announcements assignment 1 solutions posted assignment 2 due thursday first mid-term thursday...
Post on 20-Jan-2016
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Announcements
• Assignment 1 solutions posted
• Assignment 2 due Thursday
• First mid-term Thursday October 27th (?)
Lecture 8 Overview
• Inductors in transient circuits
• Semiconductors
• Diodes
• Rectifying circuits
• Other Diode Applications
• Transistors
Time response of Inductors
Switch to position a:
0
0
iRdt
dIL
iRVL
iR
didt
L
dt
diLiR
1
Integrate and apply boundary condition t=0, i=0
)1( L
Rt
eR
i
Time constant τ=L/R.
Switch to position b:L
Rt
eR
i
Talk about "Charging a capacitor"
"Current build-up" in an inductor
)1( L
Rt
eR
i
)L
Rt
L ev
LL v
Ri ,
Time response of Inductors
A battery is connected to an inductor. When the switch is opened does the light bulb:
1.Remain off2.Go off3. Slowly Dim out4. Keep burning as brightly as it did before the switch was opened5. Flare up brightly, then dim and go out
Answer 5
SemiconductorsSimple review of basic concepts: What is a semiconductor?(for more detail see e.g. Simpson Ch. 4)
Elements such as Silicon and Germanium have 4 valence electrons in their outer shell
They form covalent bonds with neighbouring atoms to form strong crystal lattice structures.In pure silicon, all valence electrons are bound in the lattice structure
SemiconductorsThe addition of impurities ("doping"), such as Sb(Antimony) with 5 valence electrons, leaves one electron unbound and free to move and create a current flow (n-type semiconductor). Alternatively, an impurity with 3 valence electrons can be used to create positive "holes".
When a p-type and an n-type are joined (p-n junction), mobile electrons diffuse from the n-type to the p-type, forming positive and negative ions at fixed positions in a state of equilibrium which inhibit further transfer of electrons (depletion region) depletion region E-field
(~0.2V Ge, ~0.5V Si)+-
What happens when you apply a voltage?
Reverse bias: Apply an electric field in this direction, mobile electrons are driven away from the junction (unlike fixed charged ions). Mobile holes are also driven away in the opposite direction. Depletion region acts like an insulating slab - No current flows
Forward bias: Helps electrons overcome the depletion region. Current flows easily
For the device to conduct, electrons from the n-type region must cross the junction
applied E-field
applied E-field
Depletion region E-field
Depletion region E-field
Ideal diode• A diode is a non-linear circuit element
• Only passes current in one direction
• Constructed from a p-n semiconductor junction
Real diode
e
Tkv
eIi
BT
vvS
T 1
Diode law:IS = reverse-leakage currentv = voltage across the diodekB = Boltzmann's constante- = electron chargeT = Temperature (K)
Strong dependence on TIS is small ~ 10-6A (Ge), ~10-8(Si)
Diode Circuit
• Diodes are non-linear; how do we calculate the operating conditions? (Can’t easily use V=IR)
•Consider the simplest diode circuit
TD VVSD eII
R
VVI DDD
D
Must satisfy both equations: Operating point can be calculated by seeing when diode law line intersects load line
KVL:
When ID=0; VD=VDD
When VD=0; ID=VDD/R
Rectifying Circuit
One of the most important applications of a diode is in rectifying circuits: used to convert an AC signal into the DC voltage required by most electronics
Ideal transformer: VS/VP=NS/NP
Real transformers are ~98% efficient
Half-wave rectifier
• Only lets through positive voltages. Rejects negative voltages
Full-wave rectifier• To use both halves of the input sinusoid,can use a centre-tapped transformer:
+ +
+
- -
-
e.g. Battery Charger
or use a Bridge rectifier
• Does not require centre-tapped transformer
• Requires 2 diodes in each direction – cheap, but voltage drop is double
Bridge rectifier
• Current flow in the bridge
vO vO+ +--
Peak rectifier• Most devices need steady DC
• To smooth out the peaks and obtain a DC voltage
When source voltage < capacitor voltageDiode is reversed biasedCapacitor discharges through resistor
Another diode application: Voltage doubler
• High Voltage transformers are expensive and impractical at voltages above a few thousand Volts. How do we get higher?
C2 charges to Vsec
C1 charges to 2Vsec
Voltage doubler
• Can extend this circuit to produce extremely high voltages (~750kV).
Voltage Quadrupler
• Cockroft-Walton voltage multiplier •1932, Cavendish Labs• reached 250 kV• Accelerated protons onto a Lithium target• Split the atom!•http://www.youtube.com/watch?v=RdBqMtioh6U