answer scheme science form 4 paper 2...
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ANSWER SCHEME SCIENCE FORM 4 PAPER 2 2010
1. (a) 7,8,4,6
(b)
(c) Type of variation is discontinuous variation
2 (a) 102oC(b) Impurities in the water increase the boiling point.(c) (i) Manipulated variable: Type of water
(ii) Responding variable: Boiling point of the water(d) Distilled water is a substance that boiled at 100 oC
4 (a)
Number of pupils
Group of thumb printsCurve Loop Whorl Composite
10
8
6
4
2
0
Weight/Berat badan / kg
41 - 45 46 - 50 51 - 55 56 - 60 61 - 65 66 - 70 71 - 75 76 - 80
Number of students/Bilangan
pelajar1 3 5 6 6 3 4 2
Correct 4 hingga 7 1 m All correct- 2 m
(b)
Transfer all points corrrectly – 1 m Bar chart has th – 1 m
(c) Continous variation/Variasi selanjar. 1 m
Total 5 m
40 45 50 55 60 65 70 75 80 85
Number of student/Bilanganpelajar
6
5
4
3
2
1
5 (a) P : Cell body Q : EffectorsR : Receptor
(b) Muscle contract
(c) (i) Reflex action (ii) Spinal Cord
6. (a) (i) R : Thyroid
(ii) Low metabolism rate // Physical retardation // Mental retardation
(b) (i) S : Testis
(ii) To control the secondary sexual characteristics of male
(c) (i) Excessive secretion of growth hormone
(ii) Pituitary gland
7 (a) Voluntary action (b) (i)
(ii) Cerebrum
(c) (i) Sensory neurone(ii) Muscle // leg
(d) The student cannot kick the ball
8 (a) discontinuous variation (b) the ability to roll the tongue @ thumb prints @ blood group @ hair type (c) genetic factor (d)
(e) free ear lobes
9 (a) Q : Boy/male (lelaki)
Tt Tt Tt Tt
R : Boy/male (lelaki)2m(b) Fertilization (Persenyawaan)1 m(c) (i) Identical twins (Kembar seiras)1 m
(ii) One ovum is fertilized by one sperm (to form one zygote)// 1m
the zygote formed splits into two(Satu ovum disenyawakan oleh satu sperma (dan membentuk satu zigot)// Zigot yang terbentuk membahagi dua)
(d) Siamese twins is formed (Kembar Siam terbentuk)1 m
10 (a) As the mass increases, the oscillation period increases.1 m
(b) (i) Aim : To study the relationship between the mass of load with the oscillation period
1 m
(ii) Manipulated variable : mass of loadResponding variable : oscillation period Fixed variable : length of string / swing force / swing angle (any two)
2 m
(iii) Apparatus / material:500 g and100 g loads, string, retort stand (2 stop watch)
1 m
(vi) Procedure:1. Hang the 500g load to the retort stand.
1 m2. Swing the load and state the time until the load
stops swinging.1 m
3. Repeat steps 1 and 2 for 100 g load1 m
(v)Mass of load(g) Oscillation period
500100
1 m
(vi) Hypothesis is accepted // if the mass of the load increases, the oscillation period also increases.// other suitable hypothesis.
1 m
Total 10 m
11 (a) Able to state 2 parts of brainAnswer:Cerebrum , cerebellum , medula oblongata (any two) 2 m
Parts of brain Main fuctionCerebrum Control controlled actions Cerebellum Control body balance Medula oblongata Control uncontrolled actions
(Any two correct pairs)2 m
Total 4 m
b) Able to show steps in developing concept Identify two identical characteristics
2 m Develop early concept
1 m Give another example
1 mand non-example 1 m
Explain the real concept 1 m