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Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

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Page 1: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Announcements

Course Evaluations

Final is Wednesday Afternoon on May 9th

Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Page 2: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Course Evaluations

Request from ThelmoRequest from Thelmo “Teaching is a complex endeavor, capable of an almost

infinite variety of successful expressions, and thus, success as a teacher cannot be judged by any one criterion or through one single mechanism.”

Consider the many facets of the learning environment over the course of whole semester

How will your feedback be used?How will your feedback be used? Read by me to evaluate which aspects of the course most

contribute to student learning formative

Read by PSC as part of faculty’s permanent file to evaluate faculty for promotion and tenure

summative

Page 3: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Concentration Concentration dependency of Edependency of E

Page 4: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Concentration Dependency of E

Eo values are based on standard conditions. The E value will vary if any of the concentration vary

from standard conditions Theoretically

Predicted by the Nernst Equation

Page 5: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

The Nernst Equation

The Nernst Equation

For aA + ne- bB

Qn

VEE o log

05916.0

aA

bBo

n

VEE

AA

log05916.0

Page 6: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Example Equilibrium constant and Eo

Find the equilibrium constant for the reaction

Cu (s) + 2Fe3+ 2Fe2+ + Cu2+

Page 7: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Example

Find the voltage of the cell Half reaction

Ag (s) into a solution of 0.50 M AgNO3 (aq)

The other half-reactionCd (s) is immersed into a 0.010 M Cd(NO3)2 (aq)

Metals are connected by wires Solution connected with salt bridge

Page 8: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

0.50 M AgNO0.50 M AgNO330.010 M Cd(NO0.010 M Cd(NO33))22

Find the voltage of the cell

Page 9: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Potentiometric Methods

Page 10: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Potentiometric Methods

Basis of Method The difference b/w the E (not Eo) values for two

halves of a cell give rise to Eoverall.,

If one half reaction is known and held constant, we can measure the concentration of species on the other side!!!

Page 11: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

ReferenceReference

Indicating Indicating electrode – electrode – The part of the cell The part of the cell that contains the that contains the solutions we are solutions we are interested in interested in measuringmeasuring

Page 12: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Electrodes The previous cell would

be difficult to use for many systems. We would like something

that can be placed in the solution we wish to measure

The electrodes in the following slides have that goal in mind but THEY STILL represent a

complete electrochemical cell when used

Page 13: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Reference Electrodes

Ag/AgCl

Page 14: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Reference Electrodes

Calomel Electrode (SCE) Very Common Hg|Hg2Cl2 (sat), KCl|| Chloride is used to

maintain constant ionic strength

Page 15: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Reference Electrodes

The SCE (Saturated Calomel Electrode) Different KCl concentrations

can (and are used) 0.1 M – least temperature

sensitive Saturated – easier to make

and maintain.

Eref = 0.244 V @STP

Reaction Eo (V)Hg2Cl2 + 2e- ->2Hg(l) + 2Cl- 0.244 V

Page 16: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

HgHg22ClCl22 + 2e + 2e-- ->2Hg(l) + 2Cl ->2Hg(l) + 2Cl-- 0.241 0.241AgClAgCl (s) (s) + e + e-- ->Ag(s) + Cl ->Ag(s) + Cl-- 0.197 0.197

Page 17: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Sensing electrodes

Several types Simple Metal Solid State Electrodes Glass Membrane Etc.

Let’s look at some examples.

Page 18: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Sensing electrodes

Several types Simple Metal Solid State Electrodes Glass Membrane Etc.

Let’s look at some examples.

Page 19: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Simple metal electrodes

A bare metal in contact with a solution.

General Form: Mn+ + ne- -> M(s)

Page 20: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Simple Metal Electrodes A bare metal in contact with a

solution of its cation.

Ag+ + 1e- -> Ag(s) 0.799 V

General formMn+ + ne- -> M(s)

][

1log

0592.0

AgnEE o

ind

][

1log

0592.0n

oind Mn

EE

Page 21: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Example

A potential of 0.5000V was measured vs. SCE. What is the concentration of Ag+?

