPM) Increase 4 times (GPM)

• Travel speed • Travel speed

Decrease by 1/2 (GPA)Decrease by 1/2 (GPA)


1. Select application ratefrom the label

2. Select an appropriate ground speed

3. Determine effective sprayed width

4. Determine the flow rate required

5. Select nozzle that will give the required flow rate

6. Convert flow rate from GPM to OPM

7. Collect the output from one or all nozzles

8. Determine the amount of pesticide needed - label

9. Operate the sprayer at speed from step 2

10. Check flow frequently- compare all nozzles

Calibration Steps:


Calculations

GPA=

5940

#$!@&%!#$!@&%!


4. Determining MPH Example #1:A sprayer takes 22 seconds for the first pass

and 24 seconds for the return pass to travel a measured course of 200 feet, what is the speed in MPH?

Speed(MPH)Distance(ft) x 60

Time(seconds) x 88

MPH= 88 X

60 X = SPEED

NDS SECO= 2

+ = TIME AVERAGE22 24

200

23

23

5.9


5. GPA Example #2:

• Your sprayer is set up with flat fan nozzles spaced at 20-inches and have a measured flow rate of .51 gpm at 35 psi. What would be the application rate when using these nozzles at 35 psi traveling 7 MPH?

• Which equation should you use?

• To calculate for application rate or flow rate?

Application Rate


GPA Example Solution:

GPA=?

GPAGPM X 5940

MPH X W

GPM=? MPH=? W=?GPA=? GPM=.51 MPH=7 W=20


GPA.51 X 5940

7 X 20


GPAGPM X 5940

MPH X W

Answer 21.6


6. GPM Example #3:

• You want to broadcast a soil applied herbicide at 15 GPA traveling 7 MPH using flooding nozzles on 40-inch spacing.

• Which equation should you use?

• To calculate for application rate or flow rate?

Flow Rate



GPM=? GPA=? MPH=? W=?GPM=? GPA=15 MPH=7 W=40

GPMGPA x MPH x W

5940


GPM Example Solution:

GPMGPA x MPH x W

5940

GPM15 x 7 x 40

5940

Answer .71


MIXING PROCEDURE

THE RECOMMENDED APPLICATION RATE OF A PESTICIDE IS GIVEN AS:

• Active ingredient (a.i.)

• Product or Formulation


MIXING PROCEDURE



• Product or Formulation

needs adjustment!


MIXING PROCEDURE:



• Product or Formulationready

to use!


8A.Dry Ingredient example #4:A recommendation of 2 lb. active ingredient

(a.i.) per acre is given for benefluralin. The sprayer has a 400-gallon tank and is calibrated to apply 75 GPA. Determine the amount of Balan 60DF to be added to the tank.

key word - active ingredient (a.i.)

How many acres per tank?

How much product per acre?

How much product per tank?


Acres / Tankful400 gal

75gpa5.3acres

2lbs./Acre100%60%

3.3lbs.

Answer

Dry ingredient example solution:

5.3 A/tank X 3.3 lbs. product/A = 17.5 lbs


8B. Liquid ingredient example #5:An applicator needs to apply a broadleaf herbicide using a 400 gallon sprayer at a rate of 2 pounds (a.i.) active ingredient per acre. A 4EC material will be used. With a calibrated rate of 20 gallons per acre - how much herbicide will be needed to be added to the spray tank?

key word - (a.i.)How many acres per tank?

How much product per acre?

How much product per tank?


Acres / Tankful400 gal

20 gpa20 acres

Liquid a.i. example solution:

Lbs.product / Albs a.i. recommended

lbs. a.i. purchased24

0.5 gpa

Answer

20 A/tank X 0.5 gpa product/A = 10 gal.


8C. Liquid formulation example #6:

You are to spray a 4EC herbicide to a 5 acreturf area. The rate to apply is 1.5 quarts formulation in 20 gallons of water per acre.

How much herbicide should be added to the tank?

keyword - formulation

Size of area? 5 acres


Solution:

What is the rate?

1.5 quarts/acre

1.5 quarts x 5 acres = 7.5 quarts


8D. Liquid formulation/area - #7:You have a product which is a 4E and

recommended at the rate of 3.2 qts. per acre. How much of this product is needed to treat an area measuring 250 ft. by 575 ft.?

_____ ft. X _____ ft. = ________ square feet_____ ft. X _____ ft. = ________ square feet250 575 143,750

es_______acr ft/a sq 43,560

ft sq 143,750

3.3

________ acres X 3.2 qts. =3.3 ______ qts10.56


Good Luck on Your Test!

Click to return to menu

End of module

application equipment and calibration g. s. manual - chap. 7 workbook - pp. 22-26 application...

Documents