ANCHOR BOLT DESIGN CALCULATIONFILLING PUMP HOUSE

I. Structural Shape

II. Design Loada. Permanent Load- Axial P = 8.895 Ton- Shear H = 0.51 Ton- Moment M = 1.344 Ton meter

b. Temporaray Load- Axial P = 8.85 Ton- Shear H = 0.489 Ton- Moment M = 1.275 Ton meter

III. Design Data

- Anchor bolt Distance 340 mm

350 mm

- Anchor bolt Diameter 16 mm- Anchor Capacity H = 1072 Kg See Anchor Bolt Capacity

T = 2051 Kg

IV. Analysis

a. Permanen Load

a.1 Check Tension Strength- Tension anchor bolt due to moment external

###3953 Kg34

So, tension on 1 (one) Anchor bolt = 1976 Kg

- Result : < T Ok!

a.2 Check Shear Strength- Shear strength on 1 (one) Anchor bolt :

510127.5 Kg4

- Result :

< Ok!

d1 =

d2 =

Db =

T o

H o Hallow

d1

d2

d1

H M

T =

=

P

d1

M =

xxx

T

Retained by 2 Ancor Bolt

Ho =

=nH =

Ddd2

b. Temporary Load

b.1 Check Tension Strength- Tension anchor bolt due to moment external

###3750 Kg34

So, tension on 1 (one) Anchor bolt = 1875 Kg

- Result : < 1.33*T Ok!

b.2 Check Shear Strength- Shear strength on 1 (one) Anchor bolt :

489122.25 Kg4

- Result :

< 1.33*H Ok!

T o

H o

T =

=d1

M = Retained by 2 Ancor Bolt

Ho =

=nH =

ANCHOR BOLT CAPACITYFILLING PUMP HOUSE

Design Data :- Anchor Bolt Diameter, D = 16 mm

- 450 mm

- Anchor Yield strength, Fy = 2400

- Concrete Grade 175

Analysis :

I. TENSION CAPACITYa. Based on steel material :

- Netto Area.

An = 0.85 * Ag 2.01

An = 1.709

- Allowable tension of anchor

Fy / 1.5

= 1600

1200

T = 2051

b. Based on concrete bonding to stell anchor :

Up = 0.1 Fc' Fc' = = 0.83 * 175

= 145

Up = 0.1 * 145.3

Up = 14.53

Anchor Length which buried by concrete can be calculate :

Where :

12 mmPJTN = 64 mm

40 mm

25 mm

321 mm

Allowable tension of anchor

T =T = 2344 Kg

2051 Kg

Anchor Bolt Length, Lanchor =

Kg/cm2

s bk = Kg/cm2

Ag = 0.25 * p * D2 = cm2

cm2

T = s tr * An s d =

Kg/cm2

s tr = 0.75 * sd

s tr = Kg/cm2

Kg/cm2

Allowable Concrete Bonding Stress (Up)

0.83 * s bk

Kg/cm2

Kg/cm2

Lburied = Lanchor - PJTN - tcover - tgrouting

PJTN = t baseplate + 2D + 20mm

tbs.pl. =

tcover =

tgrout =

Lburied =

Up x p x D x L buried

So, Allowable tension capacity of anchor T =

PJTN

L buried

tgrouting

tcover

tbs. pl

L anchor

II. SHEAR CAPACITYa. Based on steel material :

- Gross area.

2.01

- Allowable shear of anchor

(PPBBI 1984)= 928 Kg/cm2

H = 1866 Kg

b. Based on concrete bearing :- Maximum contact stress contact between concrete & rebar = 0.85 fc'

0.85 Fc' = 123

- Development length :

Ld = 0.02 Ab Fy Ab = Ag = 201 mm

Ld = 253 mm

- Sketch stress diagram :

La = 253 mm

c =c = 71 mm

Hrz force Volume of Diagram

0.5 * (0.85 Fc') * La * D

2501 Kg

S M = 0H = 1302 Kg

c. Based on bending stress of anchor :

M =

M/W W = 0.402 cm3

H = = 1072 Kg

So : 1072 Kg

Ag = 0.25 * p * D2 = cm2

H = t * Ag t = 0.58 s d

s c = kg/cm2

La = min (Lburied , Ld.)

tcover + tgrout + 0.5 t bs. pl

Ho =

Ho =

Ho =

Ho * (2/3 *La) = H * (La + c)

H x (0.5*tbs.pl)

s bend = p/32 x D3 =

Allowable shear capacity of anchor H =

Fc' 0.5

L a

0.85 Fc'

H

Ho

c

s bend x W

0.5*tbs.pl

Combine of Equation

BASE PLATE DESIGN CALCULATIONFILLING PUMP HOUSE

I. Structural Shape

External force & Stress Diagram

II. Design Loada. Permanent Load- Axial P = 8.895 Ton- Shear H = 0.51 Ton- Moment M = 1.344 Ton meter

b. Temporaray Load- Axial P = 8.85 Ton- Shear H = 0.489 Ton- Moment M = 1.275 Ton meter

III. Design Data- Base plate thickness tp = 19 mm- Base plate size N = 300 mm

B = 200 mm- Column Size H - 200 150 6 9

- Yield strength stress Fy = 2400

- Concrete Grade 225

IV. Analysisa. Permanen Load

a.1 Bearing Stress on Concrete- Concrete bearing stress :

8895 13440059.625

600 3000

- Allowable bearing stress for Concrete :

Fp = 78.75

- Result : < Fp Ok!

a.2 Bearing Stress on Base Plate- Moment maximum on base plate

m= 0.5 (N - 0.95d) = 5.5 cm

### Kg cm

n = 0.5 (B - 0.80bf) = 4.00 cm

Kg/cm2

Kg/cm2

Kg/cm2

0.35 sbk = Kg/cm2

s

M1 = 1/2 (sxB) m2

M1 =

M2 = 1/2 (sxN) n2

B

N

bf

d

P/A

H M

s =

=

sbk =

P

BxNP + M

1/6 BxN2+ =

xxx

M/W

n

n

0.80*bf

0.95*d mm

M2

M1

### Kg cm

- Stresses on base plate :

18036.561499

12.03

14310.00792.8

18.05

- Allowable bending stress of base plate :

0.75 * Fy = 1800

- Summary :

< Ok!

< Ok!

b. Temporary Load

b.1 Bearing Stress on Concrete- Concrete bearing stress :

8850 12750057.25

600 3000

- Allowable bearing stress for Concrete :

Fp = 105

- Result : < Fp Ok!

b.2 Bearing Stress on Base Plate- Moment maximum on base plate

m= 0.5 (N - 0.95d) = 5.5 cm

### Kg cm

n = 0.5 (B - 0.80d) = 4.00 cm

### Kg cm

- Stresses on base plate :

17318.131439

12.03

13740.00761.2

18.05

- Allowable bending stress of base plate :

1.33 (0.75 * Fy) = 2394

- Summary :

< Ok!

< Ok!

M2 =

s1 =M1

Kg/cm2

1/6xBxtp2

s2 =M2

Kg/cm2

1/6xNxtp2

s allow = Kg/cm2

s1 s allow

s2 s allow

Kg/cm2

1.33*0.35 sbk = Kg/cm2

s

M1 = 1/2 (sxB) m2

M1 =

M2 = 1/2 (sxN) n2

M2 =

s1 =M1

Kg/cm2

1/6xBxtp2

s2 =M2

Kg/cm2

1/6xNxtp2

s allow = Kg/cm2

s1 s allow

s2 s allow

==

==

s =

=BxN

P + M1/6 BxN2

+ =

==

==