Hg2Cl2 + 2e- 2Hg(l) + 2 Cl- Eo = 0.241V

Ag+ + e- Ag(s) Eo = 0.799VUsing a simple metal electrode (Ag) and a reference electrode (Calomel), the voltage determined from this potentiometric set-up provides us with a direct measure of concentration

no calibration plot required!!no calibration plot required!!

Page 22: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Simple Metal Electrodes

Example Silver sensing

electrode

][

1log

1

0592.0799.0

AgVEE indred

])log[(0592.0799.0 AgVEind pAgVEind 0592.0799.0

redoxcell EEE redEVV 244.05000.0 pAgVVV 0592.0799.0241.05000.0

pAg0592.0058.0 pAg

0592.0

0580.0

Page 23: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Example (cont’d)

pAg

0592.0

0580.0

pAg9797.0

][101 9797.0 Agx

][104.0 7 AgM

Page 24: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Simple Metal Electrodes For some metals, a good electrode can’t be made or no metals

are involved – just ions or gas! An inert indicating electrode is used (graphite or Pt).

This type only measures the ratios of ions.

No quantitation but suitable for titrations!No quantitation but suitable for titrations!

Page 25: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Simple Metal Electrodes For some metals, a good

electrode can’t be made or no metals are involved – just ions or gas! An inert indicating electrode is used (graphite or Pt).

This type only measures the ratios of ions.

No quantitation but suitable for titrations!

Calomel(Hg2Cl2)

Page 26: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Simple Metal Electrodes

Eoverall = Eox + Ered

Calomel(Hg2Cl2)

][

][log

1

0592.03

2

Fe

FeEE o

red

Constant = -0.241 V

Reduction at Platinum Electrode:Reduction at Platinum Electrode:

Reaction Eo

Fe3+ + 1e- -> Fe2+ 0.771 V

][

][log0592.0771.0

3

2

Fe

FeVEred

Page 27: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Simple Metal Electrodes For some metals, a good

electrode can’t be made or no metals are involved – just ions or gas!

This type only measures the ratios of ions.

No direct quantitation but suitable for titrations! Calomel

(Hg2Cl2)

CeCe4+4+

Page 28: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

REDOX titrations

“Your titrant is commonly an oxidizing agent although reducing titrants can be used.”

Consider:Ce4+ + Fe2+ Ce3+ + Fe3+

General form:Aox + Bred Ared + Box

Page 29: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Determination of the Equivalence Point

The equivalence point is based on the concentration of the oxidized and reduced form of all species involved Use Nernst Equation to find Eeq.

Page 30: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Equivalence Point

][

][log

05916.0

ox

red

A

oAA A

A

n

VEE

][

][log

05916.0

ox

red

B

oBB B

B

n

VEE

Since at equilibrium, [Ared] = [Box] and [Bred] = [Aox] we massage the two general equations to yield:

BA

oBB

oAA

eq nn

EnEnE

Nernst Equation for ANernst Equation for A

Nernst Equation for BNernst Equation for B

Page 31: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Equivalence Point

BA

oBB

oAA

eq nn

EnEnE

Note: This expression only works for simple REDOX TITRATIONS:

Simple redox titrations:Only Aox, Box, Ared, Bred are involved in the reaction …

Page 32: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Two examples

Determine Eeq for the following reactions: Fe2+ + Ce4+ -> Fe3+ + Ce3+

Sn2+ + 2Ce4+ -> Sn4+ + 2Ce3+

Page 33: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Titration curves

What does a titration curve look like for an acid/base titration?

Typical pH titration

0

2

4

6

8

10

12

14

0 5 10 15 20

mL of HBr

pH

Page 34: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

REDOX Titrations

Ecell

OverTitration

Page 35: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Just like Acid/Base Titrations

There are four significant regions, The StartThe Start The Buffer RegionThe Buffer Region The equivalence PointThe equivalence Point OvertitrationOvertitration

Let’s Use our simple example:Let’s Use our simple example: FeFe2+2+ + Ce + Ce4+4+ Fe Fe3+3+ + Ce + Ce3+3+

Page 36: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Our simple example

Let’s Use our simple example:Let’s Use our simple example: FeFe2+2+ + Ce + Ce4+4+ Fe Fe3+3+ + Ce + Ce3+3+

Titrate 50 mL of 0.05 M Fe2+ with 0.10 M Ce4+

Page 37: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

0% Titration0% Titration

Unlike acid/base titrations, we can’t find this point exactly.

