announcements homework set 1 is due today homework set 2: chapter 2 # 45, 46, 50, 52, 53 & 54...
TRANSCRIPT
Announcements•Homework Set 1 is due today
•Homework set 2: Chapter 2 # 45, 46, 50, 52, 53 & 54
•Use Exam Formula Sheet as you do the homework to familiarize yourself with where things are on it.
Hint for homework problems # 52, 53 & 54
Terrestrial CoordinatesLongitude is measured CCW (+) or CW (-) around from Greenwich England
Latitude is measured North or South of the equator
Both are measured in degrees, minutes and seconds
Celestial CoordinatesThe angle between the celestial equator and the ecliptic is 23.5°
Right Ascension (RA) is measured CCW from the Vernal Equinox and is in hours, minutes and seconds
Declination (Dec) is measured above (+) or below (-) the celestial equator and is in degrees, minutes and seconds
See Appendix A6 for more on celestial coordinates
Finding the CE and NCP at your latitude
Altitude of NCP above due north horizon along the meridian is just f, your latitude (+ for north, - for south)Altitude of the celestial equator above due south horizon along the meridian is 90°-f
ExampleChapter 2 problem # 43: The Moon’s orbit is tilted by about 5° relative to the Earth’s orbit around the Sun. What is the highest altitude in the sky that the Moon can reach, as seen in Philadelphia (latitude 40° North)?
Example SolutionWhat is being asked?...Maximum altitude of the Moon from 40° North latitude.
What information is given?...latitude = 40° N
Tilt angle of Moon from ecliptic = 5°Tilt angle of ecliptic from celestial
equator = 23.5°
Example Solution 2Equation(s) to use: Refer to diagram two slides back. The altitude of the celestial equator above the local horizon is 90° - Latitude
CE = 90° - 40° = 50°
Maximum altitude of Ecliptic = CE + 23.5° = 50° + 23.5° =
73.5°
Maximum altitude of Moon = EclipticMax + 5°
= 73.5° + 5° = 78.5°
Time and AstronomyThe 24 Hour Day?
One rotation of Earth = 1 sidereal day
23 hours 56 minutes 4.091 secondsThis is the time required for the
Earth to complete one rotation with respect to the fixed stars
As the Earth rotates it also moves around
the Sun.
So, for the Sun to return to the same place in the sky the Earth must rotate a little more than one complete rotation
Noon–to–noon isn’t always 24 hours
The Mean Solar Day is exactly 24 hours. It is the time between meridian transits of the Sun averaged over four years
The Year
1 orbit around the Sun = 365.2564 days The sidereal year
1 Tropical Year = 365.2422 mean solar days The time from Vernal equinox to Vernal equinox
Pope Gregory XIII’s CalendarThe Gregorian Calendar (1582)
Most years have 365 days
Years evenly divisible by 4 have 366 days except century years.
Only century years evenly divisible by 400 are leap years
Precession of the Equinox
Like a spinning gyroscope, the Earth precesses. The period of the precession is 25,920 years
The Precession of the Equinox leads to a shift of the celestial
pole
It also shifts the constellations of the zodiac
The Lunar CycleSidereal versus Synodic
The sidereal period is
the orbital period with respect to the “fixed”
stars: 27.32166
days
The Synodic period is the length of the cycle of phases
29.530589 days
Since the angular size of the Sun and Moon are almost the
same, eclipses occur
The Saros Cycle is an eclipse cycle
223 Synodic Months or 18 years 11.3213 days
The Saros Cycle is the repetition cycle of eclipse