While some Fe3+ must be present, we can only guess what the concentration is.

No Ce4+ or Ce3+ present, so we don’t have a complete reaction

Page 38: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

0% Titration0% Titration

][

][log

05916.03

2

Fe

Fe

n

VEE

A

oFeFe

0

05.0log

1

05916.0771.0

VVEFe

FeENO … some of the iron is oxidized by air to give some Fe3+ … how much ? We generally estimate that less Than one in 1000 are oxidized.

5105

05.0log

1

05916.0771.0

x

VVEFe

SHE vs.594.0177.0771.0 VVV

Page 39: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

“Buffer Region”

FeFe2+2+ + Ce + Ce4+4+ Fe Fe3+3+ + Ce + Ce3+3+

10 ml of Ce4+ is added

Goes to completion … Excess Fe2+ pushes equilibrium to the right.

Thus E is not dependent on Ce3+/Ce4+, but only on Iron.

Page 40: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

“Buffer Region”

][

][log

05916.03

2

Fe

Fe

n

VEE

A

oFeFe

2

2

107.1

105.2log

1

05916.0771.0

V

VEFe

VVEFe 761.0010.0771.0

Page 41: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Closer look at the “buffer” region

Fe2+/Fe3+ E

9 0.715

4 0.735

1.5 0.761

1 0.771

.25 0.807

.11 0.829

Page 42: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Equivalence PointEquivalence Point

From Before Eeq = 1.24 V

What volume?

25 ml

Page 43: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Excess Ce4+ (post titration) FeFe2+2+ + Ce + Ce4+4+ Fe Fe3+3+ + Ce + Ce3+3+

The predominate change is that CeThe predominate change is that Ce4+4+ is being added and is being added and diluteddiluted into a solution of Ceinto a solution of Ce3+3+..

All FeAll Fe2+2+ has been converted to Fe has been converted to Fe3+3+ and no longer figures into the and no longer figures into the calculationscalculations

We just need to keep track of the amounts of CeWe just need to keep track of the amounts of Ce3+3+ and Ce and Ce4+4+ as as well as the well as the VOLUME of the system.VOLUME of the system.

Page 44: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Excess Ce4+ (post titration)

At 30.0 mL Ce4+ Vt = 30.0 mL+ 50.0 mL

][

][log

05916.04

3

Ce

Ce

n

VEE oCeCe

][

][log

1

05916.070.1

4

3

Ce

CeVECe

Page 45: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Excess Ce4+ (post titration)

FeFe2+2+ + Ce + Ce4+4+ Fe Fe3+3+ + Ce + Ce3+3+

Ce3+/Ce4+

?][ 3 Ce

?][ 4 Ce

Page 46: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Excess Ce4+ (post titration)

][

][log

1

05916.070.1

4

3

Ce

CeVECe

3

2

102.6

101.3log

1

05916.070.1

x

xVECe

SHE vs.66.1041.070.1 VECe

Page 47: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Redox IndicatorsRedox Indicators

General

Specific

Page 48: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

General Redox Indicators

Varies as a function of Ecell

Rely on a color change with Indox and Indred being different colors.

Indox + ne- Indred

][

][log

05916.0

ox

redoind Ind

Ind

n

VEE

Page 49: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

General Redox Indicators

In order to see a color change, you typically need approximately a 10% conversion from one form to another.

1

10

10

1

][

][ or

Ind

Ind

ox

red

n

VEE oind

05916.0

Page 50: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

General Redox Indicators

Examples Consider 1,10 phenanthrolene-Fe

C

C

N N

Fe(III)

C

C

N N

Fe(II)

+ e-

BLUEBLUE REDRED

Eo = 1.06 V

Page 51: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

General Redox Indicators

NH

S

O

O

OH

Examples Consider Diphenylamine sulphonic acid

Used with the iron in the dichromate method

Eo = 0.80V

Page 52: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

SPECIFIC INDICATORS

Example from lab Starch

Starch + I3- blue complex

It is easy to detect and color change is rapid!! This interaction explains why we use iodine as a titrant even though it is a very weak oxidant.

Page 53: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Common Titrants

Usually oxidizing agents. Cr2O7

2- - need an indicator Very stable E=1.44 V

MnO4-

Solutions must be standardized Reagent slowly degrades No indicator needed excess reagent is pink - E=1.51 V

Ce4+ - Example in Class

Page 54: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Common titrants

Reducing Titrants Fe2+

Usually Fe(NH4)2(SO4)2.6H2O in 1M H2SO4

Solution must be standardized each day I-

Indirect methodYour lab was an excellent example

Page 55: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Sensing electrodes

Several types Simple Metal Glass Membrane Solid State Electrodes Etc.

Let’s look at some examples.

Page 56: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Membrane Electrodes A potential difference is

created across a membrane that can be measured.

THERE IS NO CHANGE IN THE SOLUTIONS

“These electrodes are fundamentally different from metal electrodes in that they DO NOT involve redox reactions!!

These Electrodes ‘selectively bind’ the ion of interest

Page 57: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Membrane electrodes

pH Electrode First Discovered in early 1900’s! Refined through

the 1950’s Probably the most important

Relies on a Glass Membrane H3O+ selectively binds to glass membrane Na+ sluggishly transported across Potential is measured across the membrane!

Page 58: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

pH membrane

Special Glass (72% SiO2) Doped with Na2O (22%)

and CaO (6%)

SiOCation

Key

Page 59: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Membrane Electrodes In order to work the Glass

must be hydrated To allow for diffusion of H+

and Na+ H3O+ populates BOTH side

of the electrode BUT DOES NOT cross the membrane

To perform an electrical measurement - Must be a complete circuit! But Na+ ‘sluggishly’ crosses

the membrane. Na+ transport ~ salt bridge Membranes resistance ~

1x108-9

Page 60: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Membrane Electrodes

While H3O+ causes a response, other ions also ‘interfere’. Alkali Error Many alkali metals (Li+, Na+, K+)

Severe interference result when Alkali ion is in greater concentration than H3O+

This false response is called Alkaline Error b/c of error associated when measuring solutions of sodium hydroxide. (NaOH)

Note – the electrode shows little interference with OH-. Why?

Page 61: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Membrane Electrodes

Acid Error Too many of the Si-O- sites are saturated with

H3O+ and no more sites are available for protonation.

The response of real glass electrodes is described by the following equation:

)(log)0592.0(constant outsideAE H B is the electromotive efficiency (ideally =1, usually > 0.98)

Page 62: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Sensing electrodes

Several types Simple Metal Glass Membrane Solid State Electrodes Etc.

Let’s look at some examples.

Page 63: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Solid State Electrodes

The F- ISE The original solid state

electrode Works due to defects in a

LaF3 crystal.

Other Solid state electrodes work based on the presence of primary absorbed ion.

LaF3/Eu

Page 64: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

F- Inorganic CrystalThe solid state electrode is a very popular type of ISE. As easy to maintain as a pH electrode (sometimes easier).

Page 65: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Solid State Electrodes

Our TISAB the pH was 5-6 and the ionic strength was held constant. Why?

F- and OH- are about the same size AND same CHARGE!! LaF3/Eu2+ doped crystal selects for size and charge Thus, OH- will cause a response.

Page 66: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Solid State Electrodes

Our TISAB the pH was 5-6 and the ionic strength was held constant. Why?

)(log)0592.0(constant outsideAE F

)]([log)0592.0(constant outsideFE F

)](log[)0592.0(log)0592.0(constant outsideFE F

Constant

)](log[)0592.0('constant outsideFE

Page 67: Announcements Course Evaluations Final is Wednesday Afternoon on May 9 th Homework 14-15, 14-26, 15-6, 16-3, 16-6,

Conclusions Several types

Simple Metal – Using Metal associated with Ion

Direct Quantitation Using Inert Electrode

Yields Information on Ratio of concentrations Glass Membrane

pH Electrode Two reference electrodes (Constant Potential) Measuring the ‘junction’ potential Alkali Error

Solid State Electrodes Flouride ISE Measuring junction potential Acid and Base Error

Interferences are based on similar size and charge for Membrane electrodes and SS Electrodes

Detection limits are between 10-6 M and 10-8